Open star clusters tend to orbit within the disk. Globular star clusters contain hundreds of thousands of stars, and some – like Omega Centauri, shown above – contain millions of stars. Open star clusters tend to contain only hundreds of stars.
What moves up and down in an antenna or transmitter to produce a radio wave?
Answer:
Radio waves move up and down in the antenna or transmister
Explanation:
A car accelerates from rest. It reaches a velocity of 25m/s in 10 seconds. What was the cars acceleration?
Answer:
We are Given:
initial velocity (u) = 0m/s
final velocity (v) = 25 m/s
time (t) = 10 seconds
acceleration (a) = a m/s/s
From the first equation of motion, we know that:
v = u + at
solving for a, we get:
a = (v-u) / t
now, plugging the given values in this equation
a = (25 - 0) / 10
a = 25 / 10
a = 2.5 m/s/s
Therefore, the acceleration of the car is 2.5 m/s/s
why should you have a good attitude School. 3 pages
Answer:
positive attitude lets you relax, remember, focus and absorb information as you learn. You're ready to welcome new experiences and recognize many different kinds of learning opportunities. And when you can see opportunities, hope increases.
anaerobic transmission is when you touch a contaminated surface true or false
Anaerobic transmission is when you touch a contaminated surface is a false statement.
What is anaerobic respiration?Anaerobic organisms are the living things that can survive and grow where there is no oxygen in the surrounding environment so we can conclude that Anaerobic transmission is when you touch a contaminated surface is a false statement.
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A bullet is fired straight up with a muzzle velocity of 1200 ft/s. How high does the bullet go, neglecting any air resistance?
The height of the bullet as it travels is 72727.27 ft.
What is height?Height is the vertical distance between two points. The unit of height is meter (m).
To calculate the height the bullet will go, we use the formula below
Formula:
v² = u²+2gH.............. Equation 1Where:
v = Final velocity of the bulletu = initial velocity of the bulletg = acceleration due to gravityH = Height the bullet will go.Make H the subject of the equation
H = (v²-u²)/2g................ Equation 2From the question,
Given:
u = 1200 ft/sv = 0 m/s (at maximum height)g = -9.8 m/s² (against gravitational force)Substitute these values into equation 2
H = (0²-1200²)/2×(-9.8)H = -1440000/-19.8H = 72727.27 ft.Hence, The height of the bullet as it travels is 72727.27 ft.
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In which position is it most likely that the spring has lost its elastic potential energy?
A.W
B.X
C.Y
D.Z
Answer:
w
Explanation:
its not being streched lol hope dis help
Option A is correct. At position W the spring will lose its elastic potential energy. When spring is extended or shortened, work is done. In the spring, elastic potential energy is stored.
What is the elastic potential energy of spring?When a spring is stretched or compressed, work is done. In the spring, elastic potential energy is stored.
The work done is equal to the elastic potential energy stored, assuming no inelastic deformation has occurred.
The potential energy of the spring is equal to the work done on the spring;
Potential energy = Work done
The mechanical potential energy contained in the structure of a material or physical system as it is forced to elastic deformation by work done on it is referred to as elastic energy.
When things are impermanently crushed, extended, or distorted in any way, elastic energy is released.
The mechanical potential energy stored in the configuration of a material or physical system as it is subjected to elastic deformation by work done on it is referred to as elastic energy.
At position W, the spring has zero deformation. So there should be no stretching causes the potential energy of the system is zero.
Hence option A is correct. At position W the spring will lose its elastic potential energy.
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Consider a 35-L evacuated rigid bottle that is surrounded by the atmosphere at 100 kPa and 22 ℃. A valve at the neck of the bottle is now opened and the atmospheric air is allowed to flow into the bottle. The air trapped in the bottle eventually reaches thermal equilibrium with the atmosphere as a result of heat transfer through the wall of the bottle. The valve remains open during the process so that the trapped air also reaches mechanical equilibrium with the atmosphere. Determine the net heat transfer through the wall of the bottle during this filling process. -pinterest\.\*
Answer:
3.5 KJ
Explanation:
Energy balance equation is given as;
E_in - E_out = ΔE_system
Thus;
Q_in = (m_2•u_2) - (m_i•h_i)
Now, m_i = m_2
Tbus;
Q_in = (m_2•u_2) - (m_2•h_i)
Q_in = m_2(u_2 - h_i)
Now mass of the air in the bottle is given as;
m_2 = (P_2•V)/(R•T2)
From table A-1 attached, R = 0.287 KJ/Kg.k
We are given;
P_2 = 100 kPa
V = 35 L = 0.035 m³
T2 = 22°C = 22 + 273 K = 295 K
Thus;
m_2 = (100 × 0.035)/(0.287 × 295)
m_2 = 0.04134 kg
Now, from table A-17 attached, at Temperature of 295 K, we have;
Internal energy; u2 = 210.49 KJ/Kg
Enthalpy; h_i = 295.17 KJ/Kg
From earlier, we saw that;
Q_in = m_2(u_2 - h_i)
Thus;
Q_in = 0.04134(210.49 - 295.17)
Q_in = -3.5 KJ
Thus, Q_out = 3.5 KJ
So, the net heat transfer = 3.5 KJ
19. Two objects of equal masses collide head-on while moving in the opposite directions and join together. Show that the fractional loss of original KE of the objects is given by the 1 expression.
E=(1/2)+(V1V2/V1²+V2²)
Answer:
Explanation:
mass of each object = m
momentum conservation: mv₁ + mv₂ = 2mv, so v = (v₁ + v₂)/2
Initial KE = mv₁²/2 + mv₂²/2 = m(v₁² + v₂²)/2
final KE = (2m)v²/2 = m(v₁ + v₂)²/4
Change in KE = m(v₁² + v₂²)/2 - m(v₁ + v₂)²/4 = m(v₁ + v₂)²/4
= m(v₁² + v₂² + 2v₁v₂)/4 = (1/2) m(v₁² + v₂²)/2 + mv₁v₂/2
Fraction loss = change in KE / initial KE = 1/2 + v₁v₂/(v₁² + v₂²)
A passenger plane is travelling down the runway with a speed of 20\,\dfrac{\text{km}}{\text{h}}20 h km 20, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction, then speeds up with constant acceleration over 2.4\,\text{km}2.4km2, point, 4, start text, k, m, end text over 59\,\text{s}59s59, start text, s, end text. We want to find the final velocity of the plane at the moment of take-off. Which kinematic formula would be most useful to solve for the target unknown?
Given that,
Initial speed, u = 20 km/s
Acceleration of plane, a = 2.4 km/h²
Time, t = 59 s
We need to find the expression to find the final velocity of an object.Let the final velocity is v.
Using the second equation of kinematics:
[tex]\Delta s=ut+\dfrac{1}{2}at^2[/tex]
a is acceleration, [tex]a=\dfrac{v-u}{t}[/tex]
So,
[tex]\Delta s=ut+\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\\Delta s=ut+\dfrac{1}{2}(v-u)t\\\\\Delta s=\dfrac{2ut+vt-ut}{2}\\\\\Delta s=\dfrac{vt+ut}{2}\\\\\Delta s=(\dfrac{v-u}{2})t[/tex]
We can use the above formula to find the final velocity (v) of the plane.
______________ is the length of the space between two points.
A.
Time
B.
Velocity
C.
Speed
D.
Distance
Answer:
Distance
Explanation:
When using the length of the space between two points, the distance measures the length
Answer:
D.Distance
Explanation:
Determine the equivalent capacitance of the combination shown when C = 12 n
Hi there!
Recall the following.
Capacitors in series:
[tex]C_T = \frac{1}{C_1} + \frac{1}{C_2} +...+ \frac{1}{C_n}[/tex]
Capacitors in parallel:
[tex]C_T = C_1 + C_2 + ... + C_n[/tex]
Begin by solving for the resulting capacitance of both paths.
Path on the left:
[tex]\frac{1}{C_T} = \frac{1}{2C} + \frac{1}{C} = \frac{3}{2C}\\C_T = \frac{2C}{3}[/tex]
Path on the right:
[tex]\frac{1}{C_T} = \frac{1}{C} + \frac{1}{3C} = \frac{4}{3C}\\\\C_T = \frac{3C}{4}[/tex]
Now, since we ADD capacitors in parallel, we can add the resulting capacitances together:
[tex]C_T = \frac{2C}{3} + \frac{3C}{4}[/tex]
Substitute in 12 F for C and solve.
[tex]C_T = \frac{2(12)}{3} + \frac{3(12)}{4} = \frac{24}{3} + \frac{36}{4} = 8 + 9 = \boxed{17F}[/tex]
Find the resistance at 100°C of a silver wire 1 mm in diameter and 1000 centimetre long ?
Answer:
Ro=19.350 & R¹⁰⁰=26.703
Explanation:
Select the correct answer.
Good posture is only important when you are exercising.
A.
True
B.
False
How was the 6th quark discovered?
Answer:
A team of scientists in Geneva, headed by Professor of Physics Carlo Rubbia, has found evidence of a sixth kind of quark, one of the most sought after discoveries in modern physics. ... Rubbia developed this particular proton collision method and has been working with it since the late 1970s
Why do water wet glass ?
Answer:
Forces of attraction between a liquid and a solid surface are called adhesive forces. ... Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water.
A heat engine that propels a ship produces 660 Btu/lbm of work while rejecting 300 Btu/lbm of heat. What is its thermal efficiency
This question involves the concepts of thermal efficiency.
The thermal efficiency of the heat engine is "68.75 %".
Thermal EfficiencyThe thermal efficiency of the heat engine can be given by the following formula:
[tex]\eta=\frac{W}{Q}[/tex]
where,
η = thermal efficiency = ?W = Work output = 660 Btu/lbmQ = Heat Input = W + Rejected Heat = 660 Btu/lbm + 300 Btu/lbm Q = 960 Btu/lbmTherefore,
[tex]\eta=\frac{660\ Btu/lbm}{960\ Btu/lbm}[/tex]
η = 0.6875 = 68.75 %
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In some amazing situations, people have survived falling large distances when the surface they land on is soft enough. During a traverse of Eiger's infamous Nordvand, mountaineer Carlos Ragone's rock anchor gave way and he plummeted 515 feet to land in snow. Amazingly, he suffered only a few bruises and a wrenched shoulder. Assuming that his impact left a hole in the snow 3.5 ft deep, estimate his average acceleration as he slowed to a stop (that is while he was impacting the snow). Pick a coordinate system where down is positive.
Have you seen my dad?
What are the Economic importance of rusting of iron
Answer:
Rusting is the corrosion of iron which is the most widely used structural metal.
what is the distance of sun from earth?
Explanation:
Scientists sometimes call our region of space the "Goldilocks Zone" because it appears to be just right for life. As noted earlier, Earth's average distance to the Sun is about 93 million miles (150 million kilometers) from the Sun.
who is the father of kinematics ?
explain +)
Answer:
FRANZ REULEAUX
Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.
An object increases its velocity from 20 m/s to 63 m/s in 10 s. What is the acceleration of the object?
Answer:
An object increases its velocity from 20 m/s to 63 m/s in 10 s. What is the acceleration of the object?
Explanation:
A box sits at the top of an incline that is 50.0 cm tall and that makes an angle of 25° with the ground. The box has a mass of 2.0 kg. It is given an initial speed of 3.0 m/s down the incline. If the coefficient of kinetic friction between the box and the incline is 0.10, how long does it take the box to reach the bottom of the incline?
As the box sits at the top of an incline that is 50.0 cm tall and makes an angle of 25° with the ground, The time it takes to reach the bottom of the incline is mathematically given as
t=0.148s
What is the time it takes the box to reach the bottom of the incline?Generally, the equation for the acceleration is mathematically given as
[tex]a=g(sin\theta-uscos\theta)[/tex]
Therefore
a=(9.8sin-(0.15cos35))
a=4.417
Thereofore
v^2=v0^2+2al
[tex]v^2=V0^2+2ahsin\theta\\\\V^2=(2.0+2(4.417))*60*0.01sin35[/tex]
v=2.6533
In conclusion, The time t is
t=v-v0/a
2.65-20/4.417
t=0.148s
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As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 46.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.
a. The salmon's acceleration
b. The magnitude of the force F during this interval N
Answer:
a
[tex]a = 12.32 \ m/s^2[/tex]
b
[tex]F = 1017.52 \ N[/tex]
Explanation:
From the question we are told that
The length of the Chinook salmon is [tex]l = 1.50 \ m[/tex]
The mass of the Chinook salmon is [tex]m = 46.0 \ kg[/tex]
The upward velocity in water is [tex]u = 3.00 \ m/s[/tex]
The upward velocity in air is [tex]v = 5.80 \ m/s[/tex]
Generally from kinematic equations
[tex]v^2 = u^2 + 2as[/tex]
=> [tex] 5.80^2 = 3.00^2 + 2 * a * [ [\frac{2}{3} * l ][/tex]
=> [tex] 5.80^2 = 3.00^2 + 2 * a * [ [\frac{2}{3} * 1.5 ][/tex]
=> [tex] 5.80^2 = 3.00^2 + 2 * a * [1 ][/tex]
=> [tex]a = 12.32 \ m/s^2[/tex]
Generally magnitude of the force F during this interval in N is mathematically represented as
[tex]F = m (a + g )[/tex]
=> [tex]F = 46.0 (12.32 + 9.8 )[/tex]
=> [tex]F = 1017.52 \ N[/tex]
A student in the Biomechanics class has decided that she would like to make her arms
stronger. She has a mass of 63 kg, She chooses to complete some elbow flexion exercises
using a kettlebell. For this problem, consider the hand and forearm to be a single segment.
The distance from her elbow to her wrist is 22.86 cm.
The force from the kettlebell is applied to her hand, which is 30.48 cm from her elbow joint.
She knows that the moment arm of the elbow extensor muscles about the elbow axis is
The resistive force from load of the kettle lifted by the arm is determined from principle of moment and the magnitude is 71 kg.
Moment of force about a pointThe moment of force about a point is the product of applied force and the perpendicular distance of the force action. The moment of force about a point is equal to the torque exerted by the force.
τ = Fr
where;
F is the resistance force of the kettler is perpendicular distanceF₁r₁ = F₂r₂
925(22.86) = F₂(30.38)
696 N = F₂
in kg, m = 696/9.8 = 71 kg
Thus, the resistive force from the applied force and distance is 71 kg.
The complete question is below:
If she wants the elbow flexors to exert 925 N of force during an isometric contraction, what should the resistance force be at 90 deg of flexion (the upper arm is vertical and the forearm is parallel to the ground) in kg
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What is the force with which a body
is attracted by the earth towards its centre?
| वह कौन सा बल है जिसके कारण कोई भी
व्तुपर्थृवी के केंद्र की ओर आक र्तष होती है?
A : Mass | द्रव्यमान
B : Weight | भार
C : Volume | आयतन
D : Density | घनत्व
Ans:
B : Weight | भार
Answer:
Explanation:
Gravity
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.
What are the functions of stems? (Select all that apply.)
Stems absorb water from the soil.
Stems transport water and minerals.
Stems produce additional plants.
Stems help turn the leaves toward sunlight.
Explanation:
A. Stems absorb water from the soil.
B. Stems transport water and minerals.
Hope this helps you
have a good day.
Answer : Stems produce water and soil
And Stems help turn the leaves towards sunlight.
Explanation:
Because of this picture, (if its not obvious), the 2 ones that i got wrong, are not the answer, and the 2 in the middle are is the answer.
A certain spring stretches 15 cm when a load of 50.0 N is suspended from it. How much will the spring stretch if 78N is suspended from it
Answer:
23.4 cm
Explanation:
15 : 50 = x : 78
15*78 = 50x
x = 15*78/50 = 23.4 cm
The spring stretch is, 23.4 cm.
What is the stretch of the spring?Potential energy that is stored as a result of the deformation of an elastic item, such as the stretching of a spring, is known as elastic potential energy. It is equivalent to the work required to stretch the spring, which depends on both the length of the stretch and the spring constant, k.What happens to a spring when you stretch it?A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length. A spring's force acts to return the spring to its equilibrium length; it is a restoring force.What causes a spring to stretch?A typical spring is a tightly wrapped metal coil or spiral that stretches when pulled (by applying force) and returns to its original shape when released (remove the force). A spring is elastic, in other words.
According to the question:
15 : 50 = x : 78.
15×78 = 50x.
x = 15×78/50.
= 23.4 cm.
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The period of a simple pendulum (T) is the time it takes for the pendulum to make one complete swing (a round trip). g is the acceleration due to gravity. You can do an experiment of measuring the period (T) as a function of string length (l). You linearize the equation so that you can plot your experimental data and and apply a linear trendline. The equation of the trendline has the form y = a x + b, where a is the slope and b is the y-intercept.
Required:
How do you use the slope to determine "little g" ?
Answer:
Please find the answer in the explanation
Explanation:
Given that an experiment of measuring the period (T) as a function of string length (l) is performed. To linearize the equation so that you can plot your experimental data and and apply a linear trendline,
The graph of length L will be plot against square of period T.
Given that the equation of the trendline has the form y = a x + b, where a is the slope which is equal to the acceleration due to gravity and b is the y-intercept.
When length L is plotted against square of period T, a linear graph will be achieved. The S.I unit of the slope will be m/s^2 which is acceleration g.
A projectile in flight explodes into several fragments. The total momentum of the fragments immediately after this explosion: ___________
a. is the same as the momentum of the projectile immediately before the explosion
b. has been changed into kinetic energy of the fragments
c. is less than the momentum of the projectile immediately before the explosion
d. is more than the momentum of the projectile immediately before the explosion
e. has been changed into radiant energy
Answer:
answer is a.
Explanation:
Newton's first law: inertia
If you still can't get it, look at the book.
the conservation of momentum:
the total momentum of a system is conserved, provided that there is no external net force acting on the system.
The total momentum of a system is conserved. Therefore, the total initial momentum of a body after collision is equal to the total final momentum. Thus, option a is correct.
What is momentum ?Momentum of an object is the ability of an object to bring the force applied to make a maximum displacement. It is the product of its mass and velocity. Momentum is a vector quantity. It have both magnitude and direction.
The momentum in a collision is conserved. Thus total initial momentum is equal to the final momentum. Let m be the colliding mass and the u and v be the initial and final velocity.
Then, mu = m v after collision.
The initial momentum of the flight will be equal to the total momentum of the fragments immediately after the explosion. This is called conservation of momentum.
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In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal different information. You will use the both momentum principle and the energy principle in this problem.A satellite of mass 7500 kg orbits the Earth in a circular orbit of radius of 8.7 106 m (this is above the Earth's atmosphere).The mass of the Earth is 6.0 1024 kg.What is the magnitude of the gravitational force on the satellite due to the earth
Explanation:
The gravitational force equation is the following:

Where:
G = Gravitational constant = 
m1 & m2 = the mass of two related objects
r = distance between the two related objects
The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.