if an arrow is aimed at 45.0 angle and needs to land 90.4 m away how fast should it be fired?

Answers

Answer 1

The arrow should be fired with an initial speed of approximately 31.2 m/s to land 90.4 meters away when aimed at a 45.0-degree angle.

To calculate the initial speed required for an arrow fired at a 45.0-degree angle to land 90.4 meters away, we can utilize the principles of projectile motion.

In projectile motion, the horizontal and vertical components of motion are independent. We can break down the initial velocity into its horizontal and vertical components.

Angle of projection (θ) = 45.0 degrees

Range (horizontal distance) (R) = 90.4 meters

We can start by finding the horizontal component of the initial velocity (Vx) using the formula:

Vx = V * cos(θ)

Where V is the initial velocity.

Since the angle is 45.0 degrees, the cosine of 45.0 degrees is equal to 1 / √2.

Vx = V / √2

Next, we can find the vertical component of the initial velocity (Vy) using the formula:

Vy = V * sin(θ)

Again, since the angle is 45.0 degrees, the sine of 45.0 degrees is equal to 1 / √2.

Vy = V / √2

To determine the initial speed required, we need to consider the time of flight (T) for the arrow to reach the range. The time of flight can be calculated using the formula:

T = (2 * Vy) / g

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Once we have the time of flight, we can calculate the horizontal component of the initial velocity (Vx) using the formula:

Vx = R / T

Now, we can substitute the expressions for Vx and Vy into the original equation:

Vx = V / √2

Vx = R / T

Solving for V:

V = Vx * √2

V = (R / T) * √2

Plugging in the given values of R and T:

V = (90.4 m / T) * √2

Finally, substituting the value of T:

V = (90.4 m / [(2 * Vy) / g]) * √2

Simplifying further:

V = (90.4 m * g * √2) / (2 * Vy)

V = (90.4 m * 9.8 m/s^2 * √2) / (2 * (V / √2))

V = (90.4 m * 9.8 m/s^2) / V

Squaring both sides:

V^2 = (90.4 m * 9.8 m/s^2) / V

Rearranging the equation:

V^3 = 90.4 m * 9.8 m/s^2

Taking the cube root of both sides:

V = ∛(90.4 m * 9.8 m/s^2)

Using a calculator, the final answer is:

V ≈ 31.2 m/s

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Related Questions

A 30 kg child is in a school play. She is standing on the ground at rest but she is attached to a rope with a 5 kg mass attached. A 45 kg child takes off the 5 kg mass and jumps from a height in order to hoist the 30 kg child off the ground. What is the acceleration that both children have together?

:)

Answers

20kg because a child takes off 5K mass jumps meaning it possible be 15K

what is an electric current ?​

Answers

Answer:

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.

Explanation:

A 3520 kg truck moving north at
18.5 m/s makes an INELASTIC
collision with an 1480 kg car
moving east. After colliding, they
have a velocity of 13.6 m/s at
72.6°. What was the initial velocity
of the car?

Answers

Answer: 13.7 m/s

Explanation:

[tex]$$Mass of $T r u c k$$ \ \left(m_{T}\right)=3520\mathrm{kg}[/tex]

[tex]V_{T_{y}}=18.5 \mathrm{~m} / \mathrm{s} \\&V_{\text {Tix }}=0 \mathrm{~m} / \mathrm{s}[/tex]

[tex]\mathrm{Mass \ of \ car \ (m_c) = 1480 \ kg}[/tex]

[tex]V_{c i x}=\text { ? ; } V_{c i y}=0 \mathrm{~m} / \mathrm{s}[/tex]

[tex]Final \ velocity $\left(V_{f}\right)=13.6 \mathrm{~m} / \mathrm{s} \ \ \theta=72.6$[/tex]

[tex]v_{f x}=v_{f} \cos \theta=(13.6) \cos 72.6=4.067 \mathrm{~m} / \mathrm{s}[/tex]

[tex]\mathrm {Using \ the \ conservation \ of \ momentum \ along\ the \ $x$-axis}[/tex]

[tex]\begin{aligned}m_{T} v_{T i x}+m_{c} v_{c_{i x}} &=\left(m_{T}+m_{c}\right) v_{f x} \\0+(1480) V_{c_{i x}} &=(3520+1480)(4.067) \\(1480) v_{c i x} &=20335 \\V_{c i x} &=13.7 \mathrm{~m} / \mathrm{sec}\end{aligned}[/tex]

Answer:

13.7 m/s

Explanation:

Match each description with the correct graph

Answers

Answer: 1. B, 2. A, 3. C, 4. D

Answer:

1 = B

2 = A

3 = C

4 = D

I hope this helps

The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 and kinetic=0.3. Assume both blocks are attached together. Determine if the block system will slide down or not.

Answers

Coefficient of static friction = 0.5Coefficient of Kinetic friction = 0.3Angular velocity = 500 RPMs

The Radius of the System

Let R be the radius of cylinder

[tex]m_a + m_b = 4 + 3 = 7kg[/tex]

The angular velocity is 500 RPMs

[tex]\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R[/tex]

The normal force

[tex]f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm[/tex]

Since the radius is very little for two block to execute circular motion so system will slide down.

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A pulley in the form of a uniform disk)
with mass 63 kg and a radius 20 cm is at-
tached to the ceiling in a uniform gravita-
tional field and rotates with no friction about
its pivot. The masses are connected by a
massless inextensible cord and T1, T2, and T3
are magnitudes of the tensions.
T3
20 cm
T2
63 kg
1
39 kg
T1
3.8 m
15 kg
2
What is the magnitude of the tension T?
The acceleration due to gravity is 9.8 m/s?.
Assume up is positive.
Answer in units of N.

Answers

For a  pulley in the form of a uniform disk with a mass of 63 kg and a radius of 20 cm, the magnitude of the tension T is mathematically given as

T1=292.4N

What is the magnitude of the tension T?

For 20kg

T1=196+20a

For

33kg

T2=323.4-33a

Generally, the simultaneous equation is mathematically given as

T2-T1=(323.4-33a)-(196+20a)

Hence

127.4-53.a

a=1.67m/s^2

T1=196+20(1.67)

T1=292.4N

In conclusion, the magnitude of the tension T

T1=292.4N

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1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his trip
take?

Answers

Answer:

His trip took 5.78 seconds

Explanation:

23.7m divided by 4.1m/s = 5.78048780488

A delivery drone uniformly slowed down from 45 m/s to 23 m/s in a straight line over a 30-minute duration within a 16-
kilometer radius of its warehouse. What was the magnitude of its average acceleration?

Answers

Answer: The Answer is A 1.2 x 10−2 m/s2

The average acceleration of the delivery drone as it slowed down was  -0.012 m/s².

What is average acceleration?

The average acceleration is defined as the average rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given is a delivery drone that uniformly slows down from 45 m/s to 23 m/s in a straight line over a 30-minute duration.

We can write -

[u] = 45 m/s

[v] = 23 m/s

Δt = 30 min = 30 x 60 = 1800 sec

We can write the average acceleration as -

a = Δv/Δt

a = (23 - 45)/1800

a = - 0.012 m/s²

Therefore, the average acceleration of the delivery drone as it slowed down was  -0.012 m/s².

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A disc of radius wich uniform distribution of mass rotates about on axis perpendicular to it's plane at the rim with angular speed, the moment of inertia of the disc about the axis through the centre is 1/2MR*R, what's the kinetic energy of the disc?​

Answers

Answer:

Explanation:

M3U1 Pre-Assessment

Reflection Journal - Thursday

Is the moon always showing up at the same time?

Answers

Answer:

the moon showing up at same time as what

Explanation:

???

The moon is visible in daylight nearly every day, the exceptions being close to new moon, when the moon is too close to the sun to be visible, and close to full moon when it is only visible at night




The Moon can be seen at different times during the day and night - but when and where you see it depends on the phase of the Moon. ... The time of moonrise and moonset and the shape of the Moon change throughout the month, depending on where the Moon is in space. The Moon moves around the Earth every month.

If a satellite is launched to a distance of 1000000m above the earth’s surface, what is the gravitational field strength on the satellite from the earth?

Answers

Explanation:

A 620 kg satellite above the earth's surface experiences a gravitational field strength of 4.5 N/kg.

Knowing the gravitational field strength at Earth’s sur-

face and Earth’s radius, how far above Earth’s surface

is the satellite? (Use ratio and proportion.)

Suppose a radio signal travels from Earth and through space at a speed of 3.0 × 108 m/s. How far into space did the signal travel during the first 33.3 minutes?

Answers

For a radio signal that travels from Earth and through space at a speed of 3.0 × 108 m/s, The distance into space the signal traveled during the first 33.3 minutes  is mathematically given as

d=647352m

How far into space did the signal travel during the first 33.3 minutes?

Generally, the equation for the distance is mathematically given as

d=v*t

Where

t=33.3min

t=33.3*60

t=1998sec

Therefore

d=3.0 × 108 m/s *1998sec

d=647352m

In conclusion, distance is

d=647352m

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students in a lab are doing experiments involving the motion of objects. they pull an object across a table and use a detector to measure the acceleration of the object for the entire time they pull it. The graph shows the data from the detector, with four segments labeled ​

Answers

Based on the acceleration-time graph, the segments of the motion in which the object experience a net force are both 1 and 3.

What is Newton's Second Law of Motion?

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

How to calculate the net force.

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

[tex]F=ma =\frac{m(v\;-\;u)}{t}[/tex]

Where:

m is the mass.t is the time.u is the initial velocity.u is the final velocity.a is the acceleration.

Note: Mass represents the conversion factor between net force and acceleration on an acceleration-time graph.

Based on the acceleration-time graph, the segments of the motion in which there is a net force acting on the object are both 1 and 3 while it experienced constant acceleration at segment 2 and 4.

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You walk out to the edge of a 2,384 m. cliff and you toss a rock down to watch it drop. What is the rocks acceleration?

Answers

Answer:

9.8m/s

Explanation:

Wherever you're on the earth's surface, gravitational force remains the same and it does not matter either its a rock that's being tossed or a sheet of paper, the acceleration remains 9.8m/s only. *Condition applied=air resistance neglected

Now imagine everyone in the group hug starts moving away from each other what effect do you think that would have on your temperature

Answers

your temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always

temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

What is Temperature?

Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).

Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.

As opposed to extensive characteristics, like mass or volume, temperature is referred to as an intense property—one that is independent of the quantity of matter being considered—along with pressure, density, and other comparable properties.

Therefore, temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

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the diagram below shows the movement of matter in a portion of the water cycle.

what does p most likely represent

rivers
lakes
infiltration
precipitation

Answers

Answer:

Infilteration

what is kinetic energy

Answers

Answer:

energy which a body possesses by virtue of being in motion.

Explanation:

hope this help

pls mark as brainliest

what is digital vernier calliper


Answers

Answer:

a precision instrument for taking extremely precise measurements. It's the newest advancement in caliper technology.

Explanation:

A framed picture hangs from two cords attached to the ceiling. Which shows the correct free body diagram of the hanging picture?​

Answers

Answer: the answer is in the picture

Explanation:

Answer:

C

Explanation:

i did the test and got 100 :)

If a person weighs 692 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that planet?

Answers

Answer:

Approximately [tex]75.3\; \rm m \cdot s^{-2}[/tex]. (Approximately [tex]7.69\, g[/tex], where [tex]g[/tex] denotes the acceleration due to gravity on the surface of the earth.)

Explanation:

The weight of an object is the size of the overall gravitational pull on that object. If the mass of this person is [tex]m[/tex], the weight of this person at a point with gravitational acceleration [tex]g[/tex] would be [tex]m \cdot g[/tex].

Let [tex]g_{0}[/tex] denote the gravitational acceleration on the surface of the earth. The weight of this person on the surface of the earth would be [tex]m \cdot g_0[/tex].

Let [tex]g_1[/tex] denote the gravitational acceleration on the surface of that "nearby planet". The weight of this person on the surface of that planet would be [tex]m \cdot g_1[/tex].

According to the question:

Weight of this person on the surface of the earth: [tex]692\; \rm N[/tex]. Therefore, [tex]m \cdot g_0 = 692\; \rm N[/tex].Weight of this person on the surface of that nearby planet: [tex]5320\; \rm N[/tex]. Therefore: [tex]m \cdot g_1 = 5320\; \rm N[/tex].

Take the quotient of these two equations:

[tex]\displaystyle \frac{m\cdot g_1}{m \cdot g_0} = \frac{5320 \; \rm N}{692\; \rm N}[/tex].

[tex]\displaystyle \frac{g_1}{g_0} \approx 7.6879[/tex].

[tex]g_1 \approx 7.6879 \, g_0[/tex].

In other words, the gravitational acceleration on the surface of that nearby planet is approximately [tex]7.6879[/tex] times the gravitational acceleration on the surface of the earth.

The gravitational acceleration on the surface of the earth is approximately [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex]. Therefore, the gravitational acceleration on the surface of that planet would be approximately [tex]7.6879\, g \approx 7.8679 \times 9.8\; \rm m \cdot s^{-2} \approx 75.3\; \rm m \cdot s^{-2}[/tex].

11. Differentiate between refraction of light and dispersion of light.​

Answers

Answer:

Refraction refers to any bending of waves due to a change in speed. In the case of light being refracted by a prism, dispersion means that the higher the frequency light bends more. In short, Refraction is the bending of light and Dispersion is the frequency dependece of this behaviour.

an Alaskan rescue plane traveling 59 m/s drops a package of emergency rations from w height of 168 m to a stranded party of explorers.
the accelerating of gravity is 9.8 m/s^2.
where does the package strike the ground relative to the point directly below where it was released? answer units of m ​

Answers

Hence 59m/s perpendicular with y axis, Uy is zero

An object is swung in a horizontal circle on a length of string
that is 0.93 m long. Its acceleration is 26.36 m/s? What is the
time it takes the object to complete one horizontal circle?

Answers

Answer: either 3.20s or 1.18s

Explanation:

HELP PLEASE!!!!!!!!!

Answers

Answer:

2.00×[tex]10^{8}[/tex]

Explanation:

3×[tex]10^{8}[/tex]/1.5

=2.00×[tex]10^{8}[/tex]

there is a rusted nut we have a two spanners each of i 15 cm and 20 CM respectively which spanner is suitable to open the nut and why​

Answers

Answer :

20cm spanner is suitable to open this nut , Because we feel easy to apply force at the end of spanner to rusted nut. It means that as the perpendicular distance between force and axis of rotation increase the magnitude of moment also increase.

I think the Answer will helps you.....

Thank you ☺️☺️☺️

Please see the image

Answers

Answer:

i think it is 89

Which one these statements describes how to typically tell the difference
between a synthesis (S) reaction and a decomposition (D) reaction?
Tap to select or deselect answer.
An S reaction has one product and two or more reactants and a D reaction
has one reactant and two or more products.
An Sreaction has one reactant and two or more products and a D reaction
has one product and two or more Reactants.
An S reaction has oxygen as a reactant and a Dreaction has oxygen as a
product
An S reaction has oxygen as a product and a D reaction has oxygen as a
reactant

Answers

Answer: An S reaction has one product and two or more reactants and a D reaction has one reactant and two or more products.

Explanation:

In a synthesis reaction, two or more simple molecules or substances interact to form a more sophisticated product. (General equation: A + B → AB)

When one reactant decomposes into two or more products, this is known to as a decomposition reaction. (General equation: AB → A + B)

Explain how the movement of the Moon around the Earth c langes we see at night?

Answers

Answer: We can see the moon at night because the earth spins in a circle wall it is going around the sun so when the sun go down and the moon comes up the suns light will go over the top of earth and hite the moon the all the light that is hite the moon will bounce off it and the moon it a light color and light shins off lighter colored thing and it will have a little proportion of that light will come and hite earth make the moon very easy to see at night and the most light hits the moon when if it a full moon and is the most brite.

I Hope This Helped!

8. When are children MOST likely to begin using words to express meaning?​

Answers

8 to 8 months old I’m sure

Help please it’s urgent

Answers

Answer:

Explanation:

The circuit is incomplete since it is a series circuit

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