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Answer:

the correct one is F’= 4500 N

Explanation:

To solve this problem we must use Newton's second law

where F₁ is the force of the barge F₁ = 3000N and the force of the tugboat is F '

            F '- F₁ = m a

we substitute

            F '- 3000 = m a

the mass is always a positive quantity, therefore if we want the tug to pull the barge

            F ’-3000> 0

when you check it, you respect the correct one is F’= 4500 N

Answer:

The answer is -4500 N

Explanation:

I just got it right on the test

Answer:

The time for both of the balls to reach the ground would be the same.

Explanation:

If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. ... In air, a feather and a ball do not fall at the same rate.

Answer:

The initial velocity of the pitch is approximately 36.5 m/s

Explanation:

The given parameters of the thrown fastball are;

The height at which the pitcher throws the fastball, h₁ = 2.65 m

The angle direction in which the ball is thrown, θ = 2.5° below the horizontal

The height above the ground the catcher catches the ball, h₂ = 1.02 m

The distance between the pitcher's mound and the home plate = 18.5 m

Let 'u' represent the initial velocity of the pitch

From h = [tex]u_y[/tex]·t + 1/2·g·t², we have;

[tex]u_y[/tex] = The vertical velocity = u·sin(θ) = u·sin(2.5°)

h = 2.65 m - 1.02 m = 1.63 m

uₓ·t = u·cos(θ) = u·cos(2.5°) × t = 18.5 m

∴ t = 18.5 m/(u·cos(2.5°))

∴ h = [tex]u_y[/tex]·t + 1/2·g·t² =  (u·sin(2.5°))×(18.5/(u·cos(2.5°))) + 1/2·g·t²

1.63 = 8.5·tan(2.5°) + 1/2 × 9.8 × t²

t² = (1.63 - 8.5·tan(2.5°))/(1/2 × 9.8) = 0.25691469087

t = √(0.25691469087) ≈ 0.50686752763

t ≈ 0.50686752763 seconds

u = 18.5 m/(t·cos(2.5°)) = 18.5 m/(0.50686752763 s × cos(2.5°)) = 36.5334603 m/s ≈ 36.5 m/s

The initial velocity of the pitch = u ≈ 36.5 m/s.

Answer:

The answer to the equation is B hope this helps:)

Answer:

D. a continent covered in snow can be one of the driest on earth

Explanation:

Answer:

Explanation:

C goes to 1

D goes to 3

B goes to 4

A goes to 2

Answer:

  about 602 milliseconds

Explanation:

The motion can be approximated by the equation ...

  y = -4.9t^2 -22.8t +15.5

where t is the time since the arrow was released, and y is the distance above the ground.

When y=0, the arrow has hit the ground.

Using the quadratic formula, we find ...

  t = (-(-22.8) ± √((-22.8)^2 -4(-4.9)(15.5)))/(2(-4.9))

  = (22.8 ± √823.64)/(-9.8)

The positive solution is ...

  t ≈ 0.60195193

It takes about 602 milliseconds for the arrow to reach the ground.

Answer:

The answer is "36 grams".

Explanation:

In this question, the weight of the ball is not mentioned but is the weight of the cookies is declared, which is equal to 36 grams, and all the cookies are squeezes into the ball and after that, it calculates the overall weight so, let assume that ball weight is =0 and then the overall weight is:

[tex]=\text{weight of ball + cookies weight}\\\\=0+36 \ grams \\\\=36 \ grams[/tex]

Answer:

Sound is produced by an object vibrating and creating a pressure wave.

Explanation:

Answer:

v=m/s m=v.s -1*3= -3 meter/second

The velocity of the elevator after 3 seconds will be equal to 3 m/s.

We have three equations of motion that can be used to calculate components such as displacement(s), initial (u) and final velocity (v), time(t), and acceleration(a). The expressions for the three equations of motion are as follows:

First Equation of Motion :

v = u + at

Second Equation of Motion :

S = ut + (1/2) at²

The third equation of motion is:

v² - u² =2aS

Given, the initial velocity (u) of the elevator is zero as the elevator is at rest initially.

The acceleration of the elevator, a = -1 m/s² moving downward.

The  final velocity of the elevator after 3 seconds will be:

v = u + at

v = (0) + (-1 m/s²) (3 s)

v = - 3 m/s

Therefore, the velocity of the elevator after 3 seconds will be equal to 3 m/s in the downward direction.

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Answer:

The answer is...

Explanation:

If your counting the miles he went from the Pizza place and back it would be 22 if you were counting just the amount of miles he went from the pizza place then it would be D, or 11. Hope this helps.

:)

Answer:

W>R...............

Explanation:

.........................

Yes

Answer:

[tex]40 + 37 + 33 + 25 + 20 \div 5 = 155 \div 5 = 31[/tex]

Answer:

Or you could just say 31 :)

Explanation:

Answer:

58.933195 u or 59 u

Explanation:

Atomic mass of cobalt is 58.933195 u

Answer:

fif = 0.01 x 5000 = 50 N

Explanation:

u=150 m/s

v=0

m-10 y =0.01 kg

t=0.03s

s

v=utat

o= 150+a (0.03)

therefore a= -5000 m/s power 2

v power 2 = u power 2 + 2as

0=150 power 2+ 2 x (-5000) x s

therefore f=2.25 m

Answer:

Explanation:

Compete question;

A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.

centripetal acceleration a = v²/r

v is the tangential speed

r is the radius

Given

v = 15.7m/s

a = 9.8m/s²

9.8 =  15.7²/r

9.8r = 15.7²

r = 15.7²/9.8

r = 246.49/9.8

r = 25.152m

Hence the radius of the coaster is 25.152m

Answer: 13720

Explanation: the equation is....

Answer:

Tellurium

Explanation:

Answer:

Tellurium

Explanation:

Answer:

2 m/s

Explanation:

A .

Explanation:

Tiny water drops hovering in the air are called fog. Fog is like a cloud, but it is near the ground, not high in the sky. Thick fog makes it difficult to see the surrounding landscape

we have that from the Question"which of these might be carried by the wind, which causes the weathering of rocks? " it can be said that  

From the Question we are told

which of these might be carried by the wind, which causes the weathering of rocks?

A. fog

B. mud

C. pollen

D. sand

Generally

Therefore

Which of these might be carried by the wind, which causes the weathering of rocks will be

Option C

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Answer:

b

Explanation:

in this condition the atom is not stable so in order to become stable ( trying to have the last energy level completely filled like the Nobel gases) it tends to lose or gain or share the electrons and that debend on its condition . I hope that's the right answer

Answer:

The mechanical advantage increases as the slope of the incline decreases. But the load will then have to be moved a greater distance. The ideal mechanical advantage (IMA) of an inclined plane is the length of the incline divided by the vertical rise, the so-called run-to-rise ratio.

Explanation:

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[tex] \sf{• \: Power \: (P) = 60 \: w}[/tex]

[tex] \sf{• \: Resistance \: (R) = 880 \: Ω}[/tex]

[tex] \\ [/tex]

[tex] \sf• \: The \: Current \: (I).[/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{ Solution :- }}[/tex]

[tex] \sf We \: know \: that,[/tex]

[tex] \bf \red {\bigstar{ \: P = I^{2} R}}[/tex]

[tex] \rightarrow \sf 60 = I^{2} \times 880[/tex]

[tex] \rightarrow \sf \frac{60}{880} = I^{2} [/tex]

[tex] \rightarrow \sf I^{2} = 0.0681[/tex]

[tex] \rightarrow \sf I = \sqrt{0.0681}[/tex]

[tex] \rightarrow \sf I = 0.261 \: \: (approx.)[/tex]

[tex] \\ [/tex]

[tex]\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)[/tex]

Ocean waves hitting a concrete barrier that reduces their energy, scenario is the best example of matter absorbing energy from a wave.

Common examples of absorption of wave energy: waves hitting the beach usually give most of their energy to the sand. sunlight landing on a face is mostly absorbed, warming the skin. sound waves hitting thick curtains give up their energy and the sound is muffled.

"A wave is a disturbance in a medium that carries energy without a net movement of particles. It may take the form of elastic deformation, a variation of pressure, electric or magnetic intensity, electric potential, or temperature."

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Answer:

Car A has twice the energy of car B.

Explanation:

The kinetic energy of an object is given by :

[tex]K=\dfrac{1}{2}mv^2[/tex]

Where

m is the mass

v is the speed of the object

Car A has twice the mass of Car B. Both travel at the same speed i.e.

[tex]m_A=2m_B[/tex]

So,

[tex]\dfrac{K_A}{K_B}=\dfrac{(1/2)m_Av^2}{(1/2)m_Bv^2}\\\\=\dfrac{2m_B}{m_B}\\\\\dfrac{K_A}{K_B}=2\\\\K_A=2\times K_B[/tex]

So, the kinetic energy of car A is twice of the kinetic energy of car B.

Answer:

Car A has twice the energy

Explanation:

Answer:

Maximum Height

Explanation:

The maximum height is the highest point reached by a projected body. At this point, final velocity, v of the body is equal to 0; because upward motion is at its peak and the body start to fall again.

Hence, final velocity v is always 0 at this maximum point and the direction of motion changes from upward to downward.

Final velocity at this maximum height is zero because of the directional change experied by the object and the fact that upward motion of the body terminates at this point.

Answer:

Striking the head of the drum changes its shape and compresses the air inside the shell. the compressed air presses on the bottom head and changes its shape. then these changes are transmitted to the drum shell and reflected back and this action is repeated created a vibration.

Explanation:

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Answer:

0.63m

Explanation:

Volume expansivity = change in volume/original volume×temp change

Volume expansivity p = 3x

p = ∆V/V∆t

x is the linear expansivity

Given

x = 6 x 10^-4

p = 3x

p = 3(6 x 10^-5)

p = 18×10^-5

Volume = 100m³

∆t = 45-10 = 35°C

Required

Change in volume ∆V

Substitute the given values into the formula

18×10^-5 = ∆V/100(35)

18×10^-5 =∆V/3500

∆V = 3500×0.00018

∆V = 0.63m

Hence the increase in volume of the Mercury is 0.63n