see attached, thanks !!

Answer:

Distance = speed×time = 180×3 = 540 Km

Answer:

3

Explanation:

i took the quiz

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (19 ft/s − 0 ft/s) / 8.8 s

a = 2.16 ft/s/s

Given parameters:

Initial velocity  = 0m/s

Final velocity = 19ft/s

Time taken  = 8.8s

Unknown:

Acceleration

Solution:

Acceleration is the change in velocity with time of a body;

                 Acceleration  = [tex]\frac{v - u}{t}[/tex]

v is the final velocity

u is the initial velocity

t is the time taken

    input the parameters and solve;

              Acceleration = [tex]\frac{19 - 0}{8.8}[/tex]  = 2.16ft/s

Now, the acceleration is 2.16ft/s

Answer: When you change the direction of the current, you also change the direction of the magnetic field. Because the magnetic field created by the electric current in the wire is changing directions around the wire, it will repel both poles of the magnet by bending away from the wire.

Explanation:

Answer:

The amount of luminous flux per unit area

Explanation:

Explanation:

eff = m.a/ v.r

m.a = L /E

30/ 20

= 1. 5

Answer:

Explanation:

Capacity: the max amount that something can contain.

"the capacity of the freezer is 1.1 cubic feet"

capacitor: device for storing electrical energy, includes two conductor that are close to one another and insulated from each other. A simple example is a parallel-plate capacitor.

Source: Britannica.com

Answer:

Explanation:

Answer:

The correct relationships are T-fg=ma and L-fg=0.

(A) and (C) is correct option.

Explanation:

Given that,

Weight Fg = mg

Acceleration = a

Tension = T

Drag force = Fa

Vertical force = L

We need to find the correct relationships

Using balance equation

In horizontally,

The acceleration is a

[tex]T-Fd=ma[/tex]...(I)

In vertically,

No acceleration

[tex]w=L[/tex]

[tex]mg-L=0[/tex]

Put the value of mg

[tex]L-fg=0[/tex]....(II)

Hence,  The correct relationships are T-fg=ma and L-fg=0.

(A) and (C) is correct option.

In the attached picture we can see the original question.

A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag force Fd is exerted by the water on the ski. The water also exerts a vertical lift force L on the skier. The correct relationships are:

(A) [tex]T - F_d = ma[/tex]

(C) [tex]L - F_g = 0[/tex]

A water skier is moving to the right with acceleration a. If we analyze the forces in the horizontal direction, we can identify the tensión force (T), in the direction of the movement and the drag force (Fd), opposing to the movement. According to Newton's second law of motion, the resultant of these forces is equal to the product of the mass of the water skier and its acceleration.

[tex]T - F_d = ma[/tex]

In the vertical direction, we have the weight of the water skier (Fg) and the lift force (L) exerted on the skier by the water. The resultant of these 2 forces is zero, since there is no acceleration in the vertical direction.

[tex]L - F_g = 0[/tex]

A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag force Fd is exerted by the water on the ski. The water also exerts a vertical lift force L on the skier. The correct relationships are:

(A) [tex]T - F_d = ma[/tex]

(C) [tex]L - F_g = 0[/tex]

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Answer: Tesla’s Model S Performance is the fastest-accelerating production car. The luxury sedan reaches 60 mph in just 2.4 seconds, which outperforms every supercar available today.

Explanation:

The direction of the induced current is counterclockwise.

This states that induced electric current flows in a direction such that the current opposes the change that induced it.

The direction of the induced current is counterclockwise as a result of the north pole being oriented downwards which is the opposite direction of the hands of a clock movement.

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Answer:

114.29s

Explanation:

average speed = distance/Time

Given

speed = 7m/s

distance = 800m

Required

Time taken by the runner to complete the race

From the formula:

Time = Distance/speed

Time = 800/7

Time = 114.29seconds

Hence it took the runner 114.29s to complete the race

Answer:

a = 4.125 [m/s^2]

Explanation:

In order to calculate the value of acceleration, we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces [N]

m = mass [kg]

a = acceleration [m/s^2]

Performing a summation of forces on the x-axis, we have:

4000 - 700 = m*a

4000 - 700 = 800*a

a = 4.125 [m/s^2]

Answer:

observation

hypothesis

theory

matter

agent

experimental group

control group

temperature

particle

criteria

Explanation:

The image of the Douglas fir post is missing, so i have attached it.

Answer:

-0.00025918 mm

Explanation:

We are given the points it passes through as;

(y1, w1) = (0, 4)

(y2, w2) = (2, 12)

Thus, the slope is;

K = (w2 - w1)/(y2 - y1)

K = (12 - 4)/(2 - 0)

K = 8/2

K = 4

Now, substituting one of the points into the slope equation, we have;

w - w1 = k(y - y1)

w - 4 = 4(y - 0)

w = 4y + 4

For us to now find the total force the distributed load applies to the body, we will integrate to give;

W(y) = ∫w•dy

Thus;

W(y) = ∫(4y + 4)dy

W(y) = 2y² + 4y

So, the value of this force which is at y = 2 m will be;

W(2) = 2(2²) + 4(2)

W(2) = 16 KN

Now, at equilibrium, we sum up the forces in the vertical y-direction to give;

W - 20 + F = 0

F = 20 - W

F = 20 - 16

F = 4 KN

If we cut through the body to get a free body diagram and sum forces in y-direction to zero, the displacement of the top of the post A with respect to its bottom B is;

δ_B/A = [(L, 0∫)(W - 20)dy]/AE

Where A is πr²

We are given diameter = 100 mm

So, radius = 100/2 = 50 mm = 0.05 m

Also, from tables the Young's modulus of Douglas fir is 13.1 GPa or 13.1 × 10^(9) Pa

Thus;

δ_B/A = [(2, 0∫)(2y² + 4y - 20)dy]/(π × 0.05² × 13.1 × 10^(9))

δ_B/A = [((2 × 2³/3) + (2 × 2²) - 20(2)) - 0] /(0.102887 × 10^(9))

δ_B/A = (16/3 + 8 - 40)/(0.102887 × 10^(9))

δ_B/A = -0.00000025918 m = -0.00025918 mm

answer:

change in momentum = 37,500kg.m/s in the opposite direction

time it takes = 12.5s

working:

u=25m/s

v=0m/s

F=ma

-3000=(1500)(a)

-3000÷1500=a

a= -2m/s^2

Change in momentum=mv-mu

(1500)(0)-(1500)(25)

= -37,500kg.m/s

relax the( - ) represents direction

v=u-at

0=25-2t

2t=25

t= 12.5s

Answer:

(1).  This motion is projectile motion.

(2). The horizontal initial velocity is 19.3 m/s.

The vertical initial velocity is 22.9 m/s.

(3). The time is 3.9 sec.

(4). The range of the ball assuming the ground is flat and horizontal is 90.4 m.

Explanation:

Given that,

Angle = 40°

Velocity = 30 m/s

(1). A soccer ball is kicked at an angle from the ground at a speed of 30 m/s.

So, this motion will be projectile motion.

(2). We need to calculate the vertical and horizontal components of the initial velocity of the ball

Using formula of  vertical initial velocity

[tex]u_{y}=u\cos\theta[/tex]

Put the value into the formula

[tex]u_{y}=30\cos40[/tex]

[tex]u_{y}=22.9\ m/s[/tex]

Horizontal initial velocity ,

[tex]u_{x}=u\sin\theta[/tex]

Put the value into the formula

[tex]u_{x}=30\sin40[/tex]

[tex]u_{x}=19.3\ m/s[/tex]

(3). We need to calculate the time

Using formula of time

[tex]t=\dfrac{2u\sin\theta}{g}[/tex]

Put the value into the formula

[tex]t=\dfrac{2\times19.3}{9.8}[/tex]

[tex]t=3.9\ sec[/tex]

(4). We need to calculate the range of the ball assuming the ground is flat and horizontal

Using formula of range

[tex]R=\dfrac{v^2\sin2\theta}{g}[/tex]

Put the value into the formula

[tex]R=\dfrac{30^2\sin80}{9.8}[/tex]

[tex]R=90.4\ m[/tex]

Hence, (1).  This motion is projectile motion.

(2). The horizontal initial velocity is 19.3 m/s.

The vertical initial velocity is 22.9 m/s.

(3). The time is 3.9 sec.

(4). The range of the ball assuming the ground is flat and horizontal is 90.4 m.

Answer:

He must be riding on a horse named Saturday.

Explanation:

He rode Saturday on Friday, stayed in the town for 3 days and left on his horse, named Saturday.

I've heard this many times.

he left his house on a Thursday got their on a Friday and left on Saturday Explanation:

this is the best i can do

Whenever someone want to study regions where star formation is currently happening Infrared emission to identify T Tauri stars.

A star-forming region  serves as a  region of the celestial sphere where predominately young stellar objects can be found and  where formation is likely occurring.

Infrared emission to identify T Tauri stars can be used in determining the formation, however it should be noted that Einstein X-ray Observatory made earliest detections of X-rays from T Tauri stars.

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Answer:

ggggggfjhfbgehfe no idk yes maybe

Explanation:

Answer:

it increases

Explanation:

The final speed of the cart increases in relation to the pattern in the position data.

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Answer:

T = 530 N ,     t = 12.65 s

Explanation:

This is an exercise on Newton's second law,

           T - W = m a

where T is the tension of the cable, W the weight and the steel of the box

            T = W + ma

the weight of a body is

            W = m g

Let's replace

          T = m g + ma

          T = m (g + a)

let's calculate

          T = 50 (9.8 + 0.8)

          T = 530 N

To calculate the time we use

          y = v₀t + ½ a t²

since the box starts from rest on the sole its initial velocity is zero

          y = ½ a t2

           t = √ 2y / a

let's calculate

          t = √ (2 10 / 0.8)

         t = 12.65 s

TRASLATE

Este es un ejercicio de la segunda ley de Newton,

           T – W = m a

donde T es la tension del cable, W el peso y a la aceracion de la caja

            T = W + ma

el pesode un cuerpo es

            W = m g      

Substituyamos

          T = m g + ma

          T = m ( g +a)

calculemos

          T = 50 ( 9,8 + 0,8)

          T = 530 N

Para calcular el tiempo usamos

          y = v₀t + ½ a t²

como la caja parte del reposo en el suela su velocidad inicial es cero

          y=   ½ a t²

           t= √ 2y/a

calculemos

          t = √ (2 10/0,8)

         t = 12,65 s

Answer:

t = 0.12 s

Explanation:

Applying the second equation of motion under free fall,

h = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

where: h is the height, u is its initial velocity, t is the time taken and g is the gravitational force.

But, u = 0 m/s, h = 21 cm (0.21 m) and g = 9.8 m/[tex]s^{2}[/tex]. Then:

0.21 = 0 + [tex]\frac{1}{2}[/tex] x 9.8 x [tex]t^{2}[/tex]

0.21 = 4.9[tex]t^{2}[/tex]

[tex]t^{2}[/tex] = [tex]\frac{0.21}{4.9}[/tex]

  = 0.04286

⇒ t = 0.2070

      = 0.21 s

The time taken for the flea to jump as high as 21 cm is 0.21 s.

The time taken for the flea to reach a height of 7.0 cm (0.07 m) can be determined as;

h = ut +  [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

0.07 =  0 + [tex]\frac{1}{2}[/tex] x 9.8 x [tex]t^{2}[/tex]

0.07 =  4.9[tex]t^{2}[/tex]

[tex]t^{2}[/tex] = [tex]\frac{0.07}{4.9}[/tex]

  = 0.01429

t = 0.1195

 = 0.12 s

The value of the charge will be 35 ×10¹ C. A charge is something experienced as a force in the electric and megnetic field.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.

The given data in the problem is;

F is the electric force= 2.4 × 10-³ N

q is the electric charge=?

E is the strength of the electric field = 6.8 × 10⁻⁵ (N/C)

The electric force is given by;

[tex]\rm F =qE \\\\ \rm q= \frac{F}{E} \\\\ \rm q= \frac{2.4 \times 10^{-3}}{6.8 \times 10^{-5}} \\\\ \rm q=35 \times 10^1 \ C[/tex]

Hence the value of the charge will be 35 ×10¹ C

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Answer:

D

Explanation:

E2020

Answer:

1.) 1000 N/c

2.) 200000 N

3.) 60v

4.) 120000J

5.) 4899 m/s

Explanation:

Given that a 100V battery is connected to two oppositely charged plates that are 10cm apart. 

1.) The magnitude of electric field strength is the ratio of potential difference per distance between the plates. That is,

Electric field = V/d

Electric field = 100/0.1

Electric field = 1000 wb

2.) Electric field strength is also the ratio of force per unit ccharge. That is,

Electric field = F / q

1000 = F / 200

Cross multiply

F = 1000 × 200

F = 200000 N

3.) What is the electric potential energy of the charge when it's 8cm and 2cm from the negatively charged plate?

The distance = 8cm - 2cm = 6cm

Electric field = V / d

Substitute the electric field and the distance into the formula

1000 = V / 0.06

Make V the subject of formula

V = 1000 × 0.06

V = 60 V

4.) How much work was required to move the charge from 8cm to 2cm?

Work done = VQ

Since V = 60v

Then,

Work done = 60 × 200

Work done = 120000 J

5.) If the 10 gram point charge was at rest at point A, what is the final speed at point B?

Work done = 1/2mv^2

120000 = 1/2 × 0.01 × v^2

V^2 = 120000/ 0.005

V^2 = 24000000

V = 4899 m/s

The magnitude of electric field strength has been 1000 wb.

The electric force (F) applied by 200 C charge has been 2000,000 N.

The values for electric potential energy has been 60 V.

The work done in moving the charge across the plate has been 12 kJ.

The speed of charge at point B has been 48.98 m/s.

The magnitude of electric field strength  has been defined as the force per unit charge.

[tex]E=\dfrac{V}{d}[/tex]

Where, the voltage of battery, [tex]V=100\;\rm V[/tex]

The distance between plates, [tex]d=10\;\rm cm\;;0.1\;m[/tex]

Substituting the values for magnitude of electric field strength  (E):

[tex]E=\dfrac{100}{0.1} \\E=1000\;\rm wb[/tex]

The magnitude of electric field strength has been 1000 wb.

[tex]F=E\;\times\;q[/tex]

Where, the magnitude of electric field strength, [tex]E=1000\;\rm wb[/tex]

The charge for the force has been, [tex]q=200\;\rm C[/tex]

Substituting the values for electric force (F):

[tex]F=1000\;\times\;200\\F=200000\;\rm N[/tex]

The electric force (F) applied by 200 C charge has been 2000,000 N.

[tex]E=\dfrac{V}{d}[/tex]

The magnitude of electric field strength, [tex]E=1000\;\rm wb[/tex]

The distance between plates, [tex]d=8\rm \;cm-6\;cm\\d=2\;cm\;;0.02\;m[/tex]

Substituting the values for electric potential energy, (V):

[tex]1000=\dfrac{V}{0.0.06} \\V=1000\;\times\;0.06\\V=60\;\rm V[/tex]

The values for electric potential energy has been 60 V.

[tex]W=Vq[/tex]

Where, the electric potential energy of the battery has been, [tex]V=60\;\rm V[/tex]

The charge for the force has been, [tex]q=200\;\rm C[/tex]

Substituting the values for work done, (W):

[tex]W=60\;\times\;200\\W=12,000\;\text J\\W=12\;\rm kJ[/tex]

The work done in moving the charge across the plate has been 12 kJ.

[tex]W=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2W}{m} }[/tex]

Where, the work done on unit charge, [tex]W=12,000\;\rm J[/tex]

The mass of the charge, [tex]m=10\;g[/tex]

Substituting the values for calculating the speed of charge, (v):

[tex]v=\sqrt{\dfrac{2\;\times\;12,000}{10} } \\v=\sqrt{24,000}\\v=48.98\;\rm m/s[/tex]

The speed of charge at point B has been 48.98 m/s.

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Answer:

44

Explanation:

v=u+a(t)

v=18+4(2)

v=22(2)

v=44 (where v=final velocity,u=initial velocity,a=acceleration,and t=time)

Answer:A.325J

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