Answer:
friction. or gravity both ofbthem .....................
..
in any chemical reaction or physical change the mass of the product is ___ The mass of the reactant
a. The relationship cannot be determined by the amount of information given
b. equal to or the same
c. twice is greater than
d. twice as less than
Answer: b. equal to or the same
In Law of Conservation of mass, the mass of the product equals the mass of the reactant. A reactant is the chemical reaction of two or more elements to make a new substance, and a product is the substance that is formed as the result of a chemical reaction.
pls mark brainliest! i really need one :(
Which is true for the motion of the car during its journey along OAB?
12)
A) The velocity of the car remains constant throughout the journey.
B) The change in speed alone causes the velocity of the car to vary.
C) The change in direction alone causes the velocity of the car to vary.
D) The velocity of the car changes due to the change in speed and dir
Answer:
D
Explanation:
A is wrong as the direction of the car changes, implying velocity is changing and not constant.
B and C are wrong as both the change in speed and direction contribute to the change in velocity
Samantha's teacher asks her to describe motion in one dimension. This type of motion is always
A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.
Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.
In Science, the motion of an object or physical body is described in terms of the following parameters:
SpeedForceAccelerationDistanceTimeFurthermore, there are three (3) forms of motion based on dimension and these include:
1. Motion in one dimension
2. Motion in two dimension
3. Motion in three dimension
A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.
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A student claims that the total momentum of a system of objects is conserved when there is no net force on the system.
To test the claim, the student uses a cue ball (white) and rolls it into an eight ball (black). When the balls collide, the cue
ball comes to a complete stop and the eight ball begins to move. The mass of the cue ball is 0.17 kg, and the mass of
the eight ball is 0.16 kg. A radar is used to measure the speed of the cue ball immediately before it comes in contact
with the eight ball, and another radar is used to measure the speed of the eight-ball immediately after the point of
contact. The cue ball approaches the eight ball at a speed of 4.00 m/s. After contact, the eight ball moves away from the
cue ball at a speed of 4.25 m/s. The scenario is shown in the picture.
The total momentum of the system is conserved and the momentum did not change.
The given parameters:
Mass of the white ball, m₁ = 0.17 kgMass of the black ball, m₂ = 0.16 kgInitial velocity of the white ball, u₁ = 4 m/sFinal velocity of the black ball, v₂ = 4.25 m/sThe initial momentum of the system is calculated as follows;
[tex]P_i = m_1 u_1 + m_2 u_2\\\\P_i = 0.17 \times 4 \ + \ 0.16(0)\\\\P_i = 0.68 \ kg m/s[/tex]
The final momentum of the system is calculated as follows;
[tex]P_f = m_1 v_1 + m_2 v_2 \\\\P_f = 0.17 (0) \ + 0.16(4.25)\\\\P_f = 0.68 \ kg m/s[/tex]
Thus, the total momentum of the system is conserved and the momentum did not change.
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Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]
The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
The given parameters:
Magnitude of the vector = 350 NPosition of the vector = 30⁰ South eastThe vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.
The length of the arrow represents the magnitude of the vector which is 350 N. The direction of the arrow indicated by the arrow head represents the position of the vector.The position of the vector is 30 degrees South of East.Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
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A heavy crate is pushed across a floor at a constant velocity. Friction is present between the crate and floor. During this motion, the force of friction is _?_ the force pushing the crate forward.
Question 3 options:
less than
greater than
equal to
Answer:
less than.
Explanation: because Friction is the resistance to motion of one object moving relative to another. which means it cant be greater because how would it be greater if its pushing forward when friction is the resistance.
THANKS FOR THE POINTS :D
Which statement describes the magnetic field inside a bar magnet? It points from north to south. It points from south to north. It forms loops inside the magnet. There is no field within the magnet.
Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.
Magnetic Field:
It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.
The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.
Magnetic field lines emerge from the North pole and end in the South pole of a bar magnet. Inside the magnet are also present inside the bar magnet and never intersect at any point.Therefore, inside the bar magnet, the magnetic field points from north to south.
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Answer:b
Explanation:
anything that has mass and occupies space is called
Answer:
Matter
Hope you could get an idea from here.
Doubt clarification - use comment section.
who made the first game
A William Shakespeare
B Horace Alexander
C Doris Twitchell Allen
D William higginbotham
What does the risk of biological harm from radiation depend on?
Answer:
The effects of radiation depend on the type, energy, and location of the radiation source, and the length of exposure.
given how the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is
Answer:
I think you ask for another way of writing the joule (J). It can be expressed as the product between a force applied to a body and the deployment of the body (not necessarily caused by that force applied), so N*m (newton * meter).
The quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).
What is unit of physical quantities?The quantity with a constant magnitude that is used to measure the magnitudes of other quantities of the same type is referred to as a unit in physics.
A unit shouldn't alter as time or environmental factors like pressure and temperature change.It ought to be precisely defined.It need to be readily available and repeatable.Unit of work is that of energy, that is, Joule (J).
Again, work = force × displacement
Unit of work = Unit of force × Unit of displacement = Newton . meter (N.m).
Hence, the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).
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For a uniformly accelerated motion the graph of displacement versus time would be
Explanation:
hope this may help you
have a nice day
A 50 kg driver of a car is traveling at 35 m/s when she hits a large deer. She strikes the air bag/seatbelt combination that brings her body to a stop in 1.1s. What is the impulse imparted to the driver of the car?
Answer:1590 N
Explanation:
Impulse = change in momentum/time
change in momentum = 0 - 50 x 35 = -1750
-1750/1.1 = 1590 (3s.f.) N
I need help to build a mouse trap race car for my science class and this is my final and these are the materials I have.
So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.
Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.
Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.
Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).
If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.
Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.
Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.
Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]
Electrical tape
Rubber bands
Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)
A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball
Hi there!
I. They are the same.
Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.
The engine of a 2400 kg car applies a force of 740 N to make the car accelerate. Calculate the
acceleration of the car.
Answer:
0.31 m/s²Explanation:
The acceleration of an object given only it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass in kg
From the question
m = 2400 kg
f = 740 N
We have
[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]
We have the final answer as
0.31 m/s²Hope this helps you
A point charge of 5. 0 Ă— 10â€""7 C moves to the right at 2. 6 Ă— 105 m/s in a magnetic field that is directed into the screen and has a field strength of 1. 8 Ă— 10â€""2 T. What is the magnitude of the magnetic force acting on the charge? 0 N 2. 3 Ă— 10â€""3 N 23 N 2. 3 Ă— 1011 N.
The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.
Given to us,
the charge [tex]q[/tex] = [tex]5\times 10^{-7}[/tex] C,
the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex] m/sec,
the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,
angle between the direction of v and B [tex]\theta[/tex] = 0,
Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by
[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]
Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N
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If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50 km/h?
Answer:
This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h
24.29m/s or 87.4km/h
Explanation:
Let's find the acceleration of the car:
let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s
a = (vf-vi)/Δt
a = (16.67m/s-0)/8.0
a = 2.08m/s^2
Now we can use this acceleration to find vf in the second part:
50km/h is 13.89m/s
a = (vf-vi)Δt
vf = aΔt + vi
vf = 2.08m/s^2*5.0+13.89m/s
vf = 24.29m/s (87.4km/h)
If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?
PLEASE ANSWER
CORRECTLY PLS
Answer:
The reaction force is the water pushing the swimmer in the rightward direction.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Can someone please give me the (Answers) to this? ... please ...
Explanation:
1. By Newton's 3rd Law, both forces are equal and opposite. Hence both forces are of the same magnitude.
2. The reaction force is the force of arrow on bowstring.
3. Forward force of fish on water and vice versa?
4. The mass of the person is very small as compared to mass of earth. Hence the force exerted is very small amd hence the recoil is not noticed.
5. Reaction force is the force of ball against the bat. By Newton's Third Law, they form an action reaction pair. Hence, they are equal in magnitude and opposite in direction.
6. The reaction force will also decreases as both forces are equal in magnitude.
7 im nt sure sorry Ahahah
____________ is a medium-sized flat-topped hill with cliff-face sides that is taller than it is wide.
Answer:
mesa
Explanation:

A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.
How would you describe the motion of a transverse wave
A car has a kinetic energy of 4.33x10^5 J when traveling a speed of 25 m/s. What is the mass ?
A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling
7.0 m/s in the opposite direction. If the bumpers lock. What is the velocity of the
two vehicles together immediately following the collision?
Using law of conservation of momentum
[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]
[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]
[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]
[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]
[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]
Can someone help me with this physics question? I don't know which answer is correct.
3. Distance is a quantity that is always a vector.
B.
Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart 1. How much force is exerted into cart 2? Explain.
The force exerted on the cart 2 during the collision is 2 N.
The given parameters:
Mass of cart 1 = m1 = 1 kgMass of cart 2 = m2 = 2kgForce applied on cart 1 = 2 NAccording to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.
[tex]F_1 = -F_2[/tex]
[tex]F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N[/tex]
Thus, the force exerted on the cart 2 during the collision is 2 N.
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When a force is applied to an object, no work is being preformed on the object unless the object____.
how to find change in kinetic energy with velocity
Answer:
We know that ΔK = Kf - Ki = 1/2 m Vf^2 - 1/2 m Vi^2 = 1/2m(Vf^2-Vi^2) = 1/2 m ΔV^2.
The mass remains the same, just calculate the difference of squared velocities and multiply it by half of the mass.
what equation do you use to calculate force from work to distance
Answer:
Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
A passenger of mass 90kg is involved in a minor car crash. The car approaches a solid barrier at 32m/s. It crashes into the barrer and stops in 0.2s. Determine the impulse that must be applied to the car to bring it to rest
Answer:
I hope this helps:)
Explanation:
good luck:)