Answer:
The magnitude and direction of the centripetal acceleration will be:
[tex]a_c=5[/tex] m/s² (towards the center of the circle).
Explanation:
Given
v = 10 m/sr = 20 mUsing the formula to determine the centripetal acceleration
[tex]a_c=\frac{v^2}{r}[/tex]
[tex]a_c=\frac{\left(10\right)^2}{20}[/tex]
[tex]\:a_c=\frac{100}{20}[/tex]
[tex]a_c=5[/tex] m/s²
As the truck is moving in a circle, therefore the direction is towards the center of the circle.
Hence, the magnitude and direction of the centripetal acceleration will be:
[tex]a_c=5[/tex] m/s² (towards the center of the circle).
help me for 11 point pls
Answer:
B
Explanation:
Hope this helps. :)
Using Velocity vs Time Graphs to Find Acceleration
A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line has 4 straight segments. Line segment A runs from 0 seconds 0 meters per second to 1 seconds 15 meters per second. Then segment B runs to 2 seconds 20 meters per second. Then segment C runs to 4 seconds 20 meters per second. Then segment D runs to 5 seconds 0 meters per second.
The acceleration of segment D is m/s2.
Rank segments A, B, and C from least acceleration to greatest acceleration.
Least:
Greatest:
The acceleration at segment D is -20m/s²
The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)
Acceleration is the change in velocity with respect to time.
a = v-u/t
Acceleration at segment A:
Aa = 15-0/1-0
Aa = 15m/s²
Acceleration at segment B:
Ab = 20-15/2-1
Ab = 5m/s²
Acceleration at segment C:
Aa = 0-0/4-2
Aa = 0m/s²
Acceleration at segment D:
Ac = 0-20/5-4
Ac = -20m/s²
Hence the acceleration at segment D is -20m/s²
The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)
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help pls its been a day
Answer:
161.28m
Explanation:
The resultant is calculated using the formula
R² = dx²+dy²
R = √dx²+dy²
From the diagram. dx = 101cos60°+85
dx = 101(0.5) + 65
dx = 50.5 + 85
dx = 135.5m
For the vertical component dy
dy = dsin theta
dy = 101 sin 60
dy = 101(0.8660)
dy = 87.47
R = √135.5²+87.47²
R = √18,360.25+7,651.0009
R = √26,011.2509
R = 161.28m
Hence the magnitude of the sum of the vectors is 161.28m
Answer:
The sum of the two vectors is 161.278 m.
Explanation:
Given;
vector, B = 101 m inclined at angle 60⁰
vector, A = 85 m inclined at angle 0⁰
Y-component of the vectors;
[tex]R_y = 101(sin \ 60^0) + 85(sin \ 0^0) =87.466 \ m[/tex]
X-component of the vectors;
[tex]R_x = 101(cos \ 60^0) + 85(cos \ 0^0)\\\\R_x = 50.5 + 85 = 135.5 \ m[/tex]
Sum of the two vectors;
[tex]R = A+ B\\\\R = \sqrt{R_y^2 + R_x^2} \\\\R = \sqrt{87.466^2 \ + \ 135.5^2} \\\\R = \sqrt{26010.55} \\\\R = 161.278 \ m[/tex]
Therefore, the sum of the two vectors is 161.278 m.
Calculate the kinetic energy of a 50 kg cart moving at a speed of 18.6 m/s.
Answer:
8649 J
Explanation:
KE = 1/2mv^2
1/2(50)(18.6)^2
1/2(50)(345.96) = 8649 J
In the following figure identify ‘A’ and ‘B’ which represents different colours of the spectrum. Why does this phenomenon occur?
Answer:
A is red
B is violet
Explanation:
A has a high penetration power hence greatest frequency and short wavelength in accordance to the diagram above.
The color with greatest frequency is red.
B has the least penetration power as it is greatly refracted in accordance to the diagram which shows that it has least frequency and high wavelength.
The color of least frequency is violet.
A plane lands and comes to a complete stop. If the plane covers 200 m and decelerates at 7.5 m/s2 , what was the planes initial velocity as it touched the runway?
Answer:
The initial velocity of the plane is 54.77 m/s
Explanation:
Given;
distance covered by the plane, d = 200 m
deceleration of the plane, a = - 7.5 m/s²
The initial velocity of the plane is given by the following kinematic equation;
v² = u² + 2ad
where;
v is the final velocity of the plane when the plane comes to a complete stop = 0
u is the initial velocity of the plane
0 = u² + 2(-7.5 x 200)
0 = u² - 3000
u² = 3000
u = √3000
u = 54.77 m/s
Therefore, the initial velocity of the plane is 54.77 m/s
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 35 m/s. The ball has __________________ energy. Calculate it.
Answer:
The ball has kinetic energy
the kinetic energy is 945 J
Explanation:
Answer:
The ball has 1286.25 J of energy
Explanation:
Kinetic Energy
Is the type of energy of an object due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where:
m = mass of the object
v = speed at which the object moves
The kinetic energy is often expressed in Joules (J).
The volleyball of a mass m=2.1 Kg is served at v=35 m/s, calculating its kinetic energy:
[tex]\displaystyle K=\frac{1}{2}\cdot 2.1\cdot 35^2[/tex]
[tex]\displaystyle K=\frac{1}{2}\cdot2.1\cdot 1225[/tex]
K = 1286.25 Joule
The ball has 1286.25 J of energy
Acceleration is a change in speed or direction over time. In what two ways does the sled accelerate as it descends?
Answer:
By force and sloppy surface.
Explanation:
By applying force on the sled and slope of the path are the two ways the sled accelerate as it descends. If there is more friction between sled and the ground then force is required to push the sled to move downward while on the other hand, if the path on which sled moves is sloppy then it will move automatically without the use of force, so these two ways can accelerate the sled.
What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
A student rings a brass bell with a frequency of 200 Hz. The sound wave
travels through brass, air, and glass. What is the wavelength of the wave in
brass?
Medium
Wave speed
(m/s)
Brass
4,700
Air
346
Glass
5,640
A. 2.3 m
B. 0.43 m
C. 0.043 m
D. 23.5 m
Answer:
Option D. 23.5 m
Explanation:
From the question given above, the following data were obtained:
Frequency = 200 Hz
Speed of sound in brass = 4700 m/s
Wavelength of sound in brass =?
We can obtain the wavelength of the sound in the brass by using the following formula as illustrated below:
Wave speed = wavelength × frequency
4700 = wavelength × 200
Divide both side by 200
Wavelength = 4700 / 200
Wavelength = 23.5 m
Thus, the wavelength of the sound in the brass is 23.5 m
obtain the temp. at which the reading of Fahrenheit is double of that in Celsius scale.
Answer:
320 degrees fahrenheit and 160 degrees celcius
Explanation:
there's a formula that i definately don't remember but it exists
** 8. How many atoms of Carbon are in C2H40?
Answer:
2
Explanation:
A huge enormous gigantic number ... two in every molecule of the stuff !
the center of mass of a donut is located ?
a. in the hole
b. in material making up the donut
c. near the center of gravity
d. over a point of support
Answer:
A
Explanation:
where the hole is because it's a rigid object with uniform density.
I have to make three videos for physics about Newton's three laws of motion but I don't want to be in the videos or talk in them. Any ideas on how I could do that?
Answer:
You should face your fears sometimes, and get in front of a crowd do present your ideas. Not everyone is good at it, and many people get anxious when they have to speak in front of people but it’s best if you just do it and get it over with and maybe it won’t be as intimidating next time :)
a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3
Answer: 1.6 N
Explanation:
The weight of an object is calculated as:
W = g*m
where:
g = gravitational acceleration = 9.8m/s^2
m = mass of the object.
We also know that:
mass = density*volume.
or:
m = d*v
Let's start:
The weight of the beaker is 0.4N
And the weight of the beaker filled with water is 1.4N
Then the weight of the water alone will be:
1.4N - 0.4N = 1N = (d*v)*9.8m/s^2
And we know that the density of the water is:
1 g/cm^3
But we are working with Newtons, then we need to rewrite this with kilograms as the mass unit, we can use that:
1000g = 1kg
Now we can rewrite the density as:
d = 1 g/cm^3 = 1*(1/1000) kg/cm^3 = 0.001 kg/cm^3
Replacing that in the above equation, we get:
With this, we can find the volume that the water occupies.
W = 1 N = v* 0.001 kg/cm^3*9.8m/s^2
1 N /( 0.001 kg/cm^3*9.8m/s^2 ) = 102.04 cm^3.
Now, when we fill it with a brine with a density of 1.2 g/cm^3, the mass of this brine in a volume of 102.04 cm^3 be:
M = (1.2 g/cm^3)*( 102.04 cm^3) = 122.448 g
Rewriting this in kg we get:
M = 122.448 g = (122.448/1000) kg = 0.122448 kg
Then the weight of this brine is:
M = 0.122448 kg*9.8m/s^2 = 1.2 N
And the beaker weighs 0.4N, then the beaker filled with this brine will weight:
1.2 N + 0.4N = 1.6 N
Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
a) The resistance of each lamp.
b) The effective resistance of the circuit.
c) The current passing the lamps. pls answer correctly
Answer:
See the answers below.
Explanation:
The total power of the circuit is equal to the sum of the powers of each lamp.
[tex]P=60+100\\P=160 [W][/tex]
Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.
[tex]P=V*I[/tex]
where:
P = power [W]
V = voltage [V]
I = current [amp]
[tex]I = P/V\\I=160/240\\I=0.67 [amp][/tex]
So this is the answer for c) I = 0.67 [amp]
We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.
a)
[tex]V=I*R[/tex]
where:
V = voltage [V]
I = current [amp]
R = resistance [ohms]
Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.
[tex]P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R[/tex]
[tex]60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm][/tex]
b)
The effective resistance of a series circuit is equal to the sum of the resistors connected in series.
[tex]R = 133.66 + 225\\R = 358.67 [ohms][/tex]
2. What is the power rating of an engine capable of lifting a 100 kg object 5 m vertically
in 4 seconds?
Given values are:
Force,
f = 100Time,
t = 4 secondsNow,
→ [tex]Work \ done= f\times d[/tex]
[tex]= 100\times 50[/tex]
[tex]= 500[/tex]
hence,
The power will be:
= [tex]\frac{Work}{time}[/tex]
= [tex]\frac{500}{4}[/tex]
= [tex]125 \ watt[/tex]
Thus the response above is right.
Learn more about power here:
https://brainly.com/question/13534333
6. A student notices that when a weight is hung on a spring, the spring stretches. She decides conduct an experiment to determine the relationship between the amount of weight
placed on a spring and the distance the spring stretches. She has five different weights: 25 9,50 9.75 9, 1009, and 125 g. She selects a weight, hangs it on the spring, and
measures how far the spring stretches
What is the dependent variable in this experiment?
O weight hung from the spring
O temperature of the spring
length of unstretched spring
distance the spring stretches
Answer:
D
Explanation:
She says that the object of the experiment is to see how far the string stretches given a mass attached to the string.
The only thing that is at issue is either the mass or the amount the string stretches.
Nothing else matters.
The dependent variable therefore is the amount the string stretches. So the last choice is the answer.
A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she uses the ramp, the applied force required is
Answer:
answer is 1/2 as much force required
A 250-kg moose stands in the middle of the railroad tracks in Sweden, frozen by the lights of an oncoming 10,000kg train traveling at 20m/s. Even though the engineer attempted in vain to slow the train down in time to avoid hitting the moose, the moose rides down the remaining track sitting on the train’s cowcatcher. What is the final velocity of the train and moose after the collision?
(Momentum & Impulse)
Answer:
The final velocity of the train and the moose after collision is approximately 19.51 m/s
Explanation:
The given mass of the moose, m₁ = 250 kg
The velocity of the moose, v₁ = 0
The mass of the oncoming train, m₂ = 10,000 kg
The velocity of the train, v₂ = 20 m/s
The velocity of the moose and the train after collision = v₃
By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision
m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃
Therefore, by substitution, we have;
250×0 + 10,000× 20 = (10,000 + 250) × v₃
200,000 = 10,250 × v₃
v₃ = 200,000/10,250 ≈ 19.51 m/s
The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s
why watchman does no work but gets tired ?
Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.
Explanation:
explain the difference between reversible and irreversible
Answer:
The difference between reversible and irreversible is reversible can be changed but irreversible can not.
what are the effects of moon rotation and revolution
Answer:
The effects of the Moon's rotation includes;
1) The Moon rotation and revolution gives the appearance of a perfectly still Moon to observers of the Moon from the Earth
2) The Moon has two sides, the near side that continuously faces the Earth and the "back" or far side, which is also known as the dark side of the Moon
The effect of the Moon's revolution
1) The tides in the ocean and water bodies, due to the gravitational forces from the Moon
2) The changes in the observed shape of the Moon due to the amount of Sunlight that is able to be reflected from the Moon as a result of the relative position of the Moon, the Earth and the Sun, at a given point in time
3) Lunar and Solar eclipse, when the Earth and the Moon blocks the light coming from the Sun respectively, due to their combined revolution
Explanation:
The duration of the Moon's orbit round the Earth = 27.322 days
The time it takes the Moon to rotate round its axis = 27 days
The Moon is the closest cosmic body to the Earth.
explain why an inflated balloon is likely to burst if you leave it near a window with the sun streaming it?
Answer:
the sun light will heat up the balloon causing it to burst
1. The geologic time scale divides time into years and centuries, true or false
Answer:
The answer is "False"
Explanation:
The geologic time scale is the "schedule" for occasions in Earth history. It partitions time into named units of unique time called in descending order of duration "eons, eras, periods, epochs, and ages". The specification of those geologic time units depends on stratigraphy, which is the relationship and order of rock layers. The fossil structures that happen in the stones, nonetheless, give the central methods for setting up a geologic time scale, with the circumstance of the development and vanishing of far and wide species from the fossil record being used to outline the beginnings and endings of ages,, periods, and different stretches.
Geologic time is the broad time period involved by the geologic history of Earth. Formal geologic time starts toward the beginning of the Archean Eon (4.0 billion to 2.5 billion years back) and proceeds to the current day.
Calculate the mass of a man jogging north along the highway at a rate of 2.65 m/s and a momentum of 225.3 kg*m/s
Answer:
85.02 kgExplanation:
The mass of the man can be found by using the formula
[tex]m = \frac{p}{v} \\ [/tex]
v is the velocity
p is the momentum
From the question we have
[tex]m = \frac{225.3}{2.65} \\ = 85.01886...[/tex]
We have the final answer as
85.02 kgHope this helps you
a force of 50 newtons pulls a rope attached to a 150 newton sled across a horizontal surface at a constant velocity of 5 meters per second. The rope is at an angle of 35 degrees above the horizontal. calculate the magnitude of the frictional force acting on the sled? Show all work, including the equation and substitution with units.
Answer:
I don't know the answer I hope you find it tho good luck##
A satellite is on orbit 35600 km above the surface of the earth.its angular velocity is 7.25×10–5 rad/sec.What is the vrlocity of the satellite?(The radius of the earth is 6400 km
Answer: 3.045 km/s
Explanation:
When an object is doing a circular motion, the velocity of the object is written as;
v = r*w
where;
r = radius of the circle
w = angular velocity.
In this case, we know that:
w = 7.25*10^(-5) s^-1
And the radius will be equal to the radius of the Earth, plus the height of the satellite, this is:
R = radius of the Earth + 35600 km = 6400km + 35600 km = 42000 km
Then the velocity of the satellite will be:
v = 42000 km*7.25*10^(-5) s^-1 = 3.045 km/s
The velocity of a satellite with an orbit 35600 km above the surface of the earth and an angular velocity of 7.25×10–5 rad/sec = 3045 m/s
Velocity: This is the rate of change of displacement.
To solve this problem we need to use the formula for calculating the velocity of an object in circular motion
The Velocity of the satellite is given as
V = ωr................ Equation 1
where V = velocity of the satellite, ω = angular velocity of the satellite, r = radius of the circle.
Note: r = height of the satellite above the surface of the earth+Radius of the earth
From the question,
Given: ω = 7.25×10⁻⁵ rad/sec, r = 35600+6400 = 42000 km = 4.2×10⁷ m
Substitute these values into equation 1
V = (7.25×10⁻⁵)(4.2×10⁷ )
V = 30.45×10²
V = 3045 m/s
Hence, the velocity of the satellite is 3045 m/s
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how the number of batteries and the number of coils of wire affect the strength of an electromagnet.
A racecar is driving around a circular track. The car is moving with a speed of 49.7 m/s, and the track has a radius of 114 m. What is the magnitude of the centripetal acceleration of the car?
Answer:
21.67 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 49.7 m/s
Radius (r) = 114 m
Centripetal acceleration (a) =?
The centripetal acceleration can be obtained by using the following formula:
a = v²/r
a = 49.7² / 114
a = 2470.09 / 114
a = 21.67 m/s²
Therefore, the centripetal acceleration of the car is 21.67 m/s²