please help i need the explanation to go look back at for similar questions in the future. last word is Bold.
Answers
Answer:
50
Step-by-step explanation:
The given angles in the triangle are vertically opposite angles. Hence;
9x - 4 = 8 + 7x
Collect the like terms
9x - 7x = 8 + 4
2x = 12
x = 12/2
x = 6
Get the bolded angle
Bolded angle= 8 + 7x
Blded angle = 8 + 7(6)
Bolded angle = 8 + 42
Bolded angle = 50
Related Questions
Find the sum of: 7a² - 9a + 5 and 11a + a² + 8
Answers
Answer:
Add them:
Squares to squares, a to and number to number:
8a^2+3a+13
The simplified sum of the given expressions 7a² - 9a + 5 and 11a + a² + 8 is 8a² + 2a + 13.
To find the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8, we simply combine like terms.
The given expressions contain terms with different powers of "a."
Combining the terms with the same powers, we have:
7a² + a² = 8a² (the coefficient for the "a²" term is 7 + 1 = 8)
-9a + 11a = 2a (the coefficient for the "a" term is -9 + 11 = 2)
Finally, we combine the constant terms:
5 + 8 = 13
Putting it all together, the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8 is:
8a² + 2a + 13
To learn more about polynomials click on,
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Which relationship is always true for the angles x,y and z of triangle ABC
Answers
Answer:
B. y + z = x
Step-by-step explanation:
x is an exterior angle of the triangle.
y and z are the opposite angles opposite the exterior angle.
The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.
Thus:
y + z = x
Find the perimeter of the figure below, in feet.(Note: diagram is NOT to scale)
Answers
A credit card company uses these rules to calculate the minimum amount owed: For a bill of less than $100, the entire amount is due. For a bill of at least $100 but less than $500, the minimum due is $100. For a bill of at least $500 but less than $1,000, the minimum due is $300. For a bill of $1,000 or more, the minimum due is $500. Which graph shows the minimum amount due for a credit amount of x (given that the credit limit is $2,000).
Answers
Help is appreciated
Answers
Answer:
m = 6
n = 2√3
Step-by-step explanation:
Reference angle = 30°
Hypotenuse = 4√3
Opposite = n
Adjacent = m
✔️To find m, apply CAH:
Cos θ = Adj/Hypo
Substitute
Cos 30° = m/4√3
4√3 × Cos 30° = m
4√3 × √3/2 = m (cos 30 = √3/2)
(4*3)/2 = m
6 = m
m = 6
✔️To find n, apply SOH:
Sin θ = Opp/Hypo
Substitute
Sin 30° = n/4√3
4√3 × Sin 30° = n
4√3 × ½ = n (Sin 30 = ½)
2√3 = n
n = 2√3
Am I correct if not plz fix it ASAP I have 4 minutes left
Answers
Answer:
no not correct it should be horizontally left 2 units and vertically down 5 units
Can someone please help me?
Answers
Prove that sinxtanx=1/cosx - cosx
[tex] \sin(x) \tan(x) = \frac{1}{ \cos(x) } - \cos(x) [/tex]
Answers
Answer:
See below
Step-by-step explanation:
We want to prove that
[tex]\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}[/tex]
Taking the RHS, note
[tex]\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}[/tex]
Remember that
[tex]\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)[/tex]
Therefore,
[tex]\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}[/tex]
Once
[tex]\dfrac{\sin(x)}{\cos(x)} = \tan(x)[/tex]
Then,
[tex]\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)[/tex]
Hence, it is proved
Lines DE and AB intersect at point C.
What is the value of x?
А.
|(2x + 2)
с
(5x + 3)
Answers
Given:
Lines DE and AB intersect at point C.
To find:
The value of x.
Solution:
In the given figure it is clear that the angles and are lie on a straight line AB.
[Linear pair]
Subtract 5 from both sides.
Divide both sides by 7.
Therefore, the correct option is B.
Simplify (5 square root 2 - 1 ) ^2
Answers
Answer:
576
Step-by-step explanation:
5 square root 2 is 25
25 minus 1 is 24
24 square root 2 is 576
Answer:
25
Step-by-step explanation:
[tex](5\sqrt{(2-1)} ^{2}[/tex]
[tex](5\sqrt{1}) ^{2}[/tex]
According to the tables used by insurance companies, a 48-year old man has a 0.169% chance of
passing away during the coming year. An insurance company charges $217 for a life insurance policy
that pays a $100,000 death benefit.
What is the expected value for the person buying the insurance?
Answers
Answer:
The expected value for the person buying the insurance is of -$48.
Step-by-step explanation:
Expected value:
0.169% = 0.00169 probability of earning the death benefit of $100,000, subtracting 217, 100000 - 217 = $99,783.
100 - 0.169 = 99.831% = 0.99831 probability of losing $217.
What is the expected value for the person buying the insurance?
[tex]E = 0.00169*99783 - 0.99831*217 = -48[/tex]
The expected value for the person buying the insurance is of -$48.
In a geometric sequence, the term an+1 can be smaller than the term ar O A. True O B. False
Answers
9514 1404 393
Answer:
True
Step-by-step explanation:
In a geometric sequence, the terms a[n+1] and a[n] are related by the common ratio. If the sequence is otherwise unspecified, two sequential terms may have any a relation you like.* Either could be larger or smaller than the other.
__
* If one is zero, the other must be as well. Multiplying 0 by any finite common ratio will give zero as the next term.
So are you good at maths then what is
[tex]4 \times 6 + 9 - 46 + 54 - 13[/tex]
1. 71
2. 42
3. 63
4. 28
5. 35
6. 14
Answers
maybe 28 is the answer...
Order of operations is key here. So multiply first. Then you just add/subtract left to right.
24 + 9 - 46 + 54 - 13
33 - 46 + 54 - 13
-13 + 54 - 13
41 - 13
= 28
[tex] {x}^{2} + 2x = 0[/tex]
Answers
Answer:
[tex]\textbf{Hello!}[/tex]
[tex]\Longrightarrow2^2+2z=0[/tex]
[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}[/tex]
[tex]\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}[/tex]
[tex]\Longrightarrow =\sqrt{2^2-0}[/tex]
[tex]\Longrightarrow =\sqrt{2^2}[/tex]
[tex]\Longrightarrow=2[/tex]
[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow\frac{-2+2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{0}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{0}{2}[/tex]
[tex]=0[/tex]
[tex]\Longrightarrow\frac{-2-2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{-4}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{-4}{2}[/tex]
[tex]\Longrightarrow =-\frac{4}{2}[/tex]
[tex]=-2[/tex]
[tex]x=0,\:x=-2\Longleftarrow[/tex]
[tex]\underline{HOPE ~IT~HELPS}[/tex]
In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2 +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.
Answers
Answer:
(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]
(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant
Step-by-step explanation:
Given
[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation
[tex]n = 30[/tex]
[tex]p = 4[/tex] --- independent variables i.e. x1 to x4
[tex]SSR = 1760[/tex]
[tex]SST = 1805[/tex]
[tex]\alpha = 0.05[/tex]
Solving (a): Test of significance
We have:
[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
First, we calculate the t-score using:
[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]
[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]
[tex]t = 440 \div \frac{45}{25}[/tex]
[tex]t = 440 \div 1.8[/tex]
[tex]t = 244.44[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
Solving (c): [tex]SSE(x_2 ,x_3)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
Solving (d): F test of significance
The null and alternate hypothesis are:
We have:
[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant
[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant
For this model:
[tex]y =11.1 -3.6x_2+8.1x_3[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
[tex]SST = 1805[/tex]
[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
[tex]p_{(x_2,x_3)} = 2[/tex]
[tex]\alpha = 0.05[/tex]
Calculate the t-score
[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]
[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]
[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]
[tex]t = 27.5 \div 1.8[/tex]
[tex]t = 15.28[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Hence, we reject the null hypothesis
In grade 6, there are 40 students. There are 8 girls, find the percentage of the boys?
Answers
Therefore, there are 32 boys
(32/40)*100 = 80
Therefore, percentage of boys = 80%
Answer:
[tex]40 - 8 = 32 \\ \frac{32}{40} \times 100 \\ = 80\%[/tex]
17.
What is the value of the expression
2a + 5b + 3c for a = 12, b = 6, and
C=3?
A 10
B 21
C49
D 63
Answers
D. 63
2a+5b+3c
2(12)+5(6)+3(3)
24+30+9=63
Hope this helps! :)
Find the interest earned on $1,000 for 1 year at a 6% rate of interest when the interest is compounded quarterly.
Answers
Answer:
1060
Step-by-step explanation:
use the rules of exponents to evaluate or simplify.write without negative exponents. 1/4^-2=?
Answers
9514 1404 393
Answer:
4² = 16
Step-by-step explanation:
The applicable rule of exponents is ...
1/a^-b = a^b
So, ...
[tex]\dfrac{1}{4^{-2}}=\boxed{4^2 = 16}[/tex]
_____
Additional comment
If you were to evaluate this using the Order of Operations, you would evaluate the exponent first:
1/4^-2 = 1/(1/16)
Then, you would do the division.
1/(1/16) = 16
__
We sometimes find it convenient to manipulate exponential terms to the form with the smallest positive exponents before we begin the evaluation.
Given:
p: 2x = 16
q: 3x – 4 = 20
RE
Which is the converse of p - q?
ООО
If 2x + 16, then 3x - 47 20.
If 3x - 420, then 2x + 16.
If 2x = 16, then 3x – 4 = 20.
If 3x - 4 = 20, then 2x = 16
Answers
Given:
The given statements are:
[tex]p:2x=16[/tex]
[tex]q:3x-4=20[/tex]
To find:
The converse of [tex]p\to q[/tex].
Solution:
The statement [tex]p\to q[/tex] means if p, then q and the converse of this statement is [tex]q\to p[/tex].
[tex]q\to p[/tex] means if q , then p.
We have, [tex]p:2x=16[/tex] and [tex]q:3x-4=20[/tex].
So, the converse of given statement is:
[tex]q\to p:[/tex] If [tex]3x-4=20[/tex], then [tex]2x=16[/tex].
Therefore, the correct option is D.
Answer: Therefore, the correct option is D.
Step-by-step explanation:
Given:
p: 2x = 16
q: 3x – 4 = 20
RE
Which is the converse of p - q?
ООО
If 2x + 16, then 3x - 47 20.
If 3x - 420, then 2x + 16.
If 2x = 16, then 3x – 4 = 20.
If 3x - 4 = 20, then 2x = 16
To find:
The converse of .
Solution:
The statement means if p, then q and the converse of this statement is .
means if q , then p.
We have, and .
So, the converse of given statement is:
If , then .
Therefore, the correct option is D.
sketch a system of linear equation whose solution is (3,6)
Answers
Answer: x+y = 9, 2x+3y = 24
Step-by-step explanation:
PLEASE ANSWER MAKE SURE YOU ARE RIGHT PLEASE I WILL MARK AS BRAINIEST
FIND THE VOLUME OF THE SPHERE
Answers
Answer:
Step-by-step explanation:
r = 1/2 unit
[tex]Volume= \frac{4}{3}\pi r^{3}\\\\=\frac{4}{3}\pi *\frac{1}{2}*\frac{1}{2}*\frac{1}{2}\\\\=\frac{1}{3}*\pi *\frac{1}{2}\\\\=\frac{1}{6}\pi[/tex]
2(x +1) + 3(x -1) = 8(x -5)..plz solve this
Answers
x=17/2
don't forget to follow me
HELP ASAP WILL GIVE BRAINLIST
Consider the sequence {5,10,15,20,…}. Find n if an = 4875. Show all steps including the formulas used to calculate your answer.
Answers
Answer:
n = 975
Step-by-step explanation:
[tex]a_1 = 5 = 5 \times 1\\a_2 = 10 = 5 \times 2\\\\Therefore, \ a_n = 5 \times n\\[/tex]
[tex]Given \ a_n = 4875\\\\So, a_n = 5 \times n \\\\=> 4875 = 5 \times n\\\\=>\frac{4875}{5} = n\\\\=> 975 = n[/tex]
A right triangle has side lengths 8, 15, and 17 as shown below. Use these lengths to find tanĄ, sind, and cos 4. (GIVING POINTS AND BRAINLEST TO BEST ANSWER)
Answers
Answer:
Tan A = 8/15
Sin A = 8/17
Cos A = 15/17
I start feeling tired now
Choose the correct Set-builder form for the following set written in Roster form: { − 2 , − 1 , 0 , 1 , 2 }
Answers
Step-by-step explanation:
{x:x is an integer where x>-3 and x<3}
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
(a) P(X >10)
(b) P(X >20)
(c) P(X <30)
(d) Find the value of x such that P(X
Answers
Answer:
a) P(X > 10) = 0.6473
b) P(X > 20) = 0.4190
c) P(X < 30) = 0.7288
d) x = 68.87
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Mean equal to 23.
This means that [tex]m = 23, \mu = \frac{1}{23} = 0.0435[/tex]
(a) P(X >10)
[tex]P(X > 10) = e^{-0.0435*10} = 0.6473[/tex]
So
P(X > 10) = 0.6473
(b) P(X >20)
[tex]P(X > 20) = e^{-0.0435*20} = 0.4190[/tex]
So
P(X > 20) = 0.4190
(c) P(X <30)
[tex]P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288[/tex]
So
P(X < 30) = 0.7288
(d) Find the value of x such that P(X > x) = 0.05
So
[tex]P(X > x) = e^{-\mu x}[/tex]
[tex]0.05 = e^{-0.0435x}[/tex]
[tex]\ln{e^{-0.0435x}} = \ln{0.05}[/tex]
[tex]-0.0435x = \ln{0.05}[/tex]
[tex]x = -\frac{\ln{0.05}}{0.0435}[/tex]
[tex]x = 68.87[/tex]
Identify the outliers of the data set. Then determine if the outlier increases or decreases the value of the mean.
35, 42, 76, 38, 41, 32, 38, 36, 34, 42, 37
A: 76; decreases
B: 32; decreases
C: 32; increases
D: 76; increases
Answers
========================================================
Explanation:
The main group or cluster of values spans from 32 to 42 (inclusive).
Then off on its own is the value 76, which we consider an outlier. This value is fairly far from the group. As a rule, large outliers pull on the arithmetic mean to make it larger than it should be. Think of it like the outlier pulling on the mean as if it was done through a magnet or gravitational pull.
Similarly, small outliers pull the mean to the left to make it smaller than it should be. We don't have any small outliers in this case.
--------------
Let's consider the set
A = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 46}
where I've sorted the values and I replaced 76 with 46.
Computing the mean of set A gets us
(32+34+35+36+37+38+38+41+42+42+46)/11 = 38.27 approximately
--------------
Now let's form this set
B = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 76}
which is the original set your teacher gave you. It's nearly identical to set A, except that the 46 is now 76 again.
Compute the mean of set B
(32+34+35+36+37+38+38+41+42+42+76)/11 = 41
---------------
Set A has a mean of roughly 38.72 and set B has a mean of 41. We see that the mean has increased.
Find the area of the circle. Leave your answer in terms of T.
Answers
Answer:
4.2025 [tex]\pi m^{2}[/tex]
Step-by-step explanation:
A movie theater sells matinee tickets for $6 each and has a capacity of 100 people. The function M(x) = 6x represents the amount of money the movie theater makes from ticket sales,
where x is the number of customers. What would be the most appropriate domain for the function? (1 point)
Whole numbers less than or equal to 100
Whole numbers that are multiples of 6
All real numbers
All whole numbers
Answers
Answer:
A. Whole numbers less than or equal to 100
Step-by-step explanation:
The domain is the set of x numbers that can be plugged in to a certain equation.
Since the capacity of this movie theater is 100, x can be between 0 and 100, inclusive.
Answer choice A makes sense because whole numbers are definitionally positive integers and this choice caps out at 100.