What is the atomic number of this element?

Answers

Answer 1
The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon


So I believe it’s 6 hope this helps if not reply back

Related Questions

Now imagine everyone in the group hug starts moving away from each other what effect do you think that would have on your temperature

Answers

your temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always

temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

What is Temperature?

Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).

Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.

As opposed to extensive characteristics, like mass or volume, temperature is referred to as an intense property—one that is independent of the quantity of matter being considered—along with pressure, density, and other comparable properties.

Therefore, temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

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what is kinetic energy

Answers

Answer:

energy which a body possesses by virtue of being in motion.

Explanation:

hope this help

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there is a rusted nut we have a two spanners each of i 15 cm and 20 CM respectively which spanner is suitable to open the nut and why​

Answers

Answer :

20cm spanner is suitable to open this nut , Because we feel easy to apply force at the end of spanner to rusted nut. It means that as the perpendicular distance between force and axis of rotation increase the magnitude of moment also increase.

I think the Answer will helps you.....

Thank you ☺️☺️☺️

HELP PLEASE!!!!!!!!!

Answers

Answer:

2.00×[tex]10^{8}[/tex]

Explanation:

3×[tex]10^{8}[/tex]/1.5

=2.00×[tex]10^{8}[/tex]

A well substantiated explanation, or, a group of common ideas intended to
explain something. *
O Inference
Theory
Hypothesis
Inertia

Answers

It should be theory because of the scientific method which is a series of tests that have a similar connected idea
the answer is theory!

Help please it’s urgent

Answers

Answer:

Explanation:

The circuit is incomplete since it is a series circuit

8. When are children MOST likely to begin using words to express meaning?​

Answers

8 to 8 months old I’m sure

Explain how the movement of the Moon around the Earth c langes we see at night?

Answers

Answer: We can see the moon at night because the earth spins in a circle wall it is going around the sun so when the sun go down and the moon comes up the suns light will go over the top of earth and hite the moon the all the light that is hite the moon will bounce off it and the moon it a light color and light shins off lighter colored thing and it will have a little proportion of that light will come and hite earth make the moon very easy to see at night and the most light hits the moon when if it a full moon and is the most brite.

I Hope This Helped!

Which of the following is a poor conductor?
metal
Quarters
Ob
O
Od
C
wood
iron

Answers

Wood
Metals are good conductors while wood is not

IP A tow rope, parallel to the water, pulls a water skier directly behind the boat with constant velocity for a distance of 75 m before the skier falls. The tension in the rope is 100 N.
Is the work done on the skier by the rope positive, negative, or zero?
Explain.
Calculate the work done by the rope on the skier.

Answers

The work is done against the skier, we call it negative work, and the magnitude of the work done on the skier by the rope is 7500 J.

Work done on the skier

The work done on the skier by the rope is in opposte direction of the water skier which caused the water skier to fall after some given period of time. Since the work is done against the skier, we call it negative work.

The magnitude of the work done on the skier by the rope is calculated as follows;

W = Fd

where;

F is the applied force on the rope

d is the distance moved by the skier

W = 100 x 75

W = 7500 J

Thus, the magnitude of the work done on the skier by the rope is 7500 J.

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What is bought from an electric company

Answers

Answer: electricity

Explanation:

the answer to the question is electricity.

Please see the image

Answers

Answer:

i think it is 89

An object is swung in a horizontal circle on a length of string
that is 0.93 m long. Its acceleration is 26.36 m/s? What is the
time it takes the object to complete one horizontal circle?

Answers

Answer: either 3.20s or 1.18s

Explanation:

A 3520 kg truck moving north at
18.5 m/s makes an INELASTIC
collision with an 1480 kg car
moving east. After colliding, they
have a velocity of 13.6 m/s at
72.6°. What was the initial velocity
of the car?

Answers

Answer: 13.7 m/s

Explanation:

[tex]$$Mass of $T r u c k$$ \ \left(m_{T}\right)=3520\mathrm{kg}[/tex]

[tex]V_{T_{y}}=18.5 \mathrm{~m} / \mathrm{s} \\&V_{\text {Tix }}=0 \mathrm{~m} / \mathrm{s}[/tex]

[tex]\mathrm{Mass \ of \ car \ (m_c) = 1480 \ kg}[/tex]

[tex]V_{c i x}=\text { ? ; } V_{c i y}=0 \mathrm{~m} / \mathrm{s}[/tex]

[tex]Final \ velocity $\left(V_{f}\right)=13.6 \mathrm{~m} / \mathrm{s} \ \ \theta=72.6$[/tex]

[tex]v_{f x}=v_{f} \cos \theta=(13.6) \cos 72.6=4.067 \mathrm{~m} / \mathrm{s}[/tex]

[tex]\mathrm {Using \ the \ conservation \ of \ momentum \ along\ the \ $x$-axis}[/tex]

[tex]\begin{aligned}m_{T} v_{T i x}+m_{c} v_{c_{i x}} &=\left(m_{T}+m_{c}\right) v_{f x} \\0+(1480) V_{c_{i x}} &=(3520+1480)(4.067) \\(1480) v_{c i x} &=20335 \\V_{c i x} &=13.7 \mathrm{~m} / \mathrm{sec}\end{aligned}[/tex]

Answer:

13.7 m/s

Explanation:

A delivery drone uniformly slowed down from 45 m/s to 23 m/s in a straight line over a 30-minute duration within a 16-
kilometer radius of its warehouse. What was the magnitude of its average acceleration?

Answers

Answer: The Answer is A 1.2 x 10−2 m/s2

The average acceleration of the delivery drone as it slowed down was  -0.012 m/s².

What is average acceleration?

The average acceleration is defined as the average rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given is a delivery drone that uniformly slows down from 45 m/s to 23 m/s in a straight line over a 30-minute duration.

We can write -

[u] = 45 m/s

[v] = 23 m/s

Δt = 30 min = 30 x 60 = 1800 sec

We can write the average acceleration as -

a = Δv/Δt

a = (23 - 45)/1800

a = - 0.012 m/s²

Therefore, the average acceleration of the delivery drone as it slowed down was  -0.012 m/s².

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A framed picture hangs from two cords attached to the ceiling. Which shows the correct free body diagram of the hanging picture?​

Answers

Answer: the answer is in the picture

Explanation:

Answer:

C

Explanation:

i did the test and got 100 :)

A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet, as shown in the diagram above.

The student records observations of how much force it takes to hold the horseshoe magnet in place at each distance. Observations

• 20 cm: no force required
• 10 cm: small force required; easy to hold in place
• 5 cm: large force required; very difficult to hold in place

What do the student's observations demonstrate?

A. The electromagnet's magnetic field becomes stronger as more magnetic material is added to it.

B. The electromagnet's magnetic field is stronger as more turns are added to the wire on the nail.

C. The electromagnet's magnetic field becomes stronger as a small amount of strength is added to the system by the battery.

D. The electromagnet's magnetic field is stronger close to it than far from it.​

Answers

The closer together they are the harder it is to hold on to because the magnetic field is stronger as it gets closer.


Answer:

D. The electromagnet's magnetic field is stronger close to it than far from it.​

Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer to assist the team in other ways in doing so, he is exercising the self-care strategy of?

ANSWER correctly please!!!


A. Being flexible

B. Focusing on the good

C. Maintaining balance

D. Seeking help when needed

Answers

Answer:

Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer to assist the team in other ways in doing so, he is exercising the self-care strategy of?

Answer

A

Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer, so he is exercising the self-care strategy of being flexible that is in Option A.

What is the significance of "flexible"?

Being flexible is an important self-care strategy, as it allows individuals to adjust to and cope with change such as in Andre's case, he had his heart set on being a basketball player, but when that didn't work out, he chose to be flexible and open to new possibilities, worked hard, and also Being flexible can help reduce stress and improve well-being because it allows someone to approach situations with a more positive and open mindset.

Hence, Andre is exercising the self-care strategy of being flexible, which is in Option A, as he didn't make the basketball team as a player this year.

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if an arrow is aimed at 45.0 angle and needs to land 90.4 m away how fast should it be fired?

Answers

The arrow should be fired with an initial speed of approximately 31.2 m/s to land 90.4 meters away when aimed at a 45.0-degree angle.

To calculate the initial speed required for an arrow fired at a 45.0-degree angle to land 90.4 meters away, we can utilize the principles of projectile motion.

In projectile motion, the horizontal and vertical components of motion are independent. We can break down the initial velocity into its horizontal and vertical components.

Angle of projection (θ) = 45.0 degrees

Range (horizontal distance) (R) = 90.4 meters

We can start by finding the horizontal component of the initial velocity (Vx) using the formula:

Vx = V * cos(θ)

Where V is the initial velocity.

Since the angle is 45.0 degrees, the cosine of 45.0 degrees is equal to 1 / √2.

Vx = V / √2

Next, we can find the vertical component of the initial velocity (Vy) using the formula:

Vy = V * sin(θ)

Again, since the angle is 45.0 degrees, the sine of 45.0 degrees is equal to 1 / √2.

Vy = V / √2

To determine the initial speed required, we need to consider the time of flight (T) for the arrow to reach the range. The time of flight can be calculated using the formula:

T = (2 * Vy) / g

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Once we have the time of flight, we can calculate the horizontal component of the initial velocity (Vx) using the formula:

Vx = R / T

Now, we can substitute the expressions for Vx and Vy into the original equation:

Vx = V / √2

Vx = R / T

Solving for V:

V = Vx * √2

V = (R / T) * √2

Plugging in the given values of R and T:

V = (90.4 m / T) * √2

Finally, substituting the value of T:

V = (90.4 m / [(2 * Vy) / g]) * √2

Simplifying further:

V = (90.4 m * g * √2) / (2 * Vy)

V = (90.4 m * 9.8 m/s^2 * √2) / (2 * (V / √2))

V = (90.4 m * 9.8 m/s^2) / V

Squaring both sides:

V^2 = (90.4 m * 9.8 m/s^2) / V

Rearranging the equation:

V^3 = 90.4 m * 9.8 m/s^2

Taking the cube root of both sides:

V = ∛(90.4 m * 9.8 m/s^2)

Using a calculator, the final answer is:

V ≈ 31.2 m/s

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The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 and kinetic=0.3. Assume both blocks are attached together. Determine if the block system will slide down or not.

Answers

Coefficient of static friction = 0.5Coefficient of Kinetic friction = 0.3Angular velocity = 500 RPMs

The Radius of the System

Let R be the radius of cylinder

[tex]m_a + m_b = 4 + 3 = 7kg[/tex]

The angular velocity is 500 RPMs

[tex]\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R[/tex]

The normal force

[tex]f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm[/tex]

Since the radius is very little for two block to execute circular motion so system will slide down.

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1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his trip
take?

Answers

Answer:

His trip took 5.78 seconds

Explanation:

23.7m divided by 4.1m/s = 5.78048780488

11. Differentiate between refraction of light and dispersion of light.​

Answers

Answer:

Refraction refers to any bending of waves due to a change in speed. In the case of light being refracted by a prism, dispersion means that the higher the frequency light bends more. In short, Refraction is the bending of light and Dispersion is the frequency dependece of this behaviour.

The GPE for a 45 KG person at the top of a 2m slide

Answers

Answer:

22.5 J

Explanation:

GPE=wxh- 45kg divided by 2m= 22.5

The passenger in a moving bus falls forward suddenly explain ​

Answers

Answer:

the kinetic energy force made the not to stay in a position if the person is not careful

How do you support adolescent development?

Answers

Answer:

Adolescent Development

Adolescence is the period of transition between childhood and adulthood. Children who are entering adolescence are going through many changes. This article offers advice for adolescents and parents to negotiate these changes.

Answer:

How do you support adolescent development?

Explanation:

Parents are a key support for teens during this time of growth and reflection. Be aware of the stages of emotional development, and provide clear guidance at each phase. Acknowledge when to give space and independence to teens. Help guide teens to feel good about themselves.

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1 Figure 13.17 shows the screen of an oscilloscope. The time-base of the oscilloscope is set at 500 us div?.
Calculate the time period of the signal and hence its frequency.

Answers

Answer:

Explanation:

Time-base of the oscilloscope is set at 500 [tex]\mu s[/tex]/div. It means, one block in horizontal direction represents 500 microseconds. The period of the wave is the time to complete one oscillation and in the picture there is two-block for complete one oscillation, so the period and oscillation are:

[tex]T=(2)(500) =100 \mu s \rightarrow f=\frac{1}{T}=\frac{1}{100 \times 10^{-6}}=10000 Hz[/tex]

the time period of the signal is 1200μs and hence its frequency is 833 Hz

What is oscilloscope ?

An oscilloscope is a sort of electronic test tool that shows fluctuating electrical voltages visually as a two-dimensional plot of one or more signals as a function of time. The primary goals are to display repeating or single waveforms on the screen that would otherwise occur too quickly for the human eye to discern. The exhibited waveform may then be analysed for amplitude, frequency, rising time, time interval, distortion, and other features. Previously, these values were calculated by manually measuring the waveform against the scales incorporated into the instrument's screen. Modern digital equipment may immediately compute and show these parameters.

Given,

Time knob = 500 μs/div

wavelength of wave in oscilloscope =  2.4 div

Period of time of the wave is 2.4 div×500 μs/div = 1200μs

frequency of the wave is 1/T = 1/12μs = 833 Hz

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Suppose a radio signal travels from Earth and through space at a speed of 3.0 × 108 m/s. How far into space did the signal travel during the first 33.3 minutes?

Answers

For a radio signal that travels from Earth and through space at a speed of 3.0 × 108 m/s, The distance into space the signal traveled during the first 33.3 minutes  is mathematically given as

d=647352m

How far into space did the signal travel during the first 33.3 minutes?

Generally, the equation for the distance is mathematically given as

d=v*t

Where

t=33.3min

t=33.3*60

t=1998sec

Therefore

d=3.0 × 108 m/s *1998sec

d=647352m

In conclusion, distance is

d=647352m

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Match each description with the correct graph

Answers

Answer: 1. B, 2. A, 3. C, 4. D

Answer:

1 = B

2 = A

3 = C

4 = D

I hope this helps

Jonny is pushing a 50-kg large package along the dorm room floor with 150 N force. Both the direction of push and the floor are horizontal. While he is pushing the package, it moves in a straight line with constant 0.6 m/s speed. Please ignore air-resistance and make sure to justify your answers to the questions below.
a) (10 points) Write down as much information as you can about the main horizontal forces exerted on the package (names, directions, and if enough information is given, numerical values).
b) (10 points) Write down as much information as you can about the main vertical forces exerted on the package (names, directions, and whenever possible, if enough information is given, numerical values).
c) (5 points) How far did the package move during 3 seconds of pushing? Explain
d) (5 points) What was the package’s acceleration during that time? Explain
2

Answers

a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. The package moves 1.8 m

d. The package's acceleration is 0 m/s²

a. The horizontal forces

The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a

Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.

Also, a frictional force also acts to oppose the motion of the package.

Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.

Let

F = push force and f = frictional force

So, F - f = 0

F = f

= 150 N

So, the frictional force is 150 N and opposite to the push.

So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b Vertical forces on package

The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.

The direction of the weight is downwards while the direction of the normal force is upwards.

Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.

Let W = weight of package = mg where m = mass of package = 50 kg and g = acceleration due to gravity = 9.8 m/s² and N = normal force

So, the net force N - W = 0

N = W

= mg

= 50 kg × 9.8 m/s²

= 490 N

So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. Distance package moves

The package moves 1.8 m

Since distance, d = vt where

v = velocity = 0.6 m/s and t = time = 3 s

So, d = vt

= 0.6 m/s × 3 s

= 1.8 m

So, the package moves 1.8 m

d. The package's acceleration

The package's acceleration is 0 m/s²

Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where

m = mass of package and a = acceleration of package

Since F = 0,

ma = 0

a = 0

So, the package's acceleration is 0 m/s²

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What is the wavelength of a radio photon from an "AM" radio station that broadcasts at 1520 kilohertz? And what is its energy?

Answers

Given parameters:

Frequency of the wave  = 1520kHz   = 1520 x 10³Hz

Unknown:

Wavelength of the radio photon = ?

Energy of the wave = ?

Solution:

The wavelength of any electromagnetic wave can found using the expression below;

          C = f x ∧

Where C is the velocity of light  = 3 x 10⁸m/s

            f is the frequency of the wave

            ∧ is the wavelength

Since the unknown is ∧, input the known parameters and solve for it;

       3 x 10⁸  = 1520 x 10³  x ∧

    Wavelength  = [tex]\frac{3 x 10^{8} }{1520 x 10^{3} }[/tex]  

   Wavelength  = [tex]\frac{3 x 10^{8} }{1.52 x 10^{6} }[/tex]

  Wavelength  = 1.97 x 10²m

ii. Energy of the wave;

        Energy of a wave  = hf

where h is the planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹

           f is the frequency of the wave

Input the parameters and solve;

            Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶

                                               = 10.1 x 10⁻²⁸J

The energy of this wave is 10.1 x 10⁻²⁸J

Wavelength of the wave  = 1.97 x 10²m

Energy of the wave = 10.1 x 10⁻²⁸J

Given:

Frequency of the wave  = 1520kHz   = 1520 x 10³Hz

To find:

Wavelength of the radio photon = ?

Energy of the wave = ?

Calculation of Wavelength:

The wavelength of any electromagnetic wave can found using the expression below:

c = f * ∧

Where,

c is the velocity of light  = 3 x 10⁸m/s

f is the frequency of the wave

∧ is the wavelength

On substituting the values:

3 x 10⁸  = 1520 x 10³  x ∧

Wavelength  = 1.97 x 10²m

Calculation of Energy of the wave:

Energy of a wave  = h*f

where,

h is the Planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹

f is the frequency of the wave

On substituting the values:

Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶

Energy of the wave = 10.1 x 10⁻²⁸J

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