For a system mass of 600g and a hanging weight of 0.50 N, determine the acceleration of the system

Answers

Answer 1

Answer:

A=0.80

Explanation:

a=2×100/time^2. a=2×100/15.86^2. = a=0.80

Answer 2

The acceleration of the system will be 0.833 meters per second square.

What is newton's second law?

The behavior of things is predicted by Newton's first rule of motion when all external forces are equal. The first law, sometimes known as the law of inertia, asserts that if an entity's energies are balanced, its acceleration will be zero meters per second.

When all forces are balanced, an object is said to be in equilibrium and won't accelerate. Newton postulated that an item will only accelerate in the presence of a net or uneven force. An object will accelerate if there is an imbalanced force present, altering its direction, speed, or both.

Let 'm' be the mass of the object in kilogram and 'a' is the acceleration of the object in meters per second square. Then the force on the system is calculated as,

F = ma

For a system mass of 600g and a hanging weight of 0.50 N. Convert the mass of the object into kilogram. Then we have

m = 600 / 1000

m = 0.6 kg

Then the acceleration of the system will be calculated as,

0.50 = 0.6 × a

a = 0.833 meters per second square

The acceleration of the system will be 0.833 meters per second square.

More about newton's second law link is given below.

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Related Questions

When a pendulum is at the center position, what is true of the kinetic and potential energy?
A.
Both potential energy and kinetic energy are at their minimum values.
B.
Both potential energy and kinetic energy are at their maximum values.
X c.
Potential energy is maximum and kinetic energy is minimum.
D.
Kinetic energy is maximum and potential energy is minimum.

Answers

Answer:

C is the answer to your question

Answer:

D.

Kinetic energy is maximum and potential energy is minimum.

Explanation:

Relate the changes in molecular motion of particles as they change from solid to liquid to gas.

As the phase changes occur, the freedom of motion of the particles

increases.

As the phase changes occur, the freedom of motion of the particles

decreases.

Eliminate

As the phase changes occur, the freedom of motion of the particles

compresses.

As the phase changes occur, the freedom of motion of the particles is

constant.

When a colid cuch as ice begins to melt heat energy is added. What is the function of this added heat

Answers

Answer:

As the phase changes occur, the freedom of motion of the particles increases

Explanation:

In thermodynamics the state of matter: solid, liquid and gaseous.

We can characterize them, the solid state maintains a certain shape, which is why particles are tightly bound and can hardly move from their equilibrium positions.

The liquid state does not hold its shape, so the particles have more energy and can move a lot from their equilibrium position.

The gaseous state does not maintain the shape or the volume, so the interaction between the particles is very small, so they can move almost freely.

When examining the answer, the correct one is: As the phase changes occur, the freedom of motion of the particles increases.

A student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. In trial 1, the student exerts the force on a cart of mass M. In trial 2, the student exerts the force on a cart of mass 3M. In trial 3, the student exerts the force on a cart of 5M. In which trial will the cart experience the greatest change in momentum from 0 s to 2 s?

Answers

Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

[tex]F = m a\\\\a =\frac{F}{m}[/tex]

We use movies and find lips

[tex]\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t[/tex]

The moment is defined by

[tex]\to p = m v[/tex]

The moment change

[tex]\Delta p = m v - m v_0[/tex]

Let's replace the speeds in this equation

[tex]\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0 + F t - m v_0\\\\\Delta p = F t[/tex]

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

Brainliest for correct answer :))

Answers

Choose the 2nd Option.....

Second. They fall freely At an acceleration of 10ms^-2 troughout

What is the velocity of a wave with a frequency of 45 Hertz and a wavelength of 3 meters?

Answers

Explanation:

By using v=( f )x( lambda )

v= 45 s^-1 x 3 m

Therefore v = 135 ms^-1

Please help Solve! I need help!

Question:
Jermaine runs exactly 2 laps around a 400-meter track. What is the displacement?

Multiple choice answers (I need help I don't understand I don't know what the answer is PLEASE HELP ME):
a. 200
b. 800
c. 400
d. 0

Answers

D

Explanation

Given,

Distance covered in 1 lap = 400m

= Distance covered in 2 laps = 400 × 2

=800m

If Jermaine runs 2 whole laps, she comes back to her starting point.

So the answer is 0m

10. The elevator in the new office building warns that it can safely lift 300 kg at one time. If John (850N), Betty (530N), Robert (740N), and Alice (610N) all get in the elevator at once, can the elevator safely carry them up to the third floor?

Answers

I can't tell right away.  The elevator's limit is given in terms of mass, but the four people are listed in terms of their weights.  In order to compare them, we'll have to convert one or the other.

The total of the four people's weights is:

John . . . . . . . 850N

Betty . . . . . . . 530N

Robert . . . . . . 740N

Alice . . . . . . . .610N

Total . . . . . . 2,730N

The elevator can't accept more than 300 kg of mass.

The weight of any mass is (mass) x (gravity).

On Earth, 300kg weighs (300kg) x (9.8 m/s²) = 2,940 N.

Wonderful !  

2,730N is less than 2,940N.

Yes ! According to Otis' engineers, John, Betty, Robert and Alice can safely ride the elevator together, (although Betty and Alice may have a different opinion).

A hockey stick moves toward a puck sitting on ice. A blue arrow labeled A points up from the puck. A blue arrow labeled F subscript g points down from the puck. What force is represented by vector A? If the hockey puck is moving to the right, what will happen when it is hit with a significant force by the hockey stick?

Answers

Answer:

normal force, the pluck will move off in a different direction

Explanation:

Answer:

Normal force, the puck will move off in a different direction

Explanation:

A light wave has a frequency of [tex](6 \times {10}^{8}).[/tex]
What is the wavelength of the light wave?
(Assume the speed of light to be [tex](3 \times {10}^{8}).[/tex])

Answers

Answer:

0.5m or 50 cm

Explanation:

11. All objects gain or release heat at the same rate. *

Answers

The statement is false.

An arrow is shot at an angle of 35° and a velocity of 50 m/s. How long does it take to return to its original starting height?

Answers

Answer:

4.02 s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 35°

Initial velocity (u) = 50 m/s

Acceleration due to gravity (g) = 10 m/s²

Time of flight (T) =?

The time of flight of the arrow can be obtained as follow:

T = 2uSineθ / g

T = 2 × 35 × Sine 35 / 10

T = 70 × 0.5736 / 10

T = 7 × 0.5736

T = 4.02 s

Therefore, the time taken for the arrow to return is 4.02 s

An athlete whirls a 8.00 kg hammer m from the axis of rotation in a horizontal circle, as shown in the figure below . The hammer makes one revolution in s. What is the centripetal force on the hammer ?

Answers

Answer:

[tex]mv \div r \\ mass \times velocity \div radius[/tex]

100 POINTS!!!
Which condition is NOT necessary for a hurricane to form?
warm ocean waters
very low air pressure
high air pressure
warm, moist air rising

Answers

Answer:

very low air pressure and that's not 100 points

How much thermal energy is absorbed when 145 g of water at 23ºC is heated until it boils and turns into vapour?

Answers

Answer:

the thermal energy absorbed is 46,893 J

Explanation:

Given;

mass of the water, m = 145 g = 0.145 kg

initial temperature of the water,  t₁ = 23 ⁰C

final temperature of the water, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg.⁰C

The thermal energy absorbed is calculated as;

H = mcΔt

H = 0.145 x 4,200 x (100 - 23)

H = 46,893J

Therefore, the thermal energy absorbed is 46,893J

What property of sound does a decibel measure

Answers

Intensity. They relate the intensity of a pressure wave to a normal or standard pressure

reason why the clinical thermometer has a long cylindrical bulb and not spherical bulb​

Answers

Answer: One of the factors of the rate of heat transfer is the amount of surface area contact of the thermometer and the object whose temperature is being measured. By using a cylindrical bulb, rather than a spherical bulb, the time to get an accurate temperature is reduced. hope this helps. Can u give me brainliest

Explanation:

Answer:

it is because by using a cylindrical bulb,rather than a spherical bulb,the time to get to an accurate temperature is reduced. If you place the bulb of a mercury thermometer made of glass in boiling water you can see that the column of the mecury falls before rising

Derive, with full working, the symbol equation for the power output P watts of the energy transfer that occurs when a mass of m kg falls through a height of h metres in t seconds.

Answers

I agree that the height is kg or an maybe

What kind of data does doppler radio provide
A. snowfall and freezing levels
B. temperature and atmospheric pressure
C. precipitation levels, cloud location, direction
D. flooding and tsunamis

Answers

Answer:

d

Explanation:

PLEASE HELP!!!!!!!!!!!!!

a. A light wave travels through glass (n=1.5) at an angle of 28°. What angle does it have when
it passes from the glass into water (n = 1.33)?


B. Draw a ray diagram to locate the image of the object below. Write one or two sentences to describe the type of image, it’s size relative to the object, and it’s position with respect to the lens.

C. An object is located 94.0 cm from a concave mirror. The focal length is 34.0 cm. What is the image distance? Is the image real or virtual??

D. An Object is located 65.0 cm from a concave lens. The image distance is -11.8 cm. What is the magnification?

E. For a person who is nearsighted, seeing objects that are far away is difficult. The light from these objects does not get focused far enough back in the eye. Write one or two sentences to identify the type of lens that can be used to correct nearsightedness and describe why it works.

PLEAAAASE HELP MEEE

Answers

Answer:

A. The angle with which the light passes from glass into water is approximately 31.97°

B. The image formed is, real, inverted, and smaller than the object

C. The image distance is 53.2[tex]\overline 6[/tex] cm

The image is real

D. The magnification is approximately 0.182

E. The type of lens required is a concave lens which corrects the focus of a powerful eye lens or a long eyeball

Explanation:

The given parameters for the light wave are;

The refractive index of the glass medium, n₁ = 1.5

The angle of incidence of the light, θ₁ = 28°

The refractive index of water, n₂ = 1.33

A. Let θ₂ represent the angle with which the light passes from glass into water

Snell's law is mathematically stated as follows;

n₁·sin(θ₁) = n₂·sin(θ₂)

According to Snell's law, we have;

1.5 × sin(28°) = 1.33 × sin(θ₂)

sin(θ) = (1.5 × sin(28°))/1.33 = 0.52947920615

∴ θ₂ = arcsin(0.52947920615) ≈ 31.97°

The angle with which the light passes from glass into water, θ₂ ≈ 31.97°

B. Please find attached the drawing of the image created with Microsoft Visio

From the drawing, we have that the image formed is real inverted smaller than the object and between the focus and radius of curvature

C. The location of the object from the mirror, u = 94.0 cm

The focal length of the mirror, f = +34.0 cm

The mirror formula for a concave mirror is given as follows;

[tex]\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}[/tex]

Therefore, we have;

[tex]\dfrac{1}{34.0} = \dfrac{1}{94.0} + \dfrac{1}{v}[/tex]

[tex]\dfrac{1}{v} = \dfrac{1}{34.0} - \dfrac{1}{94.0} = \dfrac{15}{799}[/tex]

[tex]\therefore \dfrac{v}{1} = v =\dfrac{799}{15} = 56.2\overline 6[/tex]

The image distance, v = 799/15 = 53.2[tex]\overline 6[/tex] cm

Therefore the image is in front of the mirror, which is a real image

The image is real

D. The given parameters of the object and lens are;

The distance of the object from the lens, u = 65.0 cm

The distance of the image formed from the lens, i = -18 cm

The magnification, M, is given as follows;

[tex]M = \dfrac{-v}{u}[/tex]

Therefore;

[tex]M = \dfrac{-(-11.8)}{65.0} = \dfrac{59}{325} \approx 0.18153846153[/tex]

The magnification, M ≈ 0.182

E. For a person who is near sighted, the light from objects from distant location are almost parallel and are brought to a focus in front of the retina and therefore, they appear blurred

The use of a concave lens is required to correct nearsightedness as it causes the light to appear come from a point before the focus such that the divergent rays of the object refracted through the concave lens comes to a focus at the.

A boom is to be dropped from moving helicopter on the ground. Explain how can it hut the target ?

Answers

Answer:

A bomb that is dropped from a moving helicopter doesn't fall directly downward rather it follows the parabolic path as it were thrown horizontally from a height with certain initial velocity. Therefore, the bomb should be dropped from farther distance equal to the horizontal range before the helicopter reaches above the target.


How much force would be expected to be needed to lift the weight of 87N when the effort length is 9.2m and the resistance length is 3.4m

Answers

Answer:

Force = 504.6 N

Explanation:

Weight, W = mg

Weight of object = 87 N

Effort length = 9.2 m

Resistance length = 3.4 m

The required length, h = Effort length - Resistance length

                                      = 9.2 - 3.4

                                      = 5.8 m

But,

F = mgh

  = W x h

F = 87 x 5.8

  = 504.6 N

The value of force required to lift the weight is 504.6 N.

a) A 12 kg object has a velocity of 37.5 m/s. What is its momentum?
b) How far does it get in 16 s?

Answers

Answer:

The answer would be 450 m kg/s

Explanation/ Explanation / Example:

Provided an object traveled 500 meters in 3 minutes , to calculate the average velocity you should take the following steps: Change minutes into seconds (so that the final result would be in meters per second). 3 minutes = 3 * 60 = 180 seconds , Divide the distance by time: velocity = 500 / 180 = 2.77 m/s .

If this doesn't help let me know!

A 0.15-m straight wire moves with a constant velocity of 7.0 m/s perpendicularly
through a magnetic field. If the magnetic field has a strength of 0.40 T, what is the
electromotive force?

Answers

Answer: force is 0.42 N

Explanation: F = l·v·B

Don't scroll down. Help pls 22 POINTS!!

Answers

Answer:

I don't know if these are all right but these are my best answers. good luck and I hope you do well.

1. true

2. true

3. false

4. true

5. true

6. true

7. true

8. true

9. false

10. false

13. it stimulates the heart through chest compressions

14. on bare skin upper right shoulder and lower left ribs

15. no CPR

Explanation:

A good example of kinetic energy would be_____.

A. a car driving on a road
B. a stretched rubber band
C. a rollercoaster at the top of a hill
D. an Apple high in a tree

PLEASE HELP ME WITH THIS QUICK IT IS TIMED AND IM ONLY ON NUMBER 5 AND THERE IS 17 QUESTIONS

Answers

Answer:

B.) a stretched rubber band

Explanation:

-

It is the disturbance or oscillation that travels through space and matter, accompanied by a transfer of energy.

Answers

Answer:

wave

Explanation:

A wave is defined as the disturbance that causes the movement of energy. The energy is transferred as the waves move from one place to another. A medium is required for the transfer of energy. Usually a wave travels through air or water. The process is carried on at a specific speed that is termed as the speed of propagation.

- The gravitational force on a 352 kg satellite is -2100 N. Find its
distance from Earth's center.

Answers

Answer:

8173.8 km

Explanation:

Fg=G(M*m/r^2)

r=sqrt(G*M*m/Fg)

G=6.6743*10^-11

M(earth)=5.972*10^24kg

M(object)=352kg

Fg=-2100N

r=sqrt((6.6743*10^-11)*(5.972*10^24kg)*(352)/-2100)

r=8173808m

r=8173.8km

According to Newton's calculations, gravity reduces to a fourth of what it was at the surface of the Earth if the distance from the planet's centre is doubled. At the Earth's surface, a satellite with a mass of 1,000 kg exerts a weight force of 9,800 N.

What gravitational force act on satellite?

Satellites are pulled toward Earth by its gravity, even when they are hundreds of kilometres distant. The satellite doesn't fall back to Earth; instead, it travels into orbit above it due to gravity and the velocity it acquired during launch into space.

A satellite that is in a steady circular orbit around the Earth is always falling. It encounters a gravitational pull toward the centre of Earth as it orbits, which forces it to shift course and “fall” towards Earth.

Therefore, Since gravity is the only force acting on a satellite in circular orbit, the centripetal force and gravity must be equal: Fc = Fg.

Learn more about satellite here:

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What is the correct reason for blinking / flickering of stars? Explain it.

A) The blasts in the stars.

B) Absorption of star light by the atmosphere.

C) Motion of the stars.

D) Changing refractive index of gases in the atmosphere.
plz suggest me a answer which can give me 3 marks​

Answers

Answer:

d. changing refractive index of gases in the atmosphere

Explanation:

light from a star passes through the atmosphere to reach our eyes. however, the layers of gases in the atmosphere are in constant motion, so the light gets bent and appears to be flickering.

i hope this helps! :D

Answer all of these questions and you will get the brain list

Answers

Answer:

1. Mechanical energy = 298.4 Joules.

2. Mechanical energy = 2140 Joules.

3. Mechanical energy = 0.2838 Joules.

Explanation:

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

1. Kinetic energy = 182.2 J

Potential energy = 116.2 J

To find the mechanical energy;

Mechanical energy = kinetic energy + potential energy

Mechanical energy = 182.2 + 116.2

Mechanical energy = 298.4 Joules.

2. Mass = 40kg

Velocity = 3m/s

Height = 5m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the mechanical energy;

We would determine the kinetic and potential energy respectively.

K.E = ½mv²

K.E = ½*40*3²

K.E = 20*9

K.E = 180 Joules.

P.E = mgh

P.E = 40*9.8*5

P.E = = 1960 Joules

Mechanical energy = K.E + P.E

Mechanical energy = 180 + 1960

Mechanical energy = 2140 Joules.

3. Mass = 0.002kg

Height = 3m

Velocity = 15m/s

To find the mechanical energy;

K.E = ½mv²

K.E = ½*0.002*15²

K.E = 0.001*225

K.E = 0.225 Joules.

P.E = mgh

P.E = 0.002*9.8*3

P.E = = 0.0588 Joules

Mechanical energy = K.E + P.E

Mechanical energy = 0.225 + 0.0588

Mechanical energy = 0.2838 Joules.

Sound waves move the fastest through which medium

Water at high temp
Water at low temp
Air at high temp
Air at low temp

Answers

Answer:

water at high temperature

Explanation:

When heated, molecules move faster which results in the sound waves being transmitted faster.

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