Why's earths magnetosphere important ?

Answers

Answer 1

Answer:

The Earth's magnetic field protects life on Earth, shielding it from damaging radiation and moderating our climate. So the idea that it could completely flip around, or collapse altogether, should cause us

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Related Questions

Solve ASAP please!!!

Which of these best describes science?
A-Science is the study of fundamental problems such as existence, values, and reason.
B-Science is the collection of all living things on Earth.
C-Science is a body of knowledge and a process of discovery that allows people to understand the natural
world.
D-Science is the practice of diagnosing, treating, and preventing disease.

Answers

It should be C
Explanation: Science is what you have to know and it’s not all about making cures and other stuff, if you should learn about our natural world.
hope this helps!

What is the velocity of v2 if m1=82kg v1= 25 m/s m2=60kg?

Answers

Given :

[tex]m_1 = 82 \ kg\\\\v_1 = 257 m/s\\\\m_2 = 60 kg[/tex]

Let, us assume that momentum is conserved during the process.

To Find :

The velocity [tex]v_2[/tex] .

Solution :

Applying conservation of momentum :

Initial momentum = Final momentum

[tex]m_1v_1 = m_2v_2\\\\82\times 257=60\times v_2\\\\v_2 = \dfrac{82\times 257}{60}\ m/s\\\\v_2 = 351.23\ m/s[/tex]

Hence, this is the required solution.

What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s

Answers

Answer: Well the answer is KE = 5.625E-7 i just don't know the units for it...

Hope this helps....... Stay safe and have a Merry Christmas!!!!!!!!!! :D

A woman has a mass of 55 kg on earth. what would be the women's weight on the moon? (The moon’s gravity is 1.6 N).

Answers

Answer:

i dont know the answer sorry have a good day

Explanation:

hsjsjdkdkdkdkdkdk

If an object has a weight of 4050 N near the surface of the Earth, what is its mass?

Answers

Answer:

417.5 kg

Explanation:

Since the gravitational for of attraction F, equals the weight of the object W when its close to the earth, F = GMm/R² = W = mg where m = mass of object and g = acceleration due to gravity close to the earth = 9.8 m/s².

g = GM/R² where  g = acceleration due to gravity close to the earth, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.927 × 10²⁴ kg and R = radius of earth = 6.4 × 10⁶ m

So, g = GM/R²

= 6.67 × 10⁻¹¹ Nm²/kg² × 5.927 × 10²⁴ kg/(6.4 × 10⁶ m)²

= 39.53 × 10¹³ Nm²/kg ÷ 40.96 × 10¹² m²

= 9.65 N/kg

≅ 9.7 N/kg

= 9.7 m/s²

Since W = 4050 N and W = mg

m = W/g = 4050 N/9.7 m/s²

= 417.53 kg

≅ 417.5 kg

So, the mass of the object is 417.5 kg

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
a. How long does it take to reach the ground?
b. How far does the rock land from the base of the cliff?

Answers

Answer:

a. t = 2.02 s

b. d = 20.2 m

Explanation:

Horizontal Motion

If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The time the object takes to hit the ground can be calculated as follows:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated by the equation:

[tex]\displaystyle d=v.t[/tex]

The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.

a.

The time taken by the rock to reach the ground is:

[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]

[tex]\displaystyle t=\sqrt{4.0816}[/tex]

t = 2.02 s

b.

The range is:

[tex]\displaystyle d=10\cdot 2.02[/tex]

d = 20.2 m

A string of length 0.67 m and mass 2.0 g is held at both ends under tension. The string
produces a 700 Hz tone when it vibrates in the fourth harmonic. During this event, what is the
wavelength of the standing wave in the string?

.34
.55
.61
.45
.49

Answers

Answer:

The value is [tex]\lambda = 0.335 \ m[/tex]  

Explanation:

From the question we are told that

     The length of the string is  [tex]l = 0.67 \ m[/tex]

      The mass is  [tex]m = 2.0 \ g = 0.002 \ kg[/tex]

      The frequency produced at  fourth harmonic vibration(i.e n =4 )  is  [tex]f = 700 \ Hz[/tex]

  Generally the wavelength of the string is  mathematically represented as

            [tex]\lambda = \frac{ 2L }{n }[/tex]

=>          [tex]\lambda = \frac{ 2 * 0.67 }{ 4 }[/tex]  

=>          [tex]\lambda = 0.335 \ m[/tex]  

De-Broglie postulated that the relationship, lambda=h/p is valid for relativistic particles. Find out the de-Broglie wavelength for an electron whose kinetic energy is 3MeV.

Answers

Given :

An electron with kinetic energy of 3 MeV.

To Find :

The de-Broglie wavelength for that electron.

Solution :

We know, de-Broglie wavelength for an electron with kinetic energy K.E is given by :

[tex]\lambda = \dfrac{h}{\sqrt{2m(K.E)}}[/tex]

Putting all given values in above equation, we get :

[tex]\lambda = \dfrac{6.626\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 3\times 10^6 \times 1.6\times 10^{-19}}}\\\\\\\lambda = 7.089 \times 10^{-13} \ m[/tex]

Hence, this is the required solution.


Write true if the statement is correct and false if the statement
1. Magnetic poles always appear in pair.
2. Iron and nickel are examples of magnetic materials.
3. The two ends of a magnet are called magnetic poles.
4. Two similar magnetic poles attract each other
5. If one end of an iron bar attracts one pole of a com
Grade 7 Physics
then the iron bar must be a magnet.
Match the terms in column A with the phrases in colu
B​

Answers

Answer:

true false

Explanation:

Answer:

1.true

2.true

3.true                              4.false                        5.true

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A 2.0 kg bullet is fired into a sandbag sitting on a wagon. The combined mass of the wagon and the sandbag is 4.5 kg. a) If the wagon/sandbag/bullet moved together with a speed of 0.22 m/s immediately after impact with the bullet, with what speed did the bullet enter the sandbag? b) Is this an elastic or inelastic collision? Explain.

Answers

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps

A communication satellite is in a circular path orbit around Earth. If the speed of the satellite is constant, the net force acting on the satellite ____.

Answers

Answer:

is changing in direction, but constant in magnitude

Explanation:

This question is a bit tricky since the velocity of the satellite is changing, but the speed is constant.

Speed is simply a measure of how fast you are going. It doesn't matter where you're going, just how quickly.

Velocity, on the other hand, does care about which direction you're going. For example, it could be then when you travel right, your velocity is positive, and when you travel left, your velocity is negative. This is the similar for a 2D shape like a circular orbit

Since we know velocity is changing, there must be acceleration which changes that velocity (since acceleration is the change in velocity: going from 0 to 60 mph, for example)

Thus, with a non-zero net acceleration, we know that there must be a force that is changing in direction, but constant in magnitude (since the orbit is a circle, and always attracted to the center of the Earth at equal distance).

Calculate the gravitational force between a 4.0 x 10^8 kg mass and a 2.8 x 10^5 kg mass separated by a distance of 1.0 x 10^4 m.

Answers

Answer:

[tex]F_{g}=7.4704\times10^{-5}[/tex]

Explanation:

Givens: d = 1.0 × [tex]10^{4}[/tex]  [tex]m_{1} = 4.0 x 10^{8}[/tex]  [tex]m_{2} = 2.8[/tex]×[tex]10^{5}[/tex]

Required: [tex]F_{g}=?[/tex]

Formula:  [tex]F_{g}= \frac{(6.67x10^{-11})(m_{1})(m_{2}) }{d^{2}}[/tex]    (6.67x10^-11  is the gravitational constant)

[tex]F_{g}=\frac{\left(6.67\cdot10^{-11}\right)\left(4.0\cdot10^{8}\right)\left(2.8\cdot10^{5}\right)}{\left(1.0\cdot10^{4}\right)^{2}}[/tex]

[tex]F_{g}=7.4704\times10^{-5}[/tex]




A 0.05 kg golf ball at rest was hit with a force of 200N. The golf ball left the club at an angle of 35° to the horizontal at 49m/s. What was the final velocity as it hits the ground

Answers

Note that when the ball is in the air, the only force acting on it is the downward pull of gravity, so the force of the swing is a red herring.

The ball hits the ground at the same height from which it was hit, so its final velocity will have the same magnitude of 49 m/s, but pointing at an angle of 35° below the horizontal.

A 6 kg block is released from rest at the top of an incline, as shown above, and slides to the bottom. The incline is 1.97 m long, is inclined at an angle of 29.4°, and the coefficient of kinetic friction between the block and the incline is 0.21.
a. Calculate the normal force the incline puts on the block.

Answers

The net force on the block acting perpendicular to the incline is

F = n - w cos(29.4°) = 0

where n is the magnitude of the normal force and w = m g is the weight of the block.

The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.

Solve for n :

n = m g cos(29.4°)

n = (6 kg) (9.80 m/s²) cos(29.4°)

n ≈ 51.2 N

What is the relationship between the speed of impact and the dropping height?

Answers

The difference is that speed means how fast u go and height is how tall you are..


1. What is the speed of a runner who runs 400 meters in 40
seconds?

Answers

Answer:

10 m/s

Explanation:

Speed = Distance / Time

Speed = 400 / 40

Speed = 10

Unit = meters per second = m/s

what is the speed of a 330kg beam dropped from 40m​

Answers

Answer:

28 m/s

Explanation:

We can use this constant acceleration kinematic equation to find the speed of this beam as it is dropped from 40 m.

Since the object is dropped vertically downwards, we know that the object is in free-fall.

The acceleration of this object is -g, which is -9.8 m/s² since we are making the positive direction upwards and the negative direction downwards.

The initial velocity is 0 m/s since the object is dropped and starts from rest.

The final velocity is what we are trying to solve for.

The displacement in the y-direction is 40 m.

Now we can see which equation contains these 4 variables:

v² = v₀² + 2aΔx

Plug in the known variables.

v² = (0)² + 2(-9.8)(-40)

Simplify this equation.

v² = 784

Take the square root of both sides.

v = 28 m/s

The speed of the 330 kg beam dropped from 40 m is 28 m/s.

Answer:

28 m/s

Explanation:

Given information :

mass = 330kg

height =40m

v = √2gh

Where ;

g = acceleration due to gravity = 9.8 or 10 m/s

h = height

how much total energy of the beam just as it hits the ground =

mgh

[tex]330\times 10\times 40\\\\\\=132000[/tex]

Speed at which  the beam will hit the ground :

[tex]v = \sqrt{2\times 10\times40} \\\\=\sqrt{800}\\\\=20\sqrt{2}\\\\v=28.28427[/tex]

In an A.C circuit current leads voltage by phase π/2 then circuit is

Answers

Answer:

  capacitive

Explanation:

In a capacitive circuit, current is proportional to the derivative of the voltage. For a sinusoidal excitation, this means current is at the highest level when voltage is increasing through zero. That is, current leads the voltage.

A Force is applied onto a mass causing it to accelerate. If the same Force was applied to a SMALLER mass, what would happen to that acceleration?

1. The acceleration would increase
2. The acceleration would stay the same
3. The acceleration would decrease
4. The acceleration would change direction

Answers

Answer:

1. The acceleration would increase.

Explanation:

This is because according to Newton's law, the less mass there is, the more velocity.

answer is number 1. the acceleration would increase

What is the mathematical relationship between wavelength and velocity? PLZ HELP MEEE

Answers

Answer: wavelength is the length of the wave, example the length of a sound wave.

Velocity is also known as speed.

Explanation:

What is an astronomical unit or AU

Answers

Answer:

D

Explanation:

Answer:

Astronomical Unit = 4.8481×10−6 pc; 1.5813×1.

Or even AU = Equal to

Explanation:

Which of the following are single-displacement reactions?

A Mg (s) + 2H,0 (g) → Mg(OH)2 (aq) + Hz (g)

B. 2C,H6 (g) + 70, (g) → 6H,0 (9) + 4CO, (g)

c. AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaN3 (aq)

D. Clz (9) + KBr (aq) → KCI (aq) + Br2 ()

Multiple answer are allowed!!!

Answers

Answer:

A & D

Explanation:

A single-displacement reaction is a chemical reaction whereby one element is substituted for another one in a compound and thereby generating a new element and also a new compound as products.

From the options, only options A & D fits this definition of single-displacement reactions.

For option D: Both left and hand and right hand sides each have one element and one compound. We can see that K is substituted from KBr to join Cl to form KCl and Br2 on the right hand side.

For option A: Both left and hand and right hand sides each have one element and one compound. We can see that OH is substituted from 2H2O to join Mg to form Mg(OH)2 and H2 on the right hand side.

The other options are not correct because they don't involve only and element and a compound on each side of the reaction.

Answer: .A AND D

Explanation:APΕX

A ship is travelling due east at 30 km/hr and a boy runs across the deck
in a south west direction at 10 km/hr. Find the velocity of the boy
relative to sea.

Answers

Answer:

Vr = 20 [km/h]

Explanation:

In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.

Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).

[tex]V_{r}=30-10\\V_{r}=20 [km/h][/tex]

Two forces act in opposite directions on a wood block. What will happen if the forces are unbalanced?
A. The block will balance the forces.
B. The forces will reverse direction.
C. The mass of the block will change.
D. The position of the block will change.

Answers

Answer:

D

Explanation:

If two unequal forces act in opposite directions, one larger force must cancel out the smaller force,

leaving the net force to be some number in one direction.

Take for example a game of tug-of-war; there are two  OPPOSITE forces (groups of people) acting on the rope, one force is pulling with a force in the negative direction while the other force is pulling in the positive direction.

If the forces on the rope were unequal, then the stronger force (group) will pull everything in their direction.

The same will happen on two unequal forces of opposite directions acting on a wooden block. Therefore, since the resultant force will have a non-zero magnitude and direction, there will be a change in the block's motion and position.

You walk exactly 250 steps North, turn around, and then walk exactly 400 steps South. How far are you from your starting
point?
steps to the
North, South, East or West)

Answers

Answer:

150 steps south

Explanation:

250 north 250 back to start then continue south for remainder of 400 steps. 150 south

please answer it fast and correctly​

Answers

Answer:

(1) chess is played by him

(2) The great black engine was seen by her

(3) Arrangements for functions had been made by him

(4) A meeting is being attended by Raman

= when the last of the guests left, I went back into the hall to look for my mobile phone that I had kept on the table, I found that my mobile phone was not there. I felt freaked and I asked to every member of my family about my phone, but nobody had idea about that. then there was a phone call made by my uncle to my father, that his son had taken the mobile by mistake. After sometime, My uncle came to return my mobile. Then I took a sigh of relief .

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Place the molecules in the list in order with the smallest molecules at the top and largest molecules at the bottom: starch molecule, water molecule, glucose molecule, carbon dioxide molecule, protein molecule, amino acid molecule, oxygen molecule

Answers

Explanation:

list in order with the smallest molecules at the top and largest molecules at the bottom:

1.Oxygen

2.Water

3.Carbon dioxide

4.amino acid

5.Glucose

6. Starch

7. Protein

The molecules can be arranged as follows with the smallest at the top is oxygen, water, carbon dioxide, amino acid, glucose, starch, protein.

The given molecules;

starch, water, glucose, carbon dioxide, protein, amino acid, oxygen

The molecular weight of the given compounds is listed as follows;

water -------- 18 g/mol

glucose -------  180.2 g/mol

starch (2 or more glucose) ------ 360 g/mol

carbon dioxide ------ 44 g/mol

protein -------- 20,000 g/mol

amino acid (glycine) ----- 75 g/mol

oxygen -------- 16 g/mol

Thus, the molecules can be arranged as follows with the smallest at the top;

oxygenwatercarbon dioxideamino acidglucosestarchprotein

Learn more here:https://brainly.com/question/19537339

difference between lower fixed point and upper fixed point​

Answers

Answer:

The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.

Explanation:

Ramas weight is 40 kg. She is carrying a load of 20 kg up to a height of 20 m. What work does she do? What work does she do?

Answers

Answer:

The work done by Ramas is 3920 N.

Explanation:

Given;

mass of the load lifted by Ramas, m = 20 kg

height through which the load is lifted, h = 20 m

The work done by Ramas is equal to gravitational potential due to the height in which the load is lifted.

W = PE = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

W = 20 x 9.8 x 20

W = 3920 N.

Therefore, the work done by Ramas is 3920 N.

A 100 kg skateboarder sits at the top of a 10 m halfpipe, ready to go down the ramp. What will be his velocity when
he is 4 m off of the ground?

Answers

Answer:

v = 10.85 m/s

Explanation:

We will apply the law of conservation of energy to the skateboarder. Neglecting the frictional effects, the law of conservation of energy can be written as:

[tex]Loss\ in\ Potential\ Energy\ of\ Skateboarder = Gain\ in\ Kinetic\ Energy\ of\ Skateboarder[/tex][tex]mg\Delta h = \frac{1}{2}mv^2\\\\v^2 = 2g\Delta h\\v = \sqrt{2g\Delta h} \\[/tex]

where,

v = velocity of skateboarder = ?

g = acceleration due to gravity = 9.81 m/s²

Δh = change in height = 10 m - 4 m = 6 m

Therefore,

[tex]v = \sqrt{{(2)(9.81\ m/s^2})({6\ m})}}[/tex]

v = 10.85 m/s

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