Answers
Formula given: [tex]y=x^{2} -x-6[/tex]
x -3 -2 -1 0 1 2 3
y 6 0 -4 -6 -4 -4 0
when x = -2
[tex]=(-2)^{2} -(-2)-6[/tex]
[tex]=0[/tex]
when x = -1
[tex]=(-1)^{2} -(-1)-6[/tex]
[tex]=-4[/tex]
when x = 1
[tex]=(1)^{2} -(1)-6[/tex]
[tex]=-6[/tex]
when x = 2
[tex]=(2)^{2} -(2)-6[/tex]
[tex]=-4[/tex]
when x = 3
[tex]=(3)^{2} -(3)-6[/tex]
[tex]=0[/tex]
Answer:
-3 -2 -1 0 1 2 3
6 0 -4 -6 -6 -4 0
Step-by-step explanation:
One is given the following function;
[tex]y=x^2-x-6[/tex]
The problem asks one to evaluate the function for certain values, substitute these values in place of the variable (x) and simplify to evaluate the function.
[tex]-2\\\\(-2)^2-(-2)-6\\=4-(-2)-6\\=4+2-6\\=6-6\\=0[/tex]
[tex]-1\\\\(-1)^2-(-1)-6\\=1-(-1)-6\\=1+1-6\\=2-6\\=-4[/tex]
[tex]1\\\\(1)^2-(1)-6\\=1-(1)-6\\=1-1-6\\=0-6\\=-6[/tex]
[tex]2\\\\(2)^2-(2)-6\\=4-(2)-6\\=4-2-6\\=2-6\\=-4[/tex]
[tex]3\\\\(3)^2-(3)-6\\=9-(3)-6\\=9-3-6\\=6-6\\=0[/tex]
Related Questions
6x - 5y= 70
7x + 2y=66
I need a answer in words step by step please help!!
Answers
Answer:
x = 10
y = -2
Step-by-step explanation:
Elimination method:
6x - 5y = 70 -----------------(I)
7x + 2y = 66 -----------------(II)
Multiply equation (I) by 2 and equation (II) by 5 and add. So, y will be eliminated and you can now find the value of x
(I)*2 12x - 10y = 140
(II)*5 35x + 10y = 330 {Now add}
47x = 470
x = 470/47
x = 10
Plugin x = 10 in equation (II)
7*10 + 2y = 66
70 + 2y = 66
Subtract 70 from both sides
2y = 66 - 70
2y = -4
Divide both sides by 2
y = -4/2
y = - 2
The volume (v) of water stored in an open tank varies due to evaporation as v=x^4-50x^2+700 where v is expressed in gallons and x is number of months elapsed. If January correspond to x=0 what will the volume of water (in gallons) in the tank be in june
A.700
B.1200
C.75
D.100
Answers
Answer:
C) 75
Step-by-step explanation:
If January corresponds to x=0 then June corresponds to x=5.
Knowing this we can replace all values of x with 5.
[tex]v=x^4-50x^2+700[/tex]
[tex]v=5^4-50(5)^2+700[/tex]
[tex]v=625-1250+700[/tex]
[tex]v=75[/tex]
Identify the coefficient(s) of the variable in the expression below.
25 - 6z
A
z
B
1
C
6
D
25 and 6
Answers
Answer:
D
Step-by-step explanation:
25 and 6
Coefficient is the number in front of the unknown variable
Identify the coefficient(s) of the variable in the expression below.
25 - 6z
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {C. \:6}}}}}}[/tex]
Explanation:
Coefficients are numbers that are attached to variables. In the expression "25 - 6z", 6 is the coefficient since it is attached to the variable z.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
Hi guys pls answer this it’s easy tbh
Answers
Answer:
this is the accurate answer of your questions
In parallelogram QRST if m∡TQR=50∘ find m∡STQ.
Answers
Based on your observations, what conclusion can you draw about the lengths of AB DB AE EC
Answers
Answer:
The ratio of AD to DB is equal to the ratio of AE to EC. In other words, the pairs of lengths are proportional.
Step-by-step explanation:
Sample answer from plato
lines a and b are parallel m<2 = ?°
Answers
Answer:
50 degrees
Step-by-step explanation:
50 degrees because angle 2 is its vertical angle
(6x+15)°
63° triangle
Answers
Answer:
x = 2
Step-by-step explanation:
The sum of the 3 angles in the triangle = 180°
Sum the 3 angles and equate to 180
6x + 15 + 90 + 63 = 180
6x + 168 = 180 ( subtract 168 from both sides )
6x = 12 ( divide both sides by 6 )
x = 2
Solve for x. (have to add extra letters so the question works)
PLEASE ADD STEPS AND EXPLAIN IT IN ANY WAY POSSIBLE SO I CAN LEARN
Answers
Answer:
x=11°
Step-by-step explanation:
-Sum of angles of a triangle should alway be 180 degrees
35+110+2+3x=180
-Add all known values
147+3x=180
-Subtract 147 from both sides
3x=33
-Isolate x by divind both sides by 3
x=11°
Find the mode of the data.
Weight (in ounces) of puppies in litter:
17, 15, 19, 18, 17, 16, 22
Mode: [?] oz
Enter
Answers
Mode=17
Step-by-step explanation:
Mode is to find the number which reoccurs/keeps on appearing.
Hope this helps u
Answer 2 questions about equations A and B.
A. 5x−2+x=x-4
B. 5x+x=x−4
1) How can we get Equation BBB from Equation AAA?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Add/subtract a quantity to/from only one side
(Choice B)
B
Add/subtract the same quantity to/from both sides
(Choice C)
C
Rewrite one side (or both) using the distributive property
(Choice D)
D
Rewrite one side (or both) by combining like terms
2) Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Yes
(Choice B)
B
No
Answers
Step-by-step explanation:
Given that,
Two equations,
A. 5x−2+x=x-4
B. 5x+x=x−4
1.
The RHS of both the equations is same. To make them equal we need to remove the difference.
If we add 2 to the left side of equation A, then we get equation B.
The correct option is (A) i.e. Add/subtract a quantity to/from only one side.
2.
As the equations are not same, they will have different solutions. The answer choice is (b) "No".
Hey There Answer Add/subtract a quantity to/from only one side
And No
Step-by-step explanation:
What is the measure of each exterior angle of a regular hexagon?
40°
45°
60°
72°
Answers
The measure of each exterior angle of a regular hexagon ( six sided regular polygon is 60°.
Option C)60° is the correct answer.
What is a polygon?A polygon is simply a two-dimensional a plane shape enclosed by line segments called sides.
The formula for calculating the exterior angles of a polygon is;
E = 360° ÷ number of sides
Given the data in the question;
The polygon in question is a regular hexagonA regular hexagon has six sides, n = 6So we substitute the value for number of sides into the expression above.
E = 360° ÷ number of sides
E = 360° ÷ 6
E = 60°
The measure of each exterior angle of a regular hexagon ( six sided regular polygon is 60°.
Option C)60° is the correct answer.
Learn more about polygons here: brainly.com/question/22408868
#SPJ2
Answer: (C) 60°
Just took it on edge
A 95% confidence interval is (70,110). what is the margin for error? A. 19 B.38 C.20 D.40
Answers
Answer:
C.20
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
The margin of error is the difference between the two bounds, divided by 2.
In this question:
Lower bound: 70
Upper bounf: 110
Margin of error:
[tex]M = \frac{110 - 70}{2} = \frac{40}{2} = 20[/tex]
Thus the correct answer is given by option C.
6. Find the slope and y-intercept of the line.
y = 7/4x-10
Answers
Answer:
Slope= 7/4
y-intercept = (0, -10)
General Formulas and Concepts:
Algebra I
Coordinates (x, y)
Slope-Intercept Form: y = mx + b
m - slope b - y-interceptStep-by-step explanation:
Step 1: Define
Identify
y = 7/4x - 10
↓ Compare to y = mx + b
Slope m = 7/4
y-intercept b = -10
Answer:
slope = 7/4
y-intercept = -10
Step-by-step explanation:
slope intercept form :
y = mx + b
m = slope
b = y-intercept
x^{2} -(3+\sqrt{3} )x +\sqrt{3} -2=0
Answers
Answer:
[tex]{ \tt{ {x}^{2} -( 3 + \sqrt{3} ) x + \sqrt{3} - 2 = 0}} \\ \\ x = 4.8 \: \: and \: \: - 0.05[/tex]
AT&T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $200 per month on cell phone expenses, how many additional lines can he afford? Which inequality represent the given situation. please help for my final
Answers
Given:
Cost of four lines = $125
Cost of each additional line = $15
Jason wants to spend at most $200 per month on cell phone expenses.
To find:
The inequality for the given situation.
Solution:
Let [tex]x[/tex] be the number of additional line.
Cost of one additional line = $15
Cost of [tex]x[/tex] additional line = [tex]\$15x[/tex]
Total cost = Fixed cost + Addition cost
= [tex]125+15x[/tex]
It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.
[tex]125+15x\leq 200[/tex]
Therefore, the correct option is C.
y <= - 1/3 * x + 2; y > 2x - 3 linear inequalities
Answers
Step-by-step explanation:
Given
Inequalities are [tex]y\leq -\dfrac{1}{3}x+2[/tex] and [tex]y>2x-3[/tex]
Take the inequality as two equations to get the intersection point
[tex]y=-\dfrac{1}{3}x+2\ and\ y=2x-3[/tex]
Equate the value of y
[tex]\Rightarrow -\dfrac{1}{3}x+2=2x-3\\\Rightarrow 5=\dfrac{7x}{3}\\\\\Rightarrow x=\dfrac{15}{7}[/tex]
[tex]\therefore y=1.286[/tex]
The common region gives the required regions for inequalities.
Triangle AEB is similar to triangle CBD by
Answers
Answer:
SAS
Step-by-step explanation:
Select the elements in H.
Let H = {cube numbers}
A-8
B-49
C-3
D-125
E-1
F-100
G-25
H-12
Answers
Answer:
H={8,125,1}
Step by step explanation:
8 is the cube of 2125 is the cube of 51 is the cube of 1Find the sum difference 104 - (-92)
Answers
Answer:
12
Step-by-step explanation:
The profit for a car company can be represented by the function P=−0.5 x² +4 x+ 12,
where P is the profit in hundred thousands of dollars and x represents the number of cars sold in thousands. What is the maximum profit the company can make?
Answers
Answer:
3x+12
Step-by-step explanation:
-0.5x*2+4x+12
Multiply 0.5x*2=x
= -x+4x+12
Add similar elements -x+4x+12
= 3x+12
Use the law of cosines to find the length of a
Answers
Answer:
Step-by-step explanation:
You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:
[tex]\frac{sin55}{175}=\frac{sin42}{a}[/tex] and solving for a:
[tex]a=\frac{175sin42}{sin55}[/tex] so
a = 143.0
Find the area of this triangle.
17 cm
10 cm
8 cm
21 cm
A = [ ? ] cm2
Answers
Answer:
84 cm^2
Step-by-step explanation:
8 * 21/2=84
every evening Jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she had 38 coins, all of them being quarters and dimes. When she added them up she had a total of $6.95. Let d=number of dimes and q= number of quarters. How many dimes did Jenna have?
Answers
d = dimes
q = quarters
d+q = 38 coins
q=38-d
0.25q + 0.10d=6.95
0.25(38-d)+0.10d=6.95
9.5-0.25d+0.10d=6.95
-015d=-2.55
d=-2.55/-0.15 = 17
q=38-17 =21
21*0.25 =5.25
17*0.10 = 1.70
5.25+1.70 = 6.95
she had 21 quarters and 17 dimes
how long is each side of a square with a perimeter of 12.32 centimeters
Answers
Step-by-step explanation:
Let each side of square be x
So, x+x+x+x = 12.32
4x = 12.32
x = 12.32/4
x = 3.02 cm
Simplify Negative two and one-third minus negative ten and one-sixth
Answers
Answer:
7 5/6
Step-by-step explanation:
-2 1/3 - (-10 1/6)
-7/3 + 61/6 (subtract neg = add positive)
-14/6 + 61/6 = 47/6 = 7 5/6
Answer:
[tex]-2\frac{1}{3} - (-10\frac{1}{6} )[/tex]
Minus minus is plus so:
[tex]-2\frac{1}{3} + 10\frac{1}{6} [/tex]
Make improper:
[tex]-\frac{7}{3} + \frac{61}{6} [/tex]
Common denominator:
[tex]-\frac{14}{6} + \frac{61}{6} [/tex]
Equals=
[tex]\frac{47}{6} [/tex]
what do i put for y and x , need help asap!!!
Answers
For ex- y = -1 and x = -3
Which choice is equivalent to the product below? √2 x √5 x √8
A. 16√5
B. 4√20
C. 4√5. <-- correct answer
D. 8√10
Answers
[tex]\longrightarrow{\green{ C. \:4 \sqrt{5} }}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] = \sqrt{2} \times \sqrt{5} \times \sqrt{8} [/tex]
[tex] = \sqrt{2 \times 5 \times 8} [/tex]
[tex] = \sqrt{2 \times 5 \times 2 \times 2 \times 2} [/tex]
[tex] = \sqrt{(2 \times 2) \times (2 \times 2) \times 5} [/tex]
[tex] = \sqrt{ {2}^{2} \times {2}^{2} \times 5} [/tex]
[tex] = \sqrt{ {2}^{2} } \times \sqrt{ {2 }^{2} } \times \sqrt{5} [/tex]
[tex] = 2 \times 2 \sqrt{5} [/tex]
[tex] = 4 \sqrt{5} [/tex]
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]
[tex]\sf Q) \sqrt{2} \times \sqrt{5} \times \sqrt{8}[/tex]
[tex]\sf\implies \sqrt{2 \times 5 \times 8}[/tex]
[tex]\sf\implies \sqrt{2 \times 5 \times 2 \times 2 \times 2}[/tex]
[tex]\sf\implies \sqrt{(2 \times 2) \times (2 \times 2) \times 5}[/tex]
[tex]\sf\implies \sqrt{ {2}^{2} \times {2}^{2} \times 5}[/tex]
[tex]\sf\implies \sqrt{ {2}^{2} } \times \sqrt{ {2 }^{2} } \times \sqrt{5}[/tex]
[tex]\sf\implies 2 \times 2 \sqrt{5}[/tex]
[tex]\sf\implies 4 \sqrt{5}[/tex]
Find the different between compound interest payable anually and half anually for a amount Rs14000 at the rate of 12•\•per annum for 2 yrs.
Answers
Answer:
$113.08
Step-by-step explanation:
The formula for calculating future value:
FV = P (1 + r/m)^mn
FV = Future value
P = Present value
R = interest rate
N = number of years
m = number of compounding
14,000(1.12)^2 = 17,561.60
14,000 ( 1 + 0.12/2)^(2x2) = 17674.68
Difference : 17674.68 - 17,561.60 = $113.08
Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0.
Answers
Answer:
a= 16
b= 2
Step-by-step explanation:
edge 2021
Answer:
a=16 and b=2
Step-by-step explanation:
next one is B.