pa help po

13.) given that " G " varies directly as " h " and g=64 when h=8 find the variation constant

can you plss answer no.# 13-15

wc in advance po
take note

nonsense answer= report
good answers will get brainlist and I'll follow you and I'll rate you

Pa Help Po 13.) Given That " G " Varies Directly As " H " And G=64 When H=8 Find The Variation Constant

Answers

Answer 1

It would take 12 men 18 days to complete the job.

1) g ∝ h

g = kh; where k is the constant of variation.

g = 64, h = 8, hence:

64 = 8k

k = 8

g = 8h

2) j ∝ 1/h

j = k/h; where k is the constant of variation.

j = 190, h = 7, hence:

190 = k/7

k = 1330

j = 1330/h

When h = 70:

j = 1330/70

j = 19

3) y represent number of men and x represent the days

y ∝ 1/x

y = k/x

9 = k/24

k = 216

y = 216/x

For 18 days:

y = 216/18 = 12 men

Hence it would take 12 men 18 days to complete the job.

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Explanation

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Answer: 2x-y=3

Step-by-step explanation:

Rewrite 2x-y=3 in standard form:  y = 2x -3

The line on the graph has a y-intercept of -3, as does this equation.  We can also see a slope of 2 (y goes up by 2 for every time x increase by 1).

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[tex] \frac{3}{4} \div \frac{3}{8} = \\ [/tex]

[tex] \frac{3}{4} \times \frac{8}{3} = \\ [/tex]

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Answers

Answer: The answer is 24

Step-by-step explanation:32/8 is 4. You just multiply 6 by 4.=24

Answer:

x = 24

Step-by-step explanation:

We require

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4, 13, 5, 8, R, 5, 11

In the data set shown, R is an integer. If the median of the data set is 8 and R < 11, what is a possible value

of R?

Answer:

Answers

Answers:

R can be either 8, 9 or 10

============================================================

Explanation:

Let's exclude the R value for now.

The set {4,13,5,8,5,11} sorts to {4,5,5,8,11,13}.

Now we'll include R back in. We're told that R is an integer and it's smaller than 11. The possible values R can take on are: {10, 9, 8, 7, ...} The countdown continues forever into the negative territory.

If R < 4, then we go from {4,5,5,8,11,13} to {R,4,5,5,8,11,13}. That R is guaranteed to be the min value since R is less than the smallest value of the previous set. Note that the middle-most item of the second set is 5; however, we want the median to be 8 instead. This allows us to rule out the case that R < 4.

So we've determined that 4 < R < 11. Because R is an integer, we can say it takes on the values from the set {5,6,7,8,9,10}

------------------------------

If R = 5, then {4,5,5,8,11,13} updates to {4,5,5,5,8,11,13} after adding in that R value. We can see the median is 5, so we can rule out the case that R = 5.

Similarly, we can rule out R = 6 as well. The set {4,5,5,8,11,13} updates to {4,5,5,6,8,11,13} in which the median is 6.

If R = 7, then the median is 7 for similar reasoning and we can rule out this R value.

So we've ruled out the cases that R = 5, R = 6 and R = 7.

If we tried R = 8, then {4,5,5,8,11,13} becomes {4,5,5,R,8,11,13} = {4,5,5,8,8,11,13}. This set has a median of 8 and R = 8 is one of the answers.

-------------------------------

Now let's consider the possibility that 8 < R < 11.

If for instance R = 9, then {4,5,5,8,11,13} becomes {4,5,5,8,9,11,13} to show that this set also has a median of 8. R = 9 is another answer.

The same idea happens when R = 10 as well because we get {4,5,5,8,10,11,13}. R = 10 is another answer.

-------------------------------

In short, R can be any of the following values: 8, 9, 10

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