Each box weighs 10lb. The coefficient of static friction between box A and box B is 0.24, and the coefficient of static friction between box B and the inclined surface is 0.3. What is the largest angle for which box B will not slip​

Answer:

5m/s ez

Explanation:

plz make me brainliest

Answer:

Speed: 109.4–120.7 km/h (68.0–75.0 mph)

Strength: Couldn't find out.

Explanation:

Answer:

The answer is #3: The kinetic energy of water is converted by a generator into electric energy.

Explanation:

Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.

The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.

We have to find the acceleration using;

v = u - at

v = final velocity = 0 m/s

u = initial velocity = 35.6m/s

a = acceleration = ?

t = time = 0.35 s

u = at

a = u/t = 35.6m/s / 0.35 s

a = 101.7 ms-2

The force on the driver =  75kg ×  101.7 ms-2 = 7629 N

Using the principle of conservation of momentum;

Momentum before collision = momentum after collision

m1u1 +m2u2 = m1v1 + m2v2

Hence

(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2

13.12 = 4.8 + 2.3v2

13.12 - 4.8 = 2.3v2

v2 = 13.12 - 4.8/2.3

v2 = 3.6 m/s

Using the principle of conservation of linear momentum;

m1u1 + m2u2 = m1v1 + m2v2

(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v

v = 79.98 + 55.1/10.1

v = 13.37 m/s

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Answer: G

Explanation:

The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

The given parameters;

The vertical pressure of the water is calculated as follows;

[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]

The vertical height of the first floor from the 13th floor = 130 ft

The vertical height of the 13 ft floor = 10  ft

[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]

Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

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Answer: 5.05 J

Explanation:

Qcalorimeter: m*c* ΔT  --> (37.5g)*(4.184J/g ° C)*(55.2 °C – 23.0 °C)    Qcalorimeter: 5.05 J

According to specific heat capacity, 5.052 kJ of heat energy is required to raise the temperature of 37.5 g of water from 23.0°C to 55.2°C.

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

Substitution in above formula, givesQ= 37.5×4.184×32.2=5052.18 J or 5.052 kJ.

Thus , 5.052 kJ of  heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C.

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Answer:

D) 4.9 m/s

Explanation:

Speed of Object in Free Fall

s = Rate of Acceleration, Due to Gravity × Length of Time

s = 9.8 × 2.0

s = m/s (Round Up to The Nearest Whole Number)

--

m/s = 9.8 ÷ 2.0 = 4.9 m/s

Answer:

Light bouncing or reflecting off an object in different ways.

I just took a quiz and this was the answer

(k12 answer)

Light bouncing or reflecting off an object in different ways causes us to perceive objects in three-dimensions. Thus, the correct option is B.

Binocular fusion permits the perception of a single clear image and it also provides extra cues for the depth perception. That is, the binocular disparity between the two images is used by the nervous system of an individual to allow the perception of a three-dimensional world where the approximate distance of an object can be determined.

The depth perception is the ability to perceive the distance to objects using the visual system and visual perception.

Therefore, the correct option is B.

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Answer:

100 m/s

Explanation:

Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.

Answer:

D.

Explanation:

I believe it is D. Because in defense you are to stop others from scoring, while trying to score. But also while trying to protect the Goal or basket. I hope this helps you out.

Answer:

d

Explanation:

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

The upward force on the indoor skydiver include the following;

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

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Answer:

Explanation:

im sorry if this doesn't help but i think  its A

Answer:

D There is no frictional force acting on the car.

Explanation:

There isnt any friction acting on the car while its going down.

The acceleration of both the rocks is only due to the gravitational force acting on them. Even though the speed of thrown rock would be greater than that of dropped rock, the acceleration of both the rocks would be g downwards.

Answer:

1.80

Explanation:

38.4=-12.5(a)-1/2(-9.80)(a)^2

a= acceleration
^2 is the exponent

Answer:

It’s a

Explanation:

Answer:

A

Explanation:

This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.

Answer:

A

Explanation:

Got it right.

Answer:

A) Slower

Explanation:

    Less / low energy means less / slower speed.

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

D.

Exercise reduces stress and boosts confidence, which can create positive change.

Answer:

the suns pull

Explanation:

The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.

The weight of an astronaut in outer space and traveling with constant velocity is equal to 0 Newton.

Given the following data:

To determine the weight of an astronaut in outer space and traveling with constant velocity:

Mathematically, the weight of an object is calculated by using the following formula;

[tex]Weight = mg[/tex]

Where:

At a constant velocity, the value of the astronaut's acceleration is equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).

Substituting the given parameters into the formula, we have;

[tex]Weight = 68 \times 0[/tex]

Weight = 0 Newton

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Answer: gravity

Explanation:

Explanation:

The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.

We have to take moments around the pivoted point.

Moment = Force × Perpendicular distance to the force

For the rod to be in equilibrium,

Clockwise moment - Anticlockwise moment = 0

Clockwise moment = Anticlockwise moment

The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm

So 20 cm× 1.2 N produces a Clockwise moment

If Perpendicular distance between pivoted point and 2N load is x,

Anticlockwise moment = x × 2N

20 cm× 1.2N = 2N × x

x = 12 cm

So 2 N load is at 12 from the pivoted point.

From the left edge of the meter ruler, 2N load is at 30-12 cm distance

= 18 cm

Answer: 18 cm

Explanation:

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that

1. the initial velocity vector is

[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]

which means the ball is thrown with an initial speed of

√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,

and

2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that

[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]

3. At time t, the ball attains a height y and horizontal range x according to

y = (13 m/s) t - g/2 t²

x = (7.5 m/s) t

where g = 9.8 m/s². When the ball reaches the ground (y = 0) for t > 0, we have

(13 m/s) t - g/2 t² = 0

13 m/s - g/2 t = 0

t = 2 (13 m/s)/g = (26 m/s)/g

Plugging this time into the x equation gives a horizontal range of

x = (7.5 m/s) (26 m/s)/g ≈ 20. m

Answer:

The horizontal forces are equal in size and opposite in direction. They are balanced, so the horizontal resultant force is zero. This means that there is no horizontal acceleration just a horizontal constant speed. If a submarine is not moving horizontally, then there are no horizontal forces.

I hope it helps.

Answer:  34cm each year

Explanation: