If 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L, the concentration of the resulting solution is A0.025 M B 0.050 M C 0.10 M D 0.50 M E 1.0 M M​

Answers

Answer 1

Answer: The concentration of the resulting solution is 0.025 M

Explanation:

According to the dilution law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of concentrated [tex]NaOH[/tex] solution = 1.0 M

[tex]V_1[/tex] = volume of concentrated [tex]NaOH[/tex] solution = 50 ml

[tex]M_2[/tex] = molarity of diluted [tex]NaOH[/tex] solution = ?

[tex]V_2[/tex] = volume of diluted [tex]NaOH[/tex] solution = 2.0 L = 2000 ml (1L=1000ml)

Putting in the values we get:

[tex]1.0\times 50=M_2\times 2000[/tex]

[tex]M_2=0.025M[/tex]

Therefore, concentration of the resulting solution is 0.025 M

Answer 2

The concentration of the resulting solution if 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L is 0.025M

HOW TO CALCULATE FINAL CONCENTRATION:

The concentration of a solution can be calculated by using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration (M)C2 = final concentration (M)V1 = initial volume (L)V2 = final volume (L)

According to this question;

C1 = 1.0MV1 = 50mLC2 = ?V2 = 2000mL = 2L

1 × 50 = C2 × 2000

50 = 2000C2

C2 = 50 ÷ 2000

C2 = 0.025M

Therefore, the concentration of the resulting solution if 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L is 0.025M.

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Answer:

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Required

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Answers

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Answers

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