Answer:
n=1500/60 to get , it into rev/sec
W=2πn = 50π
T=P*W=1.8 *50π=282.74 N.M
Explanation:
What’s are the preventive strategies for workplace violence
"Well, this is a fine how-do-you-do. I come all the way over here to introduce my friends, R.W. and Melvin, to y'all and y'all actin' like y'all ain't got no manners at all. Yeah, ole R.W. and Melvin," he said, rolling the Simmses' names slowly off his tongue to bring to our attention that he had not bothered to place a "Mister" before either, "they been mighty fine friends to me. Better than any of y'all. Look, see here what they give me." Proudly he tugged at the suit coat. "Pretty nice stuff, eh? Everything I want they give me 'cause they really likes me. I'm they best friend." —Roll of Thunder, Hear My Cry, Mildred D. Taylor What do T. J.’s actions indicate?
A. He dislikes that his old friends never bought him things.
B. He is showing off his new friends’ generosity.
C. He feels sorry that his old friends do not have nice things.
D. He is angry about the way his old friends treated him.
Answer:
B. He is showing off his new friends’ generosity.
Explanation:
Answer: B He is showing off his new friends' generosity
Explanation: 2020 EDGE is correct with B
An alternating current is supplied to an electronic component with a rating that it be used only for voltages below 12 V. What is the highest Vrms that can be supplied to this component while staying below the voltage limit
Answer:
[tex]V_{rms}=6\sqrt2\ V[/tex]
Explanation:
Given that,
The maximum voltage of an alternating current, [tex]V_{max}=12\ V[/tex]
We need to find the highest Vrms that can be supplied to this component while staying below the voltage limit.
Let rms voltage in terms of peak voltage is given by :
[tex]V_{rms}=\dfrac{V}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\times \dfrac{\sqrt2}{\sqrt2}\\\\=\dfrac{12\sqrt2}{2}\\\\=6\sqrt2\ V[/tex]
Hence, the required rms voltage is [tex]6\sqrt2\ V[/tex].
list the major parts in a shop's air supply system
Answer:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
Answer:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
Explanation:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
30 KJ of heat energy is supplied to a 4.5 kg block of aluminum at 20°C.Calculate the final temperature of the block,if the specific heat capacity of aluminum is 948 J kg^-1 K^-1 and no loss of heat energy
Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calculate the metal removal rate (MRR)
Answer:
Explanation:
The material rate of removal is the total amount of material removed per unit time during any operation. The material rate of removal is usually given by the formula
Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where
Radial Depth of Cut, RDOC = 25 mm
Axial depth of cut, ADOC = 200 mm
Feed rate, FR = 25 mm/min
On multiplying all together, we will then have our Material Rate of Removal, which is
MRR = 25 mm * 200 mm * 25 mm/min
MRR = 125000 mm³/min
Or we convert it to cm³/min and have
MRR = 125000 mm³/min ÷ 1000
MRR = 125 cm³/min
Select three mechanical processes used in the manufacturing phase of engineering.
Drying
Mixing
Cooling
Crystallization
Size reduction
Food packaging
Answer:Size reduction
Cooling
Mixing
Explanation:
For many clients, a decision is based primarily on time and money, which are the two most abundant
resources a company has.
True or False
Electricians will sometimes call ______ "disconnects" or a "disconnecting means."
A) Two-pronged plugs
B) Electrical cords
C) Switches
D) Three-pronged plugs
(This is for my Automotive class)
Answer:
C.switches
Explanation:
A light commercial building located in Philadelphia, Pa has construction and use characteristics much like a residence and design heating load of 120,000 Btu/h and cooling of 60,000 Btu/h. Determine the following: (a) Heating energy requirement, Btu(b) Gallons of No. 2 fuel oil/year, assuming efficiency of the furnace is 75 %(c) Cubic feet of natural gas/year(d) kWh of electricity for cooling for air conditioner with SEER of 8.5 using degree day method.(6 points)
Answer:
b
Explanation:
Which of the following is the term for a sliding device that moves against or is moved by fluid pressure?
turbine
valve
piston
fluid
Answer:
piston
a sliding device that moves against or is moved by fluid pressure; usually consists of a cylindrical body within a cylindrical chamber
Explanation:
2021 EDGE I got it correct :D
A fluid flows though a horizontal 0.1 inch diameter pipe. When the Reynold number is 1508, the head loss over a 20-ft length of the pipe is 6.2 ft. Determine the fluid velocity.
Answer:
The fluid velocity V = 1.98 ft/s
Explanation:
From the information given:
The fluid velocity can be determined from the head-loss [tex]h_L[/tex] of a laminar pipe and it is expressed as:
[tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]
where;
f = frictional factor ; l = length; D = diameter; V= fluid velocity and g = acceleration due to gravity.
And;
[tex]f = \dfrac{64}{Re}[/tex]
For fluid movement in a laminar flow, the Reynolds number (Re) is usually lesser than 2100.
Given that:
Re = 1508 < 2100 ( laminar flow)
Then;
[tex]f = \dfrac{64}{1508}[/tex]
f = 0.04244
Also;
the head-loss [tex]h_L[/tex] = 6.2 ft
frictional force f = 0.04244
length = 20-ft
acceleration due to gravity (g) = 32.2 ft/s²
Replacing all the values into the equation [tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]; the fluid velocity is:
[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.1 \times \dfrac{1}{12} \times 2\times 32.2}[/tex]
[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.53667}[/tex]
6.2 × 0.53667 = 0.04244 × 20 × V²
3.327354 = 0.8488 × V²
[tex]V^2= \dfrac{3.327354} { 0.8488}[/tex]
[tex]V^2=3.92[/tex]
[tex]V = \sqrt{3.92}[/tex]
V = 1.98 ft/s
Naomi needs to test an application that will be accessed by multiple users simultaneously. She is planning to use LoadRunner to test the performance of the application. How can a testing tool such as LoadRunner help her with performance testing?
A.
by using a large number of testers
B.
by increasing the number of test cases
C.
by automating your test cases
D.
by creating a number of virtual users
Water vapor at a rate of 40,000 kg/h and at 8 MPa and 500 C enters an adiabatic turbine and leaves the turbine at 40 kPa as saturated vapor. The rate of entropy generation for this turbine is close to,
Answer:
M(dot)= 40000 kg/h Pressure= 8Mpa and T= 500C If its adiabatic then you know that it loses no heat or Q(dot) =0 You have a turbine which drives a shaft producing work for the other systems.We want to find entropy production of alpha.Steam enters a steady-flow adiabatic nozzle with a low inlet velocity (assume ~0 m/s) as a saturated vapor at 6 MPa and expands to 1.2 MPa.
a. Under what conditions is the velocity from this nozzle maximized?
b. Determine the maximum exit velocity of the steam, in m/s.
This happens as a result of a gain in kinetic energy at the expense of a decrease in enthalpy brought on by gas expansion as air passes through the diverging region of the nozzle.
What velocity from this adiabatic nozzle maximized?A nozzle is a tool used to change the characteristics of a fluid flow as it leaves a confined chamber or conduit, particularly to enhance velocity. The reciprocal of the nozzle length, pressure, and the square root of the nozzle diameter all increase air velocity.
A nozzle needs to be made to expand steam from 500 PA at 210 °C to 100 kPa at a rate of 0.1 kg/s. In order to reach critical or sonic conditions (i.e., choked flow) at its throat, the flow is accelerated when a nozzle is used.
Therefore, The steam's specific volume at the nozzle's exit is determined to be 1.4 m3/kg and its velocity at that point to be 700 m/s.
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Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calculate the metal removal rate (MRR)
Answer:
125 cm³/min
Explanation:
The material rate of removal is usually given by the formula
Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where
Radial Depth of Cut = 25 mm
Axial depth of cut = 200 mm
Feed rate = 25 mm/min
On multiplying all together, we will then have
MRR = 25 mm * 200 mm * 25 mm/min
MRR = 125000 mm³/min
Or we convert it to cm³/min and have
MRR = 125000 mm³/min ÷ 1000
MRR = 125 cm³/min
A hubbing press has capasity of 175tons. If the workpice ia a copper alloy part with a 2in^2 projected area, what is the strongest alloy that can be hubbed?
Answer:
The answer is "[tex]\bold{175000 \ \frac{lbs}{in^2}}[/tex]"
Explanation:
The formula for the max value of UTS:
[tex]= \frac{F}{A} \\\\= \frac{175\ ton}{ 2 \ in^2} \\\\= \frac{350000}{2}\\\\[/tex]
Max UTS:
[tex]\to 175000 \ \frac{lbs}{in^2}[/tex]
Type the correct answer in the box. Spell all words correctly.
A genetically engineered hormone, , can treat Mary’s child for growth hormone deficiencies by stimulating body growth and increasing muscle mass.
Answer:
recombinant human growth
Explanation:
Answer:
recombinant human growth
Explanation:
yes
Whose responsibility is it to identify confined spaces and reduce hazards? A The employee B The rescuer C The employer D OSHA
Answer:
C. The Employer
Explanation:
Under OSHA's Confined Space Standard, it is the responsibility of the "employer" to identify or evaluate the spaces whether they are "permit spaces" or "confined spaces." These spaces have serious safety hazards or health hazards. Examples: tanks, vessels, pits, underground vaults, and the like.
The employers need to disclose the information of the permit spaces and their risks to the employees. Thus, he should have a written permit of the permit space if he will be allowing the employees to enter. It is also the employer's responsibility to reduce the hazards imposed to the employees such as verifying the entry conditions that are acceptable, making sure the permit space is isolated, providing barriers, etc.
A(94,0,14) B(52,56,94) C(10,6,48) D(128,64,10)
The goal of the assignment is to apply methods of transforming orthogonal projections to solving metric problems.
The coordinates of four points ABCD are given (see next table). Determine the following values by transforming projection planes:
• 1. The size of the dihedral angle at the edge AB.
• 2. The shortest distance between ribs DA and BC.
• 3. Distance from vertex D to plane ABC.
• 4. Natural size of triangle ABC.
An example how to complete the task is shown after the table
9514 1404 393
Answer:
see below
Explanation:
We presume the drawing you want is contained in the figure you attached. The true sizes are identified with corresponding numbers.
Without your example, or your given methods of transforming projections, it is difficult to tell exactly how you want to compute the various distances or sizes.
_____ refers to the knowledge and skills necessary to manage, control, and work with hazardous materials and pollutants.
An ignition coil is an example of a. A. Step-up transformer. B. Step- down transformer. C. Relay.
D. Solenoid.
Answer:
D
Explanation:
An ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.
What is Solenoid?Solenoids may be characterized as a coil of wire that is usually in a cylindrical form and carries a current that acts like a magnet. Due to this, a migratory core is drawn into the coil when a current flows, and that is utilized especially as a switch or control for a mechanical device.
Similarly, an ignition coil also represents an example of a solenoid because it also consists of a coil of wire and carries a current that acts like a magnet. While the concept of the transformers is different as it stores a huge amount of electric current and spread it accordingly.
Therefore, an ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.
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Which term refers to an application of biotechnology to forensic science?
Cloning
Transgenesis
Bioprocessing
DNA profiling
Biomanufacturing
Answer:
DNA profiling
Explanation:
took the test
Which of these credit building options do you personally think is the easiest method that you can see yourself doing? Explain your reasoning.
Answer:
Explanation:
Your 3-B Annual Credit Reports & Scores with Enhanced Credit Report Monitoring.
Trusted by Millions
The credit building options that I think is the easiest method that you can see yourself doing is Secured credit cards.
What is the Secured credit cards?Secured credit cards are known to be a type of card that are said to be backed by a specific refundable security deposit.
This kind of deposit is known to limit or lower the lender's risk and thus makes it better for people who do not have credit or when they do not qualify for that type of credit. This credit option is easier to get when compared to unsecured cards, as it does not need a lot of requirement.
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A bronze bushing 60 mm in outer diameter and 40 mm in inner diameter is to be pressed into a hollow steel cylinder of 120-mm outer diameter. Calculate the tangential stresses for steel and bronze at the boundary between the two parts
Answer:
The tangential stress for the steel at 30mm = 88.8MPa.
The tangential stress for the steel at 60mm = 35.5 MPa.
The tangential stress for the bronze at 20mm = - 191.9 MPa.
The tangential stress for the bronze at 30mm = - 138.6 MPa.
Explanation:
The outer radius bronze bushing = 60 mm/2 = 30 mm, the inner radius for bronze bushing = 40mm/2 = 20mm and the cylinder radius = 120mm/2 = 60mm.
Step one: The first step is to calculate or Determine the interface pressure.
The interface pressure = 0.05/ [ [ 30 × ( 1/210 ×10⁹) ] × [( 60² + 30²/ ( 60² - 30²) + 0.3 ] + [ 1/105 × 10⁹× [ ( 20² + 30²)/( 30² - 20²) - 0.3] ].
The interface pressure = 53.3 MPa
Step two: Determine the tangential stresses for steel and bronze as given below:
The tangential stress for the steel at 30mm = 10⁶ × 53.3 [ ( 0.06)² + (0.03)²/ ( 0.06)² - (0.03)² ] = 88.8 MPa.
The tangential stress for the steel at 60mm = 10⁶ × 53.3 × 2 × [0.03]²/ ( 0.06)² - (0.03)² ] = 35.5 MPa.
The tangential stresses for the bronze is calculated below;
=> The tangential stress for the bronze at 20mm = - [ 10⁶ × 53.3 × 2 × [0.03]² ] / ( 0.03)² - (0.02)² ] = - 191.9 MPa.
The tangential stress for the bronze at 30mm = - [ 10⁶ × 53.3 × [ 0.03]² + (0.03)² ] / ( 0.03)² - (0.02)² ] = - 138.6 MPa.
In order to avoid slipping in the shop, your footwear should ___________.
(This is for my automotive class by the way)
Answer:
good shoes
Explanation:
yes
What is the base unit that is divided in an engineering scale?
An engineering scale is based on unit increments of a/n ____.
Explanation:
The most often used architect's scale is 1/4" = 1'-0". The basic unit of measure for metric scales is the millimeter (mm). Drafting scales are either open-divided or full-divided.
I really have no clue if this is right or not because, well, I'm not an expert.
If this is wrong, don't hesitate to report my answer if it's wrong.
What is the step in which you are testing your hypothesis
Answer:
Step 1: State your null and alternate hypothesis. ...
Step 2: Collect data. ...
Step 3: Perform a statistical test. ...
Step 4: Decide whether the null hypothesis is supported or refuted. ...
Step 5: Present your findings.
The vector from the origin to point A is given as (6, −2, −4), and the unit vector directed from the origin toward point B is (2, −2, 1)/3. If points A and B are ten units apart, find the coordinates of point B.
Following the given vectors, the coordinates of point B are given as (7.38, -7.38, 3.92). This was arrived at by utilizing the constraint of the distance between points A and B.
What is a Constraint?In mathematics, a constraint refers to a condition or requirement that the problem indicated must satisfy. That is, it is a permanent factor in the equation of that problem.
What is the solution to the problem above?Taking the vector quantities:
(6, -2, -4)
We can state that the Vector taken from the origin of Point B will be expressed as a multiple of the unit vector - U⁸= (2/3, -2/3, 1/3).
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(20 points) A 1 mm diameter tube is connected to the bottom of a container filled with water to a height of 2 cm from the bottom. Air flows from the tube into the liquid and creates spherical bubbles with diameter about the diameter of the tube (1 mm). Everything is at 298 K. The tube is short but is connected to a much longer 2 m long hose that is 6 mm in diameter. The hose is connected to the gas supply. If there is no gas flow the water will leak into the tube and into the supply hose. When gas flows the water is blocked from entering the tube and bubbling starts. State all assumptions in answering the following questions. (a) What should be the minimum air flow rate and the gas supply pressure to keep the water from leaking back into the tube? (b) Is the flow in the hose laminar or turbulent? Is the flow in the tube laminar or turbulent?
Solution :
Given :
h = 2 cm
Diameter of the tube , d = 1 mm
Diameter of the hose, D = 6 mm
Between 1 and 2, by applying Bernoulli's principle, we get
As point 1 is just below the free surface of liquid, so
[tex]$P_1=P_{atm} \text{ and} \ V_1=0$[/tex]
[tex]$\frac{P_{atm}}{\rho g}+\frac{v_1^2}{2g} +h = \frac{P_2}{\rho g}$[/tex]
[tex]$\frac{101.325}{1000 \times 9.81}+0.02 =\frac{P_2}{\rho g}$[/tex]
[tex]$P_2 = 111.35 \ kPa$[/tex]
Therefore, 111.325 kPa is the gas supply pressure required to keep the water from leaking back into the tube.
Velocity at point 2,
[tex]$V_2=\sqrt{\left(\frac{111.135}{\rho g}+0.02}\right)\times 2g$[/tex]
= 1.617 m/s
Flow of water, [tex]$Q_2 = A_{tube} \times V_2$[/tex]
[tex]$=\frac{\pi}{4} \times (10^{-3})^2 \times 1.617 $[/tex]
[tex]$1.2695 \times 10^{-6} \ m^3/s$[/tex]
Minimum air flow rate,
[tex]$Q_2 = Q_3 = A_{hose} \times V_3$[/tex]
[tex]$V_3 = \frac{Q_2}{\frac{\pi}{4}D^2}$[/tex]
[tex]$V_3 = \frac{1.2695 \times10^{-6}}{\pi\times 0.25 \times 36 \times 10^{-6}}$[/tex]
= 0.0449 m/s
b). Reynolds number in hose,
[tex]$Re = \frac{\rho V_3 D}{\mu} = \frac{V_3 D}{\nu}$[/tex]
υ for water at 25 degree Celsius is [tex]$8.9 \times 10^{-7} \ m^2/s$[/tex]
υ for air at 25 degree Celsius is [tex]$1.562 \times 10^{-5} \ m^2/s$[/tex]
[tex]$Re_{hose}=\frac{0.0449 \times 6 \times 10^{-3}}{1.562 \times 10^{-5}}$[/tex]
= 17.25
Therefore the flow is laminar.
Reynolds number in the pipe
[tex]$Re = \frac{V_2 d}{\nu} = \frac{1.617 \times 10^{-3}}{8.9 \times 10^{-7}}$[/tex]
= 1816.85, which is less than 2000.
So the flow is laminar inside the tube.