Express the dollowing fraction in decimal form as a terminating decimal or as a infinite repeating decimal 3/16

Answer:

both isosceles???

Step-by-step explanation:

Answer:

They are similar.

Step-by-step explanation:

There might be other ways but

<X(Angle of x) is used for both triangle XAB and XYZ

And lines AB and YZ are parallel, From this we know that a line intersected by parallel lines it forms same angles for both parallel angles.

The similarity statement is: AAA Because angle(A=B , B=Z)

Answer:

Part A - he will need 2 cups of sugar  

Part B - 12 : 6 : 3

Step-by-step explanation:

Part A :

8 divided by 4 is 2

Part B :

Multiply all the numbers by 3

Hope this helped! :)

Answer:

22.53-9.99=12.54

12.54 divided by 6 = 2.09

Each pencil costs $2.09

Step-by-step explanation:

Answer:

Step-by-step explanation:

y = (4/7)x - 1

Answer:

Thermodynamics is a branch of physics that deals with heat, work, and temperature, and their relation to energy, entropy, and the physical properties of matter and radiation.

Answer:

[tex]x^{2}[/tex] - 10x + 16

Step-by-step explanation:

If the 0s are 2 and 8, then the factors are (x - 2) and (x - 8)

Multiply them together to get [tex]x^{2}[/tex] - 10x + 16

Answer:

x=-10

Step-by-step explanation:

since there's a given 120 degrees, and it's a isosceles triangle, we know that the line adds up to 180 (where the 120 degrees is). so 120+x=180, the interior angle measures 60 degrees. That being said, the 3 angles measure 60 degrees also. now there's a right angle mark on top, so we find the angle of the smaller triangle (near angle 2) by doing 90-60=30 degrees.

angle 2 is said to be x+160, and there's a line, which tells us that they must add to 180.. so x+160+30=180

x+190=180

x=-10.

Given :-

To Find :-

Solution :-

The given triangle is a right isosceles triangle . So here we can use the Pythagoras theorem as ,

[tex]\longrightarrow[/tex] hypotenuse² = perpendicular ² + base²

[tex]\longrightarrow[/tex] x² = 4² + 4²

[tex]\longrightarrow[/tex] x² = 16 + 16

[tex]\longrightarrow[/tex] x² = 32

[tex]\longrightarrow[/tex] x = √32

[tex]\longrightarrow[/tex] x = √2⁵

[tex]\longrightarrow[/tex] x = 4 × 1.732

[tex]\longrightarrow[/tex] x = 6.928 ≈ 7

#1

[tex]\\ \sf\hookrightarrow -5x+4=-1[/tex]

[tex]\\ \sf\hookrightarrow -5x=-5[/tex]

[tex]\\ \sf\hookrightarrow x=1[/tex]

Incorrect

#2

[tex]\\ \sf\hookrightarrow 4x-3=-7[/tex]

[tex]\\ \sf\hookrightarrow 4x=-4[/tex]

[tex]\\ \sf\hookrightarrow x=-1[/tex]

Correct

#3

[tex]\\ \sf\hookrightarrow 3y-4=5[/tex]

[tex]\\ \sf\hookrightarrow 3y=9[/tex]

[tex]\\ \sf\hookrightarrow y=3[/tex]

Ans not given

#4

[tex]\\ \sf\hookrightarrow -2y+7=12[/tex]

[tex]\\ \sf\hookrightarrow -2y=5[/tex]

[tex]\\ \sf\hookrightarrow y=-5/2[/tex]

Incorrect

#5

[tex]\\ \sf\hookrightarrow 3a-6=18-a[/tex]

[tex]\\ \sf\hookrightarrow 4a=24[/tex]

[tex]\\ \sf\hookrightarrow a=6[/tex]

Incorrect

#6

[tex]\\ \sf\hookrightarrow 5(2t-1)=2[/tex]

[tex]\\ \sf\hookrightarrow 10t=7[/tex]

[tex]\\ \sf\hookrightarrow t=7/10[/tex]

Incorrect

#7

[tex]\\ \sf\hookrightarrow ax-b=0[/tex]

[tex]\\ \sf\hookrightarrow x=\dfrac{b}{a}[/tex]

Correct

Done

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

The value of x from the given equation is -1

Given the equation expressed as:

[tex]3(x - 10) - 5x = 2x - 26[/tex]

Expand using the distributive law as shown:

3x - 3(10) - 5x = 2x - 26

3x - 30 - 5x = 2x - 26

Collect the like terms to have:

3x - 5x - 2x = -26 + 30

-2x - 2x = -26 + 30

Simplify the result by addition and subtraction:

-4x = 4

Divide both sides by -4 (Division property of equality)

-4x/-4 = 4/-4

x = -1

Hence the value of x from the given equation is -1

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Answer:

3 2/2

Step-by-step explanation:

Answer:

15.3 GAL.

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

In the ordered pair (2,1), 2 is the x-value and 1 is the y-value.

In the first equation, replace x with 2 and y with 1.

8x+7y

= 11

8(2)+7(1)

≟ 11

16+7

≟ 11

23

≟ 11

No, 23≠11.

Plugging (2,1) into the first equation did not result in a true statement. So, (2,1) is not a solution to the system of equations.

Answer:

22.5 degrees

Step-by-step explanation:

Complementary angles add up to be 90 degrees. You can model the simple equation [tex]x+3x=90[/tex] where is x is the small angle and 3x is the large angle.

[tex]4x=90\\x=22.5[/tex]

the smaller angle is 22.5 degrees

Answer:

1) 1584.72

2) 4811.2

3) 2381.721

4) 1672.376

5) 3901.59

Step-by-step explanation:

Answer:

two negitives equals a positive so C none of the above

Hope This Helps!!!

Answer:

A and B

Step-by-step explanation:

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

Answer:

14 nickels is the answer

Step-by-step explanation:

Answer:

3x²+3x-7

Step-by-step explanation:

(f+g)(x)=2x²+x²+3x-7

=3x²+3x-7

Answer:

Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need,  in general what you want is to move one end of the segment up, the other right, and stretch it.

That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.

For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]

The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.

The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.

Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at  [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.

Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]

Answer:

-270,810

Step-by-step explanation:

c.r.  r=-30/-10=3

[tex]a_{n} =a_{1}r^{n-1} \\a_{4}=-10(3)^{4-1}\\=-10(3)^3=-10 \times 27=-270\\a_{5}=-10 \times(3)^{5-1}\\=10 \times3^4\\=-810[/tex]

[tex]\textit{Half-Angle Identities}\qquad tan\left(\cfrac{\theta}{2}\right)= \begin{cases} \pm \sqrt{\cfrac{1-cos(\theta)}{1+cos(\theta)}} \\\\ \cfrac{sin(\theta)}{1+cos(\theta)}~~\leftarrow \textit{let's use this one} \\\\ \cfrac{1-cos(\theta)}{sin(\theta)} \end{cases} \\\\\\ 2\cdot \cfrac{\pi }{12}\implies \cfrac{\pi }{6}~\hspace{10em} \cfrac{~~ \frac{\pi }{6}~~}{2}\implies \cfrac{\pi }{6}\cdot \cfrac{1}{2}\implies \cfrac{\pi }{12}[/tex]

so let's use the double of the angle in the half-angle identities, check the picture below for the cosine, sine pairs

[tex]tan\left( \cfrac{~~ \frac{\pi }{6}~~}{2} \right)=\cfrac{sin\left( \frac{\pi }{6} \right)}{1+cos\left( \frac{\pi }{6} \right)}\implies tan\left( \cfrac{~~ \frac{\pi }{6}~~}{2} \right)=\cfrac{~~ \frac{1}{2}~~}{1+\frac{\sqrt{3}}{2}}[/tex]

[tex]tan\left( \cfrac{~~ \frac{\pi }{6}~~}{2} \right)=\cfrac{~~ \frac{1}{2}~~}{~~\frac{2+\sqrt{3}}{2}~~}\implies tan\left( \cfrac{~~ \frac{\pi }{6}~~}{2} \right)=\cfrac{1}{2}\cdot \cfrac{2}{2+\sqrt{3}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill tan\left( \cfrac{~~ \frac{\pi }{6}~~}{2} \right)=\cfrac{1}{2+\sqrt{3}}~\hfill[/tex]

Answer:

what ang hirap nmn anong grade ka na ba

[tex]f(x) = ab^x~\hfill \begin{array}{llll}\textit{we know that}~f(0)=-4\begin{cases}x=0\\f(x)=-4\end{cases}\\\\-4=ab^0\implies -4=a(1)\implies -4=a\end{array}\\\\\\\stackrel{therefore}{f(x)=-4b^x}~\hfill \textit{we also know that}~f(-2)=-64\begin{cases}x=-2\\f(x)=-64\end{cases}[/tex]

[tex]-64=-4b^{-2}\implies \cfrac{-64}{-4}=b^{-2}\implies 16=b^{-2}\implies 16=\cfrac{1}{b^2} \\\\\\ b^2=\cfrac{1}{16}\implies b=\sqrt{\cfrac{1}{16}}\implies b = \cfrac{\sqrt{1}}{\sqrt{16}}\implies b = \cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill f(x)=-4\left( \frac{1}{4} \right)^x~\hfill[/tex]

To determine the total number of cell phone subscribers that were in Centerville in 2020 is 5,928,227 people.

Given the following data:

Increment rate = 165% = 1.65

To determine the total number of cell phone subscribers that were in Centerville in 2020:

First of all, we would calculate the difference in years:

[tex]Year = 2020 - 2000[/tex]

Year = 20 years

Mathematically, the growth rate of cell phone subscribers that were in Centerville in 2020 is given by the formula:

[tex]A_n = Pr^t[/tex]

Substituting the given parameters into the formula, we have;

[tex]A_{20}=285(1.65)^{20}\\\\A_{20}=285 \times 22370.67\\\\A_{20}=5,928,227.55[/tex]

Subscribers = 5,928,227 people.

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Answer:2

Step-by-step explanation:

x+3=5

subtract 3 from both sides

x=5-3

x=2

Answer:

x=    2

Step-by-step explanation: