Hi! Please help me!

Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a
resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total
resistance in the
circuit, t, with this equation, in which r represents the resistance of the second lightbulb.
t =
1207
+ 120
Find the inverse of Janine's equation.

Look at photo below

Thank you have a nice day:)

Hi! Please Help Me! Lightbulbs Act As Resistors. Janine Is Building A Circuit That Contains Two Lightbulbs

Answers

Answer 1

Answer:

The answer is t^-1 (r)=120r/120-r

i hope this is right sry if im wrong have a good day :)

Answer 2

The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

What is resistance?

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).

According to the question

Janine is building a circuit that contains two lightbulbs in parallel.

One of the lightbulbs has a resistance of 120 ohms.

R = 120ohms

r = resistance of the second lightbulb

t = total resistance in the circuit  

[tex]t = \frac{120r}{r+120}[/tex]

Now,

The inverse of Janine's equation in which we will make r independent

[tex]t = \frac{120r}{r+120}[/tex]

[tex]t(r+120) = 120r[/tex]

[tex]tr + 120t = 120r[/tex]

[tex]120t = 120r - tr[/tex]

[tex]120t = r(120-t)[/tex]

[tex]r = \frac{120t}{120-t}[/tex]

Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

To know more about  resistance here:

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[tex] \huge{꧁\: \large \frak{ \huge question } \: \huge꧂}[/tex]


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Answers

Answer:

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Answer:

Parentheses

Exponents

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Division

Addition

Subtraction

Step-by-step explanation:

5/5 =1

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(Have a Great Day)

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Answers

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Answer:

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Answers

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Answers

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Answer:

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Answers

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Answers

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Answers

Answer:

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