Answers
Answer: the answer is x= -11.
Related Questions
Dannette and Alphonso work for a computer repair company. They must include the time it takes to complete each repair in their repair log book. The dot plots show the number of hours each of their last 12 repairs took. Part a. Calculate the median, mean, IQR, and standard deviation of each data set. Part b. Which measure of central tendency and spread should you use to compare the two data sets? Explain your reasoning. Part c. Determine whether there are any outliers in either data set. Dannette's Repair Times х х X X X X Х Х + 9 + 1 0 Relations 2 3 4 8 10 12 5 6 7 Repair Time (hours) Geometry Alphonso's Repair Times Groups X Trigonometry X Х X X X х X х Statistics 7 X + 3 10 9 0 4 12 Series 8 1 2 5 7 Repair Time (hours) Greek
PLZ HELP
Answers
Answer:
(a):
Dannette Alphonso
[tex]\bar x_D = 4.33[/tex] [tex]\bar x_A = 5.17[/tex]
[tex]M_D = 2.5[/tex] [tex]M_A = 5[/tex]
[tex]\sigma_D = 3.350[/tex] [tex]\sigma_A = 1.951[/tex]
[tex]IQR_D = 7[/tex] [tex]IQR_A = 1.5[/tex]
(b):
Measure of center: Median
Measure of spread: Interquartile range
(c):
There are no outliers in Dannette's dataset
There are outliers in Alphonso's dataset
Step-by-step explanation:
Given
See attachment for the appropriate data presentation
Solving (a): Mean, Median, Standard deviation and IQR of each
From the attached plots, we have:
IQR_A = 1.5 ---- Dannette
[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso
n = 12 --- number of dataset
Mean
The mean is calculated
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]
[tex]\bar x_D = \frac{52}{12}[/tex]
[tex]\bar x_D = 4.33[/tex] --- Dannette
[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]
[tex]\bar x_A = \frac{62}{12}[/tex]
[tex]\bar x_A = 5.17[/tex] --- Alphonso
Median
The median is calculated as:
[tex]M = \frac{n + 1}{2}th[/tex]
[tex]M = \frac{12 + 1}{2}th[/tex]
[tex]M = \frac{13}{2}th[/tex]
[tex]M = 6.5th[/tex]
This implies that the median is the mean of the 6th and the 7th item.
So, we have:
[tex]M_D = \frac{2+3}{2}[/tex]
[tex]M_D = \frac{5}{2}[/tex]
[tex]M_D = 2.5[/tex] ---- Dannette
[tex]M_A = \frac{5+5}{2}[/tex]
[tex]M_A = \frac{10}{2}[/tex]
[tex]M_A = 5[/tex] ---- Alphonso
Standard Deviation
This is calculated as:
[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]
So, we have:
[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]
[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]
[tex]\sigma_D = 3.350[/tex] ---- Dannette
[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]
[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]
[tex]\sigma_A = 1.951[/tex] --- Alphonso
The Interquartile Range (IQR)
This is calculated as:
[tex]IQR =Q_3 - Q_1[/tex]
Where
[tex]Q_3 \to[/tex] Upper Quartile and [tex]Q_1 \to[/tex] Lower Quartile
[tex]Q_3[/tex] is calculated as:
[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]
[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]
[tex]Q_3 = \frac{3}{4}*13th[/tex]
[tex]Q_3 = 9.75th[/tex]
This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:
[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex] [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]
[tex]Q_3 = 8[/tex] ---- Dannette [tex]Q_3 = 5.5[/tex] --- Alphonso
[tex]Q_1[/tex] is calculated as:
[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]
[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]
[tex]Q_1 = \frac{1}{4}*13th[/tex]
[tex]Q_1 = 3.25th[/tex]
This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:
[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex] [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]
[tex]Q_1 = 1[/tex] --- Dannette [tex]Q_1 = 4[/tex] ---- Alphonso
So, the IQR is:
[tex]IQR = Q_3 - Q_1[/tex]
[tex]IQR_D = 8 - 1[/tex] [tex]IQR_A = 5.5 - 4[/tex]
[tex]IQR_D = 7[/tex] --- Dannette [tex]IQR_A = 1.5[/tex] --- Alphonso
Solving (b): The measures to compare
Measure of center
By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).
Since, the above is the case; we simply compare the median of both because it is not affected by outliers
Measure of spread
Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.
Solving (c): Check for outlier
To check for outlier, we make use of the following formulas:
[tex]Lower =Q_1 - 1.5 * IQR[/tex]
[tex]Upper =Q_3 + 1.5 * IQR[/tex]
For Dannette:
[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]
[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]
Since, the dataset are all positive, we change the lower outlier to 0.
So, the valid data range are:
[tex]Valid = 0 \to 18.5[/tex]
From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset
For Alphonso:
[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]
[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]
So, the valid data range are:
[tex]Valid = 1.75\to 7.75[/tex]
From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset
Use the formula v = IR for current flowing through a resistor, where V is the voltage in volts, I is current in amps, and R is resistance in ohms. Find the current through a resistor with resistance 15 ohms if the voltage across it is 3 volts.
Answers
Answer:
0.2 amps
Step-by-step explanation:
Given data
The formula V=IR is the formula for ohms law
Which state that the voltage is directly proportional to the current and the resistance in an electric circuit
Now
R= 15 ohms
V= 3volts
V= IR
3= I*15
I= 3/15
I= 0.2 amps
Hence he current flowing is 0.2 amps
If the exponential model f(x)=3(2)x is written with the base e, it will take the form A0ekx. What is A0 and what is k?
Answers
Answer:
Answer in pic
Step-by-step explanation:
The required value of A₀ = 3 and k = ln 2, as of the given exponential model.
What is an exponential function?The function which is in format f(x) =a^x where a is constant and x is variable, the domain of this exponential function lies (-∞, ∞).
here,
Since.
[tex]a^x = e^{xlna}[/tex]
According to the question,
[tex]3(2)^x = A_oe^{kx}\\3e^{xln2} = A_oe^{kx}[/tex]
Now
Compare the values,
A₀ = 3 and k = ln 2,
Thus, According to the stated exponential model, A0 = 3 and k = ln 2.
Learn more about exponential function here:
brainly.com/question/15352175
#SPJ2
FIND THE ∛ OF 188
(USE √
Answers
9514 1404 393
Answer:
∛188 ≈ 5.72865
Step-by-step explanation:
Any scientific or graphing calculator or spreadsheet can tell you the cube root of 188.
∛188 ≈ 5.72865431598...
__
You know that 5³ = 125 and 6³ = 216, so the root will lie between 5 and 6, closer to 6. As a first approximation, you can figure it is about ...
x = ∛188 ≈ 5 + (188-5³)/(6³ -5³) = 5 + 63/89 ≈ 5.71
You can figure this much using a 4-function calculator.
A closer approximation (x') can be had using the iteration formula ...
x' = (2x³ +188)/(3x²)
For x = 5.71, the value of x' is ...
x' ≈ (2×5.71³ +188)/(3×5.71²) ≈ 560.3388/97.8123 ≈ 5.7287
This value is correct when the root is rounded to 4 decimal places. Another execution of the iteration formula using this value will give the root accurate to 9 decimal places.
Solve the inequality c+12<16
Answers
Answer:
c+12<16
c=16-12
c=4
answer is this
holaaaaaaaaaaaa plz help me i need it quick △SEA is rotated 270 degrees about the origin. Draw the image of this rotation.
Answers
Answer:
A will have this new coordinate (2, 1).
S will have this new coordinate (-2, 7).
E will have this new coordinate (2, 7).
Step-by-step explanation:
A is the coordinate (-1, 2).
S is the coordinate (-7, -2).
E is the coordinate (-7, 2).
To rotate that figure 270 grades (is the same to rotate 90 grades) we need to convert those coordinates to this (y, -x).
So,
A will have this new coordinate (2, 1).
S will have this new coordinate (-2, 7).
E will have this new coordinate (2, 7).
There are some Rs2 and Rs5 coins in a box. The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3. The value of all the Rs5 coins is Rs45. What is the value of all the Rs2 coins in the box?
Answers
Given:
The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3.
The value of all the Rs5 coins is Rs45.
To find:
The value of all the Rs2 coins in the box.
Solution:
Let x be the number of Rs2 coins and y be the number of Rs5 coins.
The value of all the Rs5 coins is Rs45.
[tex]5y=45[/tex]
[tex]y=\dfrac{45}{5}[/tex]
[tex]y=9[/tex]
The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3.
[tex]\dfrac{x}{y}=\dfrac{1}{3}[/tex]
[tex]\dfrac{x}{9}=\dfrac{1}{3}[/tex]
Multiply both sides by 9.
[tex]\dfrac{x}{9}\times 9=\dfrac{1}{3}\times 9[/tex]
[tex]x=3[/tex]
The value of all the Rs2 coins in the box is:
[tex]\text{Required value}=2x[/tex]
[tex]\text{Required value}=2(3)[/tex]
[tex]\text{Required value}=6[/tex]
Therefore, the value of all the Rs. 2 coins in the box is Rs. 6.
The solution set for -18 < 5x - 3 is _____.
3 > x
3 < x
-3 < x
-3 > x
Answers
Answer:
[tex]-3 < x[/tex]
Step-by-step explanation:
Given
[tex]-18 < 5x-3[/tex]
Required
The solution
[tex]-18 < 5x-3[/tex]
Add 3 to both sides
[tex]3-18 < 5x-3+3[/tex]
[tex]-15 < 5x[/tex]
Divide both sides by 5
[tex]-3 < x[/tex]
2hr 57min+3hrs42min
Answers
Answer:
6 hrs 33 minutes
Step-by-step explanation:
2hr 57min
+3hrs42min
----------------------
5 hrs 99 minutes
But 1 hr = 60 minutes so subtract 60 minutes and add 1 hour
6 hrs 33 minutes
Answer:
6hr 39 min
Step-by-step explanation:
Add both
2hr 57 min
+ 3hr 42 min
5hr 99 min
we know that 1 hr = 60 min
then , 99 min = 1hr 39 min
so, 5hr + 1hr 39min
= 6hr 39 min
what are T-ratio ? explain
answer my question
plz
Answers
Answer:
The t-ratio is the estimate divided by the standard error. With a large enough sample, t-ratios greater than 1.96 (in absolute value) suggest that your coefficient is statistically significantly different from 0 at the 95% confidence level. A threshold of 1.645 is used for 90% confidence.
Step-by-step explanation:
Hope it help you.
What is the radius for the circle given by the equation x^2+(y-1)^2=12?
Round your answer to the nearest thousandth.
Answers
9514 1404 393
Answer:
3.464
Step-by-step explanation:
Comparing the given equation to the standard form equation of a circle:
(x -h)^2 +(y -k)^2 = r^2
we find the center to be (h, k) = (0, 1) and the radius to be √12 = 2√3.
The problem statement tells us to round the radius to the nearest thousandth, so it will be ...
2√3 ≈ 3.4641016 ≈ 3.464 . . . radius of the circle
What is tan 30? A b c d e f
Answers
Answer:
try all the square roots and wichever gets to 0.58(rounded) is your answer
Step-by-step explanation:
GIVING OUR BRAINLIEST HELP ME PLEASE !! 10 PTS!
Answers
Answer:
The solution is D. x² + y² + 4x - 2y = -1
Step-by-step explanation:
The standard form of a circle with a center at (h,k) and a radius r is:
(x-h)² + (y-k)² = r²
Since the center is (-2,1) and the radius is
2, we know that:
h = -2k = 1r = 2Thus, the equation of the circle is:
(x-(-2))² + (y-1)² = 2²
This simplifies to be
(x+2)² + (y-1)² = 4
The equation of the circle is:
(x+2)² + (y-1)² = 4
x²+4x+4+y²-2y+1 = 4
x²+y²+4x-2y+5 = 4
x²+y²+4x-2y = 4-5
x²+y²+4x-2y = -1
3. Betty rode her bike down a block that was 50 meters long. How many millimeters did she ride?
Answers
Answer:
50,000 millimeters
Step-by-step explanation:
Hope this helps : ) I have no explanation but it's correct
rule for 15,19,23 please I need it urgently
Answers
Answer:
[tex]a_{n}[/tex] = 4n + 11
Step-by-step explanation:
There is a common difference between consecutive terms, that is
19 - 15 = 23 - 19 = 4
This indicates the sequence is arithmetic with explicit rule
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 15 and d = 4 , then
[tex]a_{n}[/tex] = 15 + 4(n - 1) = 15 + 4n - 4 = 4n + 11
find the area of the following figures:
Answers
Answer:
Area = 156 square cm
Step-by-step explanation:
17. A loan of $8000 was paid back in 2
years in monthly payments of $400.
The interest on the loan as a
percentage, was
A. 5%
B. 8-%
C. 162 %
16
D. 20%
Answers
Answer:
D. 20%
Step-by-step explanation:
2 years = 24 months
400 × 24 = 9600
9600 - 8000 = 1600
1600/8000 = 1/5
1/5 = 20%
Write the following equation in the general form Ax + By + C = 0.
y - x - 1 = 0
2x - 3y + 6 = 0
2x - 3y - 6 = 0
-2x + 3y - 6 = 0
Answers
2*-3y-6
Step-by-step explanation:
Find the value for the side marked below.
Round your answer to the nearest tenth.
13
23°
у
у
[?]
Enter
Answers
Answer:
y = 30.96
Step-by-step explanation:
take 23 degree as reference angle
using tan rule
tan 23 = opposite / adjacent
0.42 = 13/y
y = 13/0.42
y = 30.96
Solve this for me guys
Answers
Answer:
x = 7.348
Step-by-step explanation:
I don't really know how to explain this over a computer, but it is correct. Answer credit of Omnicalculator.
Hope that this helps!
Last month Rudy’s Tacos sold 22 dinner specials. The next month they released a new commercial and sold 250% of last month’s dinners. How many dinner specials did they sell this month?
Answers
Answer:
the answer is 2
Step-by-step explanation: because 250 -22 is i dont even know
Answer:
55
Step-by-step explanation:
Question 10 (1 point) Find the volume of the figure. 2.5 ft 3 ft 2 ft 6 ft. What is the volume of the figure?
Answers
Answer:
I don’t know what type of figure you are talking about. But if there is supposed to be a picture attached, we see nothing
Step-by-step explanation:
You could repost this question though, I’ll be glad to help on that other question!
If a1 = 6 and an
-5an-1 + 4 then find the value of a4.
Answers
9514 1404 393
Answer:
a4 = -666
Step-by-step explanation:
Use the recursive definition repeatedly.
a1 = 6
a2 = -5(6) +4 = -26
a3 = -5(-26) +4 = 134
a4 = -5(134) +4 = -666
HELP PLEASE MATH PROBLEM
Answers
Answer:
x=41
Step-by-step explanation:
LM =JM
154=4x-10
154+10=4x
164=4x
164/4=4x/4
41=x
hope this is helpful
The endpoints of a diameter are (-3,4) and (5,-2). What is the center of the circle?
Answers
Hope this helps!!
Juan y rosa van a repartirse un pastel por partes iguales sin que sobre nada .Si de la fiesta sobró 3/4pastel .¿cuanto le tocó a cada uno?
Answers
Usando el método de polya:
a. Que se pregunta?
la fracción de cuánto obtendría cada uno de ellos y compartiría por igual.b. ¿Cuáles son los datos dados?
¾ tarta, 2 personas (Juan y Rosa)c. ¿Cuál es la operación que se utilizará?
divisiónd. oración numérica:
¾ ÷ 2e. Solución y respuesta completa:
[tex] \frac{3}{4} \div 2 \\ = \frac{3}{4} \times \frac{1}{2} \\ = \frac{3}{8} [/tex]
explicación paso a paso:
Multiplica por el recíproco: Dividir es equivalente a multiplicar por el recíproco.Multiplicar: multiplica las fraccionesForma decimal: 0.375
☆彡Hanna#CarryOnLearning
A positive real number is 4 less than another. if the sum of the squares of the two numbers is 72, then find the numbers
Answers
Answer:
x+4=72
x=72-4
x=68
Step-by-step explanation:
let x be one number and 4 be anothe number then sum of the two number be x and 4
Triangle ABC is the pre-image and triangle DFE is the image.
What is the scale factor of the dilation?
Please helppp!!!!!
Answers
Answer:
Scale factor = ½
Step-by-step explanation:
The original image is the preimage = ∆ACB
The new image is the image = ∆DFE
The scale of factor of dilation = image/preimage = DF/AC
DF = 6 cm (given)
AC = 12 cm (given)
Plug in the values into the equation to find the scale factor of dilation:
Scale factor = 6/12
Scale factor = ½
what of the following functions is graphed below
being timed help quickly will mark brainliest !!!
Answers
An engineering consulting firm wanted to evaluate the diameter of rivet heads. The following data represent the diameters (in hundredths of an inch) for a random sample of 25 rivet heads:
(20 pts) 6.81 6.79 6.69 6.59 6.65 6.60 6.74 6.70 6.76 6.84 6.81 6.71 6.66 6.76 6.76 6.77 6.72 6.68 6.71 6.79 6.72 6.72 6.72 6.79 6.83
a. Set up a 95% confidence interval estimate of the average diameter of rivet heads (in hundredths of an inch)
b. Set up a 95% CI estimate of the standard deviation of the diameter rivet heads (in hundredths of an inch)
Answers
Answer:
a)CI 95 % = ( 6.7063 ; 6.7593) ( in hundredths of an inch)
b) CI 95 % = ( 0.05 < σ < 0.089 ) ( in hundredths of an inch)
Step-by-step explanation:
From the problem statement, we have a manufacturing process and we we assume a normal distribution, from sample data:
x = 6.7328 and s = 0.0644
a) CI 95 % = ( x ± t(c) * s/√n )
t(c) df = n -1 df = 25 - 1 df = 24
CI = 95 % α = 5 % α = 0.05 α /2 = 0.025
Then from t-student table t(c) = 2.060
s/√n = 0.0644/ √ 25 s/√n = 0.01288
CI 95 % = ( x ± t(c) * s/√n ) = ( 6.7328 ± 2.060*0.01288)
CI 95 % = ( 6.7328 ± 0.02653 )
CI 95 % = ( 6.7063 ; 6.7593) ( in hundredths of an inch)
b) CI 95 % of the variance is:
CI 95 % = ( ( n - 1 ) * s² / χ²₁ - α/₂ ≤ σ² ≤ ( n - 1 )*s² / χ²α/₂ )
( n - 1 ) * s² = ( 25 - 1 ) * (0.0644)² = 24* 0.00414
( n - 1 ) * s² = 0.09936
And from χ² table we look for values of
χ² α/₂ ,df df = 24 and α/2 = 0.025
χ² (0.025,24) = 12.40 and χ²₁ - α/₂ = χ² (0.975, 24)
χ² (0.975, 24) = 39.36
Then
CI 95 % = ( 0.09936 / 39.36 ≤ σ² ≤ 0.09936 / 12.40)
CI 95 % = ( 0.0025 ≤ σ² ≤ 0.0080)
Then for the standard deviation, we take the square root of that interval
CI 95 % = ( 0.05 < σ < 0.089 )