Answer:
Non-polar
Explanation:
The way to determine if something is polar is by subtracting their electronegativity values. The two atoms in this molecule are both phosphorous which have equal electronegativity values (since they are both phosphorus). Anything minus itself will equal 0. If the final difference between the electronegativity values is less than 0.4, it will be non-polar. Since the result is 0, P2 is non-polar.
In P₂ molecule there is absence of partial charges, thus the molecule has been nonpolar.
The molecules have been differentiated based on polarity as polar and nonpolar molecules. The molecules that have been comprised of the difference in the electronegativity of the elements and develop partial charges have been termed polar compounds.
The compounds with no difference in electronegativity and absence of partial charges are termed nonpolar molecules. In the P₂ molecule, there have 2 phosphorus molecules with the same electronegativities.
Since there has been an absence of polarity in the molecule, the molecule of P₂ is nonpolar.
For more information about polar molecules, refer to the link:
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which model best shows the movement of oxygen during photosynthesis
What do electric conducts and thermal conducts have in comman?
Usually electrical conductors have loosely bound electrons. Materials that conduct heat are thermal conductors
D
Magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide as
shown.
MgCO3 → MgO + CO2
How much magnesium carbonate is needed to make 5.0g of magnesium oxide?
А
3.5g
B 4.09
C 6.5g
D 10.59
The amount of 10.5 g magnesium carbonate is needed to make 5.0g of magnesium oxide.
So, option D is correct.
Given that, Magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide as
MgCO₃ → MgO + CO₂
Molar mass of MgCO₃ = 24 + 12 + 48 = 84 g/mole
Molar mass of MgO = 24 + 16 = 40g/mole
40 gram MgO is produced from 84 gram of MgCO₃
1 gram of MgO produced from [tex]\frac{84}{40}=2.1[/tex] gram of MgCO₃
Therefore, 5 gram of MgO produced from [tex](5*2.1=10.5gram)[/tex] of MgCO₃
Thus, option D is correct.
Learn more about molar mass here:
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find the pOH of a solution made by dissolving 10.4g of HCl in a 500mL solution of water
The pOH of a solution : 13.756
Further explanationMass HCl=10.4 g
mol HCl (MW=36.5 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}=\dfrac{10.4}{36.5}=0.285[/tex]
Volume of HCl = 500 ml = 0.5 L
[tex]\tt M=\dfrac{n}{V}\\\\M=\dfrac{0.285}{0.5}=0.57~M[/tex]
HCl ⇒ H⁺ + Cl⁻
[H⁺]=[HCl]=0.57 M
pH= - log[H⁺]
pH=-log[0.57]=0.244
pH+pOH=14
pOH=14-0.244
pOH=13.756
Question 2
5 pts
(03.01 MC)
The nucleus of an atom is dense and positively charged. What was observed when
positively charged particles were radiated onto a gold atom during Rutherford's
experiment because of this?
O Negative charges were concentrated at the center of the atom.
N
Particles that struck the center of the atom were repelled.
Particles that struck the edges of the atom were repelled.
Positive charges were distributed all over the atom.
Answer:
The correct answer is particles that struck the center of the atom were repelled.
Explanation:
Rutherford performed an experiment which is called the gold foil experiment. In the gold foil experiment of the Rutherford, a gold foil is bombarded with the positively charged alpha particles. The bombardment of the alpha particles shows the unexpected result to Rutherford.
He thought these particles go through the gold foil but to his surprise, some particles bounced back and some deflected after colliding with foil. On the basis of these, he suggested that there is a positive charge present in the center of an atom that repelled the positive charge of alpha particles and leads to deflection and bouncing back.
Thus, the correct answer is particles that struck the center of the atom were repelled.
PLEASE HELP!!!! 60 points
Answer:
Have a nice Day , I would appreciate it if you could mark my answer brainliest
if 1 teacher cant teach all subjects how come 1 student can learn all subjects ?
Answer:
d
d.d.d.d.d.d..d.d.d.d.d.d.d.d..d.d.d.d.d.d.d
Explanation: