Which term describes one kind of movement of Earth?

eclipse
revolution
tilted orbit
lunar cycle

Recall the definition of the cross product with respect to the unit vectors:

i × i = j × j = k × k = 0

i × j = k

j × k = i

k × i = j

and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)

Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have

a × b = (8i + j - 2k) × (5i - 3j + k)

a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)

… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)

… … … … + 8 (i × k) + (j × k) - 2 (k × k)

a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)

a × b = - 5k - 10j - 24k - 6i - 8j + i

a × b = -5i - 18j - 29k

Answer:

Explanation:

If a = 8i + j - 2k and b = 5i - 3j + k show that a) a x b = -5i - 18j - 29k b) b X a = 50 + 18j +29k​

The characteristics of the scalar product allows to find the angle between the two vectors is:

The scalar product is the product between two vectors whose result is a scalar.

            A . B = |A|  |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

            i.i = j.j = 1

            i.j = 0

            A . B = (4 i - 4j). * -5 i + 7j)

            A . B = - 4 5 - 4 7

            A. B = -48

We look for the modulus of each vector.

           |A| = [tex]\sqrt{x^2 +y^2 }[/tex]

           |A| = [tex]\sqrt{4^2 + 4^2}[/tex]  

           |A| = 4 √2

          |B| = [tex]\sqrt{5^2 +7^2}[/tex]

          |B| = 8.60

We substitute.

            -48 = 4√2  8.60  cos θ

            -48 = 48.66 cos θ

            θ = cos⁻¹   [tex]\frac{-48}{48.664}[/tex]  

            θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

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Answer:

334

Explanation:

This question involves the concepts of the induced emf, magnetic field, and angular frequency.

The maximum emf induced in the coil is "32.68 volts".

The following formula can be used to find out the induced emf in the coil.

[tex]E =N\omega AB\ Sin(\omega t)[/tex]

But, for maximum induced emf sin function should have a value of 1. Therefore,

[tex]E = N\omega AB[/tex]

where,

E = induced emf = ?

N = No. of turns in the coil = 310 turns

ω = angular frequency = 12.2 rad/s

A = Area of coil = (0.075 m)(0.18 m) = 0.0135 m²

B = magnetic field = 0.64 T

Therefore,

[tex]E=(310)(12.2\ rad/s)(0.0135\ m^2)(0.64\ T)[/tex]

E = 32.68 volts

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Answer:

The answer is 15. Step by step is you times 80 by 65 and then you divided by 2 and you call your teacher

The shutter speed that should be used if the lens is changed to f/4.0 is; Choice D: 1/500 s.

The relationship between the shutter speed and the focal ratio is an inverse relationship.

Ratio of Areas = 5.6²/4²

Since; T1A1 = T2A2

In essence; when the focal ratio is reduced as in this case; from f/5.6 to f/4.0; the shutter speed is increased.

Ultimately, the shutter speed of the camera in discuss increases to; 1/500 s.

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Answer:

21.31 meters

Explanation:

Since we're working with gravitational potential energy (GPE):

GPE (Joules) = mass (kg) * gravity (m/s^2) * height (meters)

1. Figure out what we have:

GPE = mass * gravity * height

We're looking for height, and we have the other three, so we're set to move on.

2. Isolate the unknown variable (height):

(GPE) / (mass * gravity) = height

3. Plug in your numbers:

(3.78 * 10^7 J) / ((1.81 * 10^5 kg) * (9.8 m/s^2)) = 21.31 meters

Answer:

30.3 meters, 172 degrees

Explanation:

To insure the most accurate solution, this problem is best solved using a calculator and trigonometric principles. The first step is to determine the sum of all the horizontal (east-west) displacements and the sum of all the vertical (north-south) displacements.

Horizontal: 2.0 meters, West + 31.0 meters, West + 3.0 meters, East = 30.0 meters, West

Vertical: 12.0 meters, North + 8.0 meters, South = 4.0 meters, North

The series of five displacements is equivalent to two displacements of 30 meters, West and 4 meters, North. The resultant of these two displacements can be found using the Pythagorean theorem (for the magnitude) and the tangent function (for the direction). A non-scaled sketch is useful for visualizing the situation.

Applying the Pythagorean theorem leads to the magnitude of the resultant (R).

R2 = (30.0 m)2 + (4.0 m)2 = 916 m2

R = Sqrt(916 m2)

R = 30.3 meters

The angle theta in the diagram above can be found using the tangent function.

tangent(theta) = opposite/adjacent = (4.0 m) / (30.0 m)

tangent(theta) = 0.1333

theta = invtan(0.1333)

theta = 7.59 degrees

This angle theta is the angle between west and the resultant. Directions of vectors are expressed as the counterclockwise angle of rotation relative to east. So the direction is 7.59 degrees short of 180 degrees. That is, the direction is ~172 degrees.

Answer:

I don't understand your language

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

A. psychodynamic is the personality best explains Sam's behavior

The psychology of mental or emotional forces or processes developing especially in early childhood and their effects on behavior and mental states is called psychodynamic .

Since , any behavior  is not genetical or it never get inherited hence it is not biological . This has been  grown with time and this behavior have been grown in Sam by observing his parents doing the same hence correct option should be A. psychodynamic

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Answer:

2 times more work

Explanation:

Work is a force times distance

W = Fd

The barbell does not change mass so its weight (force) is constant.

That means work is directly proportional to the distance traveled.

twice the distance means twice the work.

this is where the sun and moon line up where you asleep only a tiny bit of the sun it's pretty cool to see

Explanation:

a solar eclipse means when the moon goes infront of the sun and the earth turns dark

Answer:

Row A is correct

Explanation:

both conduction and convection require mass to complete any heat transfer. A vacuum contains no mass

Answer:

1. Dheere Dheere (slowly slowly)

2. Har (every)

3. Kal (tomorrow)

4. Mat (don't)

5. Andar (inside)

sorry I wasn't able to write in hindi

answer: what language is this???

Answer:

The answer is a (also add)

Acceleration = (change in velocity ( final speed - starting speed))/ (time)

Acceleration = (18-30)/10.5

Acceleration = -12/10.5

Acceleration = -1.14 m/s^2

Distance = 30m/s x 10.5s + 1/2(1.14)(10.5)^2

Distance = 252.2 meters

Answer:

P = 120,000,000

Explanation:

P = m.v

m = (20,000.1000)= 20,000,000kg

v = 0.6 m/s

p = (20,000,000)(0.6)

p = 120,000,000 kg⋅m/s

Answer:

(a) f' = 878 Hz

(b) f' = 735 Hz

Explanation:

Answer:

C) high efficiency light bulbs, because they produce more heat

Light bulbs produce useful energy in the form of light and waste energy in the form of heat, the kind of light bulb would you use to incubate eggs are low-efficiency light bulbs, because they produce more heat, therefore the correct answer is option B.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

The type of light bulb you would use to incubate eggs is a low-efficiency light bulb since they produce more heat; consequently, option B is the right response. Light bulbs produce useful energy in the form of light and waste energy in the form of heat.

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This question involves the concepts of density, volume, and mass.

(a) The volume occupied by this amount of water is "90 m³".

(b) The length of an edge of each small cube is "83 μm".

(c) The length of the edge of each small cube is "equal" to the diameter of a molecule.

(a)

The volume can be found using the following formula:

[tex]V = \frac{nM}{\rho}[/tex]

where,

V = volume occoupied = ?

n = no. of moles = 5 mol

M = molar mass = 18 g/mol

[tex]\rho[/tex] = density of water = 1 g/m³

Therefore,

[tex]V=\frac{(5\ mol)(18\ g/mol)}{1\ g/m^3}\\\\[/tex]

V = 90 m³

(b)

First, we will find the volume of an individual molecule:

[tex]V_i =\frac{V}{nN_A}[/tex]

where,

[tex]N_A[/tex] = Avogadro's number = 6.02 x 10²³ molecules/mol

Therefore,

[tex]V_i=\frac{90\ m^3}{5\ mol(6.02\ x\ 10^{23}\ molecules/mol)}[/tex]

Vi = 3 x 10⁻²³ m³

This volume can be given as a volume of the sphere:

[tex]V_i=\frac{4}{3}\pi r^3\\\\r=\sqrt[3]{\frac{3(3\ x\ 10^{-23}\ m^3)}{4\pi}}[/tex]

r = 4.15 x 10⁻⁷ m

Diameter = d = 2r = 2(4.15 x 10⁻⁷ m)

d = 8.3 x 10⁻⁷ m = 83 μm

since the cubes are adjacent to each other. Therefore, the diameter will be equal to the edge length.

Edge Length = L = d

L = 8.3 x 10⁻⁷ m = 83 μm

(c)

The edge length is equal to the diameter of the molecule.

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Answer:

1.96 N

Explanation:

⇒This is your full answer

Let m₁ and m₂ be the masses of the two objects, and v₁ and v₂ their initial velocities. So

m₁ = 30.0 g = 0.0300 kg

m₂ = 13.0 g = 0.0130 kg

v₁ = + 20.5 cm/s = 0.205 m/s

v₂ = + 15.0 cm/s = 0.150 m/s

and we want to find v₁' and v₂', the final velocities of either object after their collision.

Momentum is conserved throughout the objects' collision, so that

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

where v₁' and v₂' are the first and second object's velocities after the collision.

Kinetic energy is also conserved, so that

1/2 m₁v₁² + 1/2 m₂v₂² = 1/2 m₁(v₁')² + 1/2 m₂(v₂')²

or

m₁v₁² + m₂v₂² = m₁(v₁')² + m₂(v₂')²

From the first equation (omitting units), we have

0.0300 • 0.205 + 0.0130 • 0.150 = 0.0300 v₁' + 0.0130 v₂'

0.0810 = 0.0300 v₁' + 0.0130 v₂'

81 = 30 v₁' + 13 v₂'

From the second equation,

0.0300 • 0.205² + 0.0130 • 0.150² = 0.0300 (v₁')² + 0.0130 (v₂')²

0.00155 ≈ 0.0300 (v₁')² + 0.0130 (v₂')²

1.55 ≈ 30 (v₁')² + 13 (v₂')²

Solving both equations simultaneously gives two solutions, one of which corresponds to the initial conditions. The other yields

v₁' ≈ + 0.172 m/s

and

v₂' ≈ + 0.227 m/s

The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

Work is defined by the scalar product of force and displacement.

          W = F . d

Where the bold indicate vectors, W is work, F is force and d is displacement.

The work energy theorem relates work and kinetic energy.

            W = ΔK = [tex]K_f - K_o[/tex]

In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:  

          W = - K₀

Therefore, the initial kinetic energy that the car has is converted into work in its brakes.  In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.

In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

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Answer:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

Explanation:

X and Y components:

Y = 6.36 m/s

X = 10.18 m/s

Position after 0.5 seconds:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

The x and y positions of the ball 0.50s after it is kicked are 5.09 meter and  1.95 meter respectively.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Initial speed of the soccer ball at an angle 32° above the horizontal is: u = 12m/s.

Time interval: t = 0.50 second.

Now, x component of initial velocity = u cosθ = 12 × cos 32° m/s = 10.17 m/s.

y component of initial velocity = u sinθ = 12 × sin32° =6.36 m/s.

Hence,

after 0.50 s, x-position of the ball =  u cosθ t

= 10.17 × 0.50 meter

= 5.09 meter.

after 0.50 s, y-position of the ball =  u sinθ t -gt²/2

= 6.36 × 0.50 - (9.8×0.50²/2) meter

= 1.95 meter.

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5.08 m

Explanation:

The weight of the electron is being counteracted by the attractive electrostatic force exerted by the proton above it. We can write the force equation as follows:

[tex]m_eg = k_e\dfrac{Q_pQ_e}{r^2}[/tex]

where the Q's are the charges of the proton and electron, r is the distance between the particles, g is the acceleration due to gravity, [tex]m_e[/tex] is the mass of the electrons and [tex]k_e[/tex] is the Coulomb constant. So solving for r, we get

[tex]r^2 = k_e\dfrac{Q_pQ_e}{m_eg}[/tex]

Taking the square root of r^2, we then get the distance as

[tex]r = \sqrt{k_e\dfrac{Q_pQ_e}{m_eg}}[/tex]

The values are given as follows:

[tex]m_e = 9.11×10^{-31}\:\text{kg}[/tex]

[tex]g = 9.8\:\text{m/s}^2[/tex]

[tex]Q_p = Q_e = 1.60×10^{-19}\:\text{C}[/tex]

[tex]k_e = 8.99×10^9\:\text{N-m}^2\text{/C}^2[/tex]

Putting in all of these values in our equation for r,

[tex]r = \sqrt{\dfrac{(8.99×10^9\:\text{N-m}^2\text{/C}^2)(1.60×10^{-19}\:\text{C})^2}{(9.11×10^{-31}\:\text{kg})(9.8\:\text{m/s}^2)}}[/tex]

[tex]\:\:\:\:\:= 5.08\:\text{m}[/tex]