g A 24-gg bullet strikes and becomes embedded in a 1.50-kgkg block of wood placed on a horizontal surface just in front of the gun. Part A If the coefficient of kinetic friction between the block and the surface is 0.23, and the impact drives the block a distance of 9.5 mm before it comes to rest, what was the muzzle speed of the bullet
The muzzle speed of the bullet before the collision is 415.3 m/s.
The given parameters:
Mass of the bullet, m₁ = 24 gMass of the wood, m₂ = 1.5 kgCoefficient of kinetic friction, μk = 0.23Distance traveled by the block before stopping, d = 9.5 mApply the principle of work-energy theorem to determine the final velocity of the block-bullet system;
[tex]F_f \times d = \frac{1}{2} mv^2\\\\\mu_k F_n \times d = \frac{1}{2} mv^2\\\\\mu_ k (m_1 + m_2)g \times d = \frac{1}{2} (m_1 + m_2)v^2\\\\\mu_k g \times d= \frac{1}{2} v^2\\\\2\mu _k gd = v^2\\\\v= \sqrt{2\mu _k gd } \\\\v = \sqrt{2 \times 0.23 \times 9.8 \times 9.5} \\\\v = 6.54 \ m/s[/tex]
Apply the principle of conservation of linear momentum to determine the muzzle speed of the bullet;
[tex]m_1 u_1 \ + \ m_2u_2 = v(m_1 + m_2)\\\\0.024(u_1) \ + \ 1.5(0) = 6.54(0.024 + 1.5)\\\\0.024u_1 = 9.967\\\\u_1 = \frac{9.967}{0.024} \\\\u_1 = 415.3 \ m/s[/tex]
Thus, the muzzle speed of the bullet before the collision is 415.3 m/s.
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If 90J of energy are available for every 30C of charge, what is the potential difference?
Enter your answer as a number
V
Answer:
3 v
Explanation:
A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from
the base of the cliff does it land?
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
[tex]\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}[/tex]
There is NO initial vertical velocity, so:
[tex]\large\boxed{\Delta d= \frac{1}{2}at^2}}[/tex]
Rearrange to solve for time:
[tex]2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}[/tex]
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
[tex]t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s[/tex]
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
[tex]\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}[/tex]
Select the correct answer. Chloe is playing the flute some distance away from a crowd. If the atmospheric temperature is 15°C, what is the speed of the sound traveling from the flute? A. 340 meters/second B. 330 meters/second C. 320 meters/second D. 310 meters/second E. 300 meters/second
Answer:
A. 340 meters/second
I think this is the right answer.
What is the significance of Isaac's name?
Answer:
ghgivjgifigo ra together aigig disgust u hoodie
Identify the types of motion a) The movement of a snail on the ground b) The strings of the guitar c) The whirling of stone tied with a thread
Answer:
1. friction, gravity,
Explanation:
Please answer the question in the picture
How many valence electrons do most stable atoms have?
A) one
B) two
C) four
D) eight
Answer:
D) 8
Explanation:
Due to the octet rule the most stable atoms will have 8 valence electrons.
How much work is done on a 30 kg object when 20 Newton’s of force is exerted for a distance of 5 meters
Answer:
Work = force * displacement
= 50 N * 20 Meter
=1000 Newton meter = 1000 joule .
Explanation:
Using the figure shown, if I₃= 1.17 A, then (I₁ , I₂) A is:
a- (3.17 , 2.00)
b- (1.33 , 0.17)
c- (1.67 , 0.50)
d- (1.27 , 0.10)
The value of the current in each arm of the circuit is given by Kirchhoff's
Rules.
The correct option for (I₁, I₂) is; b-. [tex]\underline{(1.33, \ 0.17)}[/tex]Reasons:
By Kirchhoff's junction rule, we have that the sum of current at a junction is given as follows;
[tex]\displaystyle \mathbf{ \sum \limits_{k = 1}^ n I_K} = 0[/tex]Which by the direction of the currents in the given circuit diagram, we have;
I₁ - (I₃ + I₂) = 0Therefore;
I₁ = I₃ + I₂
According to Kirchhoff's loop rule theory, we have;
[tex]\displaystyle \mathbf{\sum \limits_{k = 1}^ n V_K} = 0[/tex]In the loop having the 2 Volts emf., we have;
-I₃·R₁ + 2 + I₂·R₂ = 0
I₃ = 1.17 A
R₁ = 2 Ω
R₂ = 2 Ω
Which gives;
-1.17 × 2 + 2 + I₂×2 = 0
I₂ × 2 = 2.34 - 2 = 0.34
I₂ = 0.34 ÷ 2 = 0.17
I₂ = 0.17 A
From the loop having the 7 Volts emf. we have;
7 - 0.17×2 - I₁ × 4 - I₁ × 1 = 0
Which gives;
7 - 0.34 - 5·I₁ = 0
5·I₁ = 7 - 0.34 = 6.66
I₁ = 6.66 ÷ 5 = 1.332
Therefore;
[tex]\underline{\mathbf{(I_1, \, I_2)} = (1.33, \, 0.17)}[/tex]Learn more about electric circuits here:
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A physics professor leaves her house and walk along the sidewalk toward campus. After 5 min it starts to rain and she returns home. Her distance from her house as a function of time shown in figure: 1. At which of the labelled point is her velocity (a) zero? (b) Constant and positive? (c) constant and negative ? (d) Increasing in magnitude? (e) Decreasing in magnitude?
Answer: I think its zero-
I dont really know about this...
Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answer:
25%
Explanation:
1. The acceleration equation of a certain particle is a=2t, after 4s, its velocity reaches 20m/s, then the initial velocity of the particle movement is ) ms B Sms 2.
Answer:
Change in velocity is the integral of all the differential accelerations acting over the period of acceleration.
[tex]20 = u + \int\limits^4_0 {2t} \, dt[/tex]
20 = u + t²[tex]\left \{ {{4} \atop {0}} \right.[/tex]
20 = u + 4² - 0²
20 = u + 16
u = 4 m/s
Who did the ram caught in the thicket (Genesis 22:13) represent?
Answer:
I'm no Bible person, but I think it stands for i-dont-give-a-donkey-poop.
and suck-dog-nuts.
an electron moves in a circular path in a region os space filled with a uniform magnetic field B= 0.4 T. to double the radius of the electron’s path, the magnitude of the magnetic field must become:
a. 0.8 T
b. 0.2 T
c. 0.1 T
d. 0.3 T
e. zero
Answer:
[tex]0.2\; {\rm T}[/tex], assuming that the speed of the electron stays the same.
Explanation:
Let [tex]v[/tex] denote the speed of this electron. Let [tex]q[/tex] denote the electric charge on this electron. Let [tex]m[/tex] denote the mass of this electron.
Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.
Let [tex]B[/tex] denote the strength of this magnetic field. The size of the magnetic force on this electron would be:
[tex]F = q\, v\, B[/tex].
Assuming that there is no other force on this electron. The net force on this electron would be [tex]F = q\, v\, B[/tex]. By Newton's Second Law of motion, the acceleration of this electron would be:
[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{q\, v\, B}{m}\end{aligned}[/tex].
On the other hand, since this electron is in a circular motion with a constant speed:
[tex]\begin{aligned} a = \frac{v^{2}}{r} \end{aligned}[/tex].
Combine the two equations to obtain a relationship between [tex]r[/tex] (radius of the path of the electron) and [tex]B[/tex] (strength of the magnetic field:)
[tex]\begin{aligned}\frac{q\, v\, B}{m} = \frac{v^{2}}{r}\end{aligned}[/tex].
Simplify to obtain:
[tex]\begin{aligned}r &= \frac{m\, v^{2}}{q\, v\, B} \\ &= \frac{m\, v}{q\, B} \\ &= \left(\frac{m\, v}{q}\right)\, \frac{1}{B}\end{aligned}[/tex].
In other words, if the speed [tex]v[/tex] of this electron stays the same, the radius [tex]r[/tex] of the path of this electron would be inversely proportional to the strength [tex]B[/tex] of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to [tex]0.2\; {\rm T}[/tex].)
A book is at rest on a flat table. The book is pushed across the table, causing it to move
and eventually come to rest again. How does the potential and kinetic energy change
during this process? (1 point)
The potential and kinetic energy will stay the same unless the book speeds
up or slows down
The potential energy increases as the book is pushed across the table.
The kinetic energy stays the same.
The potential energy will stay the same as long as the book stays on the
table. The kinetic energy increases as the book is pushed across the table.
The potential and kinetic energy decreases as the book comes to rest
again
Answer:
Explanation:
As no altitude or mass changed, the potential energy remained constant.
The potential energy will stay the same as long as the book stays on the
table.
Kinetic energy went from zero at rest to a positive value while moving, and then returned to zero when the book was at rest again.
The kinetic energy increases as the book is pushed across the table.
Identify the types of motion:-
the movement of the snail on the ground
the strings of the guitar
the whirling of stone tied with a thread
Answer:
the movement of snail on the ground is in random motion.
the strings of the guitar is in oscillatory motion.
the whirling of stone tied with a thread is in circular motion.
Lisa runs up 4 flights of stairs in 22 seconds. She weighs 510 Newtons. If each flight rises 310 cm: (a) What is her change in potential energy? (b) What average power (watts) was required during the 22 s?
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
Potential energy is the amount of energy possessed by a body due to its position relative to another object.
a) Potential energy = weight * height = 510 N * 4 flight * 3.1 m per flight
Potential energy = 6324 Joules
b) Power = Energy / time = 6324 Joules / 22 seconds = 263.5 Watts
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
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If the speed of the magnet is doubled, the induced voltage is ________ . twice as great four times as great half as great unchanged
If the speed of the magnet is doubled, the induced voltage is twice as great
Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:
ε=Blv
Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.
The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.
If the speed of the magnet is doubled, the induced voltage is twice as great
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1. A 10 kg rocket blast off the ground with an applied force of 150 N, calculate the net force
of your rocket
The net force on the rocket at the given applied force is 52 N.
The given parameters:
Mass of the rocket, m = 10 kgApplied force, F = 150 NThe net force on the rocket is calculated by applying Newton's second law of motion as follows;
F(net) = F(up) - F(down)
F(net) = 150 - mg
F(net) = 150 - (10 x 9.8)
F(net) = 150 - 98
F(net) = 52 N
Thus, the net force on the rocket at the given applied force is 52 N.
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Use words in the box to complete the diagram, and the definitions below it. Some words will be used
more than once and some words may not be used at all
Hertz
period
metros
dip
seconds
peak
wavelength trough
crest
frequency
amplitudo
oscillation equilibrium line
- the top of a wave
the bottom of a wave
the level if the wave flattened out
a repeated action back and forth or up and down
the number of waves that pass every second (measured in
the time it takes for one complete wave to pass (measured in
Answer:
There ya go
Explanation:
The correct words to fill the given blanks would be as follows:
- Peak
- Trough
- Equilibrium Line
- Oscillation
- Frequency, Hertz
- Period, seconds
The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave. The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.Oscillation is defined as the process in which an object moves in the "back and forth motion."Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.Amplitude is the breadth or magnitude of the waves.Learn more about "Oscillation" here:
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An electrician reads a resistance of 65 ohms and when energize the circuit runs 1.77 amps. what voltage to the system run on?
Answer:
115.05 Volts
Explanation:
We can use Ohm's Law!
V=IR
V= 1.77 * 65
V=115.05 Volts
True or False. Father of a multitude" obeyed God's command to kill His son because the Ten Commandments had not yet been given.
Answer:
Explanation:
The father of the Multitude was Abraham. And he did precede the 10 commandments. But the story really has nothing to do with the 10 commandments.
He obeyed God's Command because it was God who issued it. Abraham had complete faith in God's ability to make things come out right. The sacrifice of Isaac was a test of faith.
I would advise you to answer true, but whoever wrote the question employed a twisted kind of logic. The sacrifice of Isaac had nothing to do with the 10 commandments. Thou Shalt not murder is not really covered by this circumstance.
So true might not be the correct answer. The question is very complex and does not lend itself to a simple True/ False answer.
A 4.0 ohm resistor has a current of 3.0 A for 5.0 min. How many electrons pass through the resistor during this time interval?
a. 7.5 x 10^21
b. 3.8 x 10^21
c. 8.4 x 10^21
d. 2.1 x 10^21
e. 5.6 x 10^21
Answer:
e. 5.6 x 10^21 electrons.
Explanation:
In order to calculate the charge Q passing through the resistor for in a definite amount of time is
[tex]Q \ (\mathrm{coulombs}) \ = \ I \ (\mathrm{amperes}) \ \times \ t \ (\mathrm{seconds}) \\ \\ \-\hspace{2.22cm} = \ 3.0 \ \mathrm{A} \ \times \ 5.0 \ \mathrm{min} \ \times \ \displaystyle\frac{60 \ \mathrm{sec}}{1 \ \mathrm{min}} \\ \\ \-\hspace{2.22cm} = \ 900 \ \mathrm{C}[/tex]
Thus, using the law of quantization of electric charge, the number of electrons passing through the resistor during this time interval can be calculated.
[tex]Q \ = \ n \times e \\ \\ n \-\hspace{0.18cm} = \ \displaystyle\frac{Q}{e} \\ \\ n \-\hspace{0.18cm} = \displaystyle\frac{900 \ \mathrm{C}}{1.6 \times 10^{-19} \ \mathrm{C}} \\ \\ n \-\hspace{0.18cm} = 5.6 \times 10^{21} \ \ \mathrm{electrons}[/tex], where n denotes the number of electrons and e is the unit charge of an electron ([tex]1.6 \times 10^{-19} \ \mathrm{C}[/tex]).
I need help with parts a and B of this question
Answer:
Explanation:
Let x be the leaf spring compression distance
F = kx
5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x - 0.500)
5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x) - 1.90 x 10⁵
7.10 x 10⁵ = (9.25 x 10⁵)x
x = 0.76756...
x = 0.768 m
W = ½(5.45 x 10⁵)0.768² + ½(3.80 x 10⁵)(0.768 - 0.500)²
W = 174,148.648648...
W = 174 KJ
A model shows a machine that works using electric fields. What would this machine need for the electrical field to function properly
4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead
Answer:
c. index fossil
Explanation:
Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.
2. What is the oxidation number of oxygen in most compounds?
A. 6
B.-2
C. 8
D.O
Answer:i am pro
kExplanation:
What capacitance is needed to store 3μC of charge at a voltage of 120V?
Answer:
C = 0.025F
Explanation:
Charge =q=3×[tex]10^{-6}[/tex]C
Voltage=V=120V
Q=CV
C=Q/V
=3×[tex]10^{-6}[/tex]/120
=1/40×[tex]10^{-6}[/tex]
C = 0.025F
C=2.5 [tex]10^{-4}[/tex]C 0r 25 ×[tex]10^{-3}[/tex]F
Which of the following is damaging electromagnetic radiation?
a. Gamma Ray c. Ultraviolet
b. Visible Light d. X-rays
Explanation:
Which of the following electromagnetic waves is used in medicine to destroy cancer cells?
A. IR rays
B. Visible rays
C. Gamma rays
D. Ultraviolet rays
Answer
VerifiedVerified
105.9k+ views
Hint: Electromagnetic rays that have a high frequency and highest-energy photons such that their energy is enough to penetrate several centimetres of lead is used to destroy cancer cells.
Complete step by step answer:
Electromagnetic waves with wavelengths shorter than about 100-trillionths of a meter are called gamma rays. They are used in a technique called radiation therapy to kill diseased cells in the human body. A beam of gamma rays can damage the biological molecules in living cells, causing both healthy and diseased cells to die. By carefully controlling the amount of gamma ray radiation and focusing it on the diseased area, the damage to healthy cells can be reduced during treatment.
So, the correct answer is “Option C”.
Additional Information: A. Infrared rays are used to form images of objects. Remote control and CD-drives also used infrared waves.
B. Visible light is the light that we can detect with our eyes. The spectrum of visible light shows all colours of light from long wavelength red to short wavelength violet.
D. Ultraviolet rays provide vitamin D for the body. They are also used to disinfect food, water and medical supplies. If Ultraviolet rays enter a cell, they can damage the DNA.
Note: Apart from Gamma rays, X-rays are also used in radiation therapy to kill diseased cells in the human body. X-rays are also used to form images of bones and teeth and in airport screening devices to examine contents of luggage.
hope this passage helps I don't know Its correct answer ..... its from my school PDF
Answer:
Gamma rays
Explanation:
NOTE: The higher the frequency of the radiation, the more damage it is likely to cause to the body: infrared radiation is felt as heat and causes skin to burn.
If correct please give brainliest
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