Hi there!
Recall that:
Impulse = Δ in momentum = mΔv
Impulse = Force · time
Begin by calculating the change in momentum, or impulse.
I = mΔv = m(vf - vi)
I = (79)(0 - 32) = -2528 Ns
Now, we can use the equation relating force and time to impulse.
I = Ft
Rearrange for time:
I/F = t
-2528/0.25 = -10112 N
**OR, if magnitude ⇒ |-10112| = 10112 N
a spring with a spring constant of 65 n/m is displaced -94cm. what is the magnitude of the force exerted by the spring
Answer:
Explanation:
F = kx = 65 N/m(0.94 m) = 61.1 = 61 N
1. What is the frequency of light waves with wavelength of 5 x 10-⁷ m?
Answer:
Speed of light =m/s
wavelength = m
frequency = ?
we have
Speed = frequency × wavelength
[tex]3* 10^8[/tex] = frequency × [tex]5 * 10^{-7}[/tex]
Frequency = [tex]\frac{3*10^8}{5*10^{-7}}=6*10^{14}[/tex]hz
Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.
Definition of wavelengthFirst of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Definition of frequencyOn the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Definition of propagation speedFinally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f× λ
All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.
Frequency of light waves with wavelength of 5×10⁻⁷ mIn this case, you know:
v= 3×10⁸ m/sf= ?λ= 5×10⁻⁷ mReplacing in the definition of propagation speed:
3×10⁸ m/s = f× 5×10⁻⁷ m
Solving:
3×10⁸ m/s ÷ 5×10⁻⁷ m= f
f= 6×10¹⁴ Hz
In summary, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.
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Would it be possible to direct the speeds that a coaster will reach before its ever placed on a track?How?
Yes, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.
According the principle of conservation of energy, the total kinetic energy is equal to the total potential energy.
[tex]P.E _i + K.E_i = P.E_f + K.E_f \\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\g(0) + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\\frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\v_i^2 = 2gh_f + v_f^2\\\\v_i^2 - 2gh_f = v_f^2\\\\v_f = \sqrt{v_i^2 - 2gh_f}[/tex]
where;
[tex]v_i[/tex] is the initial velocity of the roller coaster[tex]v_f[/tex] is the final velocity of the roller coaster[tex]h_f[/tex] is maximum height reached by the roller coasterThus, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.
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A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in 5.00 s. (a) what is the mass of the block office? (b) If the worker stops pushing at the end of 5.00 s, how far does the block move in the next 5.00 s?
Answer:
(a) 91 kg (2 s.f.) (b) 22 m
Explanation:
Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.
(a)
[tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2} at^{2} \\ \\ a \ = \ \displaystyle\frac{2(s \ - \ ut)}{t^{2}} \\ \\ a \ = \ \displaystyle\frac{2(11 \ - \ 0)}{5^{2}} \\ \\ a \ = \ \displaystyle\frac{22}{25} \\ \\ a \ = \ 0.88 \ \mathrm{m \ s^{-2}}[/tex]
Subsequently,
[tex]F \ = \ ma \\ \\ m \ = \ \displaystyle\frac{F}{a} \\ \\ m \ = \ \displaystyle\frac{80 \ \mathrm{kg \ m \ s^{-2}}}{0.88 \ \mathrm{m \ s^{-2}}} \\ \\ m \ = \ 91 \mathrm{kg} \ \ \ \ \ \ (2 \ \mathrm{s.f.})[/tex]
*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.
(b) To find the final velocity of the ice block at the end of the first 5 seconds,
[tex]v \ = \ u \ + \ at \\ \\ v \ = \ 0 \ + \ (0.88 \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \\ \\ v \ = \ 4.4 \ \mathrm{m \ s^{-1}}[/tex]
According to Newton's First Law which states objects will remain at rest
or in uniform motion (moving at constant velocity) unless acted upon by
an external force. Hence, the block of ice by the end of the first 5
seconds, experiences no acceleration (a = 0) but travels with a constant
velocity of 4.4 [tex]m \ s^{-1}[/tex].
[tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2}at^{2} \\ \\ s \ = \ (4.4 \ \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \ + \ \displaystyle\frac{1}{2}(0)(5^{2}) \\ \\ s \ = \ 22 \ \mathrm{m}[/tex]
Therefore, the ice block traveled 22 m in the next 5 seconds after the
worker stops pushing it.
A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position �� as a function of time . What are the oscillation’s: a. period; b. frequency; c. angular frequency; d. amplitude; and e. What is the force constant of the spring?
(a) The period of the oscillation is 0.8 s.
(b) The frequency of the oscillation is 1.25 Hz.
(c) The angular frequency of the oscillation is 7.885 rad/s.
(d) The amplitude of the oscillation is 3 cm.
(e) The force constant of the spring is 148.1 N/m.
The given parameters:
Mass of the ball, m = 2.4 kgFrom the given graph, we can determine the missing parameters.
The amplitude of the wave is the maximum displacement, A = 3 cm
The period of the oscillation is the time taken to make one complete cycle.
T = 0.8 s
The frequency of the oscillation is calculated as follows;
[tex]f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz[/tex]
The angular frequency of the oscillation is calculated as follows;
[tex]\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s[/tex]
The force constant of the spring is calculated as follows;
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m[/tex]
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What is the name of Fe(NO3)3
Answer:
Iron(III) nitrate
Explanation:
Look at the circuit given below. It consists of a cell, a bulb with two terminals X, Y and wires. P, Q, R and S are positions marked. What is the direction of the flow of current? a) PQXYRS b) SRYXQP c) SPQXYR d) PSRYXQ
The conventions for the current allow to find the result for which is the direction of the current the is circuit is:
It leaves the positive pole, goes to the blue cable, to the light bulb, from there to the red cable and reaches the negative pole.
Current is the movement of electrons in a circuit per unit time.
In an electrical circuit the electrons that have a negative charge leave the negative electrode towards the positive electrode, by convention the current goes in the opposite direction from the positive electrode towards the negative electrode.
When analyzing the given circuit, the current leaves the positive pole at the top of the battery and moves through the blue wire, reaches the light bulb and moves the red wire and reaches the negative pole of the battery.
In conclusion using the conventions for the current we can find the result for which is the direction of the current the is circuit is:
It leaves the positive pole, goes to the blue cable, to the light bulb, from there to the red cable and reaches the negative pole.
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The graph below shows the variation with distance r from the nucleus of the square of the wave function, Ψ^2, of a hydrogen atom according to Schrödinger theory.
A. is most likely to be near a.
B. is always a.
C. is always less than a.
D. is always greater than a.
The region a represents the distance of the electron from the nucleus.
According to the wave mechanical model of the atom, the probability of finding an electron within a given volume element (representing the atom) is the square of the wave function psi.
Since a is the region in space where there is the greatest probability of finding the electron in the atom, it follows that distance of the electron form the atom is always a.
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Two rods of mass m, length L are stuck together to form an X shape and spun around the center. What is the rotational inertia
8.
When minerals seep into and replace the organic cells of a dead organism, creating a
mineral replica of the organism is called ...
Petrification
b. Tar Seeps
C. Amber
d. Mummification
Answer:
a. petrification
Explanation:
tar seeps = natural trade that, because of its close proximity to the ground surface, seeps from the cracks in the Earth or between rocks forming pits or pools (tar pits)
amber = fossilized resin produced by extinct coniferous trees, typically yellow in color
mummification = a process in which the skin and flesh of a corpse can be preserved by embalming and drying
Who did the ram caught in the thicket (Genesis 22:13) represent?
Answer:
I think the answer is goat
2. Define Lightning conductor. How does it work?
In Building, there are a host of protective devices that are installed to protect lives and properties, one of them is the Lightning Conductor that a metal rod mounted on a structure and intended to protect the structure from a lightning strike. It works on the principle of induction
Principle of Operation of Lightning ConductorThe lightning conductor works on the principle of induction:
When a charged cloud passes by the building hosting the Lightning conductor, it gets a charge opposite to that of the cloud through the process of induction. They are Typically made from copper material.Most Lightening conductors are made from copper materials.
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Three people are trying to move a box. Which set of forces will result in a net
force on the box of 20 N to the left?
Answer: push force gravity tension and reverse force
Explanation: sense they are pushing the box there is a push force gravity because this is likely on earth tension because it is the reverse of gravity and the reverse force because you have to have the reverse of push
HELP ME the mean free path λ and the mean collision time τ of the molecules of a diatomic gas of molecular mass 6.00 × 10⁻²⁵ kg and radius r = 1.0 x 10⁻¹⁰ m are measured. From these microscopic data can we obtain macroscopic properties such as temperature T and pressure P? If so, consider λ = 4.32 x 10⁻⁸ m and τ = 3.00 x 10⁻¹⁰ s and calculate T and P.
The temperature of the diatomic gas is 300.5 K and the pressure is 5.33 atm.
The given parameters;
Mass of the gas molecules, m = 6 x 10⁻²⁵ kgRadius of the gas, r = 1 x 10⁻¹⁰ mMean free path, [tex]\lambda_{rms}[/tex] = 4.32 x 10⁻⁸ mMean collision time, [tex]\tau = 3 \times 10^{-10} \ s[/tex]The mean velocity of the gas molecules is calculated as follows;
[tex]\tau = \frac{\lambda _{rms}}{V_{rms}} \\\\V_{rms} = \frac{\lambda _{rms}}{\tau} \\\\V_{rms} = \frac{4.32 \times 10^{-8} }{3 \times 10^{-10}} \\\\V_{rms} = 144 \ m/s[/tex]
The temperature of the gas molecules is calculated as follows;
[tex]V_{rms} = \sqrt{\frac{3kT}{M} } \\\\V_{rms}^2 = \frac{3kT}{M} \\\\T = \frac{V_{rms} ^2 M}{3k}[/tex]
where;
k is Boltzmann constant[tex]T = \frac{V_{rms} ^2 M}{3k} \\\\T = \frac{(144)^2 \times (6.0 \times 10^{-25})}{3 \times 1.38 \times 10^{-23}} \\\\T = 300.5 \ K[/tex]
The number of gas molecules per unit volume is calculated as follows;
[tex]\lambda = \frac{1}{4\pi \sqrt{2} \ r^2 n} \\\\n = \frac{1}{\lambda 4\pi \sqrt{2} \ r^2} \\\\n = \frac{1}{(4.32 \times 10^{-8}) \times 4 \pi \times \sqrt{2} \ \times (1\times 10^{-10})^2} \\\\n = 1.303 \times 10^{26} \ molcules/m^3[/tex]
The pressure of the gas molecule is calculated as follows;
[tex]n = \frac{P}{kT} \\\\P = nkT\\\\P = (1.303 \times 10^{26} ) \times (1.38 \times 10^{-23}) \times (300.5)\\\\P = 540,341.07 \ Pa\\\\P = 5.33 \ atm[/tex]
Thus, the temperature of the diatomic gas is 300.5 K and the pressure is 5.33 atm.
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The part of the moon that is visible will appear to grow and shrink during the lunar cycle. This occurs in the direction of _____ to _____.
Answer:
left to right
Explanation:
give me brain pls
Answer:
of the moon to .......
A moving car initially has kinetic energy K. The car then moves in the opposite direction with four times its initial speed. What is the kinetic energy now
If initial speed was v, Kinetic energy was K = 1/2mv^2
When speed will be 4v, KE will be:
= 1/2 m (4v)^2
=1/2m 16 v^2
=16K
Now kinetic energy will become 16 times of initial Kinetic Energy
identify the origins of breakdown when using a spectrum analyzer
Four regions of the electromagnetic spectrum that astronomers use when observing objects in the space are the following enumerated answers.
1. First is Ultraviolet
2. Next is Infrared
3. Then the radio
4. Lastly the Visible lights.
These are the answers to the problem.
Select the best reason for studying the past and its effect on us today based on "The Terror of the Middle Ages." A. to learn what people did on a daily basis B. to enjoy stories about where people used to live O C. to study the causes of diseases and learn to prevent them D. to learn about earlier cultures and lifestyles
it is D for sure im good with history
Answer: D
Explanation: Its just s that guy ca get brainlist :D
Ben (55kg) is standing on very slippery ice when Junior (25kg) bumps into him. Junior was moving at a speed of 8m/s before the collision. Find the speed of ben and junior as they move across the ice after the collision. Give the answer in m/s. Describe the work you did to get the answer
Answer:
2.5m/s
Explanation:
m1=55kg
m2=25kg
Ben's velocity before collision=0m/s
Junior's velocity before collision= 8m/s
P1=m1v1+m2v2
P1=55kg(0m/s)+25kg(8m/s)
P1=200kg(m/s)
Know that the momentum before the collision = momentum after the collision
P2=(55kg+25kg)V
200kg(m/s)=(75kg)V
200kg(m/s)/75kg=V
V=2.5m/s.
It makes sense bc after they collide, their speed would slow down, and it wouldn't make sense if the momentum would be greater or less after they collide.
How can whales descend quickly and face no problems
Answer:
Whales face an increasing number of threats including: For hundreds of years people hunted whales for their oil to fuel lamps and candles, to lubricate machinery and to make margarine, lipsticks and other products. They also used baleen whales to make tennis racquets and corsets!
Explanation:
PLEASE HELPASP WILLGIVE 50 POINT AND BRAINLIEST!!!!!!!!!!!!!!!
A satellite moves in a circular orbit around the Earth at a speed of 5.2 km/s. Determine the satellite’s altitude above the surface of the Earth. Assume the Earth is a homogeneous sphere of radius 6370 km and mass 5.98 × 1024 kg.
The value of the universal gravitational constant is 6.67259 × 10−11 N · m2/kg2
Answer:
The altitude of the satellite above the surface of the Earth is 1,528.48 km.
F=rmv2=R2GmMrv2=R2GMr=GMv2R2r=(6.67259×10−11)×(5.98×1024)(6900)2×(6,370,000)2r=4,841,516.6 mr=4,841.52 km
A change in momentum is also called:
a. Impact
b. Imput
c. Impulse
d. Impole
Answer:
c. Impulse
Explanation:
The spring constant of Spring A is twice as great as the spring constant of Spring B. Both springs are stretched the same amount. How does the
force the Spring A applies compare to the force Spring B applies?
Answer:
FA = 2FB
Force on spring A is twice the Force on spring B
Explanation:
F = kx
FB = (kB)x
FA = (kA)x
FA= (2kB)x
FA = 2(kB)x
FA = 2FB
The force [tex]F_A[/tex] needed to stretch spring A is going to be twice as much as the force [tex]F_B[/tex] needed to stretch spring B.
Explanation:
We know that the spring constants are related as
[tex]k_A = 2k_B[/tex]
The force [tex]F_A[/tex] needed to stretch spring A is given by
[tex]F_A = -k_Ax[/tex]
Also, the force [tex]F_B[/tex] needed to stretch spring is
[tex]F_B = -k_Bx[/tex]
Taking the ratio of the forces, we get
[tex]\dfrac{F_A}{F_B} = \dfrac{-k_Ax}{-k_Bx} = \dfrac{k_A}{k_B}[/tex]
Since [tex]k_A = 2k_B,[/tex] the equation above becomes
[tex]\dfrac{F_A}{F_B} = \dfrac{2k_B}{k_B} = 2[/tex]
or
[tex]F_A = 2F_B[/tex]
This shows that since the spring constant of spring A is twice as large as that of spring B, the force needed is going to be twice as large.
Một chất điểm khối lượng m=200g chuyển
động chậm dần với vận tốc biến đổi theo qui luật
v=30 – 0,4t2 (SI). Lực hãm tác dụng vào chất điểm
lúc t = 5 giây là
A. 8 N B. 0,8 N C. 4 N D. 0,4 N
A 2.8 kg rectangular air mattress is 2.00 m long, 0.500 m wide, and
0.100 m thick. What mass can it support in water before sinking?
160 m long When a truck ulls
Mass the air mattress support before sinking will be M = 97.2 kg
What will be the mass mattress will support?Given that
mass of mattress m=2.8 kg
Length = 2.00 m
width =0.5 m
The mattress can support a total weight that is equal to the weight of water that the air mattress displaces.
The volume of the air mattress will be equal to
[tex]V= (2\times 0.5\times 0.1)[/tex]
[tex]V= 0.1 m^{3}[/tex]
This volume is equal to the maximum amount of water that the mattress can displace in the water before it begins sinking.
We know the density of water is 1000 kg / m²
We can calculate the weight of the maximum amount of water that mattress will displace
[tex]V\times density of water\times g=0.1\times 1000\times 9.81=981N[/tex]
Let M represent the mass that the mattress is supporting.
The total weight of the mattress and the supported mass is:
[tex](2.8+M)\times9.81[/tex]
Setting this weight equal to the weight of the water displaced gives:
[tex](2.8+M)\times9.81=981[/tex]
[tex]2.8+M=100[/tex]
m = 97.2 kg
Hence Mass the air mattress support before sinking will be M = 97.2 kg
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Which is the answer
Answer:
no idea thanks you veryuch
Predict changes in state according to change in particle motion. Know the vocabulary used to describe changes of state.
The change in the state of matter causes change in the motion of the particles of the matter. The gaseous state of matter has the greatest speed while the solid state has the least speed.
The change in state of every matter is accompanied by lost or gained of energy.
Example is water.
The solid state of water is ice. The motion of particles of the water is relatively zero because the molecules are held at a fixed position.
The liquid state of water occurs when the temperature of the ice is increased above zero degree Celsius. The speed of the particles of water in liquid state is greater than solid state.
The gaseous state of water occurs when the temperature of the liquid water is increased beyond 100 degree Celsius. The speed of water in gaseous state is greater than liquid state.
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A textbook weighs 34 N on the surface of the Earth. What is the book’s mass on Earth’s surface?
Answer:
About 3.47kg
Explanation:
Recall that weight is equal to mass times acceleration.
In this case, our acceleration is due to gravity which on earth is about 9.8m/s/s
So we have 34N=9.8 *mass, divide both sides by 9.8 we get mass is equal to about 3.47kg.
In the following free body diagram, what is the net force on the object?
A.10n
B.5 N to the right
C.20 N to the right
D.7 N to the right
Answer:
B
Explanation:
Simply take all forces pointing to the right of the box as positive and all of the forces pointing to the left of the box as negative and add all values.
ΣF = 7 + 18 + (-20) = 5N to the right
Which ball moved at the same speed as Ball 3?
Answer:
you forgot to attach the image