NEED AWNSER NOW! WILL MARK BRAINLY! Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through?

index of reflection

index of refraction

angle of reflection

angle of incidence

Answer:

huh?

Explanation:

Answer:

66.6 G

Explanation:

Answer:

The value is  [tex]M = 42.3 \ kg[/tex]

Explanation:

From the question we are told that

    The first  position of the fulcrum  is  x = 49.7 cm

    The mass  attached is [tex]m = 41.5 \ g[/tex]

    The position of the attachment is  [tex]x_1 = 28.5 \ cm[/tex]  

    The second position of the fulcrum is  [tex]x_2 = 39.2 \ cm[/tex]

Generally the sum of clockwise torque =  sum of anti - clockwise torque

So  

       [tex]CWT = m (x_2 - x_1)[/tex]

Here CWT  stands for clockwise torque

       [tex]ACWT = M ( x - x_2)[/tex]

So

      [tex]m (x_2 - x_1) = M ( x - x_2)[/tex]

=>   [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]

=>    [tex]M = 42.3 \ kg[/tex]

Answer:

CLEAN

Explanation:

Answer:

I just wash mine with water when I drop it . That is a good question tho :)

Explanation:

Answer:

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s

Explanation:

The given parameters are;

The curvature of the hill, r = 200 m

Due to the velocity, v, the occupants weight = 20% less than the normal weight

The outward force of an object due to centripetal (motion) force is given by the following equation;

[tex]F_c = \dfrac{m \times v^2}{r}[/tex]

Where;

r = The radius of curvature of the hill = 200 m

Given that the weight of the occupants, W = m × g, we have;

[tex]F_c = 0.2 \times W = 0.2 \times m \times g[/tex]

[tex]\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}[/tex]

v = √(0.2 × g × r)

By substitution, we have;

v = √(0.2 × 9.81 × 200) ≈ 19.81

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.

The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight and this can be determined by using the formula of centripetal force.

Given :

A car is going over the top of a hill whose curvature approximates a circle of radius 200 m.

The centripetal force acting on the car is given by the formula:

[tex]\rm F_c = \dfrac{mv^2}{r}[/tex]   ---- (1)

where m is the mass of a car, v is the velocity of the car and r is the radius of curvature.

Now, it is given that the occupants of the car appear to weigh 20% less than their normal weight that means:

[tex]\rm F_c = 0.2\times W[/tex]

[tex]\rm F_c = 0.2 \times m \times g[/tex]   --- (2)

Now, equate equation (1) with equation (2).

[tex]\rm \dfrac{mv^2}{r}=0.2\times m \times g}{}[/tex]

[tex]\rm v = \sqrt{0.2\times g \times r }[/tex]

[tex]\rm v = \sqrt{0.2\times 9.81 \times 200 }[/tex]

v = 19.81 m/sec

The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight.

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Answer:

Dynamic   a, b and d

Deformer  c and d

Explanation:

When a force is applied to an object, the acceleration may or may not change, which is analyzed from Newton's second law, this effect is a dynamic effect on the system; The environment can change the shape of the object, in this case the force creates a deformation in it.

With these clarifications let's analyze the different situations.

a) Dynamic. When pushing a car initially an acceleration is created in it, shortly after this decreases to zero and continues with constant speed.

b) Dynamic. When the nail moves it does not change the shape of the body that contains it, nor the shape itself, therefore the system can be analyzed with Newton's second law and the force is of the Dynamic type

c) Deformer. In this case the body (clay) has no net movement, but it does change its shape, so the effect of the force translates into a deformation of the system

d) Deformar and Dynamic. The launch of tennis balls has an initial deformation stage during the acceleration process, in this part the force is of the DEFORMING type, but during the trajectory the deformation disappears and the ball has (gravity) a DYNAMIC action

Answer: 60 nm

Multiply 30 and 2

Answer:

Because they could help you move on better with your strategy and ultimately get you better scores on tests  

Answer:

Through feedback, teachers can provide the students with suggestions for development, learning strategies and corrections for errors. The importance of constructive feedback allows for many positive opportunities. This component also enhances a student's self-efficacy and provides an avenue for motivation.

Answer:

31.21 m/s

Explanation:

radius=41m

time = 8 sec

circumference=2πr

from formula

circumference=2×22/7×41

=257.71m

now

velocity=total distance( circumference)/total time

=257.71/8

= 32.21m/s

The velocity of race car makes one lap around a track with a radius of 41 meters in 8 seconds is 32.19 m/s

Velocity is "rate of change of displacement with respect to time".

i.e. v= dx/dt

it is also defined as displacement over time. i.e. v=Displacement/Time.

Velocity shows how much distance can be covered in unit time. It's SI unit is m/s. It is vector quantity ( having both direction as well as momentum). where displacement is distance from mean position.

Given,

Radius of the track r= 41m

time taken by car to complete one lap T = 8s

velocity v = ?

we know that ω = 2π÷T

ω = 2×3.14 ÷ 8

ω = 0.785 rad/s

v=rω

v= 41×0.785

v= 32.185 ≅32.19 m/s

Hence velocity of the car is 32.19 m/s

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Answer:

Acceleration of the car = 2 m/s²

Average velocity of the car =28 m/s

Explanation:

Initial velocity = 20 m/s

Final velocity = 36 m/s

Time taken = 8 s

Acceleration = Δ velocity / time taken

Acceleration = 36-20 / 8 = 16/8 = 2 m/s²

Average velocity of the car =[ Initial velocity + Final velocity ] /2

Average velocity of the car = [ 20+36] / 2 = 28 m/s

Answer: the color of the cloth

Explanation:

Answer:

A. element

Explanation:

A molecule is formed when two or more atoms join together chemically. If atoms combine that are of two or more different elements, we call that a compound. All compounds are molecules, but not all molecules are compounds.

Answer:

True

Explanation:

It is true i am right

Answer:

500N

Explanation:

50kgx10N/kg

= 500N

Answer:Fn

Explanation:

Answer:

the weight of an object is the force acting on the object due to gravity. the gravitational force acting on the object. Others define weight as a scalar quantity, the magnitude of the gravitational force.

Explanation:

Answer:  shadows are not parts of their objects—we can change a shadow without changing the object

Answer:

So we can see objects by seeing silhouettes. By contrast, shadows are not parts of their objects—we can change a shadow without changing the object (say, by putting another object in between the object and the light source). So we cannot see objects by seeing shadows.

Answer:

Its the third quarter or waning quarter

  Hope this helps :3

Answer:

Explanation: 46 billion light years I think

Aww I wanted brainliest:( be doggo, doggo sad :(

Answer:

a) La piedra es lanzada desde una altura de 0,785 metros.

b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Explanation:

a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:

[tex]y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (1)

Donde:

[tex]y[/tex] - Altura final, medida en metros.

[tex]y_{o}[/tex] - Altura inicial, medida en metros.

[tex]v_{o,y}[/tex] - Componente vertical de la velocidad inicial, medida en metros por segundo.

[tex]t[/tex] - Tiempo, medido en segundos.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que [tex]y = 0\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex], [tex]t = 0,4\,s[/tex] y [tex]g = -9,807\,\frac{m}{s^{2}}[/tex], entonces la altura inicial de la piedra es:

[tex]y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}[/tex]

[tex]y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}[/tex]

[tex]y_{o} = 0,785\,m[/tex]

La piedra es lanzada desde una altura de 0,785 metros.

b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:

[tex]v_{o,x} = \frac{x-x_{o}}{t}[/tex] (2)

Donde:

[tex]x_{o}[/tex], [tex]x[/tex] - Posiciones horizontales iniciales y finales, medidas en metros.

[tex]t[/tex] - Tiempo, medido en segundos.

Si tenemos que [tex]x_{o} = 0\,m[/tex], [tex]x = 2,5\,m[/tex] y [tex]t = 0,4\,s[/tex], entonces el componente horizontal de la velocidad inicial es:

[tex]v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}[/tex]

[tex]v_{o,x} = 6,25\,\frac{m}{s}[/tex]

La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Answer:

The distance from the edge of the table at which the ball will hit the ground is approximately 0.49 meters

Explanation:

The mass of the ball = 0.84 kg

The spring constant k = 142 N/m

The compression of the spring = 0.06

Therefore, by conservation of energy, we have;

The potential energy of the spring = The kinetic energy given to the ball

The potential energy of the spring = 1/2 × k × x² = 1/2 × 142 × 0.06² = 0.2556

The potential energy of the spring = 0.2556 J

The kinetic energy given to the ball = 1/2 × m × v²

Where;

v = The final velocity of the ball

Substituting gives;

1/2 × 0.84 × v² = 0.2556

∴ v = √(0.2556/(1/2 × 0.84)) ≈ 0.78

The final velocity of the ball = v ≈ 0.78 m/s

The height of the ball above the ground, h = 2.0 m

Therefore, we have;

The time, t, it takes the ball to touch the ground from the 2.0 m height, h, is given as follows;

h = 1/2·g·t²

t = √(2·h/g)

Where;

g = The acceleration due to gravity = 9.81 m/s²

∴ By substitution, we have;

t = √(2 × 2/9.81) ≈ 0.63855

t ≈ 0.63855 s

The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground

The horizontal distance covered during before the ball hits the ground = The (horizontal) velocity of the ball × The time it takes the ball to touch the ground

∴ The horizontal distance covered during before the ball hits the ground = 0.78 × 0.62855 ≈ 0.490269 ≈ 0.49

The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground  ≈ 0.49 m

Answer:

Explanation:

Trypophobia is a fear or disgust of closely-packed holes. People who have it feel queasy when looking at surfaces that have small holes gathered close together.A person may start by imagining what they fear, then looking at pictures of the fear object, and then finally being near or even touching the source of their anxiety. In the case of trypophobia, a person with symptoms may start by simply closing his eyes and imagining something such as a honeycomb or seed poThey can help you find the root of the fear and manage your symptoms. Last medically reviewed on July 20, 2017 Medically reviewed by Timothy J. Legg, Ph.D., CRNP — Written by Annamarya Scaccia ...

Answer:

46 m at 9.5 degrees east of south

Explanation:

Answer:

C

Explanation:

???

i think

Answer:

B

Explanation:

1 minute = 60 seconds

2 minutes = 2 * 60 = 120 seconds.

d = r * t

t = 120 seconds

d = 500 meters

r = d/t

r = 500 / 120 = 4.167 m/s

The closest answer is B

Answer:

Because even though our eyes have a huge dynamic range (ability to pick out details in sharply lit and lesser lit areas simultaneously) than any camera, there's a limit.

When there's strong sunlight, your pupils contract and let less light in, which makes the shadows look darker.

When it's cloudy, your pupils widen and let more light in, which makes the shadows look less dark.

Do some experiments with a camera and you'll soon get the hang of it.

NOTE: Also test HDR (high dynamic range) photography, where the camera takes three or more pictures in quick succession, with different exposure settings, and combines them to get the most detail of both bright and dark areas. The result is more or less what we percieve.

Answer: Food

Explanation:

Food is the largest contributor to land pollution.

What is  the Natural Resources Defense Council?

NRDC strives to rid our food, air, water, and household products from toxic chemicals.

40 percent of food produced in the US is trashed each year according to the Natural Resources Defense Council.

Food decomposes anaerobically and releases methane emissions, a greenhouse gas that is 28 times more potent than carbon dioxide over a 100-year period and 84 times more on a 20-year scale , when food waste ends up in landfill.

Worldwide, some percent of greenhouse gas emissions result from food waste alone.

Therefore,

Food is the largest contributor to land pollution.

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Explanation:

If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.

Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.