The complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows: 2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq)
It is important to write the complete ionic equation when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed. The reaction of lithium sulfide with copper (II) nitrate is a double displacement reaction. Lithium sulfide reacts with copper (II) nitrate to form copper sulfide and lithium nitrate.
The balanced chemical equation for the reaction is given as follows:Li2S(aq) + Cu(NO3)2(aq) → CuS(s) + 2 LiNO3(aq)The complete ionic equation can be written by representing all the ions in the aqueous solutions as dissociated ions.
Thus, the complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows:2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq.
)In the above equation, the lithium and nitrate ions do not take part in the reaction and are present in the same form in the reactant and product side. Hence, they are called spectator ions.
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Determine if the following statements are true and false. Type true or false in the space provided.Part ATo rinse the entire inner surface of the buret, one should add water from a wash bottle while rotating the buret.Part BRinsing the buret with water is always enough to clean the buret.Part CTo clean the inner surface of the buret, one should wash it with soapy water three times .Part DAfter rinsing with water and soapy water solution, one can add the titrating solution and begin the titration.Part EAlways rinse a buret with the titration solution three times before beginning a titration.
Part A: True.
Part B: False. Rinsing with water may not be enough to clean the buret completely.
Part C: False. Soapy water should not be used to clean a buret since it can leave residue.
Part D: False. After rinsing with water and soapy water solution, the buret should be rinsed with distilled water and dried before adding the titrating solution.
Part E: False. The buret should be rinsed with the titration solution only once before beginning a titration.
Titration is a laboratory procedure used to compare a solution's concentration to that of a reference solution with known concentration. It entails gradually mixing the standard solution into the sample solution up until the reaction is finished, which can be detected by a colour change or another quantifiable signal.
In many disciplines, including chemistry, medicine, and environmental research, titration is used. It can be used to quantify the quantity of a certain component in a sample, examine the concentration of acids and bases, and ascertain the purity of a substance.
Titration calls for exact volume and concentration measurements, as well as safe chemical handling and disposal. There are several different kinds of titration techniques, including complexometric, redox, and acid-base titration.
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In Part 4 of this experiment, you will construct an electrolytic cell in which copper metal is oxidized to produce Cu2+ ions in solution and H+ ions are removed from solution to produce hydrogen gas. Cu (s) → Cu2+ (aq) + 2 e E = -0.34 V 2 H+ (aq) + 2e → H2(g) E = 0.0 V a) Write the overall reaction and determine the corresponding cell potential. b) Is this reaction spontaneous? Explain why or why not. c) How can we get this reaction to occur? d) To maximize the current, why must the burette be placed about a half inch above the bottom of the beaker? e) What will you use to clean the copper electrodes? Why is it important to use clean copper electrodes in this experiment?
d) The burette must be placed about a half inch above the bottom of the beaker to maximize the current because this will allow enough space for the hydrogen gas produced to escape, allowing the reaction to continue.
How cell potential is determined positive or negative?Cell potential, or voltage, is determined by the difference in charge between the inside of a cell and the outside of a cell. Positively charged molecules in a cell, such as sodium and potassium ions, increase the positive charge inside the cell. Negative molecules, such as chloride ions, decrease the positive charge inside the cell, creating a negative potential.
Explanation.
a) Overall reaction: 2H⁺ (aq) + Cu (s) → Cu²⁺ (aq) + H₂ (g) Cell potential: -0.34 V
b) No, this reaction is not spontaneous because the cell potential is negative.
c) This reaction can be made to occur by providing an external source of electrical energy, such as a battery, to drive the reaction.
e) The copper electrodes should be cleaned with steel wool, sandpaper or a wire brush. It is important to use clean copper electrodes in this experiment to ensure that the reaction proceeds efficiently and that the copper is correctly oxidized to form copper ions in solution.
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Anyone do the 7th grade concept attainment quiz ? On stem scopes
Concept attainment quizzes are designed to assess students' understanding of a particular concept or idea.
These quizzes typically present a series of examples, some of which demonstrate the concept being assessed and others that do not. The student's task is to identify which examples are related to the concept and which are not. This type of quiz can be used to assess understanding of a range of topics, including math, science, social studies, and language arts.
To prepare for a concept attainment quiz, it is important for students to review the key characteristics or attributes of the concept being assessed. They should also familiarize themselves with examples that demonstrate the concept and be able to distinguish between examples that are related and those that are not. Practice quizzes or activities can be helpful in developing these skills.
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Will the following reaction result in a precipitate? If so, identify the precipitate.K3PO4 + Cr(NO3)+ 3 KNO3 + CrPO4A. No, a precipitate will not formB. Yes, CrPO4 will precipitateC. Yes, KNO3 will precipitate
Answer: B. Yes, CrPO4 will precipitate. In the given reaction: K3PO4 + Cr(NO3)3 → 3 KNO3 + CrPO4A precipitate is formed when two aqueous solutions are mixed that resulting in the formation of an insoluble compound.
The insoluble compound is called a precipitate. In the given reaction, K3PO4 and Cr(NO3)3 are the reactants. On mixing the two reactants, we can see that there are no common ions present in the reactants that could result in the formation of an insoluble compound. So, no precipitate is formed.
Based on solubility rules, CrPO4 is an insoluble compound. When K3PO4 reacts with Cr(NO3)3, it forms CrPO4. So, the precipitate that is formed is CrPO4. Hence, the correct option is B. Yes, CrPO4 will precipitate.
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Tripling the concentration of a reactant increases the rate of a reaction nine times. With this knowledge, answer the following questions: (a) What is the order of the reaction with respect to that reactant?
(b) Increasing the concentration of a reactant by a factor of four increases the rate of a reaction four times. What is the order of the reaction with respect to that reactant?
Answer:
a) Tripling the concentration of a reactant increases the rate of a reaction nine times.the order of the reaction with respect to that reactant is 2
b)Increasing the concentration of a reactant by a factor of four increases the rate of a reaction four times.the order of the reaction with respect to that reactant is 1.
Explanation:
a) The order of the reaction with respect to that reactant is 2. The rate law of the reaction with the stoichiometric coefficients a, b, and c would be as follows:
rate = k[A]^x[B]^y[C]^z
Where k is the rate constant and x, y, and z are the orders of the reaction with respect to the corresponding reactants. When [A] is tripled, the rate increases nine times, indicating that the rate is proportional to [A]^2. Therefore, the order of the reaction with respect to [A] is 2.
b) The order of the reaction with respect to that reactant is 1. The rate law of the reaction with the stoichiometric coefficients a, b, and c would be as follows:
rate = k[A]^x[B]^y[C]^z
When [A] is quadrupled, the rate increases four times, indicating that the rate is proportional to [A]. Therefore, the order of the reaction with respect to [A] is 1.
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what is the ph after 0.150 mol of hcl is added to the buffer from part a? assume no volume change on the addition of the acid.
The pH of the buffer from part an is 4.33 after 0.150 mol of HCl is added.The Henderson-Hasselbalch equation can be solved by substituting these values: pH = 10.73 + log(3.95) = 4.33.
The buffer has a pH of 4.58 and a buffer capacity of 0.038 M, as shown in part a. The weak base in the buffer (CH3NH2) interacts with 0.150 mol of HCl to create its conjugate acid (CH3NH3+), as shown by the equation: CH3NH2 + HCl CH3NH3+ + Cl-
The buffer is entirely depleted since the amount of HCl injected exceeds its capacity. The excess HCl content determines the pH of the resulting acidi= -log(0.150) -log(-log[H3O+] = 1.823
This number, however, does not account for the buffer's starting pH.
We must take into account both the contribution of the H3O+ ions and the CH3NH3+ ions in solution in order to get the final pH. The Henderson-Hasselbalch equation can be applied:
pH equals pKa plus log([A-]/[HA])
CH3NH2 has a pKa of 10.73. The amount of CH3NH2 transformed into CH3NH3+ and the amount of HCl added are equal at the equivalence point. Hence, 0.150/0.038 = 3.95 is the value for the [A-]/[HA] ratio.
The Henderson-Hasselbalch equation can be solved by substituting these values: pH = 10.73 + log(3.95) = 4.33.As a result, 4.33 is the final pH after adding 0.150 mol of HCl.c solution. H3O+ ions are created when the extra HCl combines with water.
The ultimate H3O+ concentration is 0.150 M since 0.150 mol of HCl were added to the buffer solution at 0.038 M. Thus, the following formula can be used to determine pH:
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write a balanced chemical equation that shows the formation of 3-methyl-2-butanol from the elements carbon (c), hydrogen (h2 ), and oxygen (o2 ).
Answer: The balanced chemical equation for the formation of 3-methyl-2-butanol is: 2C + 5H₂ + O₂ → C₅H₁₂O
Explanation: The balanced chemical equation for the formation of 3-methyl-2-butanol from the elements carbon (C), hydrogen (H₂), and oxygen (O₂) is given as follows:
2C + 5H₂ + O₂ → 3-methyl-2-butanol (C₅H₁₂O)
The above equation is balanced since the number of atoms of the elements present in the reactants is equal to the number of atoms of the elements present in the products.
Thus, the balanced chemical equation for the formation of 3-methyl-2-butanol from the elements carbon (C), hydrogen (H2), and oxygen (O2) is 2C + 5H₂ + O₂ → C₅H₁₂O
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Explain which ions cause the different colours of the solution Magnesium Chloride + Water
Answer:
Explanation:
Magnesium chloride is a compound composed of magnesium and chlorine ions. When it is dissolved in water, it dissociates into its constituent ions, which are surrounded by water molecules.
The color of the solution depends on the presence of any other ions that may be present. In the case of magnesium chloride, it is colorless in its pure form, and the color of the solution is determined by the presence of the chloride ions.
When the solution is dilute, it appears colorless. As the concentration of chloride ions increases, the color of the solution changes from light green to deep green, and finally to brownish-red. The intensity of the color is proportional to the concentration of chloride ions present.
The color change is due to the interaction between the chloride ions and the water molecules surrounding them, which absorb specific wavelengths of light. This absorption causes the solution to appear colored to the human eye. Therefore, the different colors observed in the solution of magnesium chloride and water are due to the presence of chloride ions and the concentration of these ions.
Answer:
Magnesium chloride dissolves in water to give a faintly acidic solution (pH = approximately 6).
The appearance of this reaction or solution is a bright white powder (in the picture)
The ion which makes this white powdery figure for magnesium chloride are salts that are highly soluble in water, for example: sodium ion (Na+).
To determine the amount in moles of aluminum that can be produced
from 13.0 mol of aluminum oxide, according to the following equation is : 2Al2O3(l) → 4Al(s) + 3O
Answer:
I hope it's helpful
Explanation:
2 mol of Al2O3 = 4 mol of Al
13 mol of Al2O3 =? (13/2)*4 = 26 mol
a mixture of helium, argon and krypton is made and stored in a cylinder at a total pressure of 2.80 atm. the partial pressure of helium is 900 torr, and that of argon is 250 torr. what is the partial pressure of krypton in the mixture?
The partial pressure of krypton in the mixture is 1.65 atm. This can be calculated using the ideal gas law. The ideal gas law states that the pressure of a gas (P) is equal to the number of moles (n) multiplied by the universal gas constant (R) multiplied by the temperature (T).
Using the given information, we can set up the equation:
2.80 atm = (x + 0.125 + 0.009) (0.0821) (273)Where x is the number of moles of krypton. Solving for x gives x = 0.073 moles of krypton. Finally, the partial pressure of krypton can be calculated by multiplying the number of moles of krypton (0.073) by the universal gas constant (0.0821) and temperature (273). This gives a partial pressure of krypton in the mixture of 1.65 atm.
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Codeine (C18H21NO3) is a narcotic pain reliever that forms a salt with HCI What is the pH of 0.036 M codeine hydrochloride? (pKb = 5.80)
pH = ____
The pKb value of codeine (C₁₈H₂₁NO₃) is 5.80. This drug is a narcotic pain reliever that forms a salt with HCI and its pH is around 8.00.
What would be the pH of a 0.036 M codeine hydrochloride solution?The following equation is used: pKa + pKb = pKw
where, pKa is the acid dissociation constant and pKw is the self-ionization constant of water. pKa can be calculated as follows:
pKa = pKb + pKw - pH
Since the drug is a weak base, Kb (base dissociation constant) can be calculated as follows: Kb = Kw/Ka
Kb = 1.00 × 10⁻¹⁴/2.3 × 10⁻⁶
Kb = 4.35 × 10⁻⁹
The following equation can now be used to find the value of pH:
pKb + pKa = pKw
pH = pKw - pKb - pKa
pH = 14.00 - 5.36 - (-9.36)
pH = 8.00
Therefore, the pH of 0.036 M codeine hydrochloride is 8.00.
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Classify the bonding in each molecule as ionic, polar covalent, or nonpolar covalent. Compound Bonding Br2 _______
MgF2 _______
H2S _______
MgO _______
F2 _______
HF _______
Ca3P2 _______
H2Se _______
Given the below table of compounds and the type of bonding present in each of them. Compounds Bonding Br2 nonpolar covalent, MgF2 ionic, H2S polar covalent, MgO ionic, F2 nonpolar covalent, HF polar covalent, Ca3P2 Ionic, H2Se polar covalent.
Ionic bonding is a type of chemical bond that occurs as a result of the attraction between oppositely charged ions. They are generally formed between metals and non-metals. They result in the formation of an ionic compound.
A polar covalent bond is a type of chemical bond in which electrons are shared unequally between two atoms. It generally occurs between two non-metals. It results in the formation of a polar molecule. A non-polar covalent bond is a type of chemical bond in which electrons are shared equally between two atoms. It generally occurs between two identical non-metals. It results in the formation of a non-polar molecule.
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9. Balance the following redox reactions:
a. Al3+ + K → Al + K+
b. Sn4+ + H₂ → Sn + H+
Redox reactions include the transfer of electrons between reactants. In order to balance a redox reaction, both the mass and the charge must be conserved.
How can the two reactions be balanced?This is done by identifying the species that are oxidized and reduced, and then adding electrons and adjusting coefficients as necessary to ensure that the number of electrons transferred is equal on both sides of the reaction.
In reaction (a), Al³⁺ is reduced to Al, which means it gains electrons. K is oxidized to K⁺, which means it loses electrons. To balance the reaction, we can add 3 electrons to the left side (to balance the reduction of Al³⁺) and adjust coefficients as follows:
Al³⁺ + 3K → Al + 3K⁺
Now, the number of electrons transferred is equal on both sides (3 on the left and 3 on the right), and the charge and mass are balanced.
In reaction (b), Sn⁴⁺ is reduced to Sn, which means it gains electrons. H₂ is oxidized to H⁺, which means it loses electrons. To balance the reaction, we can add 2 electrons to the left side (to balance the reduction of Sn⁴⁺) and adjust coefficients as follows:
Sn⁴⁺ + 2H₂ → Sn + 4H⁺
Now, the number of electrons transferred is equal on both sides (2 on the left and 2x2=4 on the right), and the charge and mass are balanced.
The final answer is:
a. 2Al³⁺ + 6K → 2Al + 6K⁺
b. Sn⁴⁺ + 2H⁺ + 2e⁻ → Sn²⁺ + H₂
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Thermochemistry Modified Portfolio Questions
Please help with these questions
1. Describe each part of the equation. (Look at the pdf/picture for the equation)
Heat gained or lost = Specific Heat x Mass x Change in Temperature
- Specific Heat:
- Mass:
- Change in Temperature:
2. Identify the following statements as either Heat, Thermal Energy, or Temperature
- __________ is the total heat found on the inside of a sample of matter.
- __________ is the flow of thermal energy from one loaction to another.
- __________ is the measure of average kinetic energy of the particles in a sample of matter, it is also a measure of the hotness or coldness of an object in simpler terms.
Thermal Energy is the total heat found on the inside of a sample of matter.
Heat is the flow of thermal energy from one location to another.
Temperature is the measure of average kinetic energy of the particles in a sample of matter.
What are the parts of the equation?The equation Heat gained or lost = Specific Heat x Mass x Change in Temperature is used to calculate the amount of heat gained or lost by a substance when its temperature changes.
Heat gained or lost: This is the energy that is either absorbed or released by a substance as it undergoes a temperature change. The unit of heat is joule (J) in SI units or calorie (cal) in other systems.
Specific Heat: This is a measure of the amount of heat energy required to raise the temperature of a given amount of a substance by one degree Celsius (or Kelvin). The unit of specific heat is J/g °C (or J/g K).
Mass: This refers to the amount of substance being heated or cooled, measured in grams (g).
Change in Temperature: This is the difference between the final and initial temperatures of the substance, measured in Celsius or Kelvin (°C or K).
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vinegar is a solution of acetic acid, hc2h3o2, dissolved in water. a 5.54-g sample of vinegar was neutralized by 30.10 ml of 0.100 m naoh. what is the percent by weight of acetic acid in the vinegar?
The percent by weight of acetic acid in the vinegar is 3.27% for the given 5.54-g sample of vinegar was neutralized by 30.10 ml of 0.100 m NaOH.
What is the percent of weight of acetic acid?Vinegar is a solution of acetic acid, HC₂H₃O₂, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH. Find the percentage of acetic acid by weight in vinegar. As per the question, vinegar is a solution of acetic acid, HC₂H₃O₂, dissolved in water.
A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH.
Since NaOH and HC₂H₃O₂ reacts in a 1:1 molar ratio, moles of NaOH used = moles of HC₂H₃O₂ in vinegar
So,0.100 mol/L solution of NaOH = 0.100 mol/L solution of HC₂H₃O₂ in vinegar (as they react in 1:1 ratio).
Also, Volume of NaOH = 30.10 mL = 30.10/1000 = 0.0301L
Thus, Amount of HC₂H₃O₂ in vinegar = 0.100 mol/L × 0.0301 L = 0.00301 mol.
Molar mass of HC₂H₃O₂ = 60.05 g/mol.
Weight of HC₂H₃O₂ in 5.54 g vinegar = 0.00301 mol × 60.05 g/mol = 0.18086 g.
Percentage by weight of acetic acid in the vinegar = 0.18086 / 5.54 × 100 = 3.27%.
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Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide. Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.
(a) Write a balanced equation for each step, including the state of each chemical.
(1)
(2)
(b) Write an overall balanced equation for the process, including the state of each chemical.
The answer of the following following questions are PbO(s) + PbS(s) → 2Pb(l) + SO2(g) and 2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g)
What is chemical reaction ?
A chemical reaction is a process in which one or more substances (reactants) are transformed into new substances (products) by the breaking and formation of chemical bonds. During a chemical reaction, the arrangement of atoms in the reactants is changed to form different molecules or compounds.
In a chemical reaction, the reactants are transformed into products through the rearrangement of atoms, but the total number of atoms remains the same. This is known as the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.
(a)
Step 1: Roasting of galena in oxygen gas:
PbS(s) + 3O2(g) → PbO(s) + 2SO2(g)
Step 2: Heating the metal oxide with more galena:
PbO(s) + PbS(s) → 2Pb(l) + SO2(g)
(b) Overall balanced equation for the process:
2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g)
Note: The state of the reactants and products has been indicated in the equations, with (s) representing a solid, (g) representing a gas, and (l) representing a liquid.
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Pls helppppp!!!! It’s important :(
Answer:
The new volume will be 1.61 L.
Explanation:
P₁V₁/P₂V₂
P₁=2.5atm
V₁=20L
P₂=31atm
V₂=?
20L(2.5atm)/31atm(V₂)
20*2.5/31(V₂)
V₂=1.61 L
You have 83.6 grams of H2 and 257 grams of N2 which combine to form ammonia
(NH3) according to the following equation:
N2 + 3H2
2NH3
1) Which reactant is the limiting reagent?
2) Explain how you can tell.
3) How much product is produced?
Image Text: You have 83.6 grams of H2 and 257 grams of N2 which combine to form ammonia (NH3) according to the following
N2 is the limiting reagent since it produces less NH3.
What is Limiting Reagent?
In a chemical reaction, the limiting reagent is the reactant that is completely consumed and limits the amount of product that can be formed. The amount of product formed is determined by the amount of limiting reagent available. The reactant that is not completely consumed is called the excess reagent, and some of it remains after the reaction is complete.
To determine which reactant is the limiting reagent, we need to calculate the number of moles of each reactant.
Moles of H2 = mass / molar mass = 83.6 g / 2.016 g/mol = 41.5 mol
Moles of N2 = mass / molar mass = 257 g / 28.02 g/mol = 9.17 mol
According to the balanced chemical equation, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Therefore, to react completely, 1 mole of N2 requires 3 moles of H2. Since we have more than enough H2 to react with the available N2, H2 is not the limiting reagent.
To calculate the moles of NH3 produced, we need to determine the limiting reagent.
Moles of NH3 produced if H2 is limiting reagent = 41.5 mol / 3 mol H2 per 2 mol NH3 = 27.67 mol NH3
Moles of NH3 produced if N2 is limiting reagent = 9.17 mol / 1 mol N2 per 2 mol NH3 = 4.58 mol NH3
Therefore, N2 is the limiting reagent since it produces less NH3.
We can tell that N2 is the limiting reagent because it produces less NH3 compared to the amount that would be produced if all of the H2 was used up in the reaction.
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19. which sample, when dissolved in 1.0 liter of water, produces a solution with the lowest boiling point?
The sample with the lowest boiling point when dissolved in 1.0 liter of water is sodium chloride (NaCl). Sodium chloride is a common salt compound which, when dissolved in water, lowers the boiling point of the solution.
To calculate the boiling point, use the following equation: Boiling Point = K b x m, where Kb is the ebullioscopic constant and m is the molality of the solution.
The ebullioscopic constant for sodium chloride is 0.51 K kg mol-1 and the molality is equal to the number of moles of solute divided by the volume of the solution. Therefore, for a 1.0 liter solution, the boiling point of the solution would be 0.51 K kg mol-1 x 0.78 moles/1.0 liter = 0.398 K kg mol-1.
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the distribution coefficient between methylene chloride and water for solute y is 12. an amount of 63.0 g of y is dissolved in 120 ml of water. a) what weight of y would be removed from water with a single extraction with 120-ml of methylene chloride? show calculations and report to 1 decimal place. copyright 2023. govindarajoo, g. rutgers, the state university of new jersey. all rights reserved. b) what weight of y would be removed from water (the original solution) with twosuccessive extractions with 60-ml portions each of methylene chloride? show calculations and report to 1 decimal place.
A)For a single extraction, the weight of y removed from water is calculated using the distribution coefficient (K) and the initial concentration of the solute in water (Cw). The equation used is:
Weight of y removed = K * Cw * Volume of Extract (VE)
Weight of y removed = 12 * 63.0g/120ml * 120ml
= 43.2 g
B) For two successive extractions, the weight of y removed from water is calculated using the same equation as above. The equation used is:
Weight of y removed = K * Cw * (VE1 + VE2)
Weight of y removed = 12 * 63.0g/120ml * (60ml + 60ml)
= 43.2 g
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Which can be excluded from the list of events caused by the flow of thermal energy inside the Earth? (1 point)
A. Volcanic eruptions
B. Earthquakes
C. Thunderstorms
D. Valley formations
Answer:
C. Thunderstorms
Explanation:
It is formed when three components: unstable weather conditions, uprising cold air, and enough moisture are present in the area. Based on the criteria for thunderstorms to form, it is not related to the flow of thermal energy inside the Earth.
a. Functional Group:
b. Longest Chain:
c. Branched Group Type and Location:
d. Full Name of Compound:
a. There is no functional group in 2-methylhexane as it is an alkane.
b. The longest chain in 2-methylhexane is a six-carbon chain.
c. The branched group is the methyl group (-CH3), which is attached to the second carbon atom of the longest chain.
d. The full name of the compound is 2-methylhexane.
What is functional group?A functional group is a specific group of atoms that give a molecule its characteristic chemical and physical properties and reactivity. Functional groups are responsible for the chemical behavior of a molecule and determine its chemical and physical properties, such as boiling point, melting point, solubility, acidity or basicity, and its chemical reactivity.
Functional groups are typically composed of a small number of atoms that are usually bound to a carbon atom or another element, such as nitrogen or oxygen. Some examples of common functional groups include hydroxyl (-OH), carbonyl (>C=O), amino (-NH2), carboxyl (-COOH), and phosphate (-PO4). The presence or absence of functional groups in a molecule plays a crucial role in determining its biological, chemical, and physical properties.
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A buffer is prepared by adding 23.0 g of sodium acetate ( CH3COONa) to 510 ml of a 0.155 M acetic acid ( CH3COOH) solution.A)Determine the ph of the buffer.B)Write the complete ionic equation for the reaction that occurs when a few drops of hydrochloric acid are added to the buffer.C)Write the complete ionic equation for the reaction that occurs when a few drops of sodium hydroxide solution are added to the buffer.
The pKa is 4.76 and the pH of the buffer is 4.98. Hydrochloric acid are added to the buffer will occur the complete ionic equation for this reaction is: CH3COOH + HCl -> CH3COCl + H2O.
The pH of the buffer can be determined by calculating the concentration of the acetic acid and sodium acetate in the solution. Using the Henderson-Hasselbalch equation, the pH of the buffer can be determined by: pH =[tex]pKa + log (\frac{CH3COONa}{CH3COOH} )[/tex]. With the given information, the pKa is 4.76 and the pH of the buffer is 4.98.
When a few drops of hydrochloric acid are added to the buffer, a neutralization reaction will occur. The complete ionic equation for this reaction is: CH3COOH + HCl -> CH3COCl + H2O.
When a few drops of sodium hydroxide are added to the buffer, a neutralization reaction will occur. The complete ionic equation for this reaction is: CH3COOH + NaOH -> CH3COONa + H2O.
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Step 2: Determine which of the carbocations formed is the major intermediate, First characterize each carbocation. H H carbocation A carbocation B Answer Bank secondary primary tertiary allylic dis the tion H u H ation B carbocation C carbocation D Answer Bank lylic tertiary allylic tertiary primary Draw the kinetic and thermodynamic addition products formed when one equivalent of HBr reacts with the diene shown. X carbocation A carbocation B Strategy Step 1: Draw the carbocations formed from addition of proton to each alene. Step 2: Classify the carbocations and determine the major intermediate Step 3: Draw the resonance structure for the major intermediate Step 4: Draw the 1.2 and 1,4 addition products. Step 5: Identify the kinetic and thermodynamic products, Answer Ba secondary secondary allylic The most stable carbocation is
The most stable carbocation is the tertiary carbocation, carbocation B.
Tertiary carbocations are the most stable type of carbocation due to having the most delocalization of charge, which reduces the energy of the system and makes it more stable.
This occurs due to having three alkyl groups on the carbon atom bearing the charge, allowing for the positive charge to be delocalized over three atoms,
thereby reducing the repulsive forces between the positively charged atoms.
Additionally, having three alkyl groups helps to increase the electron density around the carbon bearing the positive charge, further stabilizing the system.
The kinetic product of the reaction between one equivalent of HBr and the diene shown is an allylic carbocation, which is the intermediate formed during the reaction.
This is due to the reaction between the proton of the HBr and the double bond of the diene forming an allylic carbocation.
This allylic carbocation is relatively unstable compared to the tertiary carbocation, carbocation B, and thus is not the major intermediate.
The thermodynamic product of the reaction is a 1,4 addition product, which is the product that is most stable and therefore the thermodynamic product.
This 1,4 addition product is formed from the addition of the proton of the HBr and the lone pair of electrons of the double bond to the opposite sides of the double bond.
The most stable carbocation in this reaction is the tertiary carbocation, carbocation B, which is formed from the protonation of the double bond.
This is due to the delocalization of charge over three atoms and the increased electron density around the positively charged carbon.
The kinetic product is an allylic carbocation, while the thermodynamic product is a 1,4 addition product.
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When a scientist carefully examines any quantities repeatedly, they actually expect *
A. All measurements are just as accurate.
B. Only two measurements will be accurate.
C. All but one measurement will be the same
D. All measurements are almost but not the same
When a scientist carefully examines any quantities repeatedly, they actually expect that all but one measurement will be the same. The correct option is C.
Measurement error is the difference between the value obtained by the observer and the true value of the quantity being measured. When scientists take measurements, they try to reduce errors as much as possible so that they can have a more precise value. Measurement error is divided into two categories: systematic errors and random errors.
In any situation, scientists and researchers want to ensure that their measurements are as accurate as possible. As a result, when taking measurements, they will repeat the measurements multiple times to obtain the most precise data possible. In such a situation, a scientist will expect that all but one measurement will be the same. They will then take the average of the multiple measurements taken, which is more accurate than taking a single measurement. This technique reduces the likelihood of systematic errors, which can arise due to environmental factors, instrument errors, or personal errors.
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what information is needed to balance a chemical formula equation example periodic table or list of chemicals
To balance a chemical formula equation, you need to know the elements and their respective atomic mass. You can find this information on the periodic table.
To balance a chemical formula equation, you need the following information: periodic table or list of chemicals. A chemical formula is a symbolic representation of the elements present in a compound, as well as the proportion in which they are present. The subscripts indicate the relative number of atoms of each element in the compound's formula. The Periodic Table can also be useful in determining the atomic masses of the elements involved in the reaction. A balanced chemical equation is an essential tool for predicting the outcome of chemical reactions, calculating reaction stoichiometry, and calculating the amount of reactants needed to produce a given amount of product.
Therefore, you need to have a list of chemicals, formulas, and the number of atoms for each element in each reactant and product in order to balance a chemical equation.
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does the buffering system appear to be neutralizing all acidity associated with atmospheric carbon dioxide
The buffering system does not appear to neutralize all acidity associated with atmospheric carbon dioxide. Acid-base buffering is a physiological mechanism that maintains the pH of a solution within a certain range by resisting changes in the acidity or basicity of the solution.
It achieves this by utilizing a weak acid and its corresponding weak base, which can accept or donate H+ ions as required.
The buffering system reacts with the atmospheric carbon dioxide to form carbonic acid. The carbonic acid dissociates into hydrogen ions and bicarbonate ions, which are regulated by the lungs and kidneys. When the concentration of atmospheric carbon dioxide increases, it increases the concentration of hydrogen ions in the blood, reducing the pH of the blood.
As a result, the body increases ventilation to eliminate excess carbon dioxide, returning the pH to its normal range. The buffering system does not neutralize all of the atmospheric carbon dioxide acidity; instead, it helps to maintain the pH of the body within a certain range.
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how is burning gasoline in an automobile engine part of the carbon cycle?
Burning gasoline in an automobile engine is part of the carbon cycle as the gasoline contains carbon that is released into the atmosphere as carbon dioxide, which is then taken up by plants during photosynthesis.
When gasoline is burned in an automobile engine, the carbon in the gasoline is converted into carbon dioxide gas, which is released into the atmosphere. This carbon dioxide then becomes available to plants during photosynthesis, where it is used to create organic compounds such as sugars and starches. This process is a part of the carbon cycle, which is the natural process by which carbon is cycled through the Earth's atmosphere, oceans, and land. The carbon cycle is essential for life on Earth, as it allows carbon to be used and reused by living organisms in a sustainable way.
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before you can find the mass, what do you need to know? b. turn on show molar mass. what is the molar mass of carbon? c. what do you think the mass of 2.000 moles of carbon will be?
The molar mass of carbon is 12.0107 g/mol. Therefore, the mass of 2.000 moles of carbon is 24.0214 grams.
To calculate the mass of a substance, one must know the substance's quantity or amount (in moles) as well as its molar mass. The amount can be represented using the symbol n and is typically measured in moles (mol).The molar mass (M) is defined as the mass of one mole of a substance and is expressed in grams per mole (g/mol). The molar mass of carbon is 12.01 g/mol, so one mole of carbon weighs 12.01 grams.
To determine the mass of a certain number of moles of a substance, we can use the following formula:
mass = n x MM
where: mass = the mass of the substance (in grams)
n = the amount of the substance (in moles)
MM = the molar mass of the substance (in g/mol)
So, for carbon, if we have 2.000 moles of the element, the mass would be:
mass = 2.000 mol x 12.01 g/mol = 24.02 g
Therefore, the mass of 2.000 moles of carbon would be 24.02 g.
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HELP ASAP with a culminating project !!!
Introduction:
Many adults do not understand why some materials attract while other materials do not. We will be learning about the different kinds of elements that exist in the world that help us to create materials that we currently have to produce the clothes we wear, the phones we use, the games we play, and more. To help educate adults we will be making a board game to help people understand the properties of different elements and how we can use those properties to predict their interactions.
Challenge: You have been hired by a local Toy Store to design and create a fun and interactive game to educate young adults and children about the physical properties of elements and compounds. You will design a proposal for an interactive game to help players understand the properties of elements and apply their knowledge to show how elements interact to form compounds.
You will make a strategic guide for successfully playing their group's game and explain why the strategies are successful
Project Criteria for Success:
Decide what type of game you want to create. Consider creating your game using the same rules as a well known game (such as Monopoly, Wheel of Fortune, Jeopardy, Candyland, Shoots and Ladders, Apples to Apples, Cards against Humanity, etc).
•Create a blueprint of your game, Explain how it will be designed. Make sure your game is school appropriate
• Your game must include:
At least 8 different elements/atoms on the periodic table
Each element represents a game piece or part of a card or category (ie Wheel of Fortune/Jeopardy)
Information about the properties of the elements/atoms;
Be sure to consider the family of each element you have selected
• Show that elements combine with other elements/atoms (bond) to make compounds (form chemical reactions)
Individual Project Criteria for Success
Your strategic guide should
| Explain Your Game
What is the name of your game?
What is the maximum number of players?
How is your game played and what are the rules?
•How does someone win?
Explain patterns of elements in the Periodic Table and describe how this knowledge will help someone successful win your game
Select an element from your game and make a model (drawing with labels) to identify the different subatomic particles and their location in and around the atom.
Explain the patterns of protons across the periodic table and within families.
Explain the patterns of the number of valence elections (outer shell of atom) across the periodic table and within families.
Using your knowledge of the periodic table and elements from your game, construct an explanation to describe the patterns (trends) across a period (row) and within a family (group). Your explanation should include patterns for
radius (size)
electronegativity
reactions with water (alkali metals)
• Select elements from your game and explain how to use valence electrons to predict the formation of an ionic
compound.
• Explain how you can predict which elements can bond to form a covalent compound.
Calculate the difference in electronegativity of the two elements selected.
Game Proposal: Element Explorers
Name of Game: Element Explorers
Maximum Number of Players: 4-6 players
How to Play: Each player selects a game piece that represents one of the eight elements from the periodic table in the game. Players move around the board, answering questions related to the properties of elements and their reactions. The questions can be multiple-choice, true/false or short-answer format. Players earn points for correct answers and can use them to buy property or "compounds" on the board. The goal of the game is to collect as many compounds as possible and have the most points at the end. The winner is the player with the most points.
Element Properties: Each element in the game will be associated with its chemical symbol, family, atomic number, atomic mass, and properties such as melting point, boiling point, density, and reactivity. The families of elements represented in the game will include alkali metals, alkaline earth metals, halogens, and noble gases.
Patterns in the Periodic Table: Understanding the patterns in the periodic table is key to being successful in Element Explorers. For example, the number of valence electrons in an atom can be predicted based on the family it belongs to, which affects how it will react with other elements. The electronegativity of an element can also be predicted based on its location on the periodic table, which indicates how easily it can attract electrons and form bonds.
Subatomic Particles: Let's take one of the elements from the game, hydrogen (H), as an example. Hydrogen has one proton and one electron in its neutral state, and its atomic mass is approximately 1.0079 atomic mass units (amu). A simple drawing of a hydrogen atom would include a nucleus containing one proton and possibly one or two neutrons, with one electron in the outer shell.
Patterns in Protons and Valence Electrons: Across a period in the periodic table, the number of protons in the nucleus increases, which affects the size of the atom and its reactivity. Within a family, the number of valence electrons is the same, which affects the element's reactivity and the types of compounds it can form.
Ionic and Covalent Compounds: Valence electrons are crucial in determining whether an ionic or covalent bond will form between two elements. In an ionic bond, one element donates electrons to another element that accepts them, forming a positively charged cation and negatively charged anion. In a covalent bond, two atoms share electrons, forming a molecule. The difference in electronegativity between two elements can be used to predict whether they will form an ionic or covalent bond.
Calculating Electronegativity Difference: Let's take an example of two elements from the game, sodium (Na) and chlorine (Cl), which form an ionic compound (NaCl). Sodium has an electronegativity of 0.93, while chlorine has an electronegativity of 3.16. The difference in electronegativity is 2.23 (3.16-0.93), indicating a highly polar bond between the two elements.
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