Sound will travel fastest in air at _____.
-5°C
0°C
10°C
15°C
The following table lists the speed of sound in various materials. Use this table to answer the question.
Substance
Speed (m/s)
Glass
5,200
Aluminum
5,100
Iron
4,500
Copper
3,500
Salt water
1,530
Fresh water
1,500
Mercury
1,400
Hydrogen at 0°C
1,284
Ethyl Alcohol
1,125
Helium at 0°C
965
Air at 100°C
387
Air at 0°C
331
Oxygen at 0°C
316

Answers

Answer 1

Answer:

iron/copper

iron faster because it in the core so iron is the answer with would be 15C because its the hottest in the core and is very quick there to being moved by the core so iron being 15C is the answer.

Explanation:


Related Questions

A ball is thrown horizontally from a height of 1 m and lands 5 m away.What is the initial velocity of the ball?

Answers

Answer:

11.06797181 ms^-1 only.......

11. What is the mass of an object which has 2400 J of KE when traveling at 5 points
6 m/s?
63 kg
130 kg
270 kg
400 kg

Answers

Answer:

270 Kg e 130 kg

Explanation:

how many times is the number put together

Shine the flashlight on the liquid sheet. Did you observe evidence that light carries energy

Answers

Answer:

Think of an object you have observed ... Work with your group to gather evidence that light carries energy, then answer the questions below. Shine the flashlight on the liquid crystal sheet.

8. Which phase of matter is most common in the
universe?
a. Plasma b. Solid c. Liquid d. Gas
Need this now

Answers

A. Plasma
That is your answer!

Answer:

plasma

Explanation:

Cause in the universe many exist in either in gaseous or plasma form but plasma is greater

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch effort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. The astronaut has a mass of ma=102 kgma=102 kg and the bag of tools has a mass of mb=10.0 kg.mb=10.0 kg. If the astronaut is moving away from the space station at vi=2.10 m/svi=2.10 m/s initially, what is the minimum final speed vb,fvb,f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?

Answers

Answer:

The answer is "[tex]2.352 \ \frac{m}{s}[/tex]"

Explanation:

[tex]\to mass(m_1)=102 \ kg\\\\\to mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\[/tex]

momentum before:

[tex]\to p=(m_1+m_2)v[/tex]

       [tex]=(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2[/tex]

momentum After:

[tex]\to p=(m_1+m_2)v[/tex]

       [tex]=(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\[/tex]

Calculating the conservation of momentum:

[tex]\to \text{momentum before = momentum After}[/tex]

[tex]\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}[/tex]

Three point charges are fixed in place in a right triangle, as shown in the figure.
What is the magnitude of the electric force on the +1.00-C charge due to the other two charges?
What angle does the force make with the -x-axis? A positive angle is counterclockwise from the -x-axis.

Answers

For the three-point charges fixed in a right triangle, we have:

1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. The force does an angle of 21.68° with the x-axis.

1. Magnitude of the electric force

First, let's denote the charges as is shown in the picture below:

q₁: is the charge 1 = +0.800 μC = +0.800x10⁻⁶ Cq₂: is the charge 2 = +1.00 μC = +1.00x10⁻⁶ Cq₃: is the charge 3 = -0.600 μC = -0.600x10⁻⁶ C

                                                                       

The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:  

[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex]  (1)    

Where:  

[tex]\Sigma\vec{F}_{x}[/tex]: is the sum of the forces acting on the x-axis[tex]\Sigma\vec{F}_{y}[/tex]: is the sum of the forces acting on the y-axis

We can calculate the electrical forces with Coulomb's law:

[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]

Where:

K is the Coulomb's constant = 9.00x10⁹ Nm²/C²  q₁ and q₂ are the chargesd is the distance between the charges

     

Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])

The forces in the x-component are given by:

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex]   (2)

Where:              

θ: is the angle of the force F₂₁ with the x-axisd₁₂ = z = 9.60 cm = 0.0960 m  d₂₃ = x

We can calculate the angle θ with the following trigonometric function:

[tex]sin(\theta) = \frac{y}{z}[/tex]

[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]

To find the distance x (d₂₃), we need to use Pythagoras:

[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]

 

After entering θ and x (d₂₃) into equation 2, we have:

[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]

[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]

Hence, the x-component of the force is -1.66 N.

Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])

The only force acting on the y-axis is the y-component of the force F₂₁, so:

[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]

The minus sign is because the vector is pointing in the negative y-direction (see the picture below).

[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]

Hence, the y-component of the force is -0.66 N.

Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):  

[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]                                  

Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. Direction of the force with the x-axis

According to the picture below, the angle of the force with respect to the x-axis is given by:  

[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]

[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]

Therefore, the force does an angle of 21.68° with the x-axis.

Find more about Coulomb's law here:  

brainly.com/question/506926        

I hope it helps you!                

How many significant figures are there in the number
2.3409500?

Answers

There are 8 significant figures

What is the equation of the line that is perpendicular to y= -4x +5 and passes through the point (4,-3)?

Answers

Y=4x-19

Perpendicular because it has an opposite reciprocal slope

An ice skater of mass 82 kilograms stands at rest in her skates on the ice rink. Someone throws a 5-kg ball at her at a speed of 17.4 m/s and she catches it. At what speed will she(and the ball) slide backwards?

Answers

Answer:

1 m/s

Explanation:

I showed my work in the picture attached.

This web page helped me solve this problem and understand inelastic collisions a little better:

https://byjus.com/physics/inelastic-collision/

She slide(and the ball) backwards at the speed of 1m/s when she catches the ball of 5-kg coming at speed of 17.4 m/s.

What is momentum ?

Momentum is defined as mass times velocity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum.  its dimensions is [M¹ L¹ T⁻¹].

Momentum is conserved throughout the motion.

According to conservation law of momentum initial momentum is equal to final momentum.

Given,

mass of the skater m₁ = 82 kg

mass of the ball m₂ = 5kg

initial velocity of the ball v'₂ = 17.4 m/s

initial velocity of the skater v''₂= v'₁= 0

final velocity of the ball & skater = v''₁ = ?

According to law of conservation of momentum,

initial momentum = final momentum

m₁v'₁ +m₂v'₂ = m₁v₁'' + m₂v''₂

putting all values in the equation.

0+ 5×17.4 = 82×v₁'' + 5×v₁''

v₁''(82+5) = 87

v₁'' = 1 m/s

Hence he(and the ball) slide backwards at 1m/s

To know more about conservation of momentum click :

https://brainly.com/question/24301052

#SPJ2

Which of the following has the most kinetic energy?
A.
A car traveling at 80 kph.

B.
A tractor trailer traveling at 80 kph.

C.
A cheetah running at 80 kph.

D.
A notorcycle traveling at 80 kph.

Answers

Answer:

B

Explanation:

A tractor is the heaviest

Explain the theory of plate tectonics and how they have changed Earth’s surface over time. Include the role of plate tectonics in the creation of landforms.

Answers

Plate tectonic theory is the movement of the plates or slabs of rigid rocks over the surface of the earth or the molten rocks that is the mantel.  

It explains how the continents have drifted over time due to the changes in the earth's geology over the years.  It also explains how earthquakes, volcanic eruptions, and mountain ranges are created. Hence  the arrangement and formation of the present shape of the earth continents.

Learn more about plate tectonics and how they have changed Earth.

brainly.com/question/19649061.

give two differences between sextusl reproduction and asextual reproduction

Answers

Answer:

Sexual reproduction you need two organisms to reproduce.

Asexual is when you can multiply yourself and there is nothing different about the offspring and the parent.

The mass and weight of box is 25 Kg and 245 N respectively when on Earth. What is the value of mass and weight of the box when it is brought to the moon?

Answers

Answer:

25 (kg) and 40.5 (N).

Explanation:

1) the value of 'g' on the Earth is ~9.81 (N/kg), the value of 'g' on the Moon is ~1.62 (N/kg).

It means, the mass is not depended on the value of 'g', but the weight is depended on it.

2) the mass on the Moon is the same, 25 kg.

the weight is 25*1.62=40.5 N

A child throws a ball with an initial speed of at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00 m above the ground and experience negligible air resistance. (a) What is the magnitude of the ball's velocity just before it hits the ground? (b) At what angle below the horizontal does the ball approach the ground?

Answers

Complete Question

A child throws a ball with an initial speed of 8.00 at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00 m above the ground and experience negligible air resistance. (a) What is the magnitude of the ball's velocity just before it hits the ground? (b) At what angle below the horizontal does the ball approach the ground?

Answer:

[tex]v=9.16m/s[/tex]

[tex]\theta=48.1 \textdegree[/tex]

Explanation:

From the question we are told that

Angle of ball [tex]\angle=40 \textdegree[/tex]

Height of ball h=1m

Generally the equation for vertical component  is mathematically given by

[tex]v_y=vsin \theta[/tex]

[tex]v_y=8sin 40 \textdegree[/tex]

[tex]v_y=5.14m/s[/tex]

Generally the equation for horizontal component  is mathematically given by

[tex]v_x=vcos \theta[/tex]

[tex]v_x=8cos 40 \textdegree[/tex]

[tex]v_x=6.12m/s[/tex]

Generally the equation for vertical displacement of ball is mathematically given by

[tex]y=1+v-yt-\frac{1}{2}gt^2[/tex]

[tex]0=1+5.14t-\frac{1}{2}*9.87*t^2[/tex]

[tex]t=1.22sec[/tex]

[tex]v_yt=v_yt-gt[/tex]

[tex]5.14-(9.8*1.22)=-6.816m/s[/tex]

[tex]v_yt=-6.816m/s[/tex]

Generally the velocity of ball before it hits the ground is mathematically given by

Magnitude

[tex]v=\sqrt{6.12^2 +(-6.816)^2}\\[/tex]

[tex]v=9.16m/s[/tex]

Direction of  ball

[tex]\theta=tan^{-1}(\frac{-6.816}{6.12} )[/tex]

[tex]\theta=48.1 \textdegree[/tex]  beneath the horizontal

How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?

Answers

W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J

The bus is heading southwest at 56 miles per hour is it veloctiy or speed

Answers

Answer:

Its velocity

Explanation:

Velocity is speed with a direction.

Speed is the rate at which someone or something is able to move or operate.

In the question its telling us that the bus is going 56 miles per hour but it aslo gives us a direction, in this case is southwest.

if the earth's atmosphere were 50times denser than it is, would sunlight still be while or would it be some other colour? explain​

Answers

If the atmosphere were 50% more dense, sunlight would be much redder then it is now. As the atmosphere increase in density, more and more of the blue light would be scattered away in all directions, making the light that reaches the ground very red. Think of the color of a deep red sunset, but this would be the color even at noon.
Hope this helps!

to calculate the voltage, current, power and energy for an inductor and also to examine the behavior of an inductor under dc conditions. an inductor is a passive circuit element that opposes any change in electric current. a time-varying current induces a voltage in any conductor linked by a magnetic field. an inductor is a passive circuit element that stores energy in its magnetic field.

Answers

Answer:

To calculate the voltage, current, power and energy for an inductor and also to examine the behavior of an inductor under dc conditions.

an inductor is a passive circuit element that stores energy in its magnetic field.

Explanation:

An inductor has been described as a passive electronic component that stores electrical energy in a magnetic form.  It uses a conductor that is wound into a coil to produce DC current, acting as a short circuit when direct current is applied.  When electricity flows into the coil from the left to the right, a current is generated through a magnetic field in the clockwise direction.  It is also called a choke because of its frequency regulation.

Why do we prefer a sharp knife to a blunt one to cut vegetables ?​

Answers

So it can have a clean cut , also so it could go smoothly through the vegetable and to look professionally

Which type of wave needs a medium to travel?
ANSWER: sound waves, because they travel by oscillating molecules
What do both sound and light waves transfer?
ANSWER: Energy
How does an increase in amplitude affect sound and light waves?
ANSWER: louder sound and brighter light
What happens to the wavelength and speed of the waves when the frequency increases?
ANSWER: The wavelength decreases, but speed remains the same.
Which statement about sound waves is correct?
ANSWER: The animated particles are more concentrated along wave crests and less dense along wave troughs.

Answers

Answer:

Mechanical Waves

Why I Know:

Science Class

A type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.

What is a sound wave?

A sound wave can be defined as a form of mechanical wave that requires a medium for its propagation and it creates a disturbance in the medium. Also, the energy of a sound wave travels in a perpendicular direction.

This ultimately implies that, a sound wave needs a medium to travel and it creates a disturbance when it travels through any medium.

In conclusion, a type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.

Read more on sound wave here: https://brainly.com/question/19250621

A dolphin has a mass of 740 kg. He swims along the water at a velocity of 12 m/s and
jumps out of the water so that he has Gravitational Potential Energy of 53000 J.
How high does the dolphin jump?

Answers

Answer:

I dunno

Explanation:

I really wanted to help you, but then I realized i didnt know how to

What does the speedometer in a moving car measure?

Answers

Answer: the speedometer indicates the speed of a vehicle.


1When you look through a magnifying glass, the objects you are looking at
seem larger and you can see them in morsetail. The lenses in a magnifying
glass are​

Answers

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

Could I please get some help on this question I don’t understand .

Answers

Answer:

12.5 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 8 m

Final velocity (v) at 8 m above the lowest point =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 8)

v² = 0 + 156.8

v² = 156.8

Take the square root of both side

v = √156.8

v = 12.5 m/s

Therefore, the velocity of the roller coaster at 8 m above the lowest point is 12.5 m/s.

1 A boy kicks a ball with 40m/s at an angle of 30° with the ground. find the range the ball travels after 6 s.

240 m

208 m

120 m

139 m



Answer and I will give you brainiliest.

Answers

Answer:

208m

Explanation:

since the angle is with the ground which gives a horizontal component to the velocity = v(cos)30°

so the velocity equals 40(cos)30°= 34.64m/s

range(distance) = speed × time

34.64m/s × 6s = 207.8m = 208m

A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?

Answers

Answer:

1km west

Explanation:

Because if the cyclist is going back 2km then its 3-2=1km

An inflated spherical beach ball with a radius of 0.4000 m and average density of 10.65 kg/m3 is being held under water in a pool by Janelle. The density of the water in the pool is 1000.0 kg/m3. When Janelle releases the ball, it begins to rise to the surface. If the drag coefficient of the ball in the water is 0.520 and the constant upward force on the ball is 2630 N, what will be the terminal speed of the ball as it rises

Answers

Answer:

3.71 m/s

Explanation:

Given data :

radius of the spherical ball = 0.400 m

Density of the ball material  = 10.65 Kg/m^3

Density of water = 1000 Kg/m^3

Drag coefficient C_d= 0.520

Constant upward force  F_up= 2630

Concept: The moment before it starts to rise Upward force must be equal to downward drag force

⇒ F_up = F_D

F_D =C_d× 0.5 ×ρ_w×V^2×A

where V= terminal velocity and A=  area πR^2

equating the forces we get

2630= 0.52× 0.5×1000×V^2×π(0.4)^2

V= 3.171 m/s

Therefore, the terminal velocity of the ball = 3.71 m/s

The ball while moving through the water in the pool, experiences a drag force. Then, the magnitude of terminal speed during the rise of the ball is 3.171 m/s.

What is terminal speed?

When an object is made to fall through a liquid medium, then the maximum velocity achieved at that instant is known as terminal velocity or terminal speed.

Given data-

The radius of the spherical beach ball is, r = 0.4000 m.

The density of the ball is, [tex]\rho'=10.65 \;\rm kg/m^{3}[/tex].

The density of water in the pool is, [tex]\rho =1000.0 \;\rm kg/m^{3}[/tex].

The drag coefficient of the ball in water is, [tex]C_{d}=0.520[/tex].

The magnitude of the constant upward force is, F = 2630 N.

As per the concept of Buoyancy, "The moment before the ball starts to rise upward force must be equal to downward drag force".

F = Fd

Here,

F is the upward force.

Fd is the downward force.

[tex]F=\dfrac{1}{2} \times C_{d} \times \rho \times v^{2} \times A[/tex]

Here,

A is the area of the ball.

Solving as,

[tex]2630=\dfrac{1}{2} \times 0.520 \times 1000 \times v^{2} \times (\pi r^{2})\\\\2630=\dfrac{1}{2} \times 0.520 \times 1000 \times v^{2} \times (\pi \times 0.4000^{2})\\\\v=3.171 \;\rm m/s[/tex]

Thus, we can conclude that the magnitude of terminal speed during the rise of the ball is 3.171 m/s.

Learn more about the terminal speed here:

https://brainly.com/question/26505185

Why could the beam of particles not have a neutral charge?

Answers

Answer:

The positive and negative charges balance each other. Overall, the atom is uncharged (neutral). However, if something happens to make an atom lose or gain an electron then the atom will no longer be neutral. An atom that gains or loses an electron becomes an ion.

Explanation:

I think this is the answer : D

help help help help help help help help help

Answers

yes yes yes yes yes yes yes yes

Which diagram is the best model for a solid?
Substance A
Substance B
О Substance C

Answers

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

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