4) A drag racer starts her car from rest and accelerates at 10.0 m/s² for a distance of 400 m (1/4 mile). (a) How long did it take the race car to travel this distance? (b) What is the speed of the race car at the end of the run?​

Answer:

Fission and Fusion

Explanation:

There are two basic processes: fission and fusion. In both processes, mass is converted to energy according to the famous equation, e=mc2

In fission, heavy fuel (isotopes of uranium, plutonium, thorium, etc.) atoms split, releasing kinetic energy daughter particles and as radiation. In a reactor plant kinetic energy of the daughter particles is converted to thermal energy as the particles are slowed by the fuel matrix or primary coolant. Radiation is absorbed by various components of the reactor and converted to thermal energy. Thermal energy from both sources is then carried out of the reactor core by primary coolant to a turbine where it is converted to electrical energy which is then transmitted to the power grid.

In fusion, light atoms of hydrogen combine to form helium. Energy released from this reaction will be captured and used to generate electricity as well, once we have constructed a fusion reactor large enough to be self-sustaining (i.e. produce as much or more energy from fusion than needed to start the reaction going).

In the case of nuclear weapons, the tremendous energy from the nearly simultaneous fission/fusion reactions is used to create a fireball, intense radiation, and a large shock wave.

Answer:

1400joules

Explanation:

work(j)= force × distance.

Distance is from 5m to 12 that is 7m

Force, we weren't given, and the formula is mass × acceleration due to gravity. mass is 20kg and a is 10 or 9.8

f= 20×10

f=200

work= 200 × 7

work= 1400joules

Hope it helped(...and is correct )

Answer:

x10 - 6 +(8+6-4)= 10

10m -10x y0

Answer:

The electric field strength is dependent upon the quantity of charge on the source charge (Q) and the distance of separation (d) from the source charge.

Answer:

238.09 cm^3

Explanation:

V=mass/density

V=2500/10.5

V=238.09 cm^3

Answer: You do not deserve help, You dont help other people you only use them for points so...do not ask for help from us now

Explanation:

Answer:

It will increase.

Explanation:

Because kinetic energy is proportional to the square of the velocity, when velocity is doubled, kinetic energy is quadrupled. Kinetic energy K=mv^2/2

Answer:

Hello your question lacks some information but i will give you a more General answer about differences in temperature of bodies on same latitude

answer : Continentality is the reason

Explanation:

Sensors or objects on the same latitude are supposed to have the same air temperatures but in some cases this might not be true. This is because of the proximity of the bodies to an Ocean or any water body.  

Areas close to water bodies experience modest temperatures even if they are on the same latitude with Areas experiencing  harsh temperatures. This effect is termed as Continentality

Answer:

An object's speed or direction can be changed by a force. This means a greater force against a lesser force, and it results in acceleration. This means any push or pull against another equal push or pull. It results in no change of acceleration

Explanation:

Answer:

right

Explanation:

Answer:

knee to chest

Explanation:

I took the test

Answer:

C. Knee to chest.

Answer:

North star, its close to our solar system but not in it. hope this helps

Line - A:  (15/10)  =  1.5 inch/second

Line - B:  (0/10)  =  0

Line - C:  (10/10)  =  1.0 inch/second

Line - D:  (-25/20)  =  -1.25 inch/second

Line-A represents the greatest speed.

Complete question is;

Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by Lamar’s work?

A) The elastic potential energy is the same for any distance from a reference point.

B) The gravitational potential energy equals the work needed to lift the object.

C) The gravitational potential energy is the same for any distance from a reference point.

D) The elastic potential energy equals the work needed to stretch the object

Answer:

B) The gravitational potential energy equals the work needed to lift the object.

Explanation:

In physics, we know that potential energy is the energy of a body at rest while the energy of a body in motion is known as kinetic energy.

However,the work required to lift a body from it's position of rest is equal to the Gravitational potential energy of that body.

Elastic potential energy is the one that is stored as a result of force applied to deform an elastic object. Thus, it is not equal to the work needed to stretch the object and it is also not the same for any distance from reference point.

Thus, looking at the options, Option B is correct

Answer:

Therefore, Train A is faster with 50km/h and a 5km/h difference

Explanation:

train A

150km/3h = 50km/h

train B

180km/4h = 45km/h

Answer:

e search mo sa utak mo kasi di mo alam

Answer:

In terms of the light spectrum, blue is a primary color, which means that it is one of the base colors that exist in the universe and it cannot be created by combining different colors together. The primary pigment colors are cyan, magenta, and yellow. Cyan absorbs red, yellow absorbs blue, and magenta absorbs green.

Explanation:

Hope this helped Mark BRAINLEST!!!

Applied Force.

Gravitational Force.

Normal Force.

Frictional Force.

Air Resistance Force.

Answer:

Gravity, Electromagnetism, Weak Interaction, Strong Interaction, Unifying the Fundamental Forces.

Explanation:

Answer:

I'd say C is the answer they want, though my pedantic side wants to argue for B being true as well.

Answer: C. College graduates earn about double the income of high school graduates.

Explanation: I just took the quiz :)

Answer:

its c

Explanation:

just did it

Answer:

c

Explanation:

Answer:

The tension on the slack segment of the belt is 65 N

Explanation:

The given parameters are;

The mass of the solid disk = 70.5 kg

The diameter of the flywheel disk, D = 1.25 m

The radius of the pulley = 0.230 m

If the tension in the upper segment of the belt = 165 N

The angular acceleration of the flywheel = 1.67 rad/s²

The moment of inertia of a circular disc, I = 1/2·M·r²

The radius of the flywheel, r = D/2 = (1.25 m)/2 = 0.625 m

The moment of inertia of the flywheel, I = 1/2 × 70.5 kg × (0.625 m)² = 13.7695312 m²·kg

The moment of inertia, I = 13.7695312 m²·kg

Torque, τ = Moment of Inertia, I × Angular acceleration, α

Torque, τ = I × α

τ = 13.7695312 m²·kg × 1.67 rad/s² = 22.9951171 N·m ≈ 23 N·m

The torque applied from the pulley side is given as follows;

Let [tex]T_{slk}[/tex] represent the tension on the slack segment of the belts, we have;

23 N·m = (165 N - [tex]T_{slk}[/tex]) × 0.230 m

∴ 165 N - [tex]T_{slk}[/tex] = 23 N·m/0.230 m = 100 N

[tex]T_{slk}[/tex] = 165 N - 100 N = 65 N

The tension on the slack segment of the belt, [tex]T_{slk}[/tex] = 65 N

The tension on the slack segment of the belt is 65 N

flywheel, heavy wheel attached to a rotating shaft so as to smooth out delivery of power from a motor to a machine. The inertia of the flywheel opposes and moderates fluctuations in the speed of the engine and stores the excess energy for intermittent use.

The given parameters are;

The mass of the solid disk = 70.5 kg

The diameter of the flywheel disk, D = 1.25 m

The radius of the pulley = 0.230 m

If the tension in the upper segment of the belt = 165 N

The angular acceleration of the flywheel = 1.67 rad/s²

The moment of inertia of a circular disc, I = 1/2·M·r²

The radius of the flywheel, r = D/2 = (1.25 m)/2 = 0.625 m

Now we will  calculate tension on the slack side

The moment of inertia of the flywheel,

[tex]I = \dfrac{1}{2} \times 70.5 kg \times (0.625 m)^2 = 13.7695312 \ m^2 \ kg[/tex]

The moment of inertia, I = 13.7695312 m²·kg

Torque, τ = Moment of Inertia, I × Angular acceleration, α

Torque, τ = I × α

τ = [tex]13.7695312 \times 1.67 = 22.9951171 Nm = 23 Nm[/tex]

The torque applied from the pulley side is given as follows;

Let  represent the tension on the slack segment of the belts, we have;

23 N·m = (165 N - ) × 0.230 m

∴ 165 N -  = 23 N·m/0.230 m = 100 N

= 165 N - 100 N = 65 N

The tension on the slack segment of the belt,  = 65 N

To know more about flywheels follow

https://brainly.com/question/25709397

Answer:

Aceleracion = 5 m/s²

Explanation:

Dados los siguientes datos;

Velocidad inicial = 10 m/s

Velocidad final = 70 m/s

Tiempo, t = 12 segundos

Para encontrar la aceleración;

Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.

Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.

Por lo tanto, si restamos la velocidad inicial de la velocidad final y la dividimos por el tiempo, podemos calcular la aceleración de un objeto. Matemáticamente, la aceleración viene dada por la fórmula;

[tex] Aceleracion = \frac{final \; velocidad - inicial \; velocidad}{tiempo}[/tex]

Sustituyendo en la fórmula, tenemos;

[tex] Aceleracion = \frac{70 - 10}{12}[/tex]

[tex] Aceleracion = \frac{60}{12}[/tex]

Aceleracion = 5 m/s²

Answer:

531.65 m

Explanation:

Let d₁ be the distance between the hunter and the closer cliff and d₂ be the distance between the hunter and the farther cliff. The speed of sound v = 343 m/s.

t₁ is the time taken for the sound to reach the neared cliff and return back to the hunter as echo. Hence:

t₁ = 2d₁/343

t₂ is the time taken for the sound to reach the farther cliff and return back to the hunter as echo. Hence:

t₂ = 2d₂/343

t₂ - t₁ = 2.1

2d₂/343 - 2d₁/343 = 2.1

d₂ - d₁ = 360.15        (2)

t₃ is the time taken by the third echo as a result of the second echo reaching the nearer cliff. Hence:

t₃ = 2d₁/343

0.5 = 2d₁/343

d₁ = 85.75 m

d₂ - d₁ = 360.15

d₂ - 85.75 = 360.15

d₂ = 445.9 m

The distance between the two cliffs = d₁ + d₂ = 445.9 + 85.75 = 531.65 m

Answer:

18.75 ohms.

Explanation:

From the question,

]When four resistors are connected in parallel in a circuit,

The equilvalent resistor is given as

1/R' = 1/R₁+1/R₂+1/R₃+1/R₄............................Equation 1

Where R' = Equivalent resistor.

Given: R₁ = R₂ = R₃ = R₄ = 75.0 ohms.

Substitute these values into equation 1

1/R' = (1/75)+(1/75)+(1/75)+(1/75)

1/R' = 4/75

R' = 75/4

R' = 18.75 ohms.

Hence the equivalent resistance = 18.75 ohms.

Answer:

18.8 ohms

Explanation:

apax

Answer:

I gotchu fam. 0.0435 kg

Explanation:

m1v1+m2v2=m1v1f+m2v2f

(0.5)(23)+(m2)(0)=(0.5)(17)+(m2)(69)

11.5=8.5+69m2

3=69m2

0.0435 kg

Answer:

a)  ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J,  d)  W = 150 10⁻¹² J

Explanation:

Let's find the capacitance of the capacitor

         C = [tex]\epsilon_o \frac{A}{d}[/tex]

         C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³

         C = 2.62 10⁻¹² F

for the initial data let's look for the accumulated charge on the plates

          C = [tex]\frac{Q}{\Delta V}[/tex]

          Q₀ = C ΔV

           Q₀ = 2.62 10⁻¹² 8.70

           Q₀ = 22.8 10⁻¹² C

a) we look for the capacity for the new distance

          C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³

          C₁ = 1.04 10⁻¹² F

          C₁ = Q₀ / ΔV₁

          ΔV₁ = Q₀ / C₁

          ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²

          ΔV₁ = 21.9 V

b) initial stored energy

          U₀ = [tex]\frac{Q_o}{ 2C}[/tex]

          U₀ = (22.8 10⁻¹²)²/(2  2.62 10⁻¹²)

          U₀ = 99.2 10⁻¹² J

c) final stored energy

          U_f = (22.8 10⁻¹²) ² /(2  1.04 10⁻⁻¹²)

          U_f = 249.9 10⁻¹² J

d) the work of separating the plates

as energy is conserved work must be equal to energy change

          W = U_f - U₀

          W = (249.2 - 99.2) 10⁻¹²

          W = 150 10⁻¹² J

note that as the energy increases the work must be supplied to the system