The answer is 8 V.
Since the resistors are in series, the current passing through all of them is the same. Let's call this current "I".
Using Ohm's Law, we can find the voltage drop across each resistor:
V1 = IR1 = I(2.0 Ω) = 2I
V2 = IR2 = I(4.0 Ω) = 4I
V3 = IR3 = I(6.0 Ω) = 6I
The sum of the voltage drops across each resistor should equal the voltage provided by the emf device, which is 24 V.
V1 + V2 + V3 = 2I + 4I + 6I = 12I = 24 V
Solving for I, we get:
I = 24 V / 12 Ω = 2 A
Now we can find the voltage drop across the 4.0-Ω resistor:
V2 = IR2 = (2 A)(4.0 Ω) = 8 V
Therefore, the potential difference across the 4.0-Ω resistor is 8 V.
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To correct myopia (nearsightedness) requires ___________ lenses; to correct hyperopia (farsightedness) requires _____________ lenses to correct.
By using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.
To find the answer, we need to know about Myopia and Hyperopia.
What is Myopia and Hyperopia?Myopia is an optical defect, in which a person can see nearby objects clearly and cannot see far off objects clearly.Here the eyeball becomes too longer, and the focal length of eye lens become too short.It can be corrected by using concave lens.For Hyperopia, the person can see far off objects clearly and cannot see nearby objects clearly.This can be corrected by using convex lens.Thus, we can conclude that, by using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.
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Myopia can be corrected using concave lenses, while the Hyperopia is corrected by convex lenses.
We need to be aware of myopia and hyperopia in order to locate the solution.
Myopia and hyperopia: what are they?Myopia is an optical defect in which a person can see clearly up close but not clearly far away.Here, the eyeball lengthens excessively and the eye lens focal length contracts.Concave lenses can be used to rectify it.A person with hyperopia can clearly see distant objects but cannot see nearby objects clearly.Convex lenses can be used to fix this.Thus, we can deduce that myopia and hyperopia can be corrected using concave lenses and convex lenses, respectively.
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The evolutionary cutoff between low- and high-mass stars occurs at approximately:
The evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.
What are high-mass stars?The high-mass stars are celestial bodies that exhibit a high level of luminosity and lived for short periods of time.
Conversely, low-mass stars are small and cool stars that lived for a long period of time.
In conclusion, the evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.
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Which of the following is an advantage of recorded presentations? A. Start-times and time zones are not a factor. B. Speakers can adapt topic coverage if necessary. C. Audience members have the opportunity to provide feedback D. More visual aids can be used.
The statement describes an advantage of recorded presentations is that the audience members have the opportunity to provide feedback. Thus, the correct option for this question is C.
What do you mean by Recorded presentations?A recorded presentation may be defined as a popular format of multimedia content with a duration of several seconds or minutes that significantly expresses the advantages of a product, service, or any idea with the support of interesting graphic images, concise text, and appropriate narration.
According to the context of this question, a recorded presentation delivers an advantage to the audience to provide feedback. This is because the process of recorded PowerPoint presentation gives the actual sense and understanding to the audience similar to the real event.
Therefore, the correct option for this question is C.
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A 50.0 g stone is attached to the bottom of a vertical spring and set vibrating. If the maximum speed of the stone is 15.0 cm/s and the period is 0.500 s, find the (a) spring constant of the spring, (b) amplitude of the motion, and (c) frequency of oscillation.
Spring constant of the spring, amplitude of the motion, and frequency of oscillation are respectively 8N/m, 1.2 cm and 2Hz.
To find the answer, we need to know about angular frequency, frequency, amplitude of spring mass system.
What's the angular frequency of the spring mass system, if its time period is 0.5 second?Mathematically, w=2π/Tw= 2π/0.5= 12.6 rad/sWhat's the relation between angular frequency and spring constant?Mathematically, w =√(k/m)k= w²mHere, w= 12.6 rad/s, m= 50gm = 0.05kg k= 12.6²× 0.05 = 8 N/mWhat's the relation between amplitude, angular frequency and velocity of mass of a spring mass system?Mathematically, Amplitude= velocity/angular frequencyHere, velocity= 15 cm/s = 0.15m/s, angular frequency= 12.6 rad/sAmplitude= 0.15/12.6= 0.012m = 1.2 cmWhat's the expression of frequency in term of time period?Frequency= 1/time periodHere time period= 0.5 sFrequency= 1/0.5 = 2 HzThus, we can conclude that spring constant of the spring, amplitude of the motion, and frequency of oscillation are respectively 8N/m, 1.2 cm and 2Hz.
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When a voltage of 12 V is applied to a resistor, a current of 2.5 A passes through it. What is the resistance of the resistor
Answer:
4.8 Ω
Explanation:
Ohm's law
V = IR
or V/I = R
12/2.5 = R = 4.8 Ω
Even with the best and largest telescopes, we can’t see all the stars in the milky way galaxy, even though these same telescopes can show us other galaxies. Why is that?
Because starlight cannot pass through black space, we are unable to view all of the stars in the Milky Way galaxy, even with the best and largest telescopes.
In the Milky Way galaxy, the Earth is situated. Part of it can be seen as a broad, opaque ring of stars and dust on a clear night (from sufficiently dark areas). We can see thousands of these stars with our unaided eyes, and a telescope can reveal many more.
However, a large number of the Milky Way's stars are obscured. The supermassive black hole at the centre of the galaxy and the bulge, which is made up of stars, gas, and dust, are to blame for this. The substance in this is opaque to all but the most powerful telescopes.
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A large box is being pushed across the floor at a constant speed of 4.0 m/s. What can you conclude about the forces acting on the box?
There is no force acting on the large box.
What is the force according to Newton's law?According to Newton's second law of motion, Force is defined as the rate of change of momentum with respect to time.Mathematically, force = mass × accelerationAnd acceleration = velocity/ timeHere, the large box is moving with constant velocity. So its velocity is not changing with time.So velocity / time = zero i.e. acceleration= zeroIt leads to the force to be zero.Thus, we can conclude that the force on the large box is zero.
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Why stars are shows like twinkling in the sky’s!
Reply please!
Answer:
As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.
The work-energy principle states that the work done by all the __________ forces acting on an object (or system of objects) causes a change in total __________ of the object or system.
The work-energy principle states that the work done by all the non-conservative forces acting on an object (or system of objects) causes a change in the total mechanical energy of the object or system.
What is the work-energy principle?
The work-energy principle states that the total work done on a system is equal to the change in kinetic energy of the system. It is given as:
W.D = ΔK.E
= K.E₁ - K.E₂
where K.E₁ is the initial kinetic energy of the system
K.E₂ is the final kinetic energy of the system
What is meant by non-conservative forces?
Non-conservative forces as the name suggests are not conserved i.e. these forces cause a loss of mechanical energy from the system. A prime example of non-conservative forces is friction.
The total mechanical energy of the system is the sum of the potential energy and kinetic energy that the system contains. This energy is conserved and follows the work-energy theorem.
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A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequency of its oscillations?
The frequency of oscillation is 2.153 Hz
What is the frequency of spring?
Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.
For the mass-spring system in this problem,
The Frequency of spring is calculated with the equation:
[tex]f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]
Where,
f = frequency of spring
k = spring constant = 64 N/m
m = mass attached to spring = 350g = 0.350 kg
a = maximum acceleration = 5.3 m/s^2
Substituting the values in the equation,
[tex]f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }[/tex]
[tex]f = \frac{1}{2\pi } ( 13.522)[/tex]
[tex]f = 2.1535 Hz[/tex]
Hence,
The frequency of oscillation is 2.153 Hz
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What was Kobe’s attitude toward life and competition?
Answer: Positive
Explanation: Kobe has had an positive attitude on situations and life itself. No matter the competition he still kept a positive attitude regardless. He still wished the best for others even if his enemies thought otherwise. So Kobe was a positive person on the outlook of life and competition.
what is the best fuse for 1000 w heater?
a)3A
b)4A
c)5A
d)11A
c)5A
Explanation:
As,
[tex]I = \frac{P}{V} = \frac{1000}{220} = 5[/tex]
= Sem 2 CR-SS159VGSZE
nating a my ponnesis. I art
Since the investigative question has two variables, you
need to focus on each one separately. Thinking only
about the first part of the question, mass, what might be
a hypothesis that would illustrate the relationship
between mass and kinetic energy? Use the format of
"if...then...because..." when writing your hypothesis.
The relationship between mass and kinetic energy is K.E ∝ m and K.E ∝ v².
What is the relationship between mass and kinetic energy?The kinetic energy of an object exists as the energy that it maintains due to its motion. It is defined as the work required to accelerate a body of a disseminated mass from rest to its stated velocity. Having acquired this energy during its acceleration, the body preserves this kinetic energy unless its speed changes.
The kinetic energy is directly proportional to the mass and also directly proportional to the square of the velocity.If we increase the mass, then kinetic energy will also increase.But if we increase the velocity by n times , then the kinetic energy will increase by [tex]n^{2}[/tex] times.To know more about kinetic energy, refer:
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What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise masses d. all of the above e. none of the above
The correct option is A. The information we know about the known exoplanets is estimates of orbits and masses.
What is exoplanets?An exoplanet or extrasolar planet is a planet outside the Solar System.
In other words, exoplanet is any planet beyond our solar system.
Characteristics of exoplanetsexoplanets are known for the following characteristics;
they are usually hotthey can orbit their stars so tightly that a “year” lasts only a few daysthey can orbit two suns at onceThus, the information we know about the known exoplanets is estimates of orbits and masses.
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If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, what is the Earth's Mass
Answer: If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, then, the Earth's Mass is [tex]6*10^{24}kg[/tex].
Explanation: To find the answer, we have to know more about the Law of periods or the harmonic law.
What is the law of periods or harmonic law?The law of periods states that, the square of the period of revolution of a planet is proportional to the cube of the semi major axis of the elliptical path.We can express it as,[tex]T^2[/tex]∝ [tex]r^3[/tex]
[tex]T^2=\frac{4\pi ^2r^3}{GM}[/tex]
How to solve the problem?From the above given equation, we can reduce mass of earth as,[tex]M=\frac{4\pi ^2r^3}{GT^2}[/tex]
Substituting the values given in the question, we get,[tex]M=\frac{4\pi ^2(3.8*10^8)^3}{6.67*10^-11*(27.3*24*60*60s)^2} =\frac{2.164*10^{27} }{371.08} =5.831*10^{24}=6*10^{24}kg[/tex]
Thus, we can conclude that, the mass of earth is [tex]6*10^{24}kg[/tex] .
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An astronomy student, for her PhD, really needs to estimate the age of a cluster of stars. Which of the following would be part of the process she would follow
Plotting what is referred to as an H-R diagram for the stars in the cluster is part of the process in which the astronomy student will follow in this type of scenario.
What is H-R diagram?This is referred to as the Hertzsprung–Russell diagram and is a scatter plot which depicts the relationships between stars' absolute magnitudes versus their effective temperature. It can also be inferred that the higher the luminosity of a star, the higher the temperature and vice versa.
This helps to depict stellar evolution as a result of the features used as parameters such as the life cycle as an older star will be less luminous when properly studied by people hereby making it easier to estimate the age of stars.
This therefore the reason why plotting a Hertzsprung–Russell diagram is very important.
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A hypothetical metal has the bcc crystal structure, a density of 7. 24 g/cm3, and an atomic weight of 48. 9 g/mol. The atomic radius of this metal is.
Atomic radius of this metal is 0.85 x 10^23
Given:
density of metal = 7. 24 g/cm3
metal has the bcc crystal structure
atomic weight = 48. 9 g/mol
To Find:
atomic radius of this metal
Solution: Atomic radius is defined as half the distance between the centers of two neighboring atoms. the atomic radius of a simple cube and hcp is a/2 respectively, whereas it is a√2/4 and a√3/4 for fcc and bcc respectively.
density = Z x M/N• x a^3
a = edge length
Z = 2 atoms = numeber of atoms per unit cell
N• = 6.023 x 10^23 atoms/mol = Avogadro's number
a^3 = density x N•/Z x M
a^3 = 7.24 x 6.023 x 10^23/ 2 x 48. 9
a = 3√0.44 x 10^23
a = 1.98 x 10^23
4R = √3a
R = √3 x 1.98 x 10^23/4
R = 0.85 x 10^23
Atomic radius of this metal is 0.85 x 10^23
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Define mass .Also write the table showing the relation of 'kg' with it's sub- multiples and multiples.
Answer:
the quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.
Answer:
The quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.
Explanation:
What must the charge (sign and magnitude) of a 3.45 g particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 590 N/C
charge must be equal to 5.74 ×10⁻⁵
In the question it is said that the particle remains stationary which means the the net force on the particle is zero. So, the counterbalancing forces must be equal which means weight is equal to upward electric force.
→ Fnet =0
→ mg = qE
substituting the values we get :
0.00345 × 9.81 = q × 590
→ q = 5.74 ×10⁻⁵
Hence the charge must be equal to 5.74 ×10⁻⁵.
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You are singing a song at karaoke and reach a part that requires a louder, more intense sound. What must you do to produce a louder sound
More energy is used in creating a louder sound from the mouth.
What must you do to produce a louder sound?We use more energy in order to produce a louder sound because energy is the thing that helps in the formation of loud sound. Loudness is dependent on the energy that creates loud sound in the mouth. More energy we apply, more loud sound will produce. Energy is the main factor which gives us a loud sound in each and every instruments. Without, we can't imagine loud sound.
So we can conclude that more energy is used in creating a louder sound from the mouth.
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What is a stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second?
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .
Discharge rate = velocity * area
= velocity * depth * width
= 2 * 2 * 10 = 40 [tex]m^{3}[/tex]/sec
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .
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What was the role of gravity in the formation of the solar system?
A. Gravity caused the solar system to move closer to the Sun.
OB. Gravity caused the solar system to compress into one larger
mass.
OC. Gravity caused the solar system to separate into individual
celestial bodies.
D. Gravity caused the solar system to expand from a central point.
The role of Gravity in the formation of the solar system is that gravity caused the the solar system to move closer to the Sun.
This was possible because gravity attracted smaller particles together until they formed large particles and began to rotate around the sun.
What is Gravity?Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.
Gravity can also be said to mean an attraction between objects objects with mass.
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physical and chemical properties of water
(Not sure how many examples you need so I will put three for each)
Physical:
Chemical:
One of the most significant characteristics of water is its amphoteric tendency. Amphoteric refers to a substance's capacity to function as an acid or base. Water is neither acidic nor basic in its natural form. Its capacity to give and receive protons is the key justification. However, rainfall has a pH between 5.2 and 5.8, making it mildly acidic.Water is referred to be the all-purpose solvent. This is due to its chemical makeup, physical characteristics, high dielectric constant, and other factors that make it the most solvent material. It can attract other compound molecules, disabling their molecular forces and causing them to dissolve since hydrogen and oxygen both have positive and negative charges that are available.Water is a chemical molecule made up of two hydrogen atoms and one oxygen atom. The liquid condition of that substance is often referred to as water, and the solid and gas phases are respectively referred to as ice and steam.A lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms , what is the average electric current in the lightning?
The average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A
Why Lightning Conductors on top of a tower ?The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.
Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.
one charge = 1.6 × [tex]10^{-19}[/tex] C
Average current I = Q/t
Where
Q = charge = 1.6 × [tex]10^{-19}[/tex] Ct = time = 2ms = 2 × [tex]10^{-3}[/tex] sI = current = ?Substitute all the parameters into the formula
I = 1.6 × [tex]10^{-19}[/tex] C ÷ 2 × [tex]10^{-3}[/tex]
I = 8 × [tex]10^{-17}[/tex] A
Therefore, the average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A
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Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distance between the first- and second-order dark fringes on the screen.
Answer:
The fringes are 4.7*10^-7 m apart, such that they are adjacent.
Explanation:
Using the formula for adjacent fringes given a single slit:
Δ[tex]x=\frac{(Wavelength)(Distance between slit and screen)}{Width}[/tex]
Δ[tex]x=\frac{(590/10^{9})(1.90) }{(2.30)}[/tex]
Δ[tex]x=0.000000487 m[/tex]
Hope this helps!
The distance between the first-order and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.
Given:
wavelength, λ = 590 nm = 590 × 10⁻⁹ m
Distance between the slit and screen, D = 1.90 m
Width of slit, d = 2.30 m
Calculation:
We know that the distance between two slits is given as:
Δx = λD / d
where λ is the wavelength of light
D is the distance between the slit and screen
d is the width of the slit
Applying values in the above equation we get:
Δx = (590 × 10⁻⁹ m)(1.90 m) / (2.30 m)
= 4.874 × 10⁻⁷ m
= 4.874 × 10⁻⁵ cm
Therefore, the distance between the first- and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.
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An astronomical telescope is designed with over magnification of 35x if the object has a focal length of 100 cm what should be the focal length of the eyepiece and how far should the eyepiece be from the objective
The focal length of eyepiece is 2.85.
It is given that astronomical telescope is designed with over magnification of 35.
The object has a focal length of 100 cm.
We need to determine the focal length of the eyepiece.
The formula to be used here is for astronomical telescope is:
[tex]m=\frac{f_{0} }{f_{e} }[/tex]
Using values here, we get
[tex]35=\frac{100 }{f_{e} }[/tex]
[tex]f_{e}=100/35=2.85[/tex]
Hence, the focal length of eyepiece is 2.85
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Why is quantum computing potentially a better fit for weather forecasting than classical computers?.
Quantum computing is a better fit than classical computing because it can access advanced simulations for vast quantities of weather.
What is Quantum computing?
Quantum computing can process large number of data sets of weather for all the properties of quantum states. Unlike classical computers which contains only standard bits 0 and 1 , quantum computing use Qubit or Quantum bit in which there are more than two standard sets of bits. These Qubits can measure the light at any degrees of polarisation between 1 and 0.This is the spin attribute that corresponds to superposition. This can create a lot more possibilities beacuse we can run multiple tasks at once with only one bit of data beacuse of the superpositioned qubit. This unlike classical computers where the bit can be only 1 and 0 is more effectively used in breaking encryption tasks.
So, the analysis of vast quantities of weather data can be done in seconds using Quantum computing.
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Two parallel wires are separated by 0.36 m. Wire A carries 4.8 A and Wire B carries 8.9 A, both currents in the same direction. The force on 0.53 m of Wire A is:
The force on 0.53 m of Wire A is 1.3×10^(-5) N.
To find the answer, we need to know about the force on a current carrying wire due to another parallel wire.
What's the force experienced by a current carrying wire of length L due to another current carrying parallel wire?The magnetic force experienced by the wire here= μ₀IAIBL/(2πr)IA= current in wire A, IB= current in wire B, L = length of wire and r= separation between themWhat's the force on 0.53 m of Wire A, if IA, IB, L and r are 4.8A, 8.9A, 0.53m and 0.36 m respectively?Force = (4π×10^(-7)×4.8×8.9×0.53)/(2π×0.36)
= 1.3×10^(-5) N
Thus, we can conclude that the force on 0.53 m of Wire A is 1.3×10^(-5) N.
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It is advisable to place room heater at the ground level for effective heating
Answer:
yes
Explanation:
The heater is placed near the floor because the air currents move upwards so the hot air fills up the whole room. Whereas, an air conditioner is placed near the ceiling because the cold breeze tends to settle down. If it is placed near the floor then it will fill just the bottom of the room with cool air.
Excessive use of fossil fuels causes an energy crisis
yes, it causes an energy crisis. Burning Fossil Fuels
When we burn oil, coal, and gas, we don't just meet our energy needs, we move the current global warming crisis as well.
Fossil fuels produce large amounts of carbon dioxide when burned. Carbon emissions trap heat in the air and lead to climate change.
What are the major causes of energy crisis?
Most energy crises have been caused by localized shortages, wars and market manipulation. Some have argued that government efforts like tax hikes, nationalization of energy companies, and rule of the energy sector, shift supply and demand of energy away from its economic stability.
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