HELP WILL GIVE BRAINLIEST OF CORRECT

Answer:

1-As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

2-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

3-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks.

4-Rain shadow deserts are formed because tall mountain ranges prevent moisture-rich clouds from reaching areas on the lee, or protected side, of the range.

5-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

Explanation:

#6 and 5 are the same

Answer:

the central nervous system

Answer: C. central

Explanation:

Explanation:

Fnet = 12.0N - 5.0N = 7.0N

a = Fnet/m = 7.0N/6.5kg = 1.07m/s².

Answer:

I =  1.27×105 kg⋅m2

Explanation:

Explanation:

When the Javelin is at rest on the ground, Potential Energy and Kinetic Energy are zero.  immediately the Athlete picks the javelin up from the ground, there is an increase in the Kinetic Energy this increase continues until the javelin comes to a halt. Potential Energy also increases.

As the Athlete throws javelin, there is a decrease in the Potential Energy, the Kinetic Energy increases simultaneously until the javelin hits the ground.

after which Potential Energy  and Kinetic Energy becomes zero.

Answer:

27.95[kW*min]

Explanation:

We must remember that the power can be determined by the product of the current by the voltage.

[tex]P=V*I[/tex]

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

[tex]P=110*8.47\\P=931.7[W][/tex]

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

[tex]Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min][/tex]

Answer:

The value is [tex]\theta _2 = 0.08 \ arcsec[/tex]

Explanation:

From the question we are told that

   The first wavelength is  [tex]\lambda_1 = 660 \ nm = 660 *10^{-9 }[/tex]

   The  first angular size is  [tex]\theta_1 = 0.04 \ arcsec[/tex]

    The second wavelength is  [tex]\lambda _2 = 1320 \ nm = 1320 *10^{-9 } \ m[/tex]

Generally according to  Rayleigh Criterion we have that

          [tex]\theta= 1.22 * \frac{\lambda }{D}[/tex]

given every other thing remains constant we have that

         [tex]\theta = k * \lambda[/tex]

Here k  represented constant so

         [tex]k = \frac{\theta }{\lambda}[/tex]

=>      [tex]\frac{\theta_1}{ \lambda_1} = \frac{\theta_2}{ \lambda_2}[/tex]

=>      [tex]\frac{\theta_1}{ \theta_2} = \frac{\lambda_1}{ \lambda_2}[/tex]

So

        [tex]\frac{ 0.04}{ \theta_2} =0.5[/tex]

=>     [tex]\theta _2 = 0.08 \ arcsec[/tex]

Answer:

I am going to answer you just wait a little bit.

Answer:

1. t = 5.89 s

2. h = 170 m

3. Vf = 57.8 m/s

Explanation:

1.

First, we analyze the horizontal motion of the golf ball. Assuming the air friction to be negligible, the horizontal motion will be uniform. So, e can use the following equation:

[tex]s = vt[/tex]

where,

s = horizontal distance covered by the golf ball = 471 m

v = horizontal speed of golf ball = 80 m/s

t = time taken by the golf ball in air = ?

Therefore,

[tex]471\ m = (80\ m/s)t\\\\t = \frac{471\ m}{80\ m/s}\\\\[/tex]

t = 5.89 s

2.

Now, we analyze the vertical motion. Using 2nd equation of motion:

[tex]h = v_{i}t + \frac{1}{2}gt^2[/tex]

where,

h = height of cliff = ?

vi = vertical component of initial speed of ball = 0 m/s(ball was shot horizontally)

g = acceleration due to gravity = 9.81 m/s²

t = time of flight = 5.89 s

Therefore,

[tex]h = (0\ m/s)(5.89\ s) + \frac{1}{2}(9.81\ m/s^2)(5.89\ s)^2[/tex]

h = 170 m

3.

Now, we can use 1st equation of motion:

[tex]v_{f} = v_{i} + gt\\v_{f} = 0 m/s + (9.81\ m/s^2)(5.89\ s)\\[/tex]

Vf = 57.8 m/s

Answer:

a. Weight of Object in Water = 20 N

b. Up thrust = 20 N

c. Weight of Water Displaced = 20 N

Explanation:

a.

The weight of the object remains same in the water as well. Because, the same force of gravity is acting there as well. Hence,

Weight of Object in Water = 20 N

b.

Since, the object floats on the water. Therefore, according to Archimedes' principle the up thrust force acting on the object must be equal to the weight of object:

Up thrust = Weight of object

Up thrust = 20 N

c.

From Archimedes' Principle, we know that the up thrust or the Buoyant force is equal to the weight of the water displaced by the object. therefore:

Weight of Water Displaced = Up thrust

Weight of Water Displaced = 20 N

Answer:

The frequency stays the same and the wavelength decreases.

Explanation:

When sound wave enters a new medium where sound travels faster, its frequency will remain same because it depends only on the source.

The relation between wavelength and speed is inverse, it means when the speed of sound increases, its wavelength will decrease.

So, the frequency stays the same and the wavelength decreases. Hence, the correct option is (d).

Speed =distance/time

Speed=300/5=60 km/h

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Answer:

F = 385.56 N

Explanation:

Given that,

Mass, m = 37.8 kg

He applies a horizontal force and cross the wooden floor.

We need to find the force that must be applied to move a dog with a constant speed of 1 m/s.

The coefficient of kinetic friction between the dog in the floor is 1.02.

The net force acting on it is given by :

F = f- μmg

f is force due to constant speed, f = 0 (since, a = 0)

F = μmg

= 1.02 × 37.8 × 10

= 385.56 N

Hence, the required force is 385.56 N.

Answer:

0.462kg

Explanation:

Density = Mass/Volume

Given

Density of the wood = 0.390 g/cm^3

Volume of the wood = Length * Width * Height

Volume = 21 * 9.53 * 5.92

Volume = 1,184.7696cm³

Get the mass m;

mass = density * volume

mass = 0.390 * 1,184.7696

mass = 462.060144g

The mass in kg is 0.462kg

Answer:

see below

Explanation:

alluminium is,

1.lustrous

2.highly malleable

3.reactive metal

4.some times acts as non metal

5.good conductor

6.obtained from bauxite

7.Atomic number 13 so electrons and protons are 13

8.neurons are 14

9.ductile

10.melting point is very high approximately 660 degree celsius.

Answer:

It has low density, is non-toxic, has a high thermal conductivity, has excellent corrosion resistance and can be easily cast, machined and formed.

Explanation:

Answer:

Explanation:

1400 m/s2

The acceleration of the ball when it hits the vertical wall is -1,400 m/s²

The given expression:

velocity of the ball, v = 28 m/s

time of  motion of the ball, t = 0.02 s

To find:

The acceleration of the ball is calculated as follows:

[tex]acceleration = \frac{\Delta velocity}{\Delta time} = \frac{Final \ velocity\ - \ initial \ velocity }{time} \\\\final \ velocity \ of \ the \ ball \ when \ it \ hits \ the \ wall = 0\\\\acceleration = \frac{0 - 28}{0.02} \\\\acceleration = - \ 1,400 \ m/s^2[/tex]

Thus, the acceleration of the ball when it hits the vertical wall is -1,400 m/s²

Learn more here: https://brainly.com/question/14109204

Answer:

One bulb could go out and the strand will stay on.

Explanation:

In series circuit, there is only one path provided for the current to flow. So, all the lights are required to be in working condition, for the others to work. And if anyone light bulb goes out, the circuit will become incomplete and the rest of the strand will also go out. Because there is only one path for current flow which is now broken.

On the other hand, in parallel circuits, each light bulb has a separate connection with the source. Current path to each bulb is independent of the others. Therefore, if one bulb goes out, the rest of the strand will stay on.

So, the correct option is:

One bulb could go out and the strand will stay on.

Answer:

f = 0 N

Explanation:

It is given that,

A horse pulls a wagon with 2000N of at constant velocity.

We need to find the friction acting on the wagon.

As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.

Hence, the correct option is (a).

Answer: the intensity of the light that passes through the set of polarizers is  0.7285 S₀

Explanation:

based on the data in the question;

As the first polarizer lets all the light through because its plane of polarization is not different from light.

The second polarizer has 2 effects;

firstly, it reduces the intensity by a factor cos²0.3927^c; if you switch the calculator to radians mode, this will give you 0.85355

Secondly; it changes the plane of polarization of the light to be the same as the polarizer; therefore the light now has a plane of polarization of 0.3927 rad to the horizontal.

Hence;

after the second effect, the light enters the third polarizer at 0.3927 rad to the plane of polarization of third polarizer. So the intensity is again reduced by a factor 0.85355.

Therefore

the Overall reduction is by a factor of 0.85355 × 0.85355 S₀

= 0.7285 S₀

Therefore the intensity of the light that passes through the set of polarizers is  0.7285 S₀

Answer:

2.35 seconds

Explanation:

Remark

This is a question where direction matters.  Let us call down + and up minus. It won't matter. The answer will be the same.

Formula

a = (vf - vi)/t

Givens

a = 9.8 m/s^2

vi = - 15 m/s

vf = 8m/s

Solution

9.8 = (8 - - 15)/t                 Multiply both sides by t

t * 9.8 = 23                       Divide by 9.8

t = 23/9.8

t = 2.35 s

Answer:

18.58 mm

Explanation:

Formula for the fringe width is;

β = λL/d

We are given;

λ = 568 nm = 568 × 10^(-9) m

L = 3.5 m

d = 0.107 mm = 0.107 × 10^(-3) mm

β = (568 × 10^(-9) × 3.5)/(0.107 × 10^(-3))

β = 0.01858 m = 18.58 mm

Answer:

A

Explanation:

OKAY REAL QUICK A NOTE REPRESENTS THE 12 TONES ON THE CHROMATIC SCALE WHICH IN TURN REPRESENTS THE WHOLE OF SOUND IN ALL MUSIC- EACH NOTE HAS A PITCH THAT REPEATS IN EVERY OCTAVE.

Answer:

The force between the charged spheres is 1,223.75 N

The force is attractive because opposite charges mutually attract.

Explanation:

Coulomb's Law

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Expressing the above as a formula:

[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]

Where:

[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]

q1, q2 = the objects' charge

d= The distance between the objects

The copper spheres have charges of:

[tex]q_1=+2.2\cdot 10^{-4}\ c[/tex]

[tex]q_2=-8.9\cdot 10^{-4}\ c[/tex]

Note the charges have opposite signs.

They are separated by d=1.2 m

Applying Coulomb's formula:

[tex]\displaystyle F=9\cdot 10^9\frac{2.2\cdot 10^{-4}\cdot 8.9\cdot 10^{-4}}{1.2^2}[/tex]

[tex]\displaystyle F=9\cdot 10^9\frac{1.958\cdot 10^{-7}}{1.44}[/tex]

F = 1,223.75 N

The force between the charged spheres is 1,223.75 N

The force is attractive because opposite charges mutually attract.

Answer:

B. Distance

Explanation:

When calculating speed, the value of the given distance is first entered on the calculator because it is in the numerator.

Speed is the rate of change of distance with time;

       Speed  = [tex]\frac{distance}{time}[/tex]  

The value of the distance is inputted first before that of the time is entered.

This way the division sign evaluates for the speed.

An object that absorbs all radiation falling on it, at all wavelengths, is called a black body. When a black body is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. Its emission is called black-body radiation

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Answer:

a collision occuring between two objects in an isolated system, the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.

thank you.

Answer:

10

Explanation:

Given that :

Initial Velocity (u) = 25 m/s

Range can be obtained using the relation :

Range = (u² * sin2θ) / g

g = 10m/s ; θ = 45

Range = [10² * sin2(45)] / 10

Range = [100 * 1] ÷ 10

Range = 10

Answer:

a) The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].

b) The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].

Explanation:

a) The hoop yo-yo can be modelled as a tours with a minor radius [tex]a[/tex], related with the thickness, and with a major radius [tex]b[/tex], related with the diameter, and with an uniform mass. The momentum of inertia about its center of mass ([tex]I_{g}[/tex]), measured in kilogram-square meters, which is located at the geometrical center of the element, is determined by the following formula:

[tex]I_{g} = \frac{1}{4}\cdot m \cdot (4\cdot b^{2}+3\cdot a^{2})[/tex] (1)

[tex]b = 0.5\cdot D[/tex] (2)

[tex]a = 0.5\cdot t[/tex] (3)

Where:

[tex]D[/tex] - Diameter, measured in meters.

[tex]t[/tex] - Thickness, measured in meters.

[tex]m[/tex] - Mass, measured in kilograms.

If we know that [tex]m = 0.332\,kg[/tex], [tex]D = 0.359\,m[/tex] and [tex]t = 9.5\times 10^{-3}\,m[/tex], then the moment of inertia of the hoop yo-yo is:

[tex]a = 0.5\cdot (9.5\times 10^{-3}\,m)[/tex]

[tex]a = 4.75\times 10^{-3}\,m[/tex]

[tex]b = 0.5\cdot (0.359\,m)[/tex]

[tex]b = 0.180\,m[/tex]

[tex]I_{g} = \frac{1}{4}\cdot (0.332\,kg)\cdot [4\cdot (0.180\,m)^{2}+3\cdot (4.75\times 10^{-3}\,m)^{2}][/tex]

[tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex]

The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].

b) The hoop yo-yo rotate at a point located at a distance of half diameter from the center of mass of the element, whose moment of inertia is determined by the Theorem of Parallel Axes:

[tex]I_{O} = I_{g} +m\cdot r^{2}[/tex] (4)

Where:

[tex]r[/tex] - Distance between parallel axes, measured in meters.

If we know that [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex], [tex]m = 0.332\,kg[/tex] and [tex]r = 0.180\,m[/tex], then the moment of inertial of the hoop yo-yo rotating about the point where the tension force is applied is:

[tex]I_{O} = 0.0108\,kg\cdot m^{2}+(0.332\,kg)\cdot (0.180\,m)^{2}[/tex]

[tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex]

The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].

Answer:

I think C 250 it is correct