Answer:
q = 8.57 10⁻⁵ mC
Explanation:
For this exercise let's use Newton's second law
F = ma
where force is magnetic force
F = q v x B
the bold are vectors, if we write the module of this expression we have
F = qv B sin θ
as the particle moves perpendicular to the field, the angle is θ= 90º
F = q vB
the acceleration of the particle is centripetal
a = v² / r
we substitute
qvB = m v² / r
qBr = m v
q =[tex]\frac{m\ v}{B\ r}[/tex]
The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use
v = d / t
the distance is ¼ of the circle,
d = [tex]\frac{1}{4} \ 2\pi r[/tex]
d =[tex]\frac{\pi }{2r}[/tex]
we substitute
v = [tex]\frac{\pi r}{2t}[/tex]
r = [tex]\frac{2 \ t \ v}{\pi }[/tex]
let's calculate
r =[tex]\frac{2 \ 2.2 \ 10^{-3} \ 88}{\pi }[/tex] 2 2.2 10-3 88 /πpi
r = 123.25 m
let's substitute the values
q = [tex]\frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}[/tex]7.2 10-8 88 / 0.6 123.25
q = 8.57 10⁻⁸ C
Let's reduce to mC
q = 8.57 10⁻⁸ C (10³ mC / 1C)
q = 8.57 10⁻⁵ mC
What happens when a mixture is formed?
Answer:
Explanation:
A mixture can usually be separated back into its original components. Some examples of mixtures are a tossed salad, salt water and a mixed bag of M&M's candy.
A hiker carries a 20 kg backpack up a trail. After 30 minutes he is 300 m higher than his starting point.
Answer:
d
Explanation:
I am smart
To attain the maximum range a projectile has to be launched at 45 degrees if the landing spot and the launch spot are at the same height (neglecting air resistance effects.) Explain in a few sentences how the relation between the vertical and the horizontal components of the initial velocity affects the projectile range
Answer:
see that the velocities are the components in a Cartesian system
Explanation:
The horizontal velocity of the projectile is the x-axis component of the initial velocity
v₀ₓ = v₀ cos 45
vertical speed is
[tex]v_{oy}[/tex] = v₀ sin 45
therefore we see that the velocities are the components in a Cartesian system
What acceleration did you measure from the video? Does this match the acceleration you calculated in the first step?
Explanation:
dont know so sorryyyyyyyyy
A 15 kg mass is lifted to a height of 2m. What is gravitational potential energy at this position
Answer: 294J
Explanation:
[tex]U_g=mg(y_f-y_i)[/tex]
[tex]U_g=(15)(9.8)(2-0)=294J[/tex]
Answer:
294.3 J
Explanation:
U = mgh
U = energy
m = mass
g = gravity
h = height
so
U = 15kg * 9.81 m/s^2 * 2m
294.3 J (joules) [kg *m^2/s^2]
I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXTRA have to include in this series connection.
Answer:
The resistance that will provide this potential drop is 388.89 ohms.
Explanation:
Given;
Voltage source, E = 12 V
Voltage rating of the lamp, V = 5 V
Current through the lamp, I = 18 mA
Extra voltage or potential drop = 12 V - 5 V = 7 V
The resistance that will provide this potential drop (7 V) is calculated as follows:
[tex]R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms[/tex]
Therefore, the resistance that will provide this potential drop is 388.89 ohms.
A 60-kg passenger is in an elevator which is initially at rest. The elevator starts to travel downward. It reaches a downward speed of 7m/sec in a time of 4 seconds
Answer:
a. Acceleration = 1.75 m/s²
b. Force = 105 Newton.
Explanation:
Given the following data:
Mass = 60kg
Final velocity = 7m/s
Time = 4 seconds
Required to find the acceleration and force of the body;
a. To find the acceleration;
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Where;
a is acceleration measured in [tex]ms^{-2}[/tex]v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]t is time measured in seconds.Since the elevator is starting from rest, its initial velocity is equal to 0m/s.
Substituting into the equation, we have;
[tex]Acceleration = \frac{7 - 0}{4}[/tex]
[tex]Acceleration = \frac{7}{4}[/tex]
Acceleration = 1.75 m/s²
b. To find the force;
[tex] Force = mass * acceleration [/tex]
Substituting into the equation, we have;
[tex] Force = 60 * 1.75[/tex]
Force = 105 Newton.
Which of the following laws explains why a net force of 950,000 N is needed at takeoff to accelerate the
530,000 kg Atlas V rocket carrying the rover at a rate of 1.8 m/s2?
A
Newton's third law of motion
B
conservation of momentum
С
Newton's second law of motion
D
Newton's first law of motion
Answer:
Newton's second law of motion
A force of 350 N is applied to an object that accelerated at a rate of 5 m/sec2. What is the mass of the object
Answer:
7/ m5sec per minute ckvhxrsuvj
Use the graph one more time to help you with this question. Changes in both the North and South occurred due to the .
Answer:
industrial revolution
Explanation:
if a wave passes every 17.4 seconds, what is the frequency?
Answer:
to be completely honest I have no idea however I tried calculating it on a calculator and umm...
I think the frequency is...
17,229,452
but ya know I could be totally wrong so if I am sorry
Need help guys please
Answer:
6.378 * 10^6 m
Explanation:
Radius = 6378 km
Changing in metres
6378 km = 6378000 m
Now in scientific notation
= 6.378 * 10 ^ 6 m
What color is seen when cyan light is shown on magenta paper
Answer:
blue
You see white. What happens when you shine cyan light on a magenta shirt? You see blue.
Explanation:
A meteor falls from the sky to the Earth. The meteor already had an initial velocity downward when it
was spotted. If it hit the Earth at 335 m/s after being seen for 30 seconds, then what was the initial
velocity of the meteor?
a=9.8
How does the energy in a system of magnets change when two magnets repel and move away from each other
Problem 3 (a) Assuming the human body (skin temperature 34◦C) to behave like an ideal thermal radiator, find the wavelength where the intensity from the body is a maximum. In what region of the electromagnetic spectrum is radiation with this wavelength? (b) Making whatever (reasonable) assumptions you may need, estimate the power radiated by a typical person isolated from the surroundings. (c) Estimate the radiation power absorbed by a person in a room in which the temperature is 20◦C.
Answer:
Explanation:
a )
We shall apply Wein's displacement law
λm x T = b where λm is wavelength of radiation having maximum intensity
T is absolute temperature of body , and b is a constant
b = 2898 μm-K
T = 273 + 34 = 307 K
λm x 307 = 2898
λm = 9.44 μm
= 9440 nm
It is infrared radiation .
b )
We shall apply Stefan's law of radiation.
E = σA T⁴
E is emitted radiation by body acting as black body , A is surface area , T is absolute temperature of body
σ = 5.67 x 10⁻⁸ J / m²T⁴
Surface area of a typical man's body A = 1.9 m²
T = 273 + 34 = 307 K
Assuming human body as black body
E = 5.67 x 10⁻⁸ x 1.9 x 307⁴ J/s
= 9.57 x 10² J/s
= 957 W .
c )
Radiation absorbed
E = 5.67 x 10⁻⁸ x 1.9 x ( 273 + 20 )⁴ J/s
= 794 W .
7. An electric kettle is connected to a mains voltage of 230 V. The current in the kettle is 12 A. Calculate the power of the kettle
Answer:
2,760watts
Explanation:
Power of the kettle = current * voltage
P = IV
Given
I = 12A
V = 230V
Substitute into the formula
Power of the kettle = 12*230
Power of the kettle = 2,760watts
Identify the type of information scientists gather from each image. Drag the tiles to the correct boxes to complete the pairs.
Answer:
The bar of colors = Chemical composition of stars
All the blue stars, (image 2) = Distance of stars
All the different color stars =Temperature of stars
Explanation:
I did this same exact thing just now and i got it correct.
Define :density٬archimedes principle
Answer:
density is defined as the amount of mass contained in unit volume of a body .its si unit is kg/m*3
Answer:
Density is the amount of mass per unit volume of a substance.
Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"
How quickly would a 60kg object accelerate if the person applied a 500N force?
Answer:
acceleration =
[tex]8.33ms {}^{ - 2} [/tex]
Explanation:
we know,
force = mass × acceleration
500 = 60 × aa = 500 / 60a = 50 / 6a = 8.33 m/s^28.33 m/s² quickly would a 60kg object accelerate if the person applied a 500N force.
Describe acceleration:Acceleration the rate at which speed and direction of a moving object vary over time. A point or object moving straight ahead is accelerated whenever it accelerates or decelerates. Even if the speed remains constant, motion on the a circle accelerates so because direction is constantly shifting.
Can an acceleration be negative?An item that is slowing down will always have a negative acceleration if the current direction of motion is constantly selected as positive.
Briefing:Force = mass × acceleration
500 = 60 × a
a = 500 / 60
a = 50 / 6
a = 8.33 m/s²
To know more about Acceleration visit:
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Determine the position of a train moving at 45 m/s after 5 minutes.
The train has covered 13,500 meters of track.
We don't know its position, because we don't know where it started from, and we don't know how straight the track is.
when the body said to be in equilibrium
Answer:
Oh! I just learned abt this
Explanation:
the body is said to be in equilibrium if it is resting or moving with uniform velocity.
Answer: The body is said to be in balance if it is at rest or moving at a uniform speed. In other words, if the body's linear and angular acceleration is zero, the body is said to be in balance. 1
Two objects exert a gravitational force of 3 N on one another when they are 10 m apart. What would that forced be if the distance between the two objects were reduced to 5 m?
Answer:
New force = 12 N
Explanation:
The gravitational force between two masses is given by :
[tex]F=\dfrac{Gm_1m_2}{d^2}[/tex]
Where
d is the distance between masses
Initial force, F₁ = 3 B
Initial distance, d₁ = 10 m
Final distance, d₂ = 5 m
According to the above relation,
[tex]\dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{3\times 10^2}{5^2}\\\\F_2=12\ N[/tex]
So, the new force is 12 N.
A 16 g ball at the end of a 1.4 m string is swung in a horizontal circle. It revolves once every 1.09 s. What is the magnitude of the string's tension?
Answer and I will give you brainiliest
Answer:
6.56
Explanation:
frequency = 1/1.09 = 0.92 Hz
f = 1/(2L) × √T/m
0.92 = 1/2(1.4) × (√T/√16)
0.92 = 0.36 × (√T)/4
multiply all through by 4
3.68 = 1.44 × √T
√T = 3.68/1.44 = 2.56
T = 2.56² = 6.56
The magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton
Given the data in the question;
Mass of the ball;[tex]m = 16g = 0.016kg[/tex]String is swung in a horizontal circle, Radius; [tex]r = 1.4m[/tex]Period of revolution; [tex]T = 1.09s[/tex]Magnitude of the string's tension; [tex]F_T = ?[/tex]First, we need to get magnitude of the centripetal acceleration:
[tex]a_c = \frac{4\pi ^2r}{T^2}[/tex]
We substitute in our given values
[tex]a_c = \frac{4\pi ^2\ *\ 1.4m}{(1.09s)^2} \\\\a_c = 46.519 m/s^2[/tex]
Now, from Newton's Second Law of Motion:
[tex]F = m\ * \ a[/tex]
Where F is the force, m is the mass of the object and a is the acceleration
We substitute into the equation to get the magnitude of the string's tension.
[tex]F = 0.016kg \ *\ 46.519m/s^2[/tex]
[tex]F = 0.744 kg.m/s^2\\\\F = 0.744 N[/tex]
Therefore, the magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton
Learn more; https://brainly.com/question/14039108
it is a line that intersects a circle at exactly two points.
Secant is the answer. Please mark brainliest.
A line that intersects a circle at exactly two points is called a secant line.
hope this helped!
A person in car slides to the right when going through a very sharp left turn on the highway. Is that law of inertia or law of acceleration?
Answer:
Inertia :)
Explanation:
A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?
Answer:
Then she only traveled 1km
17. If ice has a density of 0.92g/cm?, what is the mass of a 30 cm block?
I
Answer:
Mass = 27.6 grams
Explanation:
Given the following data;
Density of ice = 0.92g/cm³
Volume = 30cm³
To find mass of ice;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Making mass the subject of formula, we have;
[tex] Mass = density * volume [/tex]
[tex] Mass = 0.92 * 30 [/tex]
Mass = 27.6 grams
Therefore, the mass of ice is 27.6 grams.
A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 458 N and have a center of gravity that is 1.34 m above the floor. His upper legs weigh 120 N and have a center of gravity that is 0.766 m above the floor. Finally, his lower legs and feet together weigh 89.8 N and have a center of gravity that is 0.204 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.
Answer:
the location of the center of gravity for the entire body is 1.08 m
Explanation:
Given the data in the question;
w1 = 458 N, y1 = 1.34 m
w2 = 120 N, y2 = 0.766 m
w3 = 89.8 N, y2 = 0.204 m
The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.
so,
[tex]Y_{centre of gravity}[/tex] = (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )
so we substitute in our values
[tex]Y_{centre of gravity}[/tex] = (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )
[tex]Y_{centre of gravity}[/tex] = 723.9592 / 667.8
[tex]Y_{centre of gravity}[/tex] = 1.08 m
Therefore, the location of the center of gravity for the entire body is 1.08 m
I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXTRA have to include in this series connection.
Answer:
The resistance that will provide this potential drop is 388.89 ohms.
Explanation:
Given;
Voltage source, E = 12 V
Voltage rating of the lamp, V = 5 V
Current through the lamp, I = 18 mA
Extra voltage or potential drop, IR = E- V
IR = 12 V - 5 V = 7 V
The resistance that will provide this potential drop (7 V) is calculated as follows:
IR = V
[tex]R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms[/tex]
Therefore, the resistance that will provide this potential drop is 388.89 ohms.