If [tex]f(x) = x[/tex]² [tex]-x+3[/tex], then what is the reaminder when [tex]f(x)[/tex] is divided by [tex]x+9[/tex]?

Answer:

what ang hirap nmn anong grade ka na ba

Answer:

two negitives equals a positive so C none of the above

Hope This Helps!!!

Answer:

A and B

Step-by-step explanation:

Answer:

#1 matches with the pizza scenario

#2 matches with the present scenario

#3 matches with the Sarah scenario

Step-by-step explanation:

Look for keywords at the end of the questions and if they go hand and hand (such as in 7 hours / yield 20 servings) then they go together as a pair

To determine the total number of cell phone subscribers that were in Centerville in 2020 is 5,928,227 people.

Given the following data:

Increment rate = 165% = 1.65

To determine the total number of cell phone subscribers that were in Centerville in 2020:

First of all, we would calculate the difference in years:

[tex]Year = 2020 - 2000[/tex]

Year = 20 years

Mathematically, the growth rate of cell phone subscribers that were in Centerville in 2020 is given by the formula:

[tex]A_n = Pr^t[/tex]

Substituting the given parameters into the formula, we have;

[tex]A_{20}=285(1.65)^{20}\\\\A_{20}=285 \times 22370.67\\\\A_{20}=5,928,227.55[/tex]

Subscribers = 5,928,227 people.

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Answer:

1) 1584.72

2) 4811.2

3) 2381.721

4) 1672.376

5) 3901.59

Step-by-step explanation:

Answer:2

Step-by-step explanation:

x+3=5

subtract 3 from both sides

x=5-3

x=2

Answer:

x=    2

Step-by-step explanation:

Answer:

part A: median is 12

part B: interquartile rage is 10

Step-by-step explanation:

Part A: to find your median on a box and whisker plot, you just need to look at your middle line in your box. In this case it's 12.

Part B: to find your interquartile range on a box and whisker plot, you subtract your Q1 and Q3. Your Q1 and Q3 will be the two outside lines that make up the rest of your box, in this case would be 6 and 16. To find your Q1 if you don't already have your plot set up, you separate the numbers that are given to you in half and find the median of each side. The first half will be your Q1 and the second half your Q3.

Answer:

[tex]x^{2}[/tex] - 10x + 16

Step-by-step explanation:

If the 0s are 2 and 8, then the factors are (x - 2) and (x - 8)

Multiply them together to get [tex]x^{2}[/tex] - 10x + 16

The value of x from the given equation is -1

Given the equation expressed as:

[tex]3(x - 10) - 5x = 2x - 26[/tex]

Expand using the distributive law as shown:

3x - 3(10) - 5x = 2x - 26

3x - 30 - 5x = 2x - 26

Collect the like terms to have:

3x - 5x - 2x = -26 + 30

-2x - 2x = -26 + 30

Simplify the result by addition and subtraction:

-4x = 4

Divide both sides by -4 (Division property of equality)

-4x/-4 = 4/-4

x = -1

Hence the value of x from the given equation is -1

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Answer:

Part A - he will need 2 cups of sugar  

Part B - 12 : 6 : 3

Step-by-step explanation:

Part A :

8 divided by 4 is 2

Part B :

Multiply all the numbers by 3

Hope this helped! :)

#1

[tex]\\ \sf\hookrightarrow -5x+4=-1[/tex]

[tex]\\ \sf\hookrightarrow -5x=-5[/tex]

[tex]\\ \sf\hookrightarrow x=1[/tex]

Incorrect

#2

[tex]\\ \sf\hookrightarrow 4x-3=-7[/tex]

[tex]\\ \sf\hookrightarrow 4x=-4[/tex]

[tex]\\ \sf\hookrightarrow x=-1[/tex]

Correct

#3

[tex]\\ \sf\hookrightarrow 3y-4=5[/tex]

[tex]\\ \sf\hookrightarrow 3y=9[/tex]

[tex]\\ \sf\hookrightarrow y=3[/tex]

Ans not given

#4

[tex]\\ \sf\hookrightarrow -2y+7=12[/tex]

[tex]\\ \sf\hookrightarrow -2y=5[/tex]

[tex]\\ \sf\hookrightarrow y=-5/2[/tex]

Incorrect

#5

[tex]\\ \sf\hookrightarrow 3a-6=18-a[/tex]

[tex]\\ \sf\hookrightarrow 4a=24[/tex]

[tex]\\ \sf\hookrightarrow a=6[/tex]

Incorrect

#6

[tex]\\ \sf\hookrightarrow 5(2t-1)=2[/tex]

[tex]\\ \sf\hookrightarrow 10t=7[/tex]

[tex]\\ \sf\hookrightarrow t=7/10[/tex]

Incorrect

#7

[tex]\\ \sf\hookrightarrow ax-b=0[/tex]

[tex]\\ \sf\hookrightarrow x=\dfrac{b}{a}[/tex]

Correct

Done

Answer:

A, D, G, H

Step-by-step explanation:

Look at the pink(or purple) lines. R and F both have 4 lines, so they're congruent. S and G both have 1 line, so those are congruent too.

-hope it helps

Answer:

1st option: ∠S ≅ ∠G

4th option: ∠T ≅ ∠H

7th option: ∠Q ≅ ∠E

8th option: ∠R ≅ ∠F

Step-by-step explanation:

Side lengths are unnecessary you just look at those loop things. Angles with the same number of "loops" are congruent like how ∠Q and ∠E both have 3 "loops", this means those angles are congruent.

Given :-

To Find :-

Solution :-

The given triangle is a right isosceles triangle . So here we can use the Pythagoras theorem as ,

[tex]\longrightarrow[/tex] hypotenuse² = perpendicular ² + base²

[tex]\longrightarrow[/tex] x² = 4² + 4²

[tex]\longrightarrow[/tex] x² = 16 + 16

[tex]\longrightarrow[/tex] x² = 32

[tex]\longrightarrow[/tex] x = √32

[tex]\longrightarrow[/tex] x = √2⁵

[tex]\longrightarrow[/tex] x = 4 × 1.732

[tex]\longrightarrow[/tex] x = 6.928 ≈ 7

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

Answer:

22.5 degrees

Step-by-step explanation:

Complementary angles add up to be 90 degrees. You can model the simple equation [tex]x+3x=90[/tex] where is x is the small angle and 3x is the large angle.

[tex]4x=90\\x=22.5[/tex]

the smaller angle is 22.5 degrees

Answer:

14 nickels is the answer

Step-by-step explanation:

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

Answer:

both isosceles???

Step-by-step explanation:

Answer:

They are similar.

Step-by-step explanation:

There might be other ways but

<X(Angle of x) is used for both triangle XAB and XYZ

And lines AB and YZ are parallel, From this we know that a line intersected by parallel lines it forms same angles for both parallel angles.

The similarity statement is: AAA Because angle(A=B , B=Z)

Answer:

22.53-9.99=12.54

12.54 divided by 6 = 2.09

Each pencil costs $2.09

Step-by-step explanation:

Answer:

Thermodynamics is a branch of physics that deals with heat, work, and temperature, and their relation to energy, entropy, and the physical properties of matter and radiation.

Answer:

3 2/2

Step-by-step explanation:

Answer: x=-1, y=-8

Step-by-step explanation: solve for the first variable in one of the equations then subsitutte the result into the other equation

Answer:

x=-10

Step-by-step explanation:

since there's a given 120 degrees, and it's a isosceles triangle, we know that the line adds up to 180 (where the 120 degrees is). so 120+x=180, the interior angle measures 60 degrees. That being said, the 3 angles measure 60 degrees also. now there's a right angle mark on top, so we find the angle of the smaller triangle (near angle 2) by doing 90-60=30 degrees.

angle 2 is said to be x+160, and there's a line, which tells us that they must add to 180.. so x+160+30=180

x+190=180

x=-10.

Answer:

-270,810

Step-by-step explanation:

c.r.  r=-30/-10=3

[tex]a_{n} =a_{1}r^{n-1} \\a_{4}=-10(3)^{4-1}\\=-10(3)^3=-10 \times 27=-270\\a_{5}=-10 \times(3)^{5-1}\\=10 \times3^4\\=-810[/tex]

Answer:

Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need,  in general what you want is to move one end of the segment up, the other right, and stretch it.

That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.

For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]

The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.

The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.

Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at  [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.

Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]

[tex]f(x) = ab^x~\hfill \begin{array}{llll}\textit{we know that}~f(0)=-4\begin{cases}x=0\\f(x)=-4\end{cases}\\\\-4=ab^0\implies -4=a(1)\implies -4=a\end{array}\\\\\\\stackrel{therefore}{f(x)=-4b^x}~\hfill \textit{we also know that}~f(-2)=-64\begin{cases}x=-2\\f(x)=-64\end{cases}[/tex]

[tex]-64=-4b^{-2}\implies \cfrac{-64}{-4}=b^{-2}\implies 16=b^{-2}\implies 16=\cfrac{1}{b^2} \\\\\\ b^2=\cfrac{1}{16}\implies b=\sqrt{\cfrac{1}{16}}\implies b = \cfrac{\sqrt{1}}{\sqrt{16}}\implies b = \cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill f(x)=-4\left( \frac{1}{4} \right)^x~\hfill[/tex]

The inequality which represents the constraints of the range is D. p(m) ≥ -875

Since the PTA was doing fundraiser and bought 500 megaphones to sell for the pep rally, and the profit, p, from the sale of megaphones can be represented by p(m) = 3.5m - 875 where m = number of megaphones sold.

To find the inequalities represents the constraints of the range of p(m), we need to know the domain of m.

Since we have 500 megaphones and we can sell from 0 to 500 inclusive. So, the domain of m is 0 ≤ m ≤ 500.

To determine the range of p(m), we insert the values of m at its extreme points into p(m).

So, when m = 0

p(m) = 3.5m - 875

p(0) = 3.5(0) - 875

p(0) = 0 - 875

p(0) = -875

when m = 500

p(m) = 3.5m - 875

p(500) = 3.5(500) - 875

p(500) = 1750 - 875

p(500) = 875

Since for a profit, m ≥ 0. So, p(m) ≥ p(0) = -875

So, p(m) ≥ -875

So, the inequality which represents the constraints of the range is D. p(m) ≥ -875

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