Answer:
3 hours 71 minutes
Explanation:
As because Speed= distance/time taken
so time taken= 3.71
If you run North for 5 meters and then East for 15 meters and then
South for 2 meters all in 22 seconds. What was your speed?
0 points
Answer:
1m/s
Explanation:
D = 22m
T = 22s
S = 22÷22
= 1 m/s
If you launch an object in space, it
will continue to move forward
until an external force stops it.
This is a characteristic of which
law?
Answer:
I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.
Relative density of mercury is 13600 what does it mean
Answer:
relative density is the density divided by some reference density.
for liquids like mercury the reference density is most likely water, so
relative density = density mercury / density of water = 13600
A ball is thrown up into the air. Ignore air resistance. When it is rising and reaches half of its maximum height,the net force acting on it is
Answer:
The net and only force acting on the ball thrown up into the air at half of its maximum height is the weight of the ball
Explanation:
When the ball is rising in the air, the force, F, acting on it is given by the product of the mass, m × acceleration, a
The acceleration of a body thrown in the air = Gravitational acceleration = g = Constant
Therefore;
The force acting on the body thrown in the air F = Constant = m × g (downwards)
The force acting on the ball thrown up into the air at half of its maximum height = The mass of the ball × The acceleration due to gravity = The weight of the ball.
What type of reaction in the diagram?
B.Fission,because the reaction absorbed energy
C.Fusion,because the reaction formed heavier nuclei
D.Fission,because the reaction formed lighter nuclei
Answer:
b, i think
Explanation:
What is the distance moved by a horse galloping at 75 km/h in 10.0 s?
750 m
208 m
125 m
7.5 m
125Answer:
Explanation:uruhavdfh
How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?
Answer:
43.2J
Explanation:
Q = m × c × ∆T
Where:
Q = amount of energy
m = mass (grams)
c = specific heat capacity
∆T = change in temperature
Mass = 5.0g
Specific heat capacity of Silver (Ag) = 0.240 J/g°C
We need to convert the temperature from Kelvin (K) to °C
Initial temperature = 298 - 273 = 25°C
Final temperature = 334 - 273 = 61°C
Q = 5 × 0.240 × (61°C - 25°C)
Q = 1.2 × 36
Q = 43.2J
What is 2 + 2 i have been stuff on this for weeks
Answer:
4..... the answer is 4
Explanation:
A resistance of a wire has a value or (r) Ohms. The wire is stretched to double its length, then, its resistance in Ohms is:
A 57.0 kg person in a
rollercoaster moving through
the bottom of a curved track of radius
42.7 m feels a normal force of 995 N.
How fast is the car moving?
Answer:
The linear speed of the car is approximately 27.30 m/s
Explanation:
The question parameters are;
The mass of the person on the rollercoaster, m = 57.0 kg
The radius of the rollercoaster track, r = 42.7 m
The normal force felt by the person, F = 995 N
The centripetal force acting on the person keep the circular motion is given by the following equation;
[tex]Centripetal \, force \ F_c = \dfrac{m \times v^2}{r}[/tex]
Where;
v = The linear velocity of motion = The linear speed of the car
The centrifugal force, F, is the force normal force felt by the person and is equal to the centripetal force, therefore, we have;
[tex]Centripetal \, force \ F_c = Centrifugal \, force \ F = \dfrac{m \times v^2}{r}[/tex]
From which we have;
[tex]F = 995 = \dfrac{57 \times v^2}{42.7}[/tex]
[tex]\therefore v = \sqrt{\dfrac{995 \times 42.7}{57} } \approx 745.38[/tex]
The linear speed of the car = v ≈ 27.30 m/s
The angular speed of the car, ω = v/r ≈ 27.30/42.7 ≈ 0.639 rad/s
Answer: 18.1 m/s
Explanation:
A spiral spring of natural length 20.00cm has a scale
pan hanging on its lower end while the other end is
fixed firmly to a support.When an object of mass 50g
is placed in the pan, the length of the spring becomes
22.00 cm.When another object of mass 70g is placed in
The pan, the length becomes 22.25cm Calculate the
mass of the scale pan. (g = 10m/s]
The mass of the scale pan : 0.11 kg
Further explanationGiven
A spiral spring's length = 20 cm
mass 50 g ⇒ the length = 22 cm
mass 70 g ⇒ the length = 22.25 cm
Required
the mass of the scale pan
Solution
Hooke's Law :
[tex]\tt F=k.\Delta x[/tex]
The spring constant (k) :
[tex]\tt k=\dfrac{\Delta F}{\Delta x}=\dfrac{g.(70-50)}{22.25-22}=\dfrac{g.20}{0.25}=g.80~g/cm=10~m/s^2\times 8~kg/m=80~N/m[/tex]
mass of the scale pan=m(for 50 g mass) :
[tex]\tt (m+0.05).g=80\times (0.22-0.20)\\\\m=0.11~kg[/tex]
Matter is defined as anything that has weight and takes up space.
Answer:
true matter takes up space and is anything that is around us
Which of the following does not illustrate a complete circuit?
Answer:
I think A
Explanation:
because it dosn't have enough tools
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
Velocity is defined as rate of change of displacement wit respect to time.
tangential velocity is (11/10)πr , where r is radius of circular track.
Since, tangential velocity is, [tex]=\frac{distance}{time}[/tex]
In one revolution, distance travelled is circumference of circular track.
If radius of circular track is r , then distance travelled in one revolution is, = 2πr
So, 11 revolutions = 11(2πr) = 22πr
Time taken = 20 second
So, tangential velocity = 22πr/20 = (11/10)πr meter per second.
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Heat _________________ throughout our environment ________________ of the ________________.
is spread
....!
!
please complete the question
tenses of
write=
read=
Answer:
present
Explanation:
read doesn't change but write is in present tense
How Many displacement vectors shown in the figure above have horizontal components
Answer:
I think it's 5.
Explanation:
Answer: 4 vectors
Explanation:
Which of the following best describes the difference between type a and type b
Helpppp!! I will make you a brainlist Calculate the force exerted on
this test dummy with a mass of 75 kg hits an airbag accelerating at 12m/s2??
Answer:
900 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question is we have
force = 75 × 12
We have the final answer as
900 NHope this helps you
Calculate the aceleration of a vehicle of 100 kg when applicates 400 N
Answer:
For this we applicate 2nd law of Newton:
F = ma
Replacing:
400 N = 100 kg * a
a = 400 N / 100 kg
a = 4 m/s²
The aceleration is 4 meters per second squared.
Answer:
....................
Explanation:
---------------------
Which of the following best describes why understanding a watershed and its boundaries is important in designing housing developments along a river?
A
The water contained in a watershed is more likely to become polluted if the soil has high permeability, so it is important to locate all point sources to reduce contamination
B
Watersheds provide habitats for hundreds of marine species, so it is important to protect their feeding and nesting sites when designing housing for humans.
c
Watersheds provide space for cultivating land to produce food and other products, so it is important to avoid locating a housing development on the most fertile land.
D
Surface water and stormwater runoff will drain downstream within the watershed boundaries, so it is important to understand the flow of water through the watershed
Answer:
d
Explanation:
The watersheds are the major hydrological structures that supports the downstream of surface water and storm water. Hence, option (D) is correct.
The given problem is based on the concept and fundamentals of watershed boundary. The watershed boundary is defined as the topmost elevations surrounding the lake or river segment, such that the drop of water falling outside the boundary will drain to another watershed.
Watersheds are the naturally occurring boundaries that determine into which streams, rivers, and oceans water naturally flows.It is necessary to plot out the concept of watershed because the surface water and storm water runoff will drain downstream within the watershed boundaries.Thus, we can conclude that the watersheds are the major hydrological structures that supports the downstream of surface water and storm water. Hence, option (D) is correct.
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https://brainly.com/question/1771000
What is a force that opposes motion between two surfaces that are in contact?
Answer:
Friction is a force that opposes motion.
How much energy is released by the conversion of 4.2 x 10 kg of mass to energy? How much mass must be converted to energy to produce 1.00 J of energy?
Explanation:
4.2×+10=42kg
energy/work =
mxacceleration
420joulse
not sure
=42 mass I guess
Jack travelled 360 km at an average speed of 80 km/h. Elaine took 1.5 hours more to complete the same amount of distance. What was Elaine’s average speed for the whole journey? _____km/h and m/s
in a hydraulic press,a force of 200N is applied to a master piston of area 25cm² if the press is designed to produce a force of 5000N,determine the radius of the slave piston
Answer:
The radius of the slave piston = 14.10 cm
Explanation:
The formula to apply here is that for pressure where ;
Pressure = Force / Area
F₁ /A₁ =F₂/A₂ where ; F₁=200 N , A₁= 25 cm² , F₂ =5000 N ,A₂ =?
Apply values in the equation as ;
200/ 25 = 5000/ A₂
A₂ = 625 cm²
Formula for area is ;
A = πr²
625 = π * r²
625/π = r²
√625/π =r
14.10 cm = r
A 5-kg object is sliding to the right and encountering a friction force that slows it down. The coefficient of friction (μ) between the object and the surface is 0.1. What is the acceleration of the object? Note: There is no applied force here.
Answer:
The friction force is 4.9 N
[tex]a = 0.98\ m/s^2[/tex]
Explanation:
Friction Force
When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration or speed because the friction force opposes motion.
The friction force when an object moves on a horizontal surface is calculated by:
[tex]Fr=\mu N[/tex]
Where [tex]\mu[/tex] is the coefficient of static or kinetics friction and N is the normal force.
If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:
N = W = m.g
Thus, the friction force is:
[tex]Fr=\mu W[/tex]
The object has a mass of m=5 Kg, calculate the weight:
W = 5 * 9.8 = 49 N
It encounters a friction force that slows it down. We are given the coefficient of friction μ = 0.1, thus the friction force is:
Fr=0.1 49 N = 4.9 N
The friction force is 4.9 N
Since the only force acting on the object is the friction force, thus the net force is F = 4.9 N, and the acceleration can be calculated by using the equation of Newton's second law:
F = m.a
Solving for a:
[tex]\displaystyle a = \frac{F}{m}[/tex]
[tex]\displaystyle a = \frac{4.9}{5}[/tex]
[tex]\mathbf{a = 0.98\ m/s^2}[/tex]
similarities between the flow of water and an electric circuit.
They both flow in currents. Water has a pump that works like a battery and pipes that work like a circuit.
An object with a mass of 10 kg is rolled down a frictionless ramp from a height of 3 meters. If a factory worker at the bottom of the ramp slows the object until it comes to a stop, how much work must the factory worker have done
Answer:
The amount of work the factory worker must to stop the rolling ramp is 294 joules
Explanation:
The object rolling down the frictionless ramp has the following parameters;
The mass of the object = 10 kg
The height from which the object is rolled = 3 meters
The work done by the factory worker to stop the rolling ramp = The initial potential energy, P.E., of the ramp
Where;
The potential energy P.E. = m × g × h
m = The mass of the ramp = 10 kg
g = The acceleration due to gravity = 9.8 m/s²
h = The height from which the object rolls down = 3 m
Therefore, we have;
P.E. = 10 kg × 9.8 m/s² × 3 m = 294 Joules
The work done by the factory worker to stop the rolling ramp = P.E. = 294 joules
Lina holownicza wytrzymuje działanie siły o wartości co najwyżej 1400 N (większa siła powoduje rozerwanie liny). Oblicz maksymalne przyspieszenie, jakie może osiągnąć samochód o masie 2000 kg holowany na takiej linie po poziomej jezdni, jeżeli wiadomo, że łączna wartość sił oporu ruchu tego samochodu w czasie holowania wynosi 400 N.
Odpowiedź:
0,5 m / s²
Wyjaśnienie:
Jeśli się uwzględni:
Masa samochodu (m) = 2000 kg
Wartość siły oporu podczas holowania = 400N
Lina o maksymalnej sile może wytrzymać = 1400N
Maksymalne przyspieszenie = siła / masa samochodu
Siła = maksymalna siła - siła oporu
Siła = 1400 N - 400 N = 1000 N.
Stąd maksymalne przyspieszenie;
1000 N / 2000 kg
= 0,5 m / s²
What is the average depth of the oceanic crust? What percentage of our planet does it cover?
Answer: Oceanic crust, the outermost layer of Earth's lithosphere that is found under ... Sort out the facts and see how deep your knowledge goes in this quiz of the world's oceans. ... They commonly are thin (only about 10 cm [4 inches] thick) and cover a ... km (85 square miles) of seafloor to an average depth of 70 metres (230 feet).
Explanation: