Find the distance, c, between (–2, 4)
and (3, –1)
on the coordinate plane. Round to the nearest tenth if necessary.

Step-by-step explanation:

question is not understandable bro i can't understand

Answer:

b ≤ 3/8

Step-by-step explanation:

Let the unknown number be b.

Translating the word problem into an algebraic expression, we have;

8b + 23 ≤ 26

Rearranging the equation, we have;

8b ≤ 26 - 23

8b ≤ 3

Dividing both sides by 8, we have;

b ≤ 3/8

Answer:

No

Yes

No

Yes

(choice 3 is a no)

Answer:

first 2 , second 50, third 8

Step-by-step explanation:

Answer:

0.9862.

Step-by-step explanation:

For each donation, there are only two possible outcomes. Either it can be safely used in a blood transfusion on someone with type A blood, or it cannot. The probability of a donation being safely used is independent of other donations, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Type A blood:

Can receive from type O(49%) and from type A(27%), which means that:

[tex]p = 0.49 + 0.27 = 0.76[/tex]

If three donations are made, what is the probability that at least 1 of them can be safely used in a blood transfusion on someone with type A blood?

Three donations mean that [tex]n = 3[/tex]

This probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{3,0}.(0.76)^{0}.(0.24)^{3} = 0.0138[/tex]

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0138 = 0.9862[/tex]

The answer is 0.9862.

The probability that at least 1 of them can be safely used in a blood is 0.9862.

Since, A person with type A blood can safely receive blood transfusions of type O and type A blood.

Given that,

49% of donations are type O blood

27% of donations are type A blood

So,    [tex]p=0.49+0.27=0.76[/tex]   and   [tex]q=1-0.76=0.24[/tex]

Where p represent probability of success and q represent probability of unsuccessful.

Now use Binomial distribution,

      [tex]P(X=r)=n_{C}_rp^{r} q^{n-r}[/tex]

Here three donations, it means that, n = 3

We have to find that the probability that at least 1 of them can be safely used in a blood.

So,     [tex]P(X\geq 1)=1-P(X=0)[/tex]

        [tex]P(X=0)=3_{C}_0(0.76)^{0} (0.24)^{3}=0.0138[/tex]

           [tex]P(X\geq 1)=1-0.0138=0.9862[/tex]

Thus, The probability that at least 1 of them can be safely used in a blood is 0.9862.

Learn more about Binomial distribution here:

https://brainly.com/question/11388449

Answer:

24x-18

Step-by-step explanation:

To simplify this we will need to use the distributive property

we can start with

6*4x=24x

then we can do

6*3=18

and since their is a negative sign in the middle that is what we do, so it will be

24x-18

Can I please have brainliest :)

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{Simplify 6(4x - 3)}[/tex]

[tex]\large\text{DISTRIBUTE}\downarrow[/tex]

[tex]\large\text{6(4x - 3)}[/tex]

[tex]\large\text{6(4x) + 6(-3)}[/tex]

[tex]\large\text{6(4x) = 24x}[/tex]

[tex]\large\text{6(-3) = -18}[/tex]

[tex]\large\text{\bf = 24x - 18}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \bf \huge 24x - 18 }}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

128

Step-by-step explanation:

32 ÷ 4• 4 ÷ 2 • 2

8 .4.2.2

128

Answer:

y = -3x + 3

Step-by-step explanation:

use the formula y - y1 = m ( x - x1)

y - 3 = -3 ( x - 0)

y - 3= -3x

y = -3x + 3

Answer:

What you should do in this case is to use the following trinonometric relationship:

senx = C.O / h

Where

C.O: Opposite leg.

h: hypotenuse.

Substituting:

senx = (7) / (9)

Clearing x:

x = ASIN ((7) / (9))

x = 51.05755873

Answer:

The value of x is

x = 51 degrees.

Step-by-step explanation:

Answer:

m<S=63°

Step-by-step explanation:

The angle formed with the radius and a tangent is 90 degrees. (<T)

180-90-27=63

Answer:

(-4,-6)

hope this helps !

Answer:

9×24-4

216-4

212

Step-by-step explanation:

I am not sure, but it might help you

Answer:

n = [tex]\frac{4}{3}[/tex]

or (because the wording is kind of confusing)

n = [tex]\frac{20}{3}[/tex]

Step-by-step explanation:

9(4 - n) = 24

36 - 9n = 24

-9n = -12

n = [tex]\frac{4}{3}[/tex]

or (because the wording is kind of confusing)

9(n - 4) = 24

9n - 36 = 24

9n = 60

n = [tex]\frac{20}{3}[/tex]

There is no attachment attached.

Answer:

B

Step-by-step explanation:

fourth term

A(4)= 7 - ( 4-1)(-3)

=-2

seventh term

A(7)= 7 - (7-1)(-3)

=-11

tenth term

A(10) = 7 - (10-1)(-3)

= -20

Answer:

Step-by-step explanation:

If the 2 is an exponent, it needs to be written as ^2.

(5+√3)²  = 5² + 10√3 + 3 = 28 + 10√3

Answer:

3 and one third %

3.3333%

Step-by-step explanation:

Answer:

x= 230

Step-by-step explanation:

since a circle is 360 degrees

x + 130 = 360

x= 360 -130

x=230

Answer:

1300

Step-by-step explanation:

Answer:

1300

Step-by-step explanation:

Answer:

[tex]Q = 1[/tex]

[tex]M = 2[/tex]

Step-by-step explanation:

Solving (a):

Given: 1-32-794182- Q

Required: Find Q

To do this, we first multiply each digit in descending order of 10.

So, we have:

[tex]Product = 1 * 10 + 3 * 9 + 2 * 8 + 7 * 7 + 9 * 6 + 4 * 5 + 1 * 4 + 8 * 3 + 2 * 2 + Q * 1[/tex]

[tex]Product = 208 + Q *1[/tex]

[tex]Product = 208 + Q[/tex]

Equate the modulus of the product by 11 to 0

[tex]Product \% 11 = 0[/tex]

[tex](208 + Q) \% 11 = 0[/tex]

The next number greater than 208 divisible by 11 is 209.

So, we have:

[tex](208 + Q) \% 11 = 209 \% 11[/tex]

Express 209 as 208 + 1

[tex](208 + Q) \% 11 = (208 + 1)\% 11[/tex]

By comparison:

[tex]Q = 1[/tex]

Hence, the checksum is 1

Solving (a):

Given: 2-429-39M18-6

Required: Find M

Apply the same step in (a)

So, we have:

[tex]Product = 2 * 10 + 4 * 9 + 2 * 8 + 9 * 7 + 3 * 6 + 9 * 5 + M * 4 + 1 * 3 + 8 * 2 + 6 * 1[/tex]

[tex]Product = 198 + 4M + 25[/tex]

[tex]Product = 223+ 4M[/tex]

Equate the modulus of the product by 11 to 0

[tex]Product \% 11 = 0[/tex]

[tex](223+ 4M) \% 11 = 0[/tex]

The next number greater than 223 divisible by 11 is 231.

So, we have:

[tex](223+ 4M) \% 11 = 231 \% 11[/tex]

Express 231 as 223 + 8

[tex](223+ 4M) \% 11 = (223 + 8) \% 11[/tex]

By comparison:

[tex]4M = 8[/tex]

Divide both sides by 4

[tex]M = 2[/tex]

Answer:

RM / RP = 10/18 = 5/9

RN/RQ = 7/21 = 1/3

Since the two ratios are not the same, triangle PRQ is not similar to triangle MRN.

Step-by-step explanation:

The triangles PRQ and MRN are not similar.

Triangles are similar if their corresponding angles are congruent and the corresponding sides are in proportion.

This means the ratio of there corresponding sides must be equal. The corresponding angles must be the same . Therefore, the following rules must apply:

∠R = ∠R

∠Q = ∠N

∠P = ∠M

The following proportion rule must apply below:

PR / MR = RQ / RN = PQ / MN

18 / 10 = 21 / 7

9 : 5 ≠ 3 : 1

Therefore, the triangles are not similar

learn more on similar triangles here: https://brainly.com/question/10810713

Answer:

$9.80

Step-by-step explanation:

Remember that the way to find the mean of a data set is by adding together all the values, and dividing by the number of the values. So, in this case, you add the 5 values together and get 49. Since there are 5 values, you divide 49 by 5 and get 9.8, or in a real world-money situation $9.80.

Answer:

75

Step-by-step explanation:

7350/98 = 75

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = [tex]2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750[/tex]

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

[tex]W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5[/tex]

The work done in pulling half the rope, W₂ = 562.5 lb·ft