Answer:
2.7
Step-by-step explanation:
I hope it helsp if its right pls amrk me as brainliest
A different camera is selling for $7.50 off the regular price. It was marked down 15%. A student used the equation:
15(7.5) = Original price
and found the regular price of the camera to be $112.50.
Explain the error(s) in the student’s work.
Answer:
The original price is $50. The student's mistake in the equation is that he should have done 7.5/0.15
The student should not have multiplied, instead divided. He also didn't put 15 in a decimal form, which would have messed the whole equation up.
Answer:
The student should have divided the discounted amount by the percent. The percent should have been written as a decimal.
Step-by-step explanation:
that is what it says in the simple reponse
A random sample of 10 size AA batteries for toys yield a mean of 3.27 hours with standard deviation, 0.68 hours.
(a) Find the critical value, t*, for a 99% CI. t* =
(b) Find the margin of error for a 99% CI.
Answer:
can u also help me if i help u?
Step-by-step explanation:
whats 1 and 5\5 as an improper fraction
Answer:
2 over 1
Step-by-step explanation:
step 1
multiply the denominator by the whole number
5×1=5
step 2
add the answer from step 1 to the numerator
5+5=10
step 3
write answer from step 2 over the denominator
10/5
10÷5=2 so,the answer is 2 over 1
5÷5=1
Which one is greater 2000 kg or 2 g
The answer is 2000kg
luke rolls a 10-sided solid with equal-sized faces labeled 1 to 10. what is the probability of rolling a 4?
help giving out 10 points to those who help and the right answer!
1 out of 10, or [tex]\frac{1}{10}[/tex]. It is unlikely to occur.
Brainliest if correct
Answer:
[tex]\frac{13}{15}[/tex]
Step-by-step explanation:
[tex]\frac{2}{3}+\frac{1}{5}=\frac{10}{15}+\frac{3}{15}=\frac{13}{15}[/tex]
Angles A and B are supplementary. Angle A has a measure of 80°. What is the measure of angle B?
The measure of angle B is
°.
Answer:
100
Step-by-step explanation:
7th grade help me plzzz
the of difference numbers is 1 and their product is 132
Answer:
11 and 12 or -11 and -12
Step-by-step explanation:
It is generally believed that nearsightedness affects about 15% of all children. A local elementary school registered 120 incoming kindergarteners.
Note that this scenario is talking about a sampling distribution since this school is a sample of size 120. Therefore, you will need to calculate the standard deviation using a formula before using the normalcdf and invNorm commands.
a) What is the mean of the sampling distribution of all samples like this:
b) What is the standard deviation of the sampling distribution of all samples like this:
Give the formula with values that you entered in your calculator as a way of showing your work:
Give your final answer rounded to 4 decimal places:
c) What is the probability that less than 10% of the incoming kindergarteners are nearsighted?
Give the command and values you used as a way of showing your work:
Give your final answer rounded to 4 decimal places:
d) If this school measures at the 80th percentile for all incoming kindergarten classes of size 120, what proportion of incoming kindergarteners are nearsighted?
Give the command and values you used as a way of showing your work:
Give your final answer rounded to 2 decimal places:
Using the normal distribution and the central limit theorem, it is found that:
a) The mean is of 0.15.
b) The standard deviation is of 0.0326.
c) There is a 0.063 = 6.3% probability that less than 10% of the incoming kindergarteners are nearsighted.
d) 0.1774 of incoming kindergarteners are nearsighted.
Normal Probability DistributionIn a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].In this problem:
It is generally believed that nearsightedness affects about 15% of all children, hence p = 0.15.A local elementary school registered 120 incoming kindergarteners, hence n = 120.Item a:
[tex]\mu = p = 0.15[/tex]
The mean is of 0.15.
Item b:
[tex]s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.15(0.85)}{120}} = 0.0326[/tex]
The standard deviation is of 0.0326.
Item c:
The probability is the p-value of Z when X = 0.1, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.1 - 0.15}{0.0326}[/tex]
[tex]Z = -1.53[/tex]
[tex]Z = -1.53[/tex] has a p-value of 0.063.
There is a 0.063 = 6.3% probability that less than 10% of the incoming kindergarteners are nearsighted.
Item d:
The proportion is X when Z has a p-value of 0.8, so X when Z = 0.84.
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]0.84 = \frac{X - 0.15}{0.0326}[/tex]
[tex]X - 0.15 = 0.84(0.0326)[/tex]
[tex]X = 0.1774[/tex]
0.1774 of incoming kindergarteners are nearsighted.
To learn more about the normal distribution and the central limit theorem, you can check https://brainly.com/question/24663213
Eva is 5 years younger than 3 times Bill's age. If Eva is 2 years old, how old is Bill?
Answer:
17 years old.
Step-by-step explanation:
5 years than 3 times can be represented as 5*3.
5*3=15.
If Eva is 2, and Bill is 15 years older, 2+15=17.
Therefore, Bill is 17 years of age.
The area of the triangle below is 4.06 square meters. What is the length of the base?
2.8 m
ET
Answer:
2.9m
Step-by-step explanation:
Hope this helps! Have a great day!
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PLEASE HELP 100 POINTS!!
Mr. Williams needs his computer hooked up to every station in the school. Not every station is connected to every other station. The cost of connecting various stations is represented in the graph below. What is the cost of the minimum spanning tree using Kurskal's Algorithm?
A) 58
B) 60
C) 62
D) 64
We need the diagonal of rectangle
AE=perpendicular=10=BBase=EH=8+9+7=24=BHypotenuse be H
Apply Pythagorean theorem
[tex]\\ \rm\Rrightarrow H^2=P^2+B^2[/tex]
[tex]\\ \rm\Rrightarrow H^2=10^2+24^2[/tex]
[tex]\\ \rm\Rrightarrow H^2=26^2[/tex]
[tex]\\ \rm\Rrightarrow H=26[/tex]
Kosi traced a rectangle on a coordinate grid. The rectangle had the following vertices: (−6, 5), (2, 5), (2, –1), and (–6, –1). Which of the following numbers are dimensions of the rectangle? Select each correct answer. A. 4 units B. 5 units C. 6 units D. 7 units E. 8 units F. 9 units. help, please!.
Answer:
C) 6 units
E) 8 units
Step-by-step explanation:
Kosi traced a rectangle on a coordinate grid. The rectangle had the following vertices: (−6, 5), (2, 5), (2, –1), and (–6, –1). Which of the following numbers are dimensions of the rectangle? Select each correct answer. A. 4 units B. 5 units C. 6 units D. 7 units E. 8 units F. 9 units. help, please!.
When given vertices for a geometric shapes we find the lengths of the side by using the formula:
When(x1, y1) and (x2, y2)
= √(x2 - x1)² + (y2 - y1)²
A= (−6, 5),B = (2, 5), C = (2, –1), and D = (–6, –1).
For AB
A= (−6, 5),B = (2, 5),
= √(2 -(-6)² + (5 - 5)²
= √8² + 0
= √64
= 8 units
For BC
B = (2, 5), C = (2, –1),.
√(2 - 2)² +(-1 - 5)²
= √0 + -6²
= √36
= 6 units
For CD
C = (2, –1), and D = (–6, –1).
= √(-6 -2)² + (-1 -(-1))²
= √-8² + 0²
= √64
= 8 units
For AD
A= (−6, 5), D = (–6, –1).
= √(-6 -(-6))² + (-1 - 5)²
= √0² + -6²
= √36
= 6 units
Therefore, the following numbers that are dimensions of the rectangle is
C) 6 units
E) 8 units
The side length of an equilateral triangle is 5 centimeters. Find the length of an altitude. Round your answer to the nearest tenth.
The length of the altitude is about
centimeters.
If the side length of an equilateral triangle is 5 centimeters, the length of altitude is about 4.33 centimeters.
What is an equilateral triangle?An equilateral triangle can be defined as a type of triangle or regular polygon that has equal side lengths and all of its interior angles are equal.
How to calculate the length of altitude.Mathematically, the length of altitude of an equilateral triangle is calculated by using this formula:
[tex]L=\frac{\sqrt{3} }{2} a[/tex]
Where:
a is the side lengths.L is the length of altitude.Given the following data:
Side length = 5 centimeters.Substituting the given parameters into the formula, we have;
[tex]L=\frac{\sqrt{3} }{2} \times 5\\\\L=\frac{5\sqrt{3} }{2}[/tex]
Length = 4.33 centimeters.
Read more on equilateral triangle here: brainly.com/question/11844452
A rectangular portrait is 3 feet wide and 3 feet high. It costs $3.83 per foot to put a gold
frame around the portrait. How much will the frame cost?
Write the equation in point slope form of the line that passes through the given point with the given slope (8.7,2.1);5.9
A cylidrical container of height 28cm and diameter of 18cm is with water. The water is then poured into another container with a rectangular base of length 27cm and width 11cm . Calculate the depth of the in the container.
Answer:
23.9894949495cm is the depth of the container.
Step-by-step explanation:
Cylindrical container:
height: 28
radius: 9 (or 18/2)
pi * 9² = 254.4690049408
254.4690049408 * 28 = 7,125.1321383424 cm²
cylidrical container area: 7,125.1321383424cm²
Container:
length: 27cm
width: 11cm
27 * 11 = 297
7,125.1321383424 / 297 = 23.9894949495cm
I assume that the container with rectangular base is precisely full when tou pour the water into it.
And that your question was how deep the container was.
Helpppppppppppppppppl
Answer:
C
Step-by-step explanation:
Rotates then reflects over the y axis.
Answer:
C) rotation, then reflection
Step-by-step explanation:
1. rotates to spot 2. then reflects to spot 3.
1. A parallelogram can be inscribed inside of a circle.
a) Always
b) Sometimes
c) Never
2. Circles can be inscribed inside of quadrilaterals.
a) Always
b) Sometimes
c) Never
Solve for x:
(4*11-x+4=33)
Step-by-step explanation:
[tex]4\cdot \:11-x+4=33[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:4\cdot \:11=44[/tex]
[tex]44-x+4=33[/tex]
[tex]\mathrm{Group\:like\:terms}[/tex]
[tex]-x+44+4=33[/tex]
[tex]\mathrm{Add\:the\:numbers:}\:44+4=48[/tex]
[tex]-x+48=33[/tex]
[tex]\mathrm{Subtract\:}48\mathrm{\:from\:both\:sides}[/tex]
[tex]-x+48-48=33-48[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]-x=-15[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}-1[/tex]
[tex]\frac{-x}{-1}=\frac{-15}{-1}[/tex]
[tex]Simplify[/tex]
[tex]x=15[/tex]
Answer:
Okay so yes the answer is 15
Step-by-step explanation:
It begins with 4X11 which is 44
So the equation becomes 44-x+4=33
Then I add 44 plus 4 which is me adding all the available terms which is 48
Then I subtracted 33 from 48 to find the value of x
And 48-33=15
So there you pretty much have it.
To be sure you can plug the answer in.
4x11=44
44-(x) which is 15 so 44-15=29
29+4=33
There ya have it!
here a subtraction problem that has been solved incorrectly 41-27-28 choose the addition sentence that check this subtraction problem
Answer:
-14 + 28 + 27
Step-by-step explanation:
well 42-27-28 is -14 so add -14 to 28 27 and you might get 42
Please help!!!!!!!!!!!
there is more than one question! please help ! i have been struggling all day and today i’m on a time limit !
Answer:
3(5h - 2g)
= 3×5h - 3×2g
= 15h - 6g
5(12g - 4f)
= 5×12g - 5×4f
= 60g - 20f
2(h - 3g)
= 2×h - 2×3g
= 2h - 6g
4(3x - g) + 4x
= 4×3x - 4×g + 4x
= 12x - 4g + 4x
= 16x - 4g
9(4g + 1) - 5g
= 9×4g + 9×1 - 5g
= 36g + 9 - 5g
= 31g + 9
PLEASE HELP
Given a graph for the transformation of f(x) in the format g(x) = f(x) + k, determine the k value.
two parabolas open up with f of x passing through negative 3 comma negative 3 and g of x passing through negative 3 comma 1
A. k = −3
B. k = 1
C. k = 4
D. k = 5
Look up to their vertexes
f(x) has vertex at (-3,-3)g(x) has vertex at (-3,1)So
[tex]\\ \rm\rightarrowtail g(x)=f(x)+k[/tex]
[tex]\\ \rm\rightarrowtail g(-3)=f(-3)+k[/tex]
[tex]\\ \rm\rightarrowtail 1=-3+k[/tex]
[tex]\\ \rm\rightarrowtail k=1+3[/tex]
[tex]\\ \rm\rightarrowtail k=4[/tex]
The required value of K for the transformation of f(x) is 4. Option C is correct.
Given that,
Graph for the transformation of f(x) in the format g(x) = f(x) + k,
To determine the k value.
Two parabolas open up with f(x) passing through (- 3, - 3)and g(x) passing through (-3, 1).
A parabola is a cross section cut out of the cone and represented by an equation
Here,
Since equation of transformation is g(x) = f(x) + k
Now put the values of the vertex in the transformation equation,
f(x) passing through (- 3, - 3)and g(x) passing through (-3, 1).
f(-3) = -3
g(-3) = 1
g(-3) = f(-3) + k
1 = -3 + k
k = 1 + 3
k = 4
Thus, the required value of K for the transformation of f(x) is 4. Option C is correct.
Learn more about parabola here:
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Bro I have the hardest test Can y’all help me it’s 1+1
Answer:
I think it's 12 bro, I'm not sure
GIVING BRAINLIEST TO WHOEVER GETS THIS CORRECT!
What is the unit rate for meters per second if a car travels 374 meters in 17 seconds?
Answer:22
374meters. 17
(/). divided by (/)
17seconds 17
Equals 22 meters per second
Step-by-step explanation:
I need helppp please
Step-by-step explanation:
3(2/3y) =3(-6)
2y=-18
2/2y= -18/2
y=-9
What's the solution to 2x – 2 > 2x + 4?
Consider the inequality first ;
[tex]{:\implies \quad \sf 2x-2\> 2x+4}[/tex]
Subtracting 2x from both sides ;
[tex]{:\implies \quad \sf \cancel{2x}-2-\cancel{2x}\> \cancel{2x}+4-\cancel{2x}}[/tex]
[tex]{:\implies \quad \sf -2\> 4}[/tex]
But , as the given situation isn't possible in mathematics , so the inequality have no solutions . Or [tex]{\bf{x\in \phi}}[/tex] , where [tex]\bf \phi[/tex] is the empty set.
in a for loop, is it possible to use indexing?
Answer:
Yes
Step-by-step explanation:
A for loop basically relies on repeating the same code for a pre-set number of times. During which you can make any code repeat inside of it, including indexing through a type of list. Many times a for-loop will use the indexes in a list to calculate the number of times that the loop has to repeat. This is usually done in order to search or apply changes in an array of other types of data structures that have countless values stored in it.