You are controlling an unmanned aerial vehicle (UAV) for surveillance. The table shows the height y (in thousands of feet) of the UAV x minutes after you start its descent from cruising altitude.

Answer: y=-1/2x+58, decreases 500, begins, 58k

Step-by-step explanation:

I'm not too sure about my equation for the word problem but I can explain how I got it.

The equation is in y=mx+b format, so we need to find the slope. They gave us the graph for a reason. You would take each side of the table and subtract/add. For example: 58-53=-5 (y), 0+10=10 (x).

Then, just put that in rise over run (-5/10).

Simplify. Which gives you -1/2.

They already gave us the y-intercept, so just put it into the equation. y=-1/2x+58.

Keep in mind I don't know if you need to add the 0's because it's thousands of feet, I would just in case though. Hoped this helped!

The equation can be given as  [tex]y= -\frac{1}{2}x +58[/tex], and slope for x and y is m that is [tex]\dfrac{-1}{2}[/tex].

Given to us,

x is time in minutes

y is the height (in thousands of feet) of the UAV

x                      y

0                      58

10                    53

20                   48

30                   43

The equation can be given as y = mx+ c

where,

x is time in minutes,

y is the height,

m is the slope,

c is the constant,

Substituting the values of x and y to get m and c,

Equation 1:

[tex]y = mx+ c\\ 58 = m(0) + c \\ c = 58[/tex]

Substituting the values of c to get m,

Equation2:

[tex]y = mx+ c\\53 = m(10) + 58\\m\times (10) = - 58 + 53\\m\times (10) = -5\\m =- \frac{1}{2}[/tex]

[tex]y= -\frac{1}{2}x +58[/tex]

Therefore, the equation can be given as  [tex]y= -\frac{1}{2}x +58[/tex], and slope for x and y is m that is [tex]\dfrac{-1}{2}[/tex].

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