Pls help me!! Thank u sm

Answer:

the SI unit of work or energy, equal to the work done by a force of one newton when its point of application moves one meter in the direction of action of the force, equivalent to one 3600th of a watt-hour.

Explanation:

Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.

Answer:

Anything in an experiment that remains unchanged.

Explanation:

An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.

Explanation:

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Answer:

69.44kJ

Explanation:

Kinetic energy is expressed as;

KE = 1/2mv^2

m is the mass = 500kg

v is the velocity

Get the velocity;

v = displacement/time

velocity = 2000/120

velcoity = 16.7m/s

Gt the kinetic energy

KE = 1/2 * 500 * 16.7²

KE = 250*277.78

KE = 69,444.4Joules

Since 1000J = 1kJ

69,444.4Joules = 69,444.4/1000

69,444.4Joules = 69.44kJ

Hence the Secretariat's average kinetic energy is  69.44kJ

Answer:C 69.0kJ

Explanation:

Answer:

Q = 2250 Coulombs

Explanation:

We are given;

Current: I = 2.5 A

Time: t = 15 minutes = 15 × 60 seconds = 900 s

Now formula for the amount of charge through the circuit is given by:

Q = It

Thus;

Q = 2.5 × 900

Q = 2250 Coulombs

Answer:

0.583 seconds

Explanation:

We are dealing with free-fall motion, which has a constant acceleration of -g, acceleration due to gravity, so we can use a constant acceleration equation to solve this problem.

List out known variables and the variable that we want to solve for:

Find the kinematic equation that contains all four of these variables:

Plug known values into the equation.

Distribute 1/2 inside the parentheses.

Set the equation equal to 0 and rearrange the terms so they are in descending degree order.

Factor this equation by using the quadratic formula. You should get:

Let's look at these numbers within the context of the problem. If the ball's speed is 20 m/s, then after 1 second, it would reach a height of 20 m.

However, we want to find the time that it would take the ball to reach a height of 10 m, which is half of 20 m. Therefore, the time to reach 10 m should be around 0.5 seconds.

t = 0.583 is the closest to 0.5 seconds, and it fits within the context of the problem. Therefore, the answer is 0.583 seconds.

Answer:

10m/s

Explanation:

Answer:

See the answers below

Explanation:

The data of 100W means power, and the other data of 220V means voltage, that is to say that bulb serves to work at a voltage of 220V100W datum means power.

J means work that is given in Joules [J], we must remember that power is defined as the relationship between work at a certain time, therefore we can determine work by means of the following expression.

[tex]P=W/t\\[/tex]

where:

P = power [Watt]

W = work [J]

t = time [s]

[tex]W=P*t\\W=100*5[hr]*[\frac{3600s}{1hr} ]\\W=1800000[J] = 1.8[MJ][/tex]

Now the electric cost.

[tex]0.1[kW]*5[hr]*55\frac{LL}{1kwhr} =27.5[LL][/tex]

Explanation:

Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing

I believe the correct answer is atmosphere (D).

Answer:

D) atmosphere

Explanation:

but the correct answer is troposhare

Answer:

[tex]a=2.4\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]

So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].

Answer:

I think it would be 179kb

1: 15m

2: 56m/s

3: 34.5m

Sorry if these are incorrect.

Answer:

gravity is everywhere in space and objects in space are always falling: towards the earth, towards the sun, and towards the galactic center

Explanation:

Answer:

5m

Explanation:

Whenever Two or more than two waves get to the same point/place, and they arrive at the same time, then there will be "superimposition" onto one another. Then there would be corresponding of each disturbance to a Amplitude or force, and since these disturbance maintain same line, "THEN THE RESULTING WAVE WILL BE THE ADDITION OF THE AMPLITUDE"

Superposition can be explained as the action that takes place as a result of two waves occupying same point.

To find the waves at this point, then " THE AMPLITUDE WILL BE ADDED TOGETHER"

Given:

Amplitude of first wave= 2.5m

Amplitude of second wave= 2.5m

The resulting wave will have an amplitude of(2.5m + 2.5m)=5.0m

Hence, The resulting wave has an amplitude of 5.0m

Answer:         Radio waves have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

Explanation:

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 1.5 × 10 × 0.22

We have the final answer as

Hope this helps you

Answer:

25J

Explanation:

Given parameters:

Mass of the dog  = 10kg

Speed of the dog  = 5m/s

Unknown:

The minimum energy required to stop the dog  = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

 To find the kinetic energy;

        K.E  = [tex]\frac{1}{2}[/tex] m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

      K.E  =  [tex]\frac{1}{2}[/tex]  x 10 x 5  = 25J

Answer:

3500joules of work

Explanation:

Work done = Force×,distance

Given

Focrce= mass ,× acceleration = 140×10 = 1400N

Distance moved = 2.5m

Workdone = 1400×2.5

Work done = 140×25

Workdone = 3500Joules

Answer:

4.9949

Explanation:

M = 3 kg

P.E = 147 joules

G = 9.81 ms^-2

H = ?

P.E = MGH

147 = 3 x 9.81 x H

147 = 29.43H

147/29.43 = 29.43H/29.43

4.9949 = H

:. H = 4.9949

Answer:

Although the weight is given and we are asked for the weight, the odd wording of the question implies that we are being asked for the gravitational force on the backpack.

If it is gravitational force that is being requested, then the correct answer is A) 41.16 Newtons.

If it is actual weight being asked for, then none of the answers are correct, as the weight of 4.2 kg is given in the question, and does not match any of the answers.

Answer:

Explanation:

a gravitational field is the region of space surrounding a body in which another body experiences a force of gravitational attraction.

The formula is: weight/mass = gravitational field strength. On Earth the gravitational field strength is 10 N/kg.

an example of how you can use it if you need to find the gravitational force from earth.

Answer:

The time taken to reach the maximum height is 3.20 seconds

Explanation:

The given parameters are;

The initial height from which the volcano erupts the lava bomb = 64.4 m

The initial upward velocity of the lava bomb = 31.4 m/s

The acceleration due to gravity, g = 9.8 m/s²

The time it takes the lava bomb to reach its maximum height, t, is given by the following kinematic equation as follows;

v = u - g·t

Where;

v = The final velocity  = 0 m/s at maximum height

u = The initial velocity = 31.4 m/s

g = The acceleration due to gravity = 9.8 m/s²

t = The time taken to reach the maximum height

Substituting the values gives;

0 = 31.4 - 9.8 × t

∴ 31.4 = 9.8 × t

t = 31.4/9.8  ≈ 3.204

The time taken to reach the maximum height rounded to three significant figures = t ≈ 3.20 seconds

Answer:

The answer is below

Explanation:

A vector quantity is a quantity that has both magnitude and direction. The magnitude of a vector is the length of that vector.

The magnitude of a vector a with a x component of x and y component of y is given by the formula:

[tex]|a|=\sqrt{x^2+y^2}[/tex]

Given that the vector has a magnitude of √8, the x component is 2 and the y component = y. Hence:

[tex]\sqrt{8}=\sqrt{2^2+y^2}\\\\squaring\ both\ sides:\\\\8=4 + y^2\\\\y^2=8-4\\\\y^2=4\\\\square\ root\ of\ both\ sides:\\\\y=\sqrt{4} \\\\y=\pm 2\\\\y=+2\ or\ y=-2[/tex]

Answer:

The donkey might be dead

Answer:

v₂ = 1.8 [m/s]

Explanation:

To be able to solve this problem we must raise the principle of conservation and quantity of movement. It is going to study the momentum before and after the firing of the rifle.

P = m*v

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now we need to analyze the moment before and after the shot.

[tex](m_{1}+m_{2})*v_{1}=-(m_{1}*v_{2})+(m_{2}*v_{3})[/tex]

where:

m₁ = mass of the rifle = 5 [kg]

v₁ = velocity of the rifle and the bullet before firing = 0 (no movement)

m₂ = mass of the bullet = 15 [g] = 0.015 [kg]

v₂ = velocity of recoil [m/s]

v₃ = velocity of the bullet after firing = 600 [m/s]

Now replacing:

[tex](5+0.015)*0 = -(5*v_{2})+(0.015*600)\\9 = (5*v_{2})\\v_{2}=1.8 [m/s][/tex]

Momentum is the product of mass and velocity. The recoil velocity of the rifle weighing 5 kg is 1.8 m/s.

According to the law of conservation of momentum if two objects are in contact with each other then for that system of the two objects the momentum of the object before will be equal to the momentum of the object after the collision.

GIven to us

Mass of the rifle, M = 5 kg

Mass of the bullet, m = 15 g = 0.015 kg

Velocity of the bullet afterwards, v₂ = 600 m/s

We know that according to the law of conservation of momentum, the momentum of the bullet and riffle before shooting will be equal to the momentum of the bullet and riffle after shooting.

[tex]Mu_1 + mu_1 = Mv_1 + mv_2[/tex]

Since, before shooting the bullet was in the riffle and the velocity of both was 0,

[tex]M(0) + m(0) = Mv_1 + mv_2\\\\-Mv_1 = mv_2\\\\v_1 = -\dfrac{m \times v_2}{M}[/tex]

Substitute the values,

[tex]v_1 = -\dfrac{0.015 \times 600}{5}\\\\v_1 = -1.8\rm\ m/s[/tex]

Thus, the recoil of the rifle is -1.8 m/s, the negative sign denotes that the velocity of recoil was in opposite direction to the bullet.

Hence, the recoil velocity of the rifle weighing 5 kg is 1.8 m/s.

Learn more about Momentum:

https://brainly.com/question/4956182

Answer:

it's 220 J

the second one

can tigger sudden mass movement

Answer:

0.5625 Joules

Explanation:

The equation to calculate kinetic energy is:

[tex]KE = \frac{1}{2}mv^2[/tex]

So, plug in all given info and calculate:

[tex]KE = \frac{1}{2}(0.5)(1.5)^2 = 0.5625J[/tex]

And that's your answer! :)