Need help with this

What is the solution to the system of equations?
3x - 2y = 8
6x - 4y = 12
Use any algebraic method (substitution or elimination) to justify that the given system of equations has no solution.
What do you know about the two lines in this system of equations graphically?
Answer:

Answer:

B and C) 7/10x= 7/3 and -7/3 =-7/10 are the answers you are looking for

Step-by-step explanation:

Hope this helps! :)

Answer:

your answer would be B and C!!

Step-by-step explanation:

that is for edge 2020.

Answer:

73920

Step-by-step explanation:

look it up

Answer:

73920

Step-by-step explanation:

There are 5280 feet in a mile

Thus, we can multiply 14 with 5280

Receving 73920

So 73920 feet is our answer

btw 14 miles is a Longggggg way to walk

Check the picture below, notice, the triangles are named ABC and DEF, so the corresponding angles will be A to D, B to E and C to F.

Answer:

Answer on image

Step-by-step explanation:

Answer:

Three consecutive means 3 numbers right next to each other.

So how we’re gonna do that.
Multiple ways.

Way #1, guess and check method

So the final result has to be -6.

Using common knowledge we know if we add a negative with a negative you’d get a smaller negative.

And also if you add negative that in which the number is greater then the positive number, then it’ll also be negative.

Positive + positive is impossible here so that already crossed out a ton of options.
Let’s explore the negative view perspectives.
Since -6 is a pretty easy integer, you can easily guess with small numbers.

First attempt: -1 + -2 + -3 = -6
There -1, -2, and -3.

Way #2, algebraically

So what is a consecutive integer.
It’s a number that comes after another so for example.

1, 2, 3

The pattern is + 1.
There has to be a base so we can do for example “x”.
x, x+1, x+2

There’s 3 consecutive integers.

If you replace x with any number, the numbers given should be consecutive.

So using that knowledge youc an solve for the interger needed here which is -6.
x + x+1 + x+2 = -6
Simplify and solve.

3x+3= -6
3x= -9

x= -3

So using that -3, we can subside into the expressions from before.
x, x+1, x+2

-3, -3 + 1, -3 +2
-3, -2, -1

They are consecutive.

Answer:

-6, -5, -4

Step-by-step explanation:

Answer:is the same number

Step-by-step explanation:289 because it’s a square all squares have same side

Basically all you need to show is –(p-q)=(-p)+q. (1)

Since 0 = (p-q) + (-(p-q)) (additive inverse), we get –p = -q +(-(p-q)). Now substitute for (–p) in (1).

Then m+q-n-p=(m+q)-(n+p) follows. (since -n-p+(n+p) = 0 implies -n-p = -(n+p) (additive inverse))

so technically all u need to show is –(p-q)=(-p)+q. Hope this helps!!

Answer: I believe it is same side interior are congruent.

Step-by-step explanation:

Answer:

same side interior angles are congruent

Step-by-step explanation:

just took the test ;)

Answer:

7

Step-by-step explanation:

Answer:

It equals 7 :)

Step-by-step explanation:

You  have to subtract 10 and three that is how you get three

Answer:

81

Step-by-step explanation:

2. substitute values

(2+3+4)²

2. solve brackets first

(9)²

3. evaluate

9² = 81

Answer:

Step-by-step explanation:

Answer:

The Gold team has 8 swimmers and the silver team also has 8 swimmers.

Step-by-step explanation:

Let T be the total number of swimmers on the Gold team. Since, the Gold team has a 2:3 ratio of 11 year olds to 12 year olds, the number of 11 year old is T' = 2/(2 + 3) × T = 2T/5 and the number of 12 year olds is T" = 3/(2 + 3) × T = 3T/5.

The silver team has a 3:8 ratio of 11 year olds to the total swimmers. Let T₁ be the number of 11 year old swimmers in the silver team. So, from the ratio 3:8, the number of 11 year old swimmers in the silver team is 3 and the total number of swimmers in the silver team is 8.

Since the number of 11 year old swimmers in both teams are the same, then

2T/5 = 3

T = 3 × 5 ÷ 2

T = 15/2

T = 7.5

T≅ 8

So, the Gold team also has 8 swimmers.

So, the Gold team has 8 swimmers and the silver team also has 8 swimmers.

Answer:

178.76

Step-by-step explanation:

Subtract .24 from 179

Answer:

x=2

Step-by-step explanation:

10=4x+2

8=4x

2=x

Answer:   [tex]D. h^{2}+9h+23[/tex]

Step-by-step explanation:

[tex]f(x)=x^{2} +3x+5[/tex]

1. Input (3+h) instead of x.

[tex]f(3+h)=(3+h)^{2} +3(3+h)+5\\[/tex]

2. Get rid of parentheses.

[tex]f(3+h)=9+6h+h^{2} +9+3h+5\\[/tex]

[tex]f(3+h)=h^{2}+9h+23[/tex]

Therefore, D is the answer.

Answer:

If p = -3 and q = 7 your answer would be 30

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

y co-ordinate is 2 when finding y intercept x has to be 0

9514 1404 393

Answer:

Step-by-step explanation:

Just as the directions tell you, multiply both parts of the ratio by the same number. Here, the equivalents we used are 1, 2, and 5 times the numbers in the reduced ratio. Your multipliers can be anything, and don't need to be positive or rational or numbers.

__

1. 5/12 = (5·2)/(12·2) = 10/24

  5/12 = (5·5)/(12·5) = 25/60

__

2. 14:32 = (7·2):(16·2) = 7:16

  7:16 = (7·5):(16·5) = 35:80

__

3. 3 to 4 = (3·2) to (4·2) = 6 to 8

  3 to 4 = (3·5) to (4·5) = 15 to 20

__

4. 7/8 = (7·2)/(8·2) = 14/16

  7/8 = (7·5)/(8·5) = 35/40

  7/8 = (7·m)/(8·m) = (7m)/(8m) . . . m ≠ 0

Step-by-step explanation:

[tex]\displaystyle \boxed {y = sin\:(x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{2}} \hookrightarrow \frac{-\frac{\pi}{2}}{1} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 1[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 1[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = sin\:x,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{2}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{2}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{2}} = \frac{-\frac{\pi}{2}}{1}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = sin\:(x + \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a wourd problem to wourk with, you MUST use the above formula for calculating the period. Onse you do that, the rest should be easy. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

Properties of y = cos(x)

The cosine wave is a sinusoidal function (sine and cosine waves are the same except for a horizontal shift).

It is a continuous function and so its domain is (-∞, ∞)

The center line is y = 0

The Amplitude (the height from the center line to the peak) is 1, and so its range is -1 ≤ x ≤ 1

The y-intercept is at (0, 1)

Its period (length of one wave) is 2π (360°)

Answer:

y=4

Step-by-step explanation:

I'm a little rusty at this but y=4 should be the correct answer.

Hope this helps!

Answer:

-5/2

Step-by-step explanation:

Answer:

1.7815

Step-by-step explanation:

Answer:

495

Step-by-step explanation:

9 + 2 = 11

11 x 45 = 495

you'd get 495 if you did 2+9 45 times.

Step-by-step explanation:

1) y=1

Obviously this is a line with a constant ordinate and parallel to the x-axis, it admits no x-intercepts since it cannot intersect the x-axis

The y-intercept is the point of coordinates (0,1)

Find the derivative of the function and solve it equal to zero to find the coordinates of the vertex

y=1

y'=1 =>0=1 Impossible

So it admits no vertex.

2)

x=3

Similarly this is a line with a constant abscissa and parallel to the y-axis.It does not have a y-intercept since it cannot intersect the y-axis.

The x intercept is the point of coordinates (1,0)

This function admits no derivative since it is a function independent of the x value (constant x)

Therefore it has no intercepts.

3)

f(x)=3x+2

Solve for f(0) to find the y-intercept

f(0)=3(0)+2=2

X-intercept (2,0)

Solve f(x)=0 to find the x-intercept(s)

3x+2=0

3x=-2

x=-2/3

Y-intercept (-2/3,0)

Find the derivative and solve it equal zero to find the coordinates of the vertex:

f(x)=3x+2

f'(x)=3

3=0 impossible, so this function admits no vertex.

4)

f(x)=x²+3x+4

to find the y-intercept solve x=0 or in other words, find f(0)

f(0)=0²+3(0)+4=4

y-intercept is (0,4)

to find the x-intercept(s) solve f(x)=0

x²+3x+4=0

find the roots to this equation

∆=b²-4ac

∆=3²-4(1)(4)

∆=9-16

∆=-7<0

which implies this function admits no x-intercepts

5)

f(x)=-x²+4x+16

f(0)=-(0)²+4(0)+16

f(0)=16

Y-intercept (0,16)

f(x)=0

-x²+4x+16=0

""Solve using the quadratic formula'"'

You get the roots:

x¹=-2.47 x²=6.47

x-intercepts (-2.47,0) (6.47,0)

f'(x)=-2x+4

f'(x)=0

-2x+4=0

-2x=-4

x=2

Find f(2)=-(2)²+4(2)+16=-4+8+16=20

Vertex (2,20)

6)

f(x)=-2x²+x+2

f(0)=-2(0)²+0+2=2

Y-intercept (0,2)

f(x)=0

-2x²+x+2=0 'use the quadratic formula'

x¹=-0.78 x²=1.78

x-intercepts (-0.78,0) (1.78,0)

f'(x)=-4x+1

f'(x)=0

-4x+1=0

-4x=-1

x=1/4=0.25

f(0.25)=-2(0.25)²+0.25+2=2.125

Vertex (0.25,2.125)