Answer:
Direct-air capture
Explanation:
To understand the technology I'm about to explain, I'll model it to something familiar. As you know, the process of photosynthesis is where trees and plants use sunlight, water, and carbon dioxide to create energy for themselves, and release oxygen as a byproduct. Direct- air capture is exactly like this. Its pulls in air and then through a range of similiar chemical reactions, it extracts the carbon dioxide from it while returning the rest of the air to the surrounding environment. Except, the Direct-air capture does this at a much faster rate than nature does. The direct-air capture uses a ginormous fan that pulls air in which then passes over plastic surfaces that have potassium hydroxide solutions covered over them. The potassium hydroxide solution chemically binds with the carbon dioxide molecules, removing them from the air and trapping them in the liquid solution as a carbonate salt. The carbon dioxide is then contained where it is compressed and purified and then stored for later use.
Grace wanted to find out the best conditions for growing lettuce plants.
She took 4 trays and planted 8 lettuce plants in each.
The results of her investigation are shown below.
How many days did the investigation last?
Use the table to help you.
Explanation:
the investigation lasts for 7 days !
hope this helps you.
The table shows the order of the Sun and some of the planets in our solar system.
The letters represent the Earth, Neptune and the Sun, so match them up in your answer.
Explanation:
A=Sun
B=Earth
C=Neptune.
hope my answer will definitely help you out.
The melting point of H₂O(s) is 0 °C. Would you expect the melting point of H₂S(s) to be 85 °C, 0 °C or -85 °C.? Justify your choice
Answer:
-85 °C
Explanation:
O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.
H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter
molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.
A balloon with an initial volume of 3.1 L at a temperature of 193 K is warmed to 374 K.
What is its volume at the final temperature? (Assume constant temperature.)
Answer:
New volume = 6.0L
Explanation:
Make a list of variables given in the question, and what we want to find:
Initial volume (L) = Vi = 3.1
Initial temperature (K) = Ti = 193
New temperature (K) = Tn = 374
New volume (L) = Vn
We have volumes and temperatures given and we're talking about gas, the equation including both these variables that should come to mind is the ideal gas equation:
PV = nRT
P = pressure (Pa)
n = number of moles
R = gas constant = 8.31
Now, we construct an equation we can solve to get the new volume:
P(Vn) = nR(Tn)
And insert the values we know:
P(Vn) = n(8.31)(374)
P(Vn) = n·3107.94
The equation contains 3 unknown variables;
We should first try to see if we can eliminate the 2 we are not interested in, namely P and n;
What we should recognise is that the pressure and number of moles will not change upon warming the balloon;
Firstly, heating the gas inside the balloon doesn't add anything to the balloon, i.e. doesn't increase the moles of gas, it simply raises the energy of the gas particles already within the balloon, so n will not change;
Secondly, I think there is a mistake in the question, it should read "assume constant pressure" in the brackets, since the temperature does change, which we are told;
Also, we can assume normal atmospheric pressure inside and outside the balloon as would be the case ordinarily;
What we want to do with this information is rearrange the equation we constructed to have these 2 constant or unchanging variables on one side and everything else on the other, so:
[tex]\frac{P}{n} = \frac{3107.94}{V_{n} }[/tex]
Next, we construct an equation for the balloon before warming:
P(Vi) = nR(Ti)
P(3.1) = n(8.31)(193)
P·3.1 = n·1603.83
Once again, rearrange to get P and n on one side of the equation and everything else on the other:
[tex]\frac{P}{n} = \frac{1603.83}{3.1} \\\\ \frac{P}{n} = 517.364516[/tex]
Now, we have two equations for P/n, we can eliminate P/n since both these values remain the same before and after warming the balloon as previously established:
[tex]\frac{3107.94}{V_{n} } = \frac{P}{n} = 517.364516 \\\\ \frac{3107.94}{V_{n} } = 517.364516 \\\\[/tex]
Now, rearrange and solve for Vn:
[tex]\frac{3107.94}{V_{n} } = 517.364516 \\\\ V_{n} = \frac{3107.94}{517.364516} \\\\ V_{n} = 6.00725...[/tex]
Vn = 6.0L
How many carbon dioxide molecules and water molecules are needed to make one molecule of glucose?
Answer:
It takes six molecules of carbon dioxide and six molecules of water to make one molecule of glucose.
if you are a scientific or a inventor what do you want to discover or to invent relate to electrogmagnetism
Answer:
Michal Faraday 19th century
Commercially prepared cloning vectors such as pUC18 are designed to contain several useful features. An example of one of these features is ________.
Vectors may be plasmids. An example of one of several useful features of commercially prepared cloning vectors is MULTIPLE CLONING SITES.
The pUC18 vector is a widely used standardized cloning vector for replication in Escherichia coli.
A multiple cloning site can be defined as a short DNA fragment observed in genetically engineered plasmids.
These DNA fragments (multiple cloning sites) contain twenty (20) or more sites where restriction enzymes can cut in order to generate recombinant DNA molecules.
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he hybridization of carbon in diamond is _________. Enter your answer with no superscripts or subscripts, i.e., ab3.
Diamond is composed of hexagonal rings in which sp3 hybridized carbon atoms are linked together.
Hybridization refers to the mixing of atomic orbitals to yield hybrid orbitals that are suitable for bonding. The energy of orbitals that combine to form hybrid orbitals must be close enough for such combination to take place.
Diamond is composed of hexagonal rings in which sp3 hbridized carbon atoms are linked together. Each carbon atom in diamond is tetrahedral.
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The mixing of the two different orbitals to form a compound is called hybridization. For example mixing of s and p orbits.
The correct answer is sp3.
The arrangement of the elements in a different manner to form a new compound is called allotropes. For example, diamond and graphite are the allotropes of carbon.
The valence electrons are in p orbitals and p orbit mixed after the s orbitals.
Therefore, the correct answer is sp3
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Sodium hydroxide neutralises hydrochloric acid as shown in the equation:
NaOH(aq) + HCl(aq) i NaCl(aq) + H2O(l)
(4)
dm3
(3)
The student found that 27.20 cm3 of 0.100 moles per dm3 sodium hydroxide neutralised 5.00 cm3 of hydrochloric acid.
Calculate the concentration of the hydrochloric acid in moles per dm3.
Give your answer to three significant figures.
Explanation:
Mole ratio of NaOH : HCl = 1: 1
Moles of NaOH used = 0.1 mol/1000 cm3 × 27.20 cm3
= 2.72 × 10^-3 mol
Therefore moles of HCl used is also 2.72 × 10^-3 mol
So concentration of HCl can be found by dividing the no.of moles of HCl by the volume of HCl as follows
2.72 × 10^-3 mol/ 5cm3
1000cm3 = 1dm3
Therefore,
1cm3 = 1/1000 dm3
5cm3 = 5/1000 dm3
HCl conc. = 2.72 × 10^-3 mol/ 5×10^-3 dm3
= 0.544 moldm-3
Oil does not dissolve in water because
Explanation:
Oils are made up of long hydrocarbon chains which are non polar. Since water is a polar solvent oil doesn't dissolve in water well.( Polar solutes dissolve in polar solvents and non polar solutes dissolve in non polar solvents) The hydrocarbon chains are hydrophobic.
If 5 g of sodium chloride saturates 12.5 g of water at 10 °C, what mass of sodium chloride would saturate 50 g of water at constant temperature?
Explanation:
since 5g saturates 12.5g of water at 10°c
so......x would saturate 50g of water at 0°c
then you can cross multiply
Describe your observations when the paper clip was gently crushed with the pestle
Answer:
We can do an experiment with vinegar to see what happens to the calcium in an eggshell when it is exposed to an acid.
Jackson uses a battery operated toothbrush that is rechargeable. what happens when Jackson plugs in his toothbrush into an electrical outlet to recharge it ?
A. chemical energy is transformed to sound energy.
B. electrical energy is transformed to kinetic energy.
C. chemical energy is transformed to kinetic energy.
D. electrical energy is transformed to chemical energy
Answer:
the answer would be B
Explanation:
The power from the charger use electricity and the electricity transforms to energy that can be moved
A chemical property is a change in _____.
density
physical state
hardness
composition of matter
Answer:
composition of an element
You are given 1.091 grams of a white powder and told that it is a mixture of potassium carbonate and sodium carbonate. You are asked to determine the percent composition by mass of the sample. You add some of the sample to 10.00 mL of 0.8903 M nitric acid until you reach the equivalence point. When you have added enough carbonate to completely react with the acid, you reweigh your sample and find that the mass is 0.573 g. Calculate the mass of the sample that reacted with the nitric acid. Calculate the moles of nitric acid that reacted with the sample.
The sample of white powder contains 47.1% K2CO3 and 0.39% Na2CO3.
Molar mass of sodium carbonate = 106 g/mol
Molar mass of potassium carbonate = 138 g/mol
Number of moles of HNO3 = 10/1000 L × 0.8903 M = 0.008903 moles
Mass of HNO3 = 0.008903 moles × 63 g/mol = 0.56 g
Mass of sample added = 1.091 g
Mass of sample left over = 0.573 g
Mass of sample reacted = 1.091 g - 0.573 g = 0.518 g
The reacted sample contains xg of Na2CO3 and (0.518 - x) g K2CO3.
Na2CO3 + 2HNO3 --> 2NaNO3 + CO2 + H2O
106g of Na2CO3 reacts with 126g of HNO3
x g of Na2CO3 reacts with (126 × x/106)g of HNO3
K2CO3 + 2HNO3 --> 2KNO3 + CO2 + H2O
138 g of K2CO3 reacts with 126 g of HNO3
(0.518 - x) g of K2CO3 reacts with [(0.518 - x) × 126/138] g
Total mass of HNO3 used;
1.19x + 0.47 + 0.91x = 0.56
2.1x + 0.47 = 0.56
2.1x = 0.56 - 0.47
2.1x = 0.09
x = 0.09/2.1
x = 0.0043 g
Mass of K2CO3 = (0.518 - x) g = 0.518 - 0.0043 = 0.5137 g
Mass percent of K2CO3 = 0.5137 g/ 1.091 g × 100/1 = 47.1%
Mass percent of Na2CO3 = 0.0043/1.091 g × 100/1 = 0.39%
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One night a student notices that one-quarter of the moon is visible. What is the likely explanation for this view?
If a student notices that one-quarter of the moon is visible, a lunar eclipse has taken place.
Eclipse is said to occur when one of the heavenly bodies casts a shadow on another heavenly body causing it to be partly visible or completely invisible. When the earth comes between the sun and the moon, a lunar eclipse is said to occur.
When a lunar eclipse occurs, the moon may be partly visible or completely invisible. Therefore, if a student notices that one-quarter of the moon is visible, a lunar eclipse has taken place.
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An element with 5 valence electrons would be a
0 - 3 anion
O +5 anion
0-5 cation
O + 3 cation
Answer:
ask you subject teacher
Explanation:
Which which characteristics determines color? A. The Measurement from crest crest. B. The highest point on the wave. C. The lowest points on the waves D. The number of waves that pass per second. Please give me a good response.
Answer:
The answer is option A
Explanation:
This is because the measure from crest to crest is also known as the wavelength, and the color of a wave always depends on its wavelength, if you see the electromagnetic spectrum
Hope this helps!
Al2(SO3)3
a. Count the number of Sulfur atom
b. How many total atoms are given in the compound
Please helppp
Answer:
from the words below underline six example of rhetorical patterns
The boiling point of a substance is tested. After 10 tests, the result is given as 37+/−3°C. Which conclusion can be drawn from this result?
A- The scientists do not need to collect more data because they have narrowed down the range of the results.
B- The scientists should not report these results until they have the exact number.
C- The actual boiling point is either 34°C or 40°C.
D- The actual boiling point is probably between 34°C and 40°C.
From the data obtained from the tests, the actual boiling point lies between 34°C and 40°C.
The boiling point of a substance is the temperature at which the pressure of the substance becomes equal to atmospheric pressure. Pure substances have a sharp boiling point while impure substances boil over a temperature range.
In this case, the boiling point of the substance after 10 tests is obtained as 37+/−3°C. This implies that the actual boiling point lies between 34°C and 40°C.
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Calculate the Ka of your acetic acid solution. Discuss this calculation. Based on the value of Ka, is acetic acid a strong acid or a weak acid
Based on our knowledge of strong and weak acids, we can confirm that the Ka value for acetic acid will be relatively low since it is a weak acid.
Acids can be strong or weak. This is determined by its tendency to break apart into ions or stay together to form molecules. Although somewhat counter-intuitive, strong acids are those that are most likely to break apart and therefore contain a high number of ions within their solutions.
Weak acids, on the other hand, are those that tend to stay together in the form of molecules and therefore possess very low ion counts in their solutions. The acid dissociation constant, Kₐ, is used to measure whether an acid is weak or strong and how much so. In the case of Acetic acid, the ka measurement will offer a low value, indicating a weak acid.
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Explain how you determine the freezing point of a solution that does not have a well-defined transition in the cooling curve.
This question is asking for a method for the determination of the freezing point in a solution that does not have a noticeable transition in the cooling curve, which is basically based on a linear fit method.
The first step, would be to understand that when the transition is well-defined as the one on the attached file, we can just identify the temperature by just reading the value on the graph, at the time the slope has a pronounced change. For instance, on the attached, the transition occurs after about 43 seconds and the freezing point will be about 4 °C.
However, when we cannot identify a pronounced change in the slope, it will be necessary to use a linear fit method (such as minimum squares) to figure out the equation for each segmented line having a significantly different slope and then equal them so that we can numerically solve for the intercept.
As an example, imagine two of the segmented lines have the following equations after applying the linear fit method:
[tex]y=-3.5 x + 25\\\\y=-0.52 x + 2[/tex]
First of all, we equal them to find the x-value, in this case the time at which the freezing point takes place:
[tex]-3.5 x + 25=-0.52 x + 2\\\\-3.5 x+0.52 x =2-25\\\\x=\frac{-23}{-2.98}=7.72[/tex]
Next, we plug it in in any of the trendlines to obtain the freezing point as the y-value:
[tex]y=-3.5 (7.72) + 25\\\\y = 1.84[/tex]
This means the freezing point takes place after 7.72 second of cooling and is about 1.84 °C. Now you can replicate it for any not well-defined cooling curve.
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https://brainly.com/question/22818252 https://brainly.com/question/9680530Draw the other possible resonance structure of each organic ion. In each case, draw the structure that minimizes formal charges. Be sure to include all appropriate nonbonding electrons and charges. A three carbon chain with a double bond between carbons 1 and 2. Carbon 1 is bonded to two hydrogen atoms, carbon two is bonded to one hydrogen atom, and carbon three is bonded to two hydrogen atoms. There is a plus one charge on the third carbon atom. Draw the resonance structure of the allyl ion. A carbon atom is single bonded to a C H 3 group, double bonded to an oxygen atom, and single bonded to an N atom. The N atom is bonded to a hydrogen atom. It has two lone pairs and a minus one charge. The O atom has two lone pairs. Draw the resonance structure of the amidate ion.
Three resonance structures can be drawn for the allyl cation while two resonance structures can be drawn for the amidate ion.
Sometimes, we cannot fully describe the bonding in a chemical specie using a single chemical structure. In such cases, we have to use a number of structures which cooperatively represent the actual bonding in the molecule. These structures are called resonance or canonical structures.
The resonance structures of the allyl cation and the amidate ion are shown in the images attached to this answer. These structures show the different bonding extremes in these organic ions.
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What mass of aluminium chloride can be obtained when 0.48mols of aluminium is completely reacted with dilute hydrochloric acid?
Equation for this reaction:
2Al + 6HCl 2AlCl3 + 3H2
Answer:
Explanation:
we will do ratio method
Aluminum chloride : Aluminum
2 : 2
0.48 : x
(cross multiply)
0.48 x 2 / 2 = 0.48 moles of aluminum
mass = 1 mole of aluminum chloride x moles
mass = 133.33 x 0.48
mass = 63.9984g (round off) = 64g
I hope this helps.
The result of a division problem is the a ) divisor . b ) quotient . c ) factor . d ) remainder .
Answer:
The number by which we divide is called the divisor. The result obtained is called the quotient. The number left over is called the remainder.
Explanation:
Hello can someone please help me. Me and my mom went to the doctor and the doctor told me I can’t have sex till 19 because of my health problems. But they didn’t tell me what health problems! Can someone tell us there any health things or a name for that?
Answer:
bladder or bowel diseases, or arthritis. These might be your answer.
) A technique once used by geologists to measure the density of a mineral is to mix two dense liquids in such proportions that the mineral grains just float. When a sample of the mixture in which the mineral calcite just floats is put in a special density bottle, the weight is 15.4448 g. When empty, the bottle weighs 12.4631 g, and when filled with water, it weighs 13.5441 g. What is the density of the calcite sample? (All measurements were carried out at 25 °C, and the density of water at 25 °C is 0.9970 g>mL)
At the left, grains of the mineral calcite float on the surface of the liquid bromoform (d = 2.890 g/mL) At the right, the grains sink to the bottom of liquid Chloroform (d = 1.444 g/mL). By mixing bromoform and chloroform in just the proportions required so that the grains barely float, the density of the calcite can be determined
Hey there!
It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.
In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:
[tex]m_{calcite}=15.4448g-12.4631g=2.9817g[/tex]
Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:
[tex]V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL[/tex]
Thus, the density of the calcite sample will be:
[tex]\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL[/tex]
This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL
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The box shows the chemical formula for bleach.
what did mosa figure out? how did mosas mesurement prove that the ball was moving to gravity
by bouncing it
Explanation:
when you bouce a ball it hits the ground because gravity pulls it down
2. Why do you think electroplated jewelleries are in demand?
Chemistry plsss
Explanation:
Electroplated jeweleries are in demand because firstly they are as shiny and attractive as real jeweleries, they are also light weighted and cost effective.