Answer:
The samples specific heat is 14.8 J/kg.K
Explanation:
Given that,
Weight = 28.4 N
Suppose, heat energy [tex]E=1.25\times10^{4}\ J[/tex]
Temperature = 18°C
We need to calculate the samples specific heat
Using formula of specific heat
[tex]Q=mc\Delta T[/tex]
[tex]c=\dfrac{Q}{m\Delta T}[/tex]
Where, m = mass
c = specific heat
[tex]\Delta T[/tex] = temperature
Q = heat
Put the value into the formula
[tex]c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}[/tex]
[tex]c=14.8\ J/kg. K[/tex]
Hence, The samples specific heat is 14.8 J/kg.K
Answer:240 gradpoint
Explanation:
A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, its water level rises to 20.3 ml.
Answer:
V=2.8 ml
Explanation:
volume of the cube is it would be 20.3 - 17.5 ml so 2.8 ml.
Why is there no weather on the Moon?
Answer:
the moon has no atmosphere, and it cannot trap heat or insulate the surface.
Explanation:
the moon is too small. ... With weak gravity, gases that are emitted from the surface quickly are lost to outer space.
If an astronaut weighs 750 N on the ground, what will he weigh in earth orbit 400 km above the earth’s surface?
R_earth = 6.38 × 10^6 m,
m_earth=5.97×10^24 kg
G=6.674×10^−11 Nm^2/kg^2
Answer:
The weight of the astronaut in Earth's orbit 400 km above the Earth's surface is 664.115 N
Explanation:
The given parameters are;
The weight of the astronaut on the ground = 750 N
The height of the orbit above the Earths surface = 400 km
The radius of the Earth = 6.38 × 10⁶ m
The mass of the Earth = 5.97 × 10²⁴ kg
The universal gravitational constant G = 6.674 × 10⁻¹¹ Nm²/kg²
From Newton's law of universal gravitation, we have;
[tex]Weight \ on \ ground \ of \ astronaut \ F_W =G\times \dfrac{M_{Earth} \times m_{astronouat}}{R_{Earth}^{2}} = 750 \ N[/tex]
[tex]F_W =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times m_{astronouat}}{(6.38 \times 10^6)^{2}} = 750 \ N[/tex]
[tex]m_{astronaut}[/tex] = ((6.38 × 10⁶)² × 750)/((6.674 × 10⁻¹¹) × (5.97 × 10²⁴)) ≈ 76.62 kg
The mass of the astronaut ≈ 76.62 kg
For the weight of the astronaut in Earth orbit 400 km (400 × 10³ m) above the Earth's surface, we have;
[tex]F_{W \ in \ orbit} =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times 76.62}{(6.38 \times 10^6 + 400 \times 10^3)^{2} } = 664.115 \ N[/tex]
The weight of the astronaut in Earth's orbit 400 km above the Earth's surface = 664.115 N.
Two fish swimming in a river have the following equations of motion:
X 1 = - 6.4 m + (- 1.2 m/s) t
X 2 = 1.3 m + (- 2.7 m/s) t
Which fish is moving faster?
Answer:
The second fish, X2, is moving faster than the first fish, X1
Explanation:
The given parameters for the equation of motion of the fishes are;
X1 = -6.4 m + (-1.2 m/s)×t
X2 = 1.3 m + (-2.7 m/s)×t
The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes
For the first fish, the intercept = -6.4 m, the slope = the speed = -1.2 m/s
For the second fish, the intercept = 1.3 m, the slope = the speed = -2.7 m/s
Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;
The magnitude of the speed of the second fish [tex]\left | -2.7 \ m/s \right | = 2.7 \ m/s[/tex], is larger than the magnitude of the speed of the first fish [tex]\left | -1.2 \ m/s \right | = 1.2 \ m/s[/tex]
Therefore, the second fish, X2, is moving faster than the first fish, X1.
Consider two identical baseballs which start at the same location; their terminal speed at this location is 32 m/s. At t = 0s, Ball A is thrown straight up at m/s; Ball B is thrown at 16m/s 30.0° below the horizontal at 32 m/s. How do the magnitudes of the baseballs' accelerations32 2at t = 0s compare (do not neglect air resistance)?
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is B
Explanation:
From the question we are told that
The terminal velocity of both balls is [tex]v_t = 32 \ m/s[/tex]
The speed with which ball A is thrown up at t =0 s is [tex]v__A}} = 16\sqrt{2}[/tex]
The speed with which ball B is thrown 30° below the horizontal at t =0 s is
[tex]v__{B}} = 32\sqrt{2}[/tex]
Generally the acceleration of ball A is (g i.e acceleration due gravity)given that it is thrown straight up
Generally the vertical acceleration of ball B is mathematically represented as
[tex]a = gcos (90 - 30)[/tex]
[tex]a = gcos (60)[/tex]
Generally the ratio of both acceleration is
[tex]\frac{a__{{A}}}{a__{{B}}}} =\frac{g}{gsin(60)}[/tex]
=> [tex]\frac{a__{{A}}}{a__{{B}}}} = \frac{1}{sin (60)}[/tex]
=> [tex]\frac{a__{{A}}}{a__{{B}}}} = \frac{1}{\frac{\sqrt{3} }{2} }[/tex]
=>[tex]\frac{a__{{A}}}{a__{{B}}}} = \frac{2}{\sqrt{3} }[/tex]
Rationalizing
=> [tex]\frac{a__{{A}}}{a__{{B}}}} = \frac{2}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} }[/tex]
=> [tex]\frac{a__{{A}}}{a__{{B}}}} = \frac{2 \sqrt{3} }{3}[/tex]
=>[tex]a__{B}} = \frac{2\sqrt{3} }{3} * a__{A}}[/tex]
How long would it take Jesse with an acceleration of -2.50 m/s2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
Answer: 5.4 seconds
Explanation:
The time taken to stop the bicycle is 5.4 seconds. The final velocity is zero. Then, the distance travelled by the bicycle is 36.45 m.
What is acceleration ?Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.
Given initial velocity = 13.5 m/s
final velocity is zero since the bicycle is stopping.
then Δt = Δv/a
Δt = 13.5 m/s/ 2.50 m/s² = 5.4 seconds.
Hence, the bicycle will take 5.4 s to complete stop.
The distance covered within this time can be determined using the equation as follows:
s = ut + 1/2 at²
where u is the initial velocity
s = (13 m/s × 5.4 s) + (-2.50 m/s² ×5.4 s ×5.4 s) = 36.4 m.
Therefore, the bicycle will travel up to 36.4 m before stopping.
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Challenge: Write a Poem
Answer:
okkk soo...
Friendship is one of life's greatest treasures. Friends that are loyal are always there to make you laugh when you are down, they are not afraid to help you avoid mistakes and they look out for your best interest. This kind of friend can be hard to find, but they offer a friendship that will last a lifetime. Other friends may not be quite as loving. The pain caused by a friendship marred by betrayal is not easy to overcome. In fact, many poems find their inspiration from the joy brought about by a loving friendship or the pain caused by a failed friendship.
Explanation:
Find the acceleration if the force is 10 N and the mass is 5 kg.
Explanation:
Hey there!
Given;
F = 10N
Mass = 5kg
Acceleration due to gravity (a)= 9.8m/s^2
We know that;
F = m*a
Put all values and solve for "m".
10 = m*9.8
Simplify it.
[tex]m = \frac{10}{9.8} [/tex]
Therefore, m= 1.0204kg.
Hope it helps...
how does a distance-time graph show you which direction the runner is moving? Use your own words and science vocabulary.
Please help will give brainliest to whoever does a 4 setence answer
In a distance time graph, when the x and y values are positive (in first quadrant), the runner is moving forward.
While, if the distance value ( in the y axis) is negative, the runner is moving backwards ( towards the start) .
Hope it helps :)
A distance-time graph shows how far an object has travelled in a certain time. This is a simple line graph that plots observations by distance versus time.
The distance is transferred to the Y axis.
Time is plotted on the X-axis.
The distance-time graph when we study the motion of bodies. If you set the distance and time of the movement of the object and transfer the same data to a rectangular graph, you will get a distance-time graph corresponding to the movement of the object.
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What type of bond is shown in the figure?
Answer:
ionic
Explanation:
help do number 16 and 17
Answer:
16 is d and i have no idea for 17
Which of the above beak depth vs time graphs represent the change in finch beak depth that would occur due to successive years of above average rainfall?
Answer:
A
Explanation:
I just did it :)
Answer:
It is A
Explanation:
I did it and got a 100
If your speed is 3 meters in 1 second (3m/s), how long would it take you to go 15
meters?
Answer:
5 seconds
Explanation:
Answer:
5 seconds
Explanation:3=1 6=2 9=3 12=4 15=5 15 equal 5 mean 15 meters in 5 sec
Janel did an experiment to see which spices can kill bacteria. She mixed a spice with bacteria food called agar. She poured the agar and spice mix into a petri dish(a plate used for growing bacteria) and added bacteria. She did the same for five different spices. This is an example of
Answer:
Antibacterial activity
Explanation:
The antibacterial property does not allow bacterias to live in an environment. Many spices have the ability to show antibacterial activity, few of these spices can be named as cinnamon, turmeric, or clove. Because they have antimicrobial or antibacterial characteristics that is why they are used for food preservation, disease prevention, and provide many health benefits. But, not every spice has antibacterial characteristics, that is why Janel experimented with five different spices to see which amongst them possess antibacterial characteristics.
Hence the correct answer is Antibacterial activity.
* 22. Mmh A car is traveling along a straight road at a velocity of 36.0 m/s when its engine cuts out. For the next twelve seconds the car slows down, and its average acceleration is For the next six seconds the car slows down further, and its average acceleration is The velocity of the car at the end of the eighteen-second period is 28.0 m/s. The ratio of the average acceleration values is Find the velocity of the car at the end of the initial twelve-second interval.
Complete question is;
A car is traveling along a straight road at a velocity of 36.0 m/s when its engine cuts out. For the next twelve seconds the car slows down, and its average acceleration is For the next six seconds the car slows down further, and its average acceleration is The velocity of the car at the end of the eighteen - second period is 28.0 m/s. The ratio of the average acceleration values is a1/a2 = 1.5.
Find the velocity of the car at the end of the initial twelve - second interval.
Your answer
Answer:
30 m/s
Explanation:
To solve this, we will use Newton's first equation of motion;
v = u + at
Since we are dealing with acceleration ratio, let's make a the subject;
a = (v - u)/t
For the first 12 seconds and initial velocity u = 36 m/s, we have;
a1 = (v - 36)/12
For the remaining 6 seconds, initial velocity is the final velocity from the initial 12 seconds. Thus;
a2 = (28 - v)/6
We are given that a1/a2 = 1.5
Thus;
[(v - 36)/12]/[(28 - v)/6] = 1.5
(6/12)((v - 36)/(28 - v)) = 1.5
(v - 36)/(28 - v) = 1.5 × 12/6
(v - 36)/(28 - v) = 3
v - 36 = 3(28 - v)
v - 36 = 84 - 3v
4v = 120
v = 120/4
v = 30 m/s
6. Most things you use every day are: a.compounds b. elements c. mixtures
Answer: B. Elements
Explanation:
Most things we use everyday are compounds which are composed of two or more elements.
What are compounds?
Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.
Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:
1)Molecular compounds where in atoms are joined by covalent bonds.
2) ionic compounds where atoms are joined by ionic bond.
3)Inter-metallic compounds where atoms are held by metallic bonds
4) co-ordination complexes where atoms are held by co-ordinate bonds.
They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.
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60 point!!!
Instructions-
Give a real life example of each of Newton's Laws in action. Be sure to specificy which law your
example is linked to.
Give examples with pulleys
Answer:
Playing hockey, driving a car, and even simply taking a walk are all everyday examples of Newton's laws of motion.
A ship is travelling due east at
30 km/hr and boy runs across
the deck in a south east west
direction at 10 km/hr. Find the
veloocity of the boy relative to sea.
Answer:
The relative velocity of the boy with respect to the sea is 37.7 km/hr
Explanation:
Answer:
37.7 km/hr I'd the velocity
Which two options are forms of kinetic energy?
A. Sound energy
B. Elastic energy
C. Magnetic energy
D. Thermal energy
E. Chemical energy
Answer:
A, C
Explanation:
SOUND ENERGY - energy from sound
MAGNETIC ENERGY - energy with magnetism
Sound energy and magnetic energy are forms of kinetic energy. Option A and C are correct.
What is kinetic energy?The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.
The passage of vibrations through matter is characterized as sound energy. When an item vibrates, sound energy is created, resulting in noise.
Sound vibrations induce pressure waves to flow through a material like air, water, wood, or metal.
Each magnetic field, also known as magnetic energy, includes energy. Electric currents create magnetic fields, magnetic energy is a kind of energy for transporting charge carriers.
Hence, the two options are A and C.
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An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical force that the objects exert on each other. Use 8.988×10 N⋅m2/C2 for the value of Coulomb's constant. Give your answer to two decimal places.
Answer:
[tex]1.917*10^8\ N[/tex]
Explanation:
Coulomb's law states that the electric force between two charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them. It is given by the formula:
[tex]F=k\frac{q_1q_2}{r^2}\\ \\q_1=first\ charge = 1.2C,q_2=second\ charge=0.36C,k=coulomb\ constant=8.988*10^9 N.m^2/C^2, r=distance=4.5m,F=force\\\\F=8.988*10^9*\frac{1.2*0.36}{4.5^2} =1.917*10^8\ N[/tex]
BRAINLIEST & 20 POINTS ANSWER THE BOTTOM TWO QUESTIONS PLEASE HURRY!!!!
Answer:
For 9 is 2,4,1 and 3.For 10 b-c moves 15 from each other and e-f moves 15 also from each other.
explain how the air balloon moves up and down.
Explain in terms of density
Answer:
hope it helps ....
Explanation:
The inside air that has been heated rises due to the difference of density between the hot and cold air particles. The heated air, the air that is inside the balloon, is less dense than the cool air, the air outside of the balloon. ... You can see that the bigger the volume gets, the smaller the density is.
Which of the following describes an ionic compound (or what is true for ionic compounds)?
a. It has a low melting points
b. It consists of shared electrons
c. It conducts electric current in water solution
d. It consists of two non-metals
Answer:
a b c
Explanation:
b. It consists of shared electrons
c. It conducts electric current in water solution
d. It consists of two non-metals
What are Ionic compound?Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.
For binary ionic compounds (ionic compounds that contain only two types of elements), the compounds are named by writing the name of the cation first followed by the name of the anion.
The properties of ionic compound are:
They form crystals. They have high melting points and high boiling points.They have higher enthalpies of fusion and vaporization than molecular compounds.They are hard and brittle.They conduct electricity when they are dissolved in water.They are good insulators.They consist of two non metals.Therefore,
b, c, d are the correct answer.
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(Please answer quickly!)
Force and energy aren't the same thing but they are closely related. explain how.
Answer:
Explanation:
Bigger pushes and pulls cause bigger changes in an object's motion or shape. When objects collide, contact forces transfer energy so as to change the objects' motions. When two objects interact, each one exerts a force on the other, and these forces can transfer energy between them.
The velocity of an object is it’s speed and __ of motion .
Answer:
direction should be the answer
plzzzzzzzzz I need to know for school!!!
What is the definition of law of conservation of energy???
Answer:
This law, first proposed and tested by Émilie du Châtelet, means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another. For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.
Explanation:
Answer:
Hi! I am confused
Explanation:
1. A car begins at a speed of 3 m/s and accelerates at 2 m/s2
over a distance of 40 m, calculate the final speed of the car.
Explanation:
v^2 = u^2 + 2as
v^2 = 9 + 160
v^2 = 169
v = 13
What type of change is making water from H^2 and O^2 ?
A. chemical
B. physical
Answer: chemical
Explanation: To change from hydrogen to oxygen is a chemical change because if you change hydrogen to oxygen, it is still a chemical. The answer is chemical.
Answer:
chemical possibly
Explanation:
fact
A soccer player applies a force of 48.4 N to a soccer ball while kicking it. If the ball has
a mass of 0.44 kg, what is the acceleration of the soccer ball?
A. 27.3 m/s2
B. 21.3 m/s2
C. 110 m/s2
D. 104 m/s2
Answer:
C. 110 m/s2
Explanation:
Force = Mass x Acceleration
Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:
Force/Mass = (Mass x Acceleration)/Mass
Acceleration = Force/Mass
Now we just have to plug in our values and calculate!
Acceleration = 48.4/0.44
Acceleration = 110m/s/s
It is option C. 110 m/s2
Hope this helped!
What distance is required for a train to stop if its initial velocity is 23 m/s and its
deceleration is 0.25 m/s²? (Assume the train decelerates at a constant rate.)
-- The train starts at 23 m/s and slows down by 0.25 m/s every second.
So it'll take (23/0.25) = 92 seconds to stop.
-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s
-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover
(11.5 m/s) x (92 sec) = 1,058 meters .
The distance required for the train to travel before stopping is 1,058 m.
The given parameters;
initial velocity of the train, u = 23 m/s
deceleration of the train, a = 0.25 m/s
The distance traveled by the train is calculated as follows;
[tex]v^2 = u^2 -2as[/tex]
where;
v is the final velocity of the train
The final velocity of the train is zero when the train stops
[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]
Thus, the distance required for the train to travel before stopping is 1,058 m.
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