give an example of a normal force. type below.

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Answer:

[tex]5.33\ m/s[/tex]

Explanation:

[tex]We\ know\ that,\\Momentum=Mass*Velocity\\p=mv\\Hence,\\Lets\ first\ consider\ the\ case\ of\ the\ two\ balls\ 'Before\ Collision':\\\\Mass\ of\ the\ green\ ball=0.2\ kg\\Initial\ Velocity\ of\ the\ green\ ball=5\ m/s\\Initial\ Momentum\ of\ the\ green\ ball=5*0.2=1\ kg\ m/s\\\\Mass\ of\ the\ pink\ ball=0.3\ kg\\Initial\ Velocity\ of\ the\ pink\ ball=2\ m/s\\Initial\ Momentum\ of\ the\ pink\ ball=0.3*2=0.6\ kg\ m/s\\\\Total\ momentum\ of\ both\ the\ balls\ 'Before\ Collision'=1+0.6=1.6\ kg\ m/s[/tex]

[tex]Hence,\\Lets\ now\ consider\ the\ case\ of\ the\ two\ balls\ 'After\ Collision':\\\\Mass\ of\ the\ green\ ball=0.2\ kg\\Final\ Velocity\ of\ the\ green\ ball=0\ m/s\\Final\ Momentum\ of\ the\ green\ ball=0\ kg\ m/s\\\\Mass\ of\ the\ pink\ ball=0.3\ kg\\Final\ Velocity\ of\ the\ pink\ ball=v\ m/s\\Final\ Momentum\ of\ the\ pink\ ball=0.3*v=0.3v\ kg\ m/s\\\\Total\ momentum\ of\ both\ the\ balls\ 'After\ Collision'=0+0.3v=0.3v\ kg\ m/s[/tex]

[tex]As\ we\ know\ that,\\Through\ the\ law\ of\ conservation\ of\ momentum,\\In\ an\ isolated\ system:\\Total\ Momentum\ Before\ Collision=Total\ Momentum\ After\ Collision\\Hence,\\1.6=0.3v\\v=\frac{1.6}{0.3}=5.33\ m/s[/tex]

Answer:

the nucleus is the size of an apple, approximately 5 cm of radius e, the atom has a radius of R = 5 cm 104 = 50000 cm = 50 km

Explanation:

In the Rutherford experiments it was proved that the atomic nucleus has the volume 10-4 the volume of the atom.

If we make a scale design in which the nucleus is the size of an apple, approximately 5 cm of radius e, the atom has a radius of R = 5 cm 104 = 50000 cm = 50 km

This shows that almost the entire volume of the atom is empty.

Answer:

182.28 W

Explanation:

Here ,

m = 7.30 Kg

distance , d= 28.0 m

time , t = 11.0 s

average power supplied = change in potential energy/time

average power supplied = m×g×d/time

average power supplied = 7.30×9.81×28/11

average power supplied = 182.28 W

the average power supplied is  182.28 W

Answer:

E_{pot} = 132.3 [J]

Explanation:

In order to solve this problem, we must use the definition of the potential energy which can be calculated by means of the following formula.

[tex]E_{pot}=W*h[/tex]

where:

Epot = potential energy [J]

W = weight = 5.4 [N]

h = elevation = 24.5 [m]

[tex]E_{pot}=5.4*24.5\\E_{pot}=132.3[J][/tex]

Answer:

26621 km

Explanation:

We are given;

Mass: m = 5.98 x 10^(24) kg

Period; T = 43200 s

Formula for The velocity(v) of the satellite is:

v = 2πR/T

Where R is the radius

Formula for centripetal acceleration is;

a_c = v²/R

Thus; a_c = (2πR/T)²/R = 4π²R/T²

Formula for gravitational acceleration is:

a_g = Gm/R²

Where G is gravitational constant = 6.674 × 10^(-11) m³/kg.s²

Now the centripetal acceleration of the satellite is caused by its gravitational acceleration. Thus;

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Plugging in the relevant values;

R = ∛((6.674 × 10^(-11) × 5.98 x 10^(24) × 43200²)/(4 × π²))

R = 26.621 × 10^(6) m

Converting to km, we have;

R = 26621 km

Answer:

2.66 *10^7

Explanation:

Sorry I don't know the process if you were interested in that :/

Answer:10 m/s

Explanation:

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Velocity is vector quantity.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time. Here in the question velocity is changing by using work energy theorem we have,

work done = change in kinetic energy

5000 = (.5).m.v² , where v is velocity.

5000 = (.5).100.v²

v = 10 m/sec

A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.

To learn more about velocity refer the link:

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Question 6

C. 72.1 N

Its simply the newton Third law, whenever two objects interact, they exert equal and opposite forces on each other.

Question 7

D. Maria is incorrect because the cart's velocity has changed

The car is accelerating so, It is not in dynamic equilibrium. Remember that by the Newton Second Law:

F = ma

The cart is in dynamic equilibrium. The correct options for the two question are:

6. C

7. A

6.) Given that a 61.0 kg grocery cart is sitting at rest. And Xavier applied 72.1 Newtons of force on the cart.

According to Newton's third law of motion which state that, in every action, there will be equal and opposite reaction. The magnitude of force That the cart exert back on Xavier's hand will be opposite and equal to the force applied. which is negative 72.1 N

7.) If the grocery cart is moving in a constant velocity, then it will achieve a dynamic equilibrium. In this scenario, the air resistance force balances with the applied force.

Therefore,  Maria is correct because the cart is traveling at a constant velocity while experiencing balanced forces.

Learn more about equilibrium of forces here: https://brainly.com/question/9076091

D) Speed, direction, or both

Mass doesn’t just CHANGE like that.

Answer:

[tex]l_o=550.055\ cm[/tex]

Explanation:

Given that,

Length of a street bridge, l = 5.5 m

The coefficient of bridge, [tex]\alpha =0.00001 ^0 C[/tex]

We need to find how much will it expand when temperatures is by 10°C.

The change in length per unit original length is given by :

[tex]\dfrac{\Delta l}{l}=\alpha \Delta T\\\\\Delta l = l\alpha \Delta T\\\\=5.5\times 0.00001 \times 10\\\\\Delta l=0.00055\\\\(l_o-l)=0.00055\\\\l_o=0.00055+5.5\\\\=5.50055\ m\\\\l_o=550.055\ cm[/tex]

Hence, the length will expanded 550.055 cm.

Answer: C- The planets appeared to move backward in the sky occasionally.

This question is incomplete, the complete question is;

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

a) (In2)R

b) 4R

c) R/(In2)

d) 2R

e) R

Answer: Option e) R is the correct answer.

Explanation:

Given that;

Inner radius = a

Outer radius = b

Conical Cylinder

∫dR = ∫(edr/2πrL)

R = e/2πL In e |ᵇₐ

R = e/2πL In(b/a) ------------- let this be equation 1

Taking a look at the second cone

a' = 2a

b' = 2a

R' = e/2πL In(2b/2a)

{L = L'}

R' = e/2πL In(b/a) -------let this be equation 2

now lets compare the two equation

R = e/2πL In(b/a)

R' = e/2πL In(b/a)

so R' = R

Therefore Option e) R is the correct answer.

Answer:

T= In(2)/___ =__ In(2)

Explanation:

the equation pices arnt on the keyboard so i put the blanks

sorry

jope it helps some. Have a good day ir night! :)

Answer:

a) ll and Ill only

Explanation:

Let the mass of the wrench = m

and the mass of the astronaut = M

Initially, the velocity of the astronaut and wrench are zero.

The astronaut throws the wrench in one direction and subsequently recoils back with a velocity in the opposite direction.

Let v and V be the velocity of the wrench and the velocity of the astronaut respectively.

In space, there is no external force acting, the momentum must be conserved.

So, m(0)+M(0)=m(v)+M(V)

So, 0=mv+MV

[tex]\Rightarrow mv=-MV[/tex] ...(i)

Here, the momentum of the wrench = mv, and the momentum of the astronaut= MV. The negative sign showing that both the momentum are in opposite direction.

Therefore, the momentum of the wrench is equal and opposite to the momentum of the astronaut.

According to Newton's second law, the rate of change of momentum = applied force.

Let it take [tex]\Delta t[/tex] seconds to change the momentum.

So, for the wrench

[tex]m(v-0)/\Delta t= F_w \\\\\Rightarrow m(v-0)=F_w\Delta t \\\\\Rightarrow mv=F_w\Delta t \cdots(ii)[/tex]

Here, [tex]F_w\Delta t[/tex] is the impulse applied to the wrench.

Similarly, for the astronaut

[tex]M(-V-0)/\Delta t= F_a[/tex] [negative sign (-V) for opposite direction]

[tex]\Rightarrow M(-V-0)=F_a\Delta t \\\\\Rightarrow -MV=F_a\Delta t[/tex]

Here, [tex]F_a\Delta t[/tex] is the impulse applied to the astronaut.

So, the impulse on the astronaut.

By using equations (i) and (ii)

[tex]F_a\Delta t=F_w\Delta t[/tex]

Therefore, the impulse applied to the wrench is equal and opposite to the impulse applied to the astronaut.

Hence, option (a) is correct.

Answer:

66.475kJ

Explanation:

Work done is the product of the force and perpendicular distance in direction of the force.

Work done = Force × distance

Given

Weight = 700lb

Distance = 70ft

1lb force = 4.448N

700lb force = 700(4.448) = 3113.6N

Distance = 70(0.305) = 21.35m

Work done = 3113.6×21.35

Work done ≈ 66,475Joules

Work done = 66.475kJ

Answer:

Enamel is used to coat the wires, it is the thinnest possible insulator. The coils are made up of large number of turns and enamel makes it possible to cram a lot of wires (coils) in much smaller space.

If the acceleration constant..

you can use the formula s = ut + 1/2at²

Known that :

s = ?

u = 0

t = 2s

a = 10ms-²

Then you can apply the formula

s = ut + 1/2at²

s = 0 + 1/2(10)(2)²

s = 5 × 4

s = 20m

Answer : 20m

Explanation :

The gravity can be 9,8 or 10. Also im not sure how people teach you but in my school, if the ball goes down the gravity is positive and not negative thats why i put 10ms-² and not -10ms-²

s = displacement/distance

u = initial speed

a = acceleration

t = time

sorry if im wrong

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  [tex]F = 25 \ N[/tex]

   The frequency is   [tex]f = 1 \ Hz[/tex]

   The mass of the bridge per unit length is  [tex]\mu = 2000 \ kg /m[/tex]

    The length of the central span is  [tex]d = 144 m[/tex]

     The oscillation amplitude of the section  considered at the time considered is  [tex]A = 75 \ mm = 0.075 \ m[/tex]

      The time taken for the undriven oscillation to decay to [tex]\frac{1}{e}[/tex]  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            [tex]m = \mu * d[/tex]

=>        [tex]m = 2000 * 144[/tex]

=>        [tex]m = 288000 \ kg[/tex]

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 [tex]A(t) = A_o e^{-\frac{bt}{2m} }[/tex]

Here b is the damping constant and the [tex]A_o[/tex] is the amplitude of the section when it was undriven

So from the question  

               [tex]\frac{A_o}{e} = A_o e^{-\frac{b6T}{2m} }[/tex]

=>            [tex]\frac{1}{e} =e^{-\frac{b6T}{2m} }[/tex]

=>          [tex]e^{-1} =e^{-\frac{b6T}{2m} }[/tex]

=>           [tex]-\frac{3T b}{m} = -1[/tex]

=>         [tex]b = \frac{m}{3T}[/tex]

Generally the amplitude of the section considered is mathematically represented as

           [tex]A = \frac{n * F }{ b * 2 \pi }[/tex]

=>       [tex]A = \frac{n * F }{ \frac{m}{3T} * 2 \pi }[/tex]

=>       [tex]n = A * \frac{m}{3} * \frac{2\pi}{25}[/tex]

=>       [tex]n = 0.075 * \frac{288000}{3} * \frac{2* 3.142 }{25}[/tex]

=>       [tex]n = 1810 \ people[/tex]

Answer:

[tex]\lambda =533.6 nm [/tex]

Explanation:

the slits spacing, d = 0.21 mm

distance of screen, D = 61 cm

The condition for minima is given as

[tex]dsin(\theta) = \left ( n+\frac{1}{2} \right )\lambda[/tex]

So, first minima, n = 0

[tex]dsin(\theta_1) = \frac{1}{2}\lambda[/tex]

fifth minima, n = 4

[tex]dsin(\theta_5) = \frac{9}{2}\lambda[/tex]

[tex]d(sin(\theta_5) -sin(\theta_1))= 4\lambda[/tex]

For small angle

[tex]d(tan(\theta_5) -tan(\theta_1))= 4\lambda[/tex]

From the figure:

[tex]d(\frac{y_5}{D}-\frac{y_1}{D})= 4\lambda[/tex]

[tex]\frac{d}{D} (y_5-y_1) = 4\lambda[/tex]

[tex]\lambda = \frac{d}{4D} (y_5-y_1)[/tex]

[tex]\lambda = \frac{0.021}{4(61)} (6.2 \times 10^{-3})[/tex]

[tex]\lambda =533.6 nm[/tex]

"533.5 nm" would be the wavelength of the light used in this experiment.

According to the question,

Slits spacing,

Distance of screen,

The condition for minima is given as:

→ [tex]d (sin \Theta) = (n+\frac{1}{2} ) \lambda[/tex]

So,

1st minima, n = 0

→ [tex]d sin(\Theta_1)= \frac{1}{2} \lambda[/tex]

5th minima, n = 4

→ [tex]d (sin (\Theta_5) - sin (\Theta_1) = 4 \lambda[/tex]

For small angle,

→ [tex]d (tan (\Theta_5) - tan (\Theta_1) = 4 \lambda[/tex]

From the figure, we get

→ [tex]d(\frac{y_5}{D} - \frac{y_1}{D} )= 4 \lambda[/tex]

  [tex]\frac{d}{D} (y_5 -y_1) = 4 \lambda[/tex]

                 [tex]\lambda = \frac{d}{4D}(y_5-y_1)[/tex]

                    [tex]= \frac{0.021}{4\times 61} (6.2\times 10^{-3})[/tex]

                    [tex]= 533.6 \ nm[/tex]

Thus the above answer is correct.  

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Answer:

Pressure = Force/Area

347 = 1300/Area

Area = 1300/347

area= 3.47m2

Answer:

I hope the above pic will help you

I will always help you understanding your assingments have a great day

#Captainpower

Answer:

The  correct option is D

Explanation:

From the question we are told that

  The intensity of the first  electromagnetic wave is  [tex]I = 18 \ W/m^2[/tex]

  The amplitude of the electric field is  [tex]E_{max}_1 =A[/tex]

   The intensity of the second electromagnetic wave is  [tex]I = 36 \ W/m^2[/tex]

Generally the an electromagnetic wave intensity is mathematically represented as

       [tex]I = \frac{1}{2} * \epsilon_o * c * E_{max}^2[/tex]

Looking at this equation we see that

     [tex]I \ \ \alpha \ \ E^2_{max}[/tex]

=>  [tex]\frac{I_1}{I_2} = [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2[/tex]

=>   [tex]E_{max}_2 = \sqrt{\frac{x}{y} } * E_{max}_1[/tex]

=>  [tex]E_{max}_2 = \sqrt{\frac{36}{18} } * E[/tex]        

=>  [tex]E_{max}_2 = \sqrt{2 } E[/tex]        

Explanation:

D. I hope i helped it should be right but if it isn't my bad

In the photoelectric effect, an electric current forms when light strikes a metal surface because electrons are knocked off the surface when light strikes it because the light acts as particles, The correct option is D.

It is the process of emission of electrons from the material because of absorption of electromagnetic radiation in form of photons of light waves.

The photoelectric effect explains the particle behavior of the light waves.

The photoelectric effect is responsible when electrons are knocked off the surface when light strikes it because the light acts as particles.

Learn more about the photoelectric effect

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Answer:

Nitrogen

Explanation:

Answer: mass remains the same

Explanation:

My teacher gave me the answer

As an astronaut travels from the surface of the earth to a position that is four times  as far away from the center of the earth, the astronaut's:

According to the given question, we can see that an astronaut is on a journey to a new location which is four times further from the center of the earth. We need to find out if there is a change to the mass of the astronaut.

As a result of this, we can see that the mass of the astronaut remains the same as he travels to a position which is four times further from the center of the earth, because the gravitational forces are the same.

Therefore, the correct answer is option B

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i think correct answer is b

Answer:

Explanation:

Answer:

The water cycle shows the continuous movement of water within the Earth and atmosphere. ... Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow. Water in different phases moves through the atmosphere (transportation).

Explanation:

It's the water cycle.

Answer and Explanation:

--> MRI (Magnetic Resonance Imaging) is an imaging technique that involves the use of radio waves and magnetic field to generate high detailed images of the human body. It's clinical applications includes:

• Bone and joint MRI:  these are done to check for bone and joint problems such as bone marrow disorders, arthritis, or bone tumours.

• A Spine MRI: This is used to investigate the spinal disc and innervations for disorders such as spinal tumours.

• Chest MRI: This is used to detect abnormalities of the heart, heart valves and coronary arteries.

--> X-RAY: These are electromagnetic waves of short wavelength with high penetrating power. They are produced when fast moving electrons strike a mass of heavy atoms such as those of metals. It's applications includes:

• They are used to detect hidden cracks in materials.

• They are used to show broken bones in human body.

• They are used in the study of internal structures of crystals.

• In agriculture, x-rays are used in killing germs.

--> ULTRASOUND: This makes use of high frequency sounds to detect abnormalities in the human body. An ultrasound machine transmits sound waves into the body which are reflected at the surfaces between the tissues of different density. It can also be used in different disciplines such as imaging, cleaning, mixing, navigation and communication   It's applications includes:

•. Detection of Cracks: when applied on metallic surface under investigation, high frequency sound wave reflects back which and be predicted and recorded.

--> INFRARED RADIATION: This is a type of electromagnetic radiation with wavelength longer than visible light. It is visible to the human eye and most heated surfaces transmits infrared radiation. It's applications includes:

• it is used for the purpose of sensing and detection. For example the night vision goggles and infrared cameras. Remote control makes use of infrared light waves to change channels in the television.