In a Healthy Jogging event, a few hundred participants were expected to jog 7 800 000 metres altogether. They had jogged 25 000 metres in the first few minutes. How many thousands must be added to 25 000 to make 7 800 000?

They can present in 96 different orders. Given, there are five student groups to present in class and one group cannot go first because they need additional set-up time.

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

We have 5 positions to fill here.

First position: 4 ways (one of the rest 4 groups will present first)

Second position: 4 ways (one of the rest 3 groups and the group which could not present first, will present second)

Third position: 3 ways (one of the rest 3 groups will present third)

Fourth position: 2 ways (one of the rest 2 groups will present fourth)

Fifth position: 1 way (rest group will present last)

Total ways in which they can present = 4*4*3*2*1 = 96

Hence, the answer is 96.

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Step-by-step explanation:

since we can officially use only one point (the given point), we need to start with the point-slope form :

y - y1 = m(x - x1)

with m being the slope, (x1, y1) being the point.

sadly, to get the slope, we need a second point anyway, because the slope is the ratio

y coordinate difference / x coordinate difference

when going from one point on the line to another.

I recommend to use (0, 50) for the "other" point, as there seems to be the smallest error in the coordinates.

so, when going from (0, 50) to the given point (6, -40) :

x changes by +6 (from 0 to 6).

y changes by -90 (from 50 to -40).

the slope m = -90/+6 = -15/1 = -15

y - -40 = -15(x - 6) = -15x + 90

y + 40 = -15x + 90

y = -15x + 50

that is the slope-intercept form.

m = -15

b = 50

y = -242

-242 = -15x + 50

-292 = -15x

x = -292/-15 = 292/15 = 19.46666666... ≈ 19

Probabilities (at least 13 graduates) = 0.29858

The variable is binomial, which means that it can only have two possible outcomes (in this case, either a student will graduate or they will drop out). The probability of at least 13 students out of 15 graduating is calculated by adding the probability of exactly 13 students graduating and the probability of exactly 14 students graduating:

P(at least 13 graduate) = P(exactly 13 graduate) + P(exactly 14 graduate)

To calculate the probability of exactly 13 students graduating, use the binomial formula:
P(X = 13) = (15 choose 13) * (0.105)13 * (0.895)2

The calculation for P(X = 13) is: (15 choose 13) * (0.105)13 * (0.895)2 = (15!/13!(15-13)!) * (0.105)13 * (0.895)2 = (15 * 14 / 1 * 1) * (0.00155) * (0.80505) = 0.16437

Similarly, to calculate the probability of exactly 14 students graduating, use the binomial formula:
P(X = 14) = (15 choose 14) * (0.105)14 * (0.895)1

The calculation for P(X = 14) is: (15 choose 14) * (0.105)14 * (0.895)1 = (15!/14!(15-14)!) * (0.105)14 * (0.895)1 = (15 / 1) * (0.01462) * (0.895) = 0.13421

Finally, add the probabilities together to find the probability of at least 13 students graduating.
P(at least 13 graduates) = P(exactly 13 graduate) + P(exactly 14 graduate)
P(at least 13 graduates) 0.16437 + 0.13421 = 0.29858, rounded to three decimal places.

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(a) The probability that exactly two cars finish the race is 0.0512.

(b) The probability that at most two cars finish the race is 0.05792.

(c) The probability that at least three cars finish the race is 0.94208.

(a) To determine the probability that exactly two cars finish the race, we have to use binomial distribution. In this case, we have n = 5 trials, and p = 0.8 is the probability that a car finishes the race (1 - 0.2). Using the binomial distribution formula:

P(X = k) = (nCk)(p^k)(1 - p)^(n - k)

Where X is the number of cars that finish the race, we get:

P(X = 2) = (5C2)(0.8²)(0.2)³= (10)(0.64)(0.008)= 0.0512

Therefore, the probability that exactly two cars finish the race is 0.0512.

(b) To determine the probability that at most two cars finish the race, we have to calculate the probabilities of 0, 1, and 2 cars finishing the race and add them up.

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)= (5C0)(0.8⁰)(0.2)⁵ + (5C1)(0.8¹)(0.2)⁴ + (5C2)(0.8²)(0.2)³= 0.00032 + 0.0064 + 0.0512= 0.05792

Therefore, the probability that at most two cars finish the race is 0.05792.

(c) To determine the probability that at least three cars finish the race, we can calculate the probability of 0, 1, and 2 cars finishing the race and subtract it from 1, which gives us the probability of at least three cars finishing the race.

P(X ≥ 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)]= 1 - (0.00032 + 0.0064 + 0.0512)= 0.94208

Therefore, the probability that at least three cars finish the race is 0.94208.

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The compass directions that are given to A, B and C. are East, South-East and North-west respectively.

North, South, East, and West are the four cardinal directions. The sun's rising and setting serve as a point of reference for these instructions.

Thus, the compass directions that are given to A, B and C. are East, South-East and North-west respectively.

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A The amount of money in a savings account with an annual interest rate of 1.5%

Accοrding tο the fοrmula fοr the quadratic equatiοn, the maximum height is 98 ft.

A quadratic equatiοn is a secοnd-degree pοlynοmial equatiοn οf the fοrm:

[tex]ax^2 + bx + c = 0[/tex]

where a, b, and c are cοnstants, and x is the variable. The term "quadratic" cοmes frοm the Latin wοrd "quadratus," meaning square, because the variable is squared in this type οf equatiοn.

Quadratic equatiοns can have οne, twο, οr zerο real sοlutiοns, depending οn the values οf the cοnstants a, b, and c. The sοlutiοns can be fοund using the quadratic fοrmula:

[tex]x = (-b\± \sqrt{(b^2 - 4ac)}) / 2a[/tex] οr by factοring the quadratic expressiοn intο twο linear factοrs.

The quadratic functiοn tο mοdel the vertical mοtiοn is:

[tex]h(t) = -16t^2 + v0t + h0[/tex]

where:

h(t) is the height at time t

t is the time in secοnds

v0 is the initial vertical velοcity in ft/s

h0 is the initial height in ft

Given v0 = 32 ft/s and h0 = 82 ft, the functiοn becοmes:

[tex]h(t) = -16t^2 + 32t + 82[/tex]

Tο find the maximum height, we can use the vertex fοrm οf a quadratic equatiοn:

[tex]h(t) = a(t - t0)^2 + h0[/tex]

where:

a is the cοefficient οf the quadratic term

t0 is the time at which the maximum height is achieved

h0 is the initial height

Cοmparing the twο fοrms, we see that a = -16 and t0 = -b/2a, where b is the cοefficient οf the linear term. In this case, b = 32, sο:

t0 = -32 / (2(-16)) = 1

Therefοre, the maximum height is achieved at t = 1 secοnd. Substituting intο the οriginal equatiοn, we get:

[tex]h(1) = -16(1)^2 + 32(1) + 82 = 98 ft[/tex]

Sο the maximum height is 98 ft.

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Answer: Do not agree.

Step-by-step explanation:

To determine if we agree with Marcus, we need to verify if the percentages he used on rides, video games, and batting cage add up to 100%.

Marcus used 25% of the tickets on rides and 1/2 on video games. So, the total percentage of tickets he used is:

25% + 1/2 × 100% = 25% + 50% = 75%

This means that Marcus should have used 25% of the tickets in the batting cage. If he said he used 23% of the tickets in the batting cage, then we do not agree with him.

The relationship in the table is a function because each input (x) has exactly one output (y). The equation for the relationship is y = 4 - x. The points (1, 3), (2, 2), and (3, 1) would all fall on this line.

In mathematics, an equation is a statement that shows the equality between two expressions, usually with one or more variables. An equation is typically represented using an equals sign (=) between the two expressions.

For example, the equation 2x + 5 = 11 shows that the expression 2x + 5 is equal to 11. This equation has one variable, x, which can be solved to find its value. In this case, we can subtract 5 from both sides of the equation to get 2x = 6, and then divide both sides by 2 to get x = 3.

The relationship in the table is a function because each input (x) has exactly one output (y).

Using words, the relationship could be described as "y is equal to 4 minus the value of x."

The equation for the relationship is y = 4 - x.

The graph of the relationship would be a straight line that starts at the point (0, 4) and slopes downward to the right. The points (1, 3), (2, 2), and (3, 1) would all fall on this line.

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Answer:

x = 4

Step-by-step explanation:

6x + 21  =  5x + 25

Then, subtract 5x from both sides:

x + 21  = 25

Then, subtract 21 from both sides.

x = 4

Therefore, x is equal to 4 degrees

the exponent of the product of 8.9 x 10¹² and 4.7 x 10⁻² in scientific notation is 11.

Exponential refers to a mathematical function or relationship in which a variable (such as x) is raised to a constant power (such as 2, 3, or e) to produce a result. The term "exponential" can also be used more broadly to describe any situation in which something grows or changes at an increasingly rapid rate over time, often with a compounding effect.

First, we multiply the two numbers:

(8.9 x 10¹²) x (4.7 x 10⁻²) = 41.83 x 10¹⁰

41.83 x 10¹⁰ = 4.183 x 10¹¹

Therefore, the exponent of the product of 8.9 x 10¹²and 4.7 x 10⁻² in scientific notation is 11.

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Answer:

same

Step-by-step explanation:

They are the same since

1/2÷4=1/2×1/4(reciprocal)

Answer:

dfgdfvdfvthtybg f cv v  

Step-by-step explanation:

Answer:

Yes, we can use the given information to prove that $\triangle ABC\cong\triangle DEF$ by the Angle-Side-Angle (ASA) congruence criterion.

We are given that $\angle A\cong\angle D$ and $\angle C\cong\angle F$, which satisfies the Angle-Angle (AA) criterion. Furthermore, we are given that $\overline{AC}\cong\overline{DF}$, which satisfies the Side-Side-Side (SSS) criterion. Therefore, by combining the AA and SSS criteria, we can conclude that $\triangle ABC\cong\triangle DEF$ by the ASA criterion.

In summary, the given information satisfies the necessary conditions for the ASA congruence criterion, and therefore we can prove that $\triangle ABC\cong\triangle DEF$.

The area of the sector is 40 cm².

Let us consider a circle of radius 2 cm. If an arc of this circle subtends an angle of 20 radian to the centre, then the length of the arc and area of the sector such formed are as follows:Length of the arcThe arc length of a circle is given by the formula L = rθ where r is the radius of the circle and θ is the angle subtended by the arc of the circle in radians.L = rθWhere L = Length of the arc, r = radius of the circle and θ = angle subtended by the arc of the circle in radians.Substituting the values r = 2 cm and θ = 20 radians, we have:L = 2 x 20 cmL = 40 cmTherefore, the length of the arc is 40 cm.Area of the sectorThe area of a sector is given by the formula A = (1/2) r²θ where r is the radius of the circle and θ is the angle subtended by the arc of the circle in radians.A = (1/2) r²θWhere A = area of the sector, r = radius of the circle and θ = angle subtended by the arc of the circle in radians.Substituting the values r = 2 cm and θ = 20 radians, we have:A = (1/2) x 2² x 20A = (1/2) x 4 x 20A = 40 cm²Therefore, the area of the sector is 40 cm².

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Answer:

Step-by-step explanation:

ur mom

The answer is the lower bound theorem identifies -2 as a lower bound for the real zeros of f(x). The upper bound theorem does not specify any upper bound for the real zeros of (x)

The Lower bound theorem states that "If the terms of a polynomial are arranged in descending order of their degrees, then the absolute value of the quotient of the constant term and the coefficient of the term of the highest degree gives a lower bound for the absolute value of its zeros." Let's examine whether the lower bound theorem identifies -2 as a lower bound for the real zeros of f(x) and whether 3 is an upper bound for the real zeros of (x).

As f(x) = 56 = x + 17x² + 11x + 23Since f(x) is not arranged in descending order of their degrees, we have to rearrange it as follows. 17x² + 11x + x + 23 + 56 = 17x² + 12x + 79 on rearranging the equation we have: 17x² + 12x + 79 = 0Hence the constant term is 79 and the coefficient of the term of the highest degree is 17. Thus, using the lower bound theorem, we can evaluate that a lower bound for the absolute value of the zeros of the polynomial is 79/17 ≈ 4.65 Since -2 is less than the calculated lower bound of 4.65, it is indeed a lower bound for the real zeros of f(x). Now, for (x), the constant term is 0, and the coefficient of the term of the highest degree is 1. Thus, using the upper bound theorem, we can evaluate that an upper bound for the absolute value of the zeros of the polynomial is 1/0, which is equal to infinity. Since infinity is not a number, 3 cannot be an upper bound for the real zeros of (x).

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Florian has to pay $2,013.3, then he own on his car for 3 months

"A method to find a single unit value from a multiple unit value and to find a multiple unit value from a single unit value."

We always count the unit or amount value first and then calculate the more or less amount value. For this reason, this procedure is called a unified procedure.

Many set values ​​are found by multiplying the set value by the number of sets.

A set value is obtained by dividing many set values ​​by the number of sets.

According to our question-

6040 is the total amount

he has to repay in 3 months

dividing the total amount/3

6040/3

$2,013.3

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Answer:

the numbers are

[tex] \sqrt{10} + 5 \\ - \sqrt{10} + 5[/tex]

Step-by-step explanation:

then there difference is

square root of 10 + 5 -(- square root of 10 +5)

=

[tex]2 \sqrt{10} [/tex]

and the cube of there sum is 15^3 = 15* 15* 15

= 3375

The given example of f(1011) = 1110 illustrates how a one-to-one function operates, in that the same bitstring is not mapped to multiple elements in the range.

For the given functions f: A -> A and g: A -> A which are one-to-one functions, the following statements are true:

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Answer: $8

Step-by-step explanation:

To find how much he saved over the course of 6 weeks, subtract 62 from 110.

110 - 62 = 48

To find how much he saved each week, divide 48 by 6.

48 ÷ 6 = 8

Liam saved $8 each week.

Normal quantile plot is a graph of points (x,y) where each x-value is from the original set of sample data, and each y-value is the corresponding Z-score that is a quantile value expected from the standard normal distribution.

What is a Normal Quantile Plot?

A normal quantile plot is a graphical tool used to determine whether a data set is normally distributed or not.

It plots sample data versus a theoretical normal distribution.

In general, the points on the plot should form a straight line if the data is normally distributed. If the data is not normally distributed, the points on the plot will not form a straight line.

A normal quantile plot can be used to evaluate the following:

The normal quantile plot of the residuals is the most important diagnostic tool for examining whether the assumptions of a linear regression model have been met.

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The equation of Line 1 in the form y=-12x+28

A measurable path between two places is referred to as a line segment. Line segments may make up the sides of any polygon since they have a set length.

Coordinates of Line 2 M(4,5) and N(6,-19)

Slope of Line 2 is =(-19-5)/(6-4)

=-24/2=-12

Slope of line 1 and line 2 are same

Cordinate of Line 1 is D(2,4)

D(2,4) must pass through line 1, so it must satisfy the equation

y=mx+b

4=2(-12)+b

4+24=b

b=28

the equation of Line 1 in the form y=-12x+28

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The value of x is equal to; A. 5.

In Mathematics, the basic proportionality theorem states that when any of the two (2) sides of a triangle is intersected by a straight line which is parallel to the third (3rd) side of the triangle, then, the two (2) sides that are intersected would be divided proportionally and in the same ratio.

By applying the basic proportionality theorem to the given triangle, we have the following:

x/(x + 5) = (x - 2)/(x + 1)

By cross-multiplying, we have the following:

x(x + 1) = (x - 2)(x + 5)

x² + x = x² + 5x - 2x - 10

By rearranging and collecting like-terms, the value of x is given by:

2x - 10 = 0

2x = 10

x = 10/2

x = 5.

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Answer:

i hope it helps, just keep it up your work. good luck

Answer:

CP of computer = 27000 rs.

Step-by-step explanation:

D% = Dis/MP*100

We know, Dis = MP-SP

Given Profit= 1160 rs.

So,CP = 27000 rs.

When both groups are shifted to a situation in which they earn an alternative reward after being trained to navigate a runway for food, the group that received three food pellets will continue to perform the task at a high level while the group that received one food pellet will experience difficulty.

It is known that rats have a natural preference for higher rewards. As a result, the group that received three pellets will be more motivated to complete the task since they have already tasted a higher reward. Therefore, they will continue to perform at a high level in the new environment.

On the other hand, the group that received only one pellet may find it challenging to adapt to the new situation since they are now receiving a lower reward. As a result, they may struggle to complete the task, and their performance may decrease.

In conclusion, the group that received three pellets will perform better than the group that received one pellet when both groups are shifted to a situation in which they earn an alternative reward. This is because the rats have a natural preference for higher rewards.

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the best rule to describe this rotation is:

(x, y) → (-y, x)

Why it is?

The given rotation is a 270 degree clockwise rotation about the origin. This means that each point in Triangle ABC is rotated 270 degrees in a clockwise direction around the origin to produce the corresponding point in Triangle A'B'C'.

One possible rule to describe this rotation is:

(x, y) → (-y, x)

This rule represents a 90 degree clockwise rotation about the origin, which can be applied three times to achieve a 270 degree clockwise rotation.

So, if we apply this rule to each vertex of Triangle ABC, we get the corresponding vertices of Triangle A'B'C':

A = (a, b) → A' = (-b, a)

B = (c, d) → B' = (-d, c)

C = (e, f) → C' = (-f, e)

Therefore, the best rule to describe this rotation is:

(x, y) → (-y, x)

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