Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
pls help me with this
Answer:
A screw
Explanation:
i) The energy stored in wound watch spring is
a) K.E
b) P.E
c) Heat Energy
d) Chemical Energy
Answer:
Springs when non compressed has potential energy.
A wagon having a mass of 42 kg is accelerated across a level road at 1.50 m/s2. What net force acts on the wagon horizontally?
Answer:
The net force acting on the wagon is 63 N
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass (m) is:
F = m.a
Where (a) is the acceleration of the object.
The wagon has a mass of m=42 Kg is accelerated at [tex]a=1.5\ m/s^2[/tex]. The net force is:
F = 42*1.5
F = 63 N
The net force acting on the wagon is 63 N
A 60 N force is applied over distance of 15 m. How much work was done? ( show work)
show your work. john uses a 25N force to push a boulder off a cliff that is 312m tall. What is the work done on the boulder?
Answer:7800
work=force x distance
Force in Newtons
Distance in Meters
Work in Joules
A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?
This needs to be done in 3 mins
Answer:
Okay I might be wrong and sorry if i am either its 12 or 0.402
Explanation:
* I recommend the second one cause its more logical
Be aware I might be wrong
A friend is coming to Tim’s house to study after school. What directions would Tim give for reaching his house from the entrance of the school?
(I WILL GIVE BRAINLIEST)
Answer:
go up the street as you exit the house and make a right and keep going up for 3 blocks and you should see the school
what does PE + KE = __
Answer:
Energy that is dependant on height is called gravitational potential energy.
The formula for potential energy is:
G.P.E.=mgh
Weight (mass x gravity) determines the amount of potential energy.
Is there potential energy in the 5 forms of energy?
Yes, potential energy can be found in fossil fuels, within the foods you eat, and the batteries that you use.
Conservation of Energy:
It is important to understand that each form of energy does not exist separately but undergoes change from one to another without a net loss in energy. Consider this example:
As a projectile is launched into the air KE is at its maximum. As the projectile gains altitude PE becomes greater than KE. At the top of its arc, PE is at its maximum. The whole cycle reverses itself on the way down.
As you can see, the loss in KE is a gain in PE. Energy is not lost but conserved.
Law of conservation of energy.
Energy cannot be created nor destroyed. It can be transformed from one form to another, but the total amount of energy never changes.
I really dont know physics
Answer:
3
Explanation:
I had this question before
29. A student notices that wearing care colors insight makes him feel warmer se he decides to conduct an experiment. He kese seces of bored and was
each one around a bete beten places alive betties in direct sunlight and measures the temperature of the water in each clean hout
what is the independent variable in this exermet
the temperature of the water
the outside temperature
the color of the con
Answer:
This question is unclear but the answer is:
the color of the con
Explanation:
In an experiment, the independent variable is the variable that is changed or manipulated by the experimenter to achieve a measurable response.
In this experiment which involves a student that notices that wearing care colors insight makes him feel warmer se. He decides to conduct an experiment by manipulating the colors of the cares, hence, the color of the con is the independent variable.
draw position time graph when speed is increasing
Explanation:
We need to draw position-time graph when the speed is increasing.
The slope of position-time graph gives the speed of an object.
Position means distance covered.
When the speed of an object is increasing with time. It means it is moving with increasing speed.
The attached figure shows the position -time graph when speed is increasing.
A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?
Answer:
3,544.375Joules
Explanation:
Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;
Kinetic energy = 1/2mv²
m is the mass of the body
v is the velocity
For the ball carrier;
KE = 1/2(75)(6.5)²
KE = 3168.75/2
KE = 1584.375Joules
For the defender;
KE = 1/2(80)(7)²
KE = 3920/2
KE = 1960Joules
The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender
kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules
A block of concrete weights 1200 N. It’s base is a square with sides 4m long. what pressure does the concrete block exert on the ground ?
Explanation:
pressure=force/area
area =4×4=16 m^2
therefore p= 1200÷16
= 75 Nm^-2/Pa
1. A book is at rest on a tabletop. Diagram the forces acting on the book.
The free-body diagram of the forces acting on a book resting on a table is shown in the figure.
When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.
So, the forces acting on a book resting on a tabletop are:
1. Weight of the book, W(downward)
2. Normal force (N) perpendicular to the surface in contact.
Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.
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I don’t know what to do help me
Answer:
oooh thats hard
Explanation:
well i would probaly search the page number or anthing on the page that should help
Need help can someone tell what each circuit is
Answer:
In geometry, parallel lines are lines in a plane which do not meet; that is, two straight lines in a plane that do not intersect at any point are said to be parallel. Colloquially, curves that do not touch each other or intersect and keep a fixed minimum distance are said to be parallel.
In a series circuit, the current that flows through each of the components is the same, and the voltage across the circuit is the sum of the individual voltage drops across each component. ... In a series circuit, every device must function for the circuit to be complete.
In a series circuit, all components are connected end-to-end, forming a single path for current flow. In a parallel circuit, all components are connected across each other, forming exactly two sets of electrically common points.
Explanation:
I hope these helps^,^ ^_^
At a sports event, the car starts from iosi, in 5.0 siis acceleration is 5.
Calculate the distance travelled by ban
100 m
25 m
63 m
O bag 6.
The Score Tower hingga laglomery 4
werissa 13
Question:
At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2. Calculate the distance travelled by car.
Answer:
62.5 metres
Explanation:
Given
[tex]u = 0[/tex] -- Initial Velocity
[tex]a = 5.0m/s^2[/tex] --- acceleration
[tex]t =5.0s[/tex] -- time
Required
Calculate the distance
This question will be solved using the following equation of motion
[tex]S = ut + \frac{1}{2}at^2[/tex]
Where S represents the distance
Substitute values for u, t and a
[tex]S = 0 * 5.0 + \frac{1}{2} * 5.0 * 5.0^2[/tex]
[tex]S = 0 + \frac{1}{2} * 5.0 * 25.0[/tex]
[tex]S = \frac{1}{2} * 5.0 * 25.0[/tex]
[tex]S = \frac{1}{2} * 125.0[/tex]
[tex]S = 62.5m[/tex]
Hence, the distance travelled is 62.5m
A skier skids to a stop at the bottom of a mountain.
What is the equal and opposite force for the force of the skier's friction pushing on the mountain as
described by Newton's third law?
Answer:
Friction of the mountain on the skier in the opposite direction
Explanation:
answered it on khan academy
Friction of the mountain on the skier in the opposite direction.
What is Newton's third law?A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.
Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).
There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
Therefore, Friction of the mountain on the skier in the opposite direction.
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How do photons help explain the photoelectric effect?
A. Changing light frequencies create opposing electric fields that affect electrons.
B. "Packets" of electromagnetic energy eject electrons.
C. Particles with positive charge attract negative electrons.
D. Single particles of light take the place of electrons that have similar mass and energy.
Answer:
Option B
"Packets" of electromagnetic energy eject electrons.
Explanation:
A photon is a tiny packet of light. Light as we know is a form of electromagnetic energy. Whenever light is incident on a photoelectric surface, the energy of the light wave gets transferred to the electron, causing it to have enough energy to eject electrons from its surface. The electrons, once ejected, are now free to move about, thus, resulting in the flow of electrical current.
This makes option B the correct answer
Answer the following
1) A piece of gold weighis 240 g and has a volume of 20 cm^3. Find the density of gold.
2) What is the perpendicular distance between the force and the turning point if a force
of 25 N produces a moment of force of 12.5 Nm
pls answer fast I will mark as brainlist
Answer:
1. 12 g/cm³
2. 0.5 m
Explanation:
1.
The weight of the gold is 240 g
The volume is 20 cm³
Density = Mass/ volume
Density = 240 / 20 = 12 g/cm³
2.
The formula for moment of a force is ;
Force * distance perpendicular between force and the turning point of force
Given that the moment of force is 12.5 Nm and force is 25 N then the perpendicular distance between the force and the turning point will be;
12.5 = 25 * d
12.5/25 = d
0.5 = d
d= 0.5 m
A 200-gram baseball traveling at 48 m/s is hit by a bat and rebounds in the opposite direction at 52 m/s. Find the average force of the bat on the ball if the time of contact is 2.0x10-3 s.
Answer:
400N
Explanation:
Given the following parameters
Mass m = 200g = 0.2kg
initial velocity u = 48m/s
Final velocity v = 52m/s
Time t = 2.0x10-3 s.
Impulse is expressed as I = Ft = m(v-u)
Ft = m(v-u)
F = m(v-u)/t
Substitute the given values into the formula
F = 0.2(52-48)/0.002
F = 0.2(4)/0.002
F = 0.8/0.002
F = 400N
Hence the average force of the bat on the ball is 400N
Calculate the speed with which you would have to throw a rock to put it into orbit around the asteroid 234 Ida near its surface, assuming 234 Ida is spherical. Ida’s mass is 4 × 1016 kg and its radius is 16 km.
Answer:
The speed with which a rock would have to be thrown to put it in 234 Ida's orbit, near its surface is approximately 12.917 m/s
Explanation:
The given parameters are;
The mass of Ida, M = 4 × 10¹⁶ kg
The radius of 234 Ida, r = 16 km = 16,000 m
The speed, v, required to put a rock in 234 Ida's orbit near its surface is given by the orbital velocity equation as follows;
[tex]v = \sqrt{{\dfrac{G \times M}{r} } }[/tex]
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²
Substituting the known values gives;
[tex]v = \sqrt{{\dfrac{6.67408 \times 10^{-11} \times 4 \times 10^{16}}{16,000} } } \approx 12.917[/tex]
Therefore, the speed required to put a rock in 234 Ida's orbit near its surface = v ≈ 12.917 m.
A bus accelerates forward. If an apple were on the floor of the bus it would move forward.
A: True
B: False
Answer:
False
Explanation:
Since it is on the bus, it would not move forward because the outside acceleration cannot be considered.
s. The resistan Rav/I., where va 1005 and
1 - 100..2. Find the percentage
emor in R.
Complete question :
the resistance r =v/i where v = (100±5 )v and I = (10±0.2) a.find percentage error in r
Answer:
7%
Explanation:
Given that :
R = V/I
V = 100 ± 5
I = 10 ± 0.2
Percentage error in R can be obtained thus :
[(dV / V) + (dI / I)] * 100%
dV = ± 5
dI = ± 0.2
[(5 / 100) + (0.2 / 10)] * 100%
(0.05 + 0.02) * 100%
= 0.07 * 100%
= 7%
Which one of the following is not a member of the solar family: (a) Morning Star (b) Evening Star (c) Pole Star (d) Tailed Star plzzz answer this...
Answer:
Tailed star
Explanation:
Tailed star
A weightlifter takes 0.5s to raise a barbell with 2 free-weights from the ground to a height of 0.9m. If each free-weight has a mass of 30kg and the barbell has a mass of 20kg, calculate how much power the weightlifter produces when lifting the barbell?
Answer:
P = 1412.82 [Watt]
Explanation:
First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.
[tex]m=30+30+20\\m= 80 [kg][/tex]
Weight is now defined as the product of mass by gravitational acceleration.
[tex]w=m*g[/tex]
where:
m = mass = 80 [kg]
g = gravity acceleration = 9.81 [m/s²]
[tex]w=80*9.81\\w=784.8[N][/tex]
Now using the product of the weight by the distance traveled we can calculate the work.
[tex]W=w*d[/tex]
where:
W = work [J]
w = weight = 784.8 [N]
d = distance = 0.9 [m]
[tex]W=784.8*0.9\\W=706.41[J][/tex]
And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.
[tex]P=W/t\\P=706.41/0.5\\P=1412.82[W][/tex]
Which of the following examples of energy transfer CANNOT happen?
A toy car rolling down a hill increases speed and then rolls to a stop.
A bunger jumper jumps from a bridge and goes up higher with each recoil.
A child playing on a swing moves fastest at the bottom of the swing's path.
A rock dropped from the top of a bridge increases in speed until it hits the water.
The energy transfer which cannot be happened is option c , at the bottom of the swing, the kinetic energy gets converted completely into its potential energy thus, it have no speed when it reached the bottom.
What is kinetic energy ?Kinetic energy of a body is generated by virtue of its motion. Kinetic energy increases as its mass and velocity increases. Potential energy of a body is the energy stored on it when it comes to rest.
When an object is falling freely to the ground its kinetic energy is converting to the potential energy up to the point it reaches the ground. When it touches the ground, the kinetic energy converts back to potential energy.
Therefore, when the child in the swing comes down from a height its speed is increasing and have greater kinetic energy but this is converted to potential energy when it reach the bottom. Hence no speed it have at the bottom.
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n Olympic diver is on a diving platform 3.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.3 m/s in the horizontal direction. What is the diver's speed, in m/s, just before she enters the water
Answer:
8.5m/s
Explanation:
Using the equation of motion
v² = u² + 2gH
v is the final speed of the diver
u is the initial speed of the diver
g is the acceleration due to gravity
H is the height of the object
Given the following
V = 1.3m/s
H = 3.60m
g = 9.8m/s²
Required
Initial speed of the diver u
Substitute the given values into the formula:
v² = u² -2gH
1.3² = u² - 2(9.8)(3.60)
1.69 = u²-70.56
u² = 1.69+70.56
u² = 72.25
u = √72.25
u = 8.5m/s
Hence the diver's speed, in m/s, just before she enters the water is 8.5m/s
can somebody calculate the velocity of this? ill give 30 points
Answer:
2m/s
Explanation:
time is 5 seconds
distance is 10m
the formula for velocity is v=d/t
so, v=10/5
v=2 m/s
‼️can someone help me‼️
• What are the other two ways that you can rewrite the
formula F=ma?
• If I push a wheelbarrow, with a force of 240 N, with an
acceleration of 4 m/s2, how much mass does the
wheelbarrow have? (Solve using formula F=ma)
Answer:
Part A:
The other two ways we can rewrite F = m·a are;
1) F = dp/dt
2) F = m × d(v)/dt
Part B:
The mass of the wheelbarrow is 60 kg
Explanation:
Part A:
The other two ways of rewriting the equation are;
1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and
2) From the above equation, where, m is constant, we have;
F = d(m·v)/dt = m × d(v)/dt
∴ F = m × d(v)/dt
Part B:
The force with which we push the wheelbarrow = 240 N
The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²
From F = m × a
Where;
m = The mass of the wheelbarrow
m = F/a = 240 N/(4 m/s²) = 60 kg
The mass of the wheelbarrow = m = 60 kg.