how many electrons are in an atom that has 25 protons and has an ion charge of negative 3

Answer:

The answer is C

Explanation:

Thomson conducted many tests with cathode rays. Which led to his discovery of the electron.

Answer:

Kr-73 = 23.625 sec

Kr-74 = 10.0625 minutes (603.75 seconds)

Kr-76 = 12.95 hours (777 minutes)

Kr-81 = 1.8375 * 10^6 years

Explanation:

What you do is multiply each of those amounts by 7/8.

27 * 7/8 = 189/8 = 23.625

23/2 * 7/8 = 161/16 = 10.0625

74/5 * 7/8 = 518/40 = 259/20 = 12.95

210000 * 7/8 = 1470000/8 = 183750 = 1.8375 * 10^6

Answer:

Mass = 713.4 ×10⁻⁴ g

Explanation:

Given data:

Number of moles of calcium phosphate = 2.3×10⁻⁴ mol

Mass of calcium phosphate = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of calcium phosphate is 310.18 g/mol

by putting values,

2.3×10⁻⁴ mol = mass / 310.18 g/mol

Mass = 2.3×10⁻⁴ mol × 310.18 g/mol

Mass = 713.4 ×10⁻⁴ g

Answer:

Boom

Explanation:

The bomb is big and it goes boom and it also creates nuclear fragments everywhere

Answer:

19.11g

Explanation:

mole = mass ÷ molar mass

mole = 2.61 ÷ 27

mole = 0.097mol

Number of atoms in 2.61g of Aluminum = 6.022 × 10^23 × 0.097

= 0.584 × 10^23

= 5.84 × 10^22atoms

To get the same number of atoms for Gold (Au), we multiply the atomic mass of Au by 0.097mol

Atomic mass of Au = 197g/mol

mass = mole × molar mass

mass = 0.097 × 197

mass = 19.109g

mass = 19.11g

Answer:

I dont see anything.

Explanation:

But an element is a substance that is made only out of one atom.

A scoop of potassium oxide was placed in 55g of water which produced 67g of potassium hydroxide then mass of potassium oxide was used is 12g

Potassium oxide is used widely in the agricultural industry as a fertilizer

Here given data is

Potassium oxide was placed in 55g of water which produced 67g of potassium hydroxide

We have to calculate mass of potassium oxide was used =?

Then the reaction is

K₂O + H₂O → KOH

x + 55g = 67g

x = 67g - 55g

x = 12g

Therefore mass of potassium oxide was used is 12g

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The mass of Aluminum tri bromide that can be made with 5.6 moles of Aluminum is 1,492.90 grams.

Relation between the mass and moles of any substance will be calculated by using the below equation as:

n = W/M, where

Given chemical reaction is:
2Al + 3Br₂ → 2AlBr₃

From the stoichiometry of the reaction, it is clear that:

Now mass of AlBr₃ will be calculated by using the above equation as:

W = (5.6mol)(266.59g/mol) = 1,492.90g

Hence required mass of AlBr₃ is 1,492.90g.

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Answer:

Petals are modified leaves that surround the reproductive parts of flowers. They are often brightly colored or unusually shaped to attract pollinators. Together, all of the petals of a flower are called corolla.

Answer:

Steps of the technological design process include: identify a problem, research the problem, generate possible solutions, select the best solution, create a model, test the model, refine and retest the model as needed, and communicate the final solution.

Explanation:

hope it helps, please mark brainliest

Steps of the technology design process include: identify a problem, research the problem, generate possible solutions, select the best solution, create a model, test the model, refine and retest the model as needed, and communicate the final solution.

Technology is the application of knowledge for achieving practical goals in a reproducible way.The word technology can also mean the products resulting from such efforts, including both tangible tools such as utensils or machines, and intangible ones such as software. Technology plays a critical role in science, engineering, and everyday life.

Technological advancements have led to significant changes in society. The earliest known technology is the stone tool, used during prehistoric times, followed by the control of fire, which contributed to the growth of the human brain and the development of language during the Ice Age. The invention of the wheel in the Bronze Age allowed greater travel and the creation of more complex machines. More recent technological inventions, including the printing press, telephone, and the Internet, have lowered barriers to communication and ushered in the knowledge economy.

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A 72 kg object moving 25 m/s will require the greatest amount of force

Given

mass of object and the velocity

Required

the greatest amount of force

Solution

Newton's 2nd law :

∑F = m. a  

F = force, N  

m = mass = kg  

a = acceleration due to gravity, m / s²  

Assuming the object is moving from rest (vo = 0) and the time needed to reach its velocity is the same (delta t = equal), it can be formulated:

[tex]\tt \Sum F=m.\dfrac{v_f-v_i}{\Delta t}\\\\F=m.\dfrac{v_f}{\Delta t}[/tex]

So the force on an object depends on the product of its mass and velocity

Or if we use the impulse and momentum formula

[tex]\tt F.\Delta t=m(v_f-v_i)\\\\F,\approx m.v_f[/tex]

So that we determine which is the greatest from the multiplication of mass and velocity will produce the greatest force as well

A 72 x 25 = 1800

B. 55 x 32 =1760

C. 75 x 22 = 1650

D.63 x 27 = 1701

Option A has the greatest force

Answer:

Teeth gridning

Explanation:

BC YOUR GRINDING IT

Answer:

tissue bone cells ,bones skeletal,dog skeletal system

Explanation:

Mass of copper : 0.165 g

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis

[tex]\tt W=\dfrac{e.i.t}{96500}[/tex]

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

[tex]\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g[/tex]

Explanation:

Moles of KCl in new solution = 0.325dm³ * (2.76mol/dm³) = 0.897mol.

Hence volume needed = 0.897mol / (3.95mol/dm³) = 0.227dm³ or 0.227L.

Answer:

Explanation:

A. conducts electricity in both solid and liquid state.

   Metal

B. conducts electricity in solid state but its electrical conductivity in liquid state is unknown. Also it burns at a vey high temperature to give off carbon dioxide gas.

   Graphite

C. conducts electricity in liquid state but not in solid state

    Ionic compound

D. does not conduct electricity in any state

    Covalent compound

A metal is a substance that conducts both heat and electricity in solid and liquid state. They do this by the presence of free mobile electrons within their atomic space.

Graphite is a non - metal but it has free mobile electrons within its carbon frame work that allows of electrical conduction.

Ionic compounds are conductors only in molten state. In solid state, they do not conduct electricity and are called electrolytes in their liquid or molten form.

Covalent compounds do not ionize in solution and will not have ions which can conduct electric current.

Answer:

It will mess up the orbit around the sun

Explanation:

The impact of Halley's Comet with Neptune may force the asteroid to descend into Neptune's orbit, which may divert somewhat from its original path.

The collision of two heavenly bodies results in a powerful impact.

This collision might prevent Halley's Comet from continuing on its path and eventually colliding with Neptune.

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form the molar concentration of the Ca(OH)2 which is a base we can deduct the pOH

pOH=-lg[OH-]

[OH-]=8.8 x 10-4 M

pOH=4

pH=14-pOH

pH=10

-lg[H+]=10

[H+]=10^-10

The concentration of Hydrogen ion [H⁺] in 8.8×10¯⁴ M Ca(OH)₂ is 5.68×10¯¹² M

The concentration of Hydrogen ion [H⁺] in a solution talks about the acidicity  the solution. Thus, we can obtain the concentration of Hydrogen ion [H⁺] in 8.8×10¯⁴ M Ca(OH)₂ solution as illustrated below:

Data obtained from the question

Concentration of Ca(OH)₂ = 8.8×10¯⁴ M  

Concentration of Hydrogen ion [H⁺] =..?  

Determination of the concentration of Hydroxide ion [OH¯]

 Concentration of Ca(OH)₂ = 8.8×10¯⁴ M

Concentration of Hydroxide ion [OH¯] =?  

Ca(OH)₂ (aq)⇄Ca²⁺ (aq) + 2OH¯(aq)  

From the balanced equation above,  

1 mole Ca(OH)₂ produced 2 moles of OH¯.

Therefore, 8.8×10¯⁴ M Ca(OH)₂ will produce = 8.8×10¯⁴ × 2 = 1.76×10¯³ M

Thus, the Concentration of Hydroxide ion [OH¯] is 1.76×10¯³ M  

Determination of concentration of Hydrogen ion [H⁺].  Concentration of Hydroxide ion [OH¯] = 1.76×10¯³ M

[tex]H^{+} * OH^{-} = 1*10^{-14}\\H^{+} * 1.76^{-3} = 1*10^{-14}[/tex]

Divide both side by 1.76×10¯³  

[tex]H^{+} = \frac{1*10^{-14} }{1.76*10^{-3}}\\[/tex]

[H⁺] = 5.68×10¯¹² M  

Therefore, the concentration of Hydrogen ion [H⁺] in the solution is 5.68×10¯¹² M  

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Answer:

Kinetic Energy (Hope This Helps)

Explanation:

(Brainliest)

Answer:

Chemical energy to kinetic energy. (Arguably heat energy (thermal) because of respiration)

Answer:

310.53 g of Cu.

Explanation:

The balanced equation for the reaction is given below:

CuSO₄ + Zn —> ZnSO₄ + Cu

Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:

Molar mass of CuSO₄ = 63.5 + 32 + (16×4)

= 63.5 + 32 + 64

= 159.5 g/mol

Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g

Molar mass of Cu = 63.5 g/mol

Mass of Cu from the balanced equation = 1 × 63.5 = 63.5 g

Summary:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Finally, we shall determine the mass of Cu produced by the reaction of 780 g of CuSO₄. This can be obtained as follow:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.

Thus, 310.53 g of Cu were obtained from the reaction.

Answer:

you must go to jones im doing the same test

Explanation:

Answer:

C) number of occupied energy shells

Explanation:

Atomic numbers of different elements must differ, as well as atomic masses. The number of oxidation states differs per atom as well.

Answer:

Sick Core corona +iep =Qurintine

Answer:

D. Halogens

Explanation:

All elements in these groups have 7 valence electrons, meaning their electronegativity is the highest among the elements.

Answer:

C

Explanation:

A. analyzing results

B. collecting data

C. choosing controlled variables

D. making a prediction

The correct answer would be choosing controlled variables.

The controlled variables are factors that are kept constant among the different groups of subjects during the course of an experiment so as to be able to isolate the effects of a single factor - the independent variable.

There are basically 3 types of variables in a scientific experiment;

1. The independent variable

2. The dependent variable

3. The controlled variable

The independent variables are the variables whose effects are to be determined in the course of experiments. The dependent variables are the variables that are actually measured during the course of experiments and whose values vary along with that of the independent variables. The controlled variables are other variables required for the experiment but which must be kept constant among subjects in order to be able to isolate the effects of the independent variable.

The correct option is C.

The empirical formula of the compound is C₃H₄O₂

From the question given above, the following data were obtained:

Carbon = 50.04%

Hydrogen = 5.59%

Oxygen = 44.37%

Divide by their molar mass

C = 50.04 / 12 = 4.17

H = 5.59 / 1 = 5.59

O = 44.37 / 16 = 2.773

Divide by the smallest

C = 4.17 / 2.773 = 1.5

H = 5.59 / 2.773 = 2

O = 2.773 / 2.773 = 1

Multiply by 2 to express in whole number

C = 1.5 × 2 = 3

H = 2 × 2 = 4

O = 1 × 2 = 2

Therefore, the empirical formula of the compound is C₃H₄O₂

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Answer:

Detail is given below

Explanation:

Differences:

Ionization involves the formation of ions while in dissociation substance are break into atoms, ions or molecules.

In ionization atoms and molecules gain positive or negative charge.

While in dissociation positive and negative ions are not essentially formed substance could be break into neutral small particles.

Ionization occur in covalent compounds while dissociation occur in ionic compound.

Ionization example:

Cl + e⁻    →  Cl⁻

Dissociation example:

NaCl   →   Na⁺ + Cl⁻

Here sodium and chloride ions are formed but in sodium chloride these ions were already present.

Another example:

N₂O₄   →     2NO₂