Answer:
12 have a bicycle
Step-by-step explanation:
There are 30 students and 40% have a bicycle
30 * .40
12
12 have a bicycle
Answer: 12
40% of 30 is 12.
If you start with 65 milligrams of Chromium 51, used to track red blood cells, which has a half-life of 27.7 days. How long will it take for 80% of the material to decay?
Answer:
Half-Life uses the formula N () = Noe # No = Initial Amount time h = length of half-life. Ifyou start with 65 milligrams of Chromium 51,used to track red blood cells, which has half-life of 27.7 days: How long will it take for 80% ofthe material to decay? t= (27.7) h5 (65) (h3) 4= (27.7) h; (05)
Step-by-step explanation:
For the given data it will take 8.69 days for 80% of the material to decay.
What is half-life?A radioactive substance's half-life is typically described as the amount of time it takes for one-half of its atoms to disintegrate or change into another substance.
It is given that, If you start with 65 milligrams of Chromium 51, used to track red blood cells, which has a half-life of 27.7 days.
N₀ = 65 milligrams
t1/2=27.7 days
N(t)=0.8(65 milligrams)=52 milligrams
[tex]N(t) = N_0(1/2)^ {\frac{t}{t_{1/2}} }[/tex]
Here,
N(t) is the amount of the substance remaining
N₀ is the initial substance amount
t is the time elapsed
t1/2 is the half-life
Substitute the given values,
[tex]N(t) = N_0(1/2)^ {\frac{t}{t_{1/2}} } \\\\ 52 = 65(1/2)^\frac{t}{27.7} \\\\ 52=65\left(\frac{1}{2}\right)^{\frac{t}{27.7}} \\\\ \frac{65\left(\frac{1}{2}\right)^{\frac{t}{27.7}}}{65}=\frac{52}{65} \\\\ \left(\frac{1}{2}\right)^{\frac{t}{27.7}}=\frac{4}{5} \\\\ \frac{t}{27.7}\ln \left(\frac{1}{2}\right)=\ln \left(\frac{4}{5}\right) \\\\ t =-\frac{27.7\ln \left(\frac{4}{5}\right)}{\ln \left(2\right)}[/tex]
[tex]t = 8.69 \ days[/tex]
Thus, for the given data it will take 8.69 days for 80% of the material to decay.
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Marking as brainliest! Find the missing side
Answer:
The trick for these is finding out what makes the largest known value into the corresponding lower value. Then we use that number to find the missing side length based on the value we know.
1. The missing side length is 40.
We can find this by dividing 70 by 56 to get 1.25. We then multiply this by 32 to get our missing side length.
2. The missing side length is 91.
We can find this by dividing 130 by 30 to get 4.333(repeating decimal). We then multiply this by our known value (21) to get our answer of 91.
3. The missing side length is 21.
We can fid this by dividing 36 by 12 to get 3. Then we multiply this by 7 (our known value) to get our answer.
Step-by-step explanation:
hope this helps. . .<3
good luck! UwU
Help I’ll mark you brainlist
Answer:
24.0
Step-by-step explanation:
do 34sin(45) to solve for x
Solve the equation.
-9x + 1 = -x + 17
Step-by-step explanation:
-9x + 1 = -x + 17
collect like terms
-9x + x = 17-1
-8x = 16
divide both sides by -8
-8x/-8 = 16/8
x = 2
What two numbers multiply to -15 and add to 8
Find the median for the following group of data items.
36, 33, 32, 31, 37, 34, 30, 32
Answer:
32.5
Step-by-step explanation:
order the numbers) 30, 31, 32, 32, 33, 34, 36, 37
cancel the numbers from each side to the middle) 32 and 33
add the values together and divide by two) [32+33] divide by 2=65/2=32.5
Are the expressions 0.85b-0.2b and 0.65b equivalent?
Hello!
0.85b-0.2b
0.65b
0.65b=0.65b
So these expressions are equivalent.
Hope it helps!
~Just a determined gal
#CarryOnLearning
[tex]MysteriousNature[/tex]
$4800 is 60% of what number?
Answer:
8000
Step-by-step explanation:
Jack’s truck had used 30 gallons of fuel from a 50 gallon tank. What percentage was used? *
anwers: is 15 because I did 30 percent of 50
[tex]2 {}^{3} \times 2 - {}^{3} [/tex]
I need answers
Lauren spends her allowance $50 a month on make up and CDs. She spends $10 more a month on CDs than she does on make up. How much money does she spend every month on each product
Answer:
$30 on CDs
$20 on Makeup
hope it helps
Step-by-step explanation:
The money spent on each product is $20 and $30 respectively.
How to solve a linear equation?A linear equation can be solved by equating the LHS and RHS of the equation following some basic rules such as by adding or subtracting the same numbers on both sides and similarly, doing division and multiplication with the same numbers.
Given that,
The money spent by Lauren on make up and CDs is $50.
Suppose the money spent on CDs be x.
Then, the money spent on make up is x + 10.
As per the question the following equation can be formed,
x + x + 10 = 50
=> 2x + 10 = 50
=> 2x = 40
=> x = 20
Thus, money spent on make up is 20 + 10 = 30 dollars.
Hence, the money spent on CDs and make up is $20 and $30 respectively.
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The length of a rectangular garden is 7 feet longer than its width. The garden's perimeter is 178 feet. Find the length of the garden.
Answer: 48
Step-by-step explanation:
l = w + 7
2w + 2l = 178
2w + 2(w + 7) = 178
2w + 2w + 14 = 178
4w = 164
w = 41
l = w + 7
l = 41 + 7
l = 48
The world population of a certain species is evaluated at 6.8 × 109. By some projections, this population will be 8 times more important in 30 years. Express the population at that time in scientific notation.
Using the multiplication operation, the population of the species in 30 years would be 8 times the current population. Hence, the population at the time would be [tex] 5.44 \times 10^{10}[/tex]
Current population = [tex] 6.8 \times 10^{9}[/tex]Therefore, 8 times the current population can be calculated thus :
[tex] 6.8 \times 10^{9} \times (8) = 54.4 \times 10^{9}[/tex]
Therefore, the population at the time would be [tex] 5.44 \times 10^{10}[/tex]
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Find the domain of the function.
f(x) = -5x + 3
Enter a problem...
Calculus Examples
Popular Problems Calculus Find the Domain and Range f(x)=5x-3
f
(
x
)
=
5
x
−
3
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
R
}
The range is the set of all valid
y
values. Use the graph to find the range.
Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
y
|
y
∈
R
}
Determine the domain and range.
Domain:
(
−
∞
,
∞
)
,
{
x
|
x
∈
R
}
Range:
(
−
∞
,
∞
)
,
{
y
|
y
∈
R
}
Please helpppp I will mark you branliest pleaseee
Answer:
no
Step-by-step explanation:
the ratios shown in this table are not proportionate. You will also never get (0,0) in this table.
Evaluate ∫ y2dx + x dy along the following paths. (a) C = C1 is the line segment from (-13, -7) to (0, 6) (b) C = C2 is the arc of the parabola x = 36 - y2 from (-13, -7) to (0, 6).
a. Parameterize C₁ by
[tex](x(t),y(t)) = (1-t)(-13,-7) + t(0,6) = (-13+13t,-7+13t)[/tex]
with 0 ≤ t ≤ 1. Then both dx = 13 dt and dy = 13 dt, so that the line integral along C₁ is
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \int_0^1 (-7+13t)^2(13\, dt) + (-13+13t)(13\,dt)[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = 13 \int_0^1 (169t^2 - 169t + 36) \, dt[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = 13 \left(\frac{169}3-\frac{169}2+36\right) = \boxed{\frac{611}6}[/tex]
b. Parameterize C₂ by
[tex](x(t),y(t)) = (36-t^2,t)[/tex]
with -7 ≤ t ≤ 6. Then dx = -2t dt and dy = dt, so the line integral is
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \int_{-7}^6 t^2(-2t\,dt) + (36-t^2)\,dt[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \int_{-7}^6 (36-t^2-2t^3) \, dt[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \left(36\cdot6-\frac{6^3}3-\frac{6^4}2\right) - \left(36\cdot(-7)-\frac{(-7)^3}3-\frac{(-7)^4}2\right) = \boxed{\frac{5005}6}[/tex]
Could I get help…………
Answer:
B
Step-by-step explanation:
HOPE IT HELPS <3
MARK as brainliest
Write 7% as a fraction or mixed number in simplest form
Answer:
7/100
Step-by-step explanation:
:)
100 points if you answer - if it's correct ill give brainliest
(01.04 MC)The elevation of city A is 60 feet above sea level; the elevation of city C is 12 feet above sea level. The elevation of city D is 1 over 2 of the elevation of city C.
Part A: Write an expression to represent the elevation, in feet, of city D. (5 points)
Part B: Solve the expression and explain why the answer is negative or positive. (5 points)
Answer & Step-by-step explanation:
A = 60 ft
C = 12
D = 1/2 of C
1/2 of 12 = 6
Part A:
e = 6ft
Part B:
It's positive because it is above sea level
Answer:
Step-by-step explanation:
gg I got the points
NEED HELP!! THANK YOU
Answer:
Expression: -7 + 8f - 2b - f + 3b + 6
# of Terms: 6
Like Terms: 8f and f, -2b and 3b, and -7 and 6
Coefficients: 8, 1, -2, and 3
Constants: -7 and 6
Expression: -11x + 4 + 8x - 4 + 3x
# of Terms: 5
Like Terms: -11x, 8x, and 3x & 4 and -4
Coefficients: -11, 8, and 3
Constants: 4 and -4
Step-by-step explanation:
The coefficient is the number in front of the variable.
The variable is any letter that you may see in an expression.
Terms are the numbers and variables, that are separated by the different signs.
Like terms are the terms that share the same variable/exponent.
Constants are the terms without variables.
Hope this helps you :)
Sorry if it's somehow wrong.
14 out of the 70 people in a company meeting were managers. What percentage of the
meeting attendees were managers?
Write your answer using a percent sign (%).
Answer:
20%Step-by-step explanation:
14 out of 70 given as percentage:
14/70*100% = 20%Lets see
14/70(100)1/5(100)20%A coach divided his team into two groups of equal size.
.
of the first group drinks at least 2 glasses of water a day
• 75% of the second group drinks at least 2 glasses of water a day.
What fraction of the team drinks at least 2 glasses of water a day?
Applying the percentages, and considering that 70% of the first group drinks at least 2 glasses of water a day, it is found that 0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
The team is divided into two equal groups, hence, each represents 50%.
The percentages associated with drinking at least 2 glasses of water a day is:
70% of 50%(first group)75% of 50%(second group)Hence, applying the weighed percentage, the total percentage is:
[tex]T = 0.7(0.5) + 0.75(0.5) = 0.725[/tex]
0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
A similar problem is given at https://brainly.com/question/1517088
5. Use the point-slope formula to determine the equation of a line that passes through the points (1, 2) and (-2, 1).
Answer:
In point-slope form the equation is:
[tex]y - 2 = \binom{1}{3} \times (x - 1)[/tex]
6 Cyclist A travels 55 km in 2 hours and 20 minutes.
Cyclist B travels 135 km in 5 hours and 36 minutes.
Which cyclist is travelling faster?
cyclist a speed is d = v × t
so you can find velocity of a and b.
then compare them both.
Help no links Pleaseeeeeee
Answer:
[tex]\huge\boxed{z=6;\ x=12.5}[/tex]
Step-by-step explanation:
If two figures are similar, then corresponding sides are in proportion.
Therefore:
[tex]\dfrac{z}{15}=\dfrac{4}{10}\qquad|\text{cross multiply}\\\\10z=(15)(4)\\\\10z=60\qquad|\text{divide both sides by 10}\\\\\boxed{z=6}[/tex]
[tex]\dfrac{x}{5}=\dfrac{10}{4}\qquad|\text{cross multiply}\\\\4x=(5)(10)\\\\4x=50\qquad|\text{divide both sides by 4}\\\\x=\dfrac{50}{4}\\\\\boxed{x=12.5}[/tex]
Find the critical points, relative extrema, and saddle points of the function. (If an answer does not exist, enter DNE.) f(x, y) = 25 − (x − 5)2 − y2
Take the first partial derivatives of f(x, y):
∂f/∂x = -2 (x - 5) = 10 - 2x
∂f/∂y = -2y
The critical points occur where both derivatives are zero:
10 - 2x = 0 ===> x = 5
-2y = 0 ===> y = 0
So there is only critical point at (5, 0), which takes on a value of f(5, 0) = 25.
Compute the Hessian matrix for f :
[tex]H(x, y) = \begin{bmatrix}\frac{\partial^2f}{\partial x^2} & \frac{\partial^2f}{\partial x\partial y} \\ \frac{\partial^2f}{\partial y\partial x} & \frac{\partial^2f}{\partial y^2}\end{bmatrix} = \begin{bmatrix}-2&0\\0&-2\end{bmatrix}[/tex]
Since det(H(x, y)) = 4 > 0 for all x, y, the critical point (5, 0) is a relative minimum.
f has no saddle points.
If f(x) = 4x + 3x2 + 1, then what is the remainder when f(x)
is divided by X -2?
Answer:
remainder = 21
Step-by-step explanation:
If f(x) is divided by (x - h) then the remainder is f(h)
Here f(x) is divided by (x - 2) with h = 2 , then remainder is
f(2) = 4(2) + 3(2)² + 1 = 8 + 3(4) + 1 = 8 + 12 + 1 = 21
The ratio of boys and girls are 2:5. If the total number of students in school are 350, find the number of girls.
Answer:
250 girls
Step-by-step explanation:
Add the ratio together (2+5=7), then do 350÷7=50
50 is one part of the ratio so to find how many girls, you would do 50x5=250
Add or subtract. write fractions in simplest form.
-5/3 + 2 1/3
how do i do this problem? i will mark you brainliest. please help!
Answer:
2/3
Step-by-step explanation:
-5/3 + 2 1/3 =
= 2 1/3 - 5/3
= 2 1/3 - 1 2/3
= 1 4/3 - 1 2/3
= 2/3
Answer:
2/3
Step-by-step explanation:
First, change 2 1/3 into an improper fraction.
2 1/3 --> 7/3
Substitute that value back into the equation
-5/3 + 7/3
At this point, you can rewrite the equation into:
7/3 - 5/3
Since they have the same denominator, just subtract the numerator's values.
2/3
Claudia trabaja en una fábrica de carritos de supermercado, como criterio de calidad de la fábrica se establece que un carrito con mercancia que tenga una masa de 30kg no debe superar los 30N de fuerza de empuje para comenzar a moverse, ni los 20N para mantenerse en movimiento, cual es el valor de la aceleración que experimentara al soltarse?
El carro de mercancía experimenta una aceleración neta de 0.333 metros por segundo al cuadrado al soltarse.
En esta situación se requiere una fuerza de 30 N para alcanzar la fuerza estática máxima ([tex]f_{s}[/tex]), entonces la fuerza de fricción ([tex]f_{k}[/tex]) se reduce a 20 N mientras se encuentre en movimiento. Si consideramos que la fuerza externa de 30 N se mantiene durante el fenómeno físico, entonces tenemos que la aceleración neta ([tex]a[/tex]), en metros por segundo al cuadrado, experimentada por el carrito de mercancía es determinada a partir de las leyes de Newton:
[tex]a = \frac{F-f_{k}}{m}[/tex] (1)
Donde [tex]m[/tex] es la masa del carrito de mercancía, en kilogramos.
Si sabemos que [tex]F = 30\,N[/tex], [tex]f_{k} = 20\,N[/tex] and [tex]m = 30\,kg[/tex], entonces la aceleración neta del carro de mercancías es:
[tex]a = \frac{30\,N-20\,N}{30\,kg}[/tex]
[tex]a = 0.333\,\frac{m}{s^{2}}[/tex]
El carro de mercancía experimenta una aceleración neta de 0.333 metros por segundo al cuadrado al soltarse.
Invitamos a consultar esta pregunta sobre la fricción seca: https://brainly.com/question/19115001