Answer: since the toy is marked down 15%,
you do p*.85
to find the remaining cost
Step-by-step explanation: I got this from a friend. But I hope this helps! <3
4,0000000000×10,00000000
Answer:
yes 40
Step-by-step explanation:
she got it correct
The accompanying table shows the number of cars of two different brands sold at a dealership during a certain month. The number of coupes and sedans is also shown.
Vehicle Brand 1 Brand 2 Total
Coupe
100
240
340
Sedan
200
85
285
Total
300
325
625
If one of these vehicles is selected at random, determine the probability that it was a coupe, given that the vehicle selected was Brand 1.
The probability that a vehicle was a coupe, given that it was Brand 1.is
(Round to four decimal places as needed.)
Answer:
0.5440
Step-by-step explanation:
Given that ;
Brand 1 : Couple Brand 2: Sedan Total
100 200 300
240 85 325
Total : 340 285 625
The probability that a vehicle selected at random is a couple given that it was brand 1 will be;
The probability that a selected vehicle is a couple is 340/625
=0.5440
Help please I don’t get it
Answer:
[tex]12+\frac{1}{4}\cdot12[/tex] [tex],[/tex] [tex]12\left(1+\frac{1}{4}\right)[/tex] [tex]and[/tex] [tex]12\cdot\frac{5}{4}[/tex]
Step-by-step explanation:
[tex]--------------------------------------------[/tex]
[tex]\frac{1}{4}[/tex] [tex]of[/tex] [tex]12[/tex] [tex]is[/tex] [tex]3[/tex]
[tex]12+3[/tex] = [tex]15[/tex]
[tex]--------------------------------------------[/tex]
[tex]12+\frac{1}{4}[/tex] = [tex]12.25[/tex] ✘
[tex]12\cdot\frac{1}{4}[/tex] = [tex]3[/tex] ✘
[tex]12+\frac{1}{4}\cdot12[/tex] = [tex]15[/tex] ✔
[tex]12\left(1+\frac{1}{4}\right)[/tex] = [tex]15[/tex] ✔
[tex]12\cdot\frac{3}{4}[/tex] = [tex]9[/tex] ✘
[tex]12\cdot\frac{5}{4}[/tex] = [tex]15[/tex] ✔
[tex]--------------------------------------------[/tex]
Sorry that it took long, really wanted to work hard on this one.
[tex]--------------------------------------------[/tex]
Hope this helps! <3
[tex]--------------------------------------------[/tex]
Amit’s school bus travelsat 36km/hr and Sushma’s school bus travels at 11 m/s. Whose school bus is faster ?
Answer:
This answer is not originally mine so Don give me credit
Step-by-step explanation:
Amit's school bus in m/s will be
36×1000/3600
36 × 10/36
= 10 m/s
While sushma's school bus has speed of 11 m/s
so sushma's school bus is faster than Amit's school bus
Answer:
Amit's: 10 m/s
Sushma's 11 m/s
Step-by-step explanation:
Amit's:
36 x 1000/3600
36 x 10/36
Sushma's:
11 m/s
Sushma's school bus is faster than Amit
The demand on a power plant changes over time. cause or effect
Answer:
effect
Step-by-step explanation:
HELP PLEASE I GIVE BRAINLIEST
Answer:
30
Step-by-step explanation:
Perimeter of rectangle = 5y - 1 + 4y + 2 + 5y - 1 + 4y + 2
= 18y + 2
18y + 2 = 128
18y = 128 - 2
= 126
y = 126 ÷ 18
y = 7
Length of AD = 4y + 2
= 4(7) + 2
= 28 + 2
= 30
What is the answer to this?
Answer:
65 reaminder 85
Step-by-step explanation:
u divided it and theres a big remainder so i did the two first reinders i found
Find the x and y intercepts of the following equation. 3x - 8y = 24
Just do q1-4 and hurry...... he’s coming for me!
1.order of operations
2.12 or variable
3.error
4.Line(12¨
hope this helps
plz consider marking brainliest
Fernando loves to make music playlists. He likes to keep the same ratio of country songs to rock songs. On his summer playlist, he has 100 country songs and 24 rock songs. On his road trip playlist, Fernando has 25 country songs.
How many rock songs are on Fernando's road trip playlist?
Answer:
There are 6 rock songs on Fernando's road trip playlist.
Step-by-step explanation:
Given that he keeps the ratio same
This means that the ratios for both summer playlist and trip playlist will be the same
Let
c1 be the country songs in summer playlist
r1 be the rock songs in trip playlist
Similarly,
c2,r2 will be the country and rock songs in trip playlist
Both will be equal so
[tex]\frac{c_1}{r_1} = \frac{c_2}{r_2}[/tex]
Putting the values
[tex]\frac{100}{24} = \frac{25}{r_2}\\100r_2 = 25*24\\100r_2 = 600r_2 = \frac{600}{100}\\r_2 = 6[/tex]
Hence,
There are 6 rock songs on Fernando's road trip playlist.
Answer:
6 songs
Step-by-step explanation:
F(x)=x/2 +8, what is f(x) when x = 10?
4
ОООО
13
36
Answer:
13
Step-by-step explanation:
Just replace x with 10, so F(10) = 10/2 + 8. Which is 5 + 8.
Stella predicted that she would sell 56 sculptures. She actually sold 30 sculptures. What are the values of a and b in the table below? Round to the nearest tenth if necessary.
Answer:
a=26 / 56 and b = 46.4 percent
Step-by-step explanation:
From the question, the Approximate value is given as = 56
While the Exact value is given as 30
Error
Absolute error= 56-30=26
Where Ratio= a= error/Approximate value=26/56
Percent error = b= 26/56×100%=46.4
it's a
have an nice day day
21. Transportation A youth group with 26 members is going skiing. Each of the five
chaperones will drive a van or sedan. The vans can seat seven people, and the
sedans can seat five people. Assuming there are no empty seats, how many of each
type of vehicle could transport all 31 people to the ski area in one trip?
Answers:
2 sedans and 3 vans
=====================================================
Work Shown:
s = number of sedans
v = number of vans
1 sedan = 5 seats
s sedans = 5s seats
1 van = 7 seats
v vans = 7v seats
5s+7v = all seats
5s+7v = 31
Let's go through all the values of s to see which values of v work.
If s = 0, then the equation turns into 7v = 31, but the solution for v isn't an integer.If s = 1, then the equation turns into 5+7v = 31 and that solves to v = 26/7 = 3.71 which also isn't an integerIf s = 2, then the equation becomes 10+7v = 31 and that solves to v = 3. So we found the answer. This means we need 2 sedans and 3 vans.As a check:
2 sedans = 5*2 = 10 seats
3 vans = 7*3 = 21 seats
10+21 = 31 seats total
This confirms the answer.
The number of vans used is three and the number of sedans is two
Let :
v represent the number of vans
s represent the number of sedans
The following equations can be gotten
7v + 5s = 31 equation 1
v + s = 5 equation 2
The elimination method would be used to solve for v and s
Multiply equation 2 by 7
7v + 7s = 35 equation 3
Subtract equation 1 from 3
2s = 4
s = 4/2
s = 2
Substitute for s in equation 2
v + 2 = 5
v = 5 - 2
v = 3
To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults
At the first game of the Major League Baseball season, a statistician keeps track of every pitch that a player throws during the game. The statistician reported that the mean pitch speed was 80 miles per hour (mph) and the standard deviation of the serve speeds was 10 mph. Assume that the statistician also gave us the information that the distribution of pitch speeds was mound- shaped and symmetric. What percentage of the player's serves were between 80 mph and 100 mph
Answer:
47.725%
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 80 mph
σ is the population standard deviation = 10 mph
For x = 80 mph
z = 80 - 80/10
z =0
Probability value from Z-Table:
P(x = 80) = 0.5
For x = 100 mph
z = 100 - 80/10
z = 2
Probability value from Z-Table:
P(x = 100) = 0.97725
Probability of the player's serves thay were between 80 mph and 100 mph is calculated as:
P(x = 100mph) - P(x = 80 mph)
= 0.97725 - 0.5
= 0.47725
The percentage of the player's serves that were between 80 mph and 100 mph is calculated as:
Converting to percentage:
0.47725 × 100 = 47.725%
For a recent evening at a small, old-fashioned movie theater, 35% of the moviegoers were female and 65% were male. There were two movies playing that evening. One was a romantic comedy, and the other was a World War II film. As might be expected, among the females the romantic comedy was more popular than the war film: 70% of the females attended the romantic comedy. Among the male moviegoers, the romantic comedy also was more popular: 60% of the males attended the romantic comedy. No moviegoer attended both movies. Let F denote the event that a randomly chosen moviegoer (at the small theater that evening) was female and ¯F denote the event that a randomly chosen moviegoer was male. Let R denote the event that a randomly chosen moviegoer attended the romantic comedy and ¯R denote the event that a randomly chosen moviegoer attended the war film. Fill in the probabilities below, and then answer the question that follows. Do not round any of your responses
P(F)=0.35
P(F and R)=
P(F and ¯R)=
P(¯R|F)=
P(R|¯F)=0.60
P(¯F and R)=
P(¯F and ¯R)=
P(¯F)=
What is the probability that a randomly chosen moviegoer attended the romantic comedy?
Answer:
[tex]P(F\ and\ R) = 0.21[/tex]
[tex]P(F\ and\ R^{-}) = 0.14[/tex]
[tex]P(R^{-}|F)= 0.40[/tex]
[tex]P(F^{-} and\ R) = 0.39[/tex]
[tex]P(F^{-}\ and\ R^{-}) =0.26[/tex]
[tex]P(F^{-}) =0.65[/tex]
Step-by-step explanation:
The variables have been defined in the question as:
[tex]F = Female\ Moviegoer[/tex]
[tex]F^{'} = Male\ Moviegoer[/tex]
[tex]R = Romantic\ Comedy[/tex]
[tex]R^{'} = War\ File[/tex]
Also, we have the following given parameters:
[tex]P(F) = 0.35[/tex]
[tex]P(F^{-}) =0.65[/tex]
[tex]P(R) =0.60[/tex]
[tex]P(R^{-}) = 0.40[/tex]
The solution is as follows:
[tex]a.\ P(F\ and\ R)[/tex]
[tex]P(F\ and\ R) = P(F) * P(R)[/tex]
Substitute values for P(F) and P(R)
[tex]P(F\ and\ R) = 0.35 * 0.60[/tex]
[tex]P(F\ and\ R) = 0.21[/tex]
[tex]b.\ P(F\ and\ R^{-})[/tex]
[tex]P(F\ and\ R^{-}) = P(F) * P(R^{-})[/tex]
Substitute values for P(F) and P(R-)
[tex]P(F\ and\ R^{-}) = 0.35 * 0.40[/tex]
[tex]P(F\ and\ R^{-}) = 0.14[/tex]
[tex]c.\ P(R^{-}|F)[/tex]
[tex]P(R^{-}|F)=\frac{P(R^{-}\ and\ F)}{P(F)}[/tex]
[tex]P(R^{-}|F)=\frac{P(R^{-})\ *\ P(F)}{P(F)}[/tex]
Substitute values for P(F) and P(R-)
[tex]P(R^{-}|F)=\frac{0.40 * 0.35}{0.35}[/tex]
[tex]P(R^{-}|F)= 0.40[/tex]
This implies that both events are independent
[tex]d.\ P(F^{-} and\ R)[/tex]
[tex]P(F^{-} and\ R) = P(F^{-}) * P(R)[/tex]
Substitute values for P(F-) and P(R)
[tex]P(F^{-} and\ R) = 0.65 * 0.60[/tex]
[tex]P(F^{-} and\ R) = 0.39[/tex]
[tex]e.\ P(F^{-}\ and\ R^{-})[/tex]
[tex]P(F^{-}\ and\ R^{-}) =P(F^{-}) * P(R^{-})[/tex]
Substitute values for P(F-) and P(R-)
[tex]P(F^{-}\ and\ R^{-}) =0.65 * 0.40[/tex]
[tex]P(F^{-}\ and\ R^{-}) =0.26[/tex]
[tex]f.\ P(F^{-})[/tex]
[tex]P(F^{-}) =0.65[/tex] --- Given
1) What is the constant of proportionality that relates y to x
х
Y
8
6
20
15
28
21
a. 1.33
6,48
0.0.75
b. 14
f
Answer: The Answer Is A Because if u just add the numbers then divide them
If you rotate figure GTR 270° clockwise about the origin. What will be the coordinates of G’T’R’ (Please Help I need this done in five minutes.)
Answer:
C. G' (4,-7), R' (2,-3), T'(6,-4)
Step-by-step explanation:
Get a piece of paper and draw 2 intersecting lines, like how a graph looks like. Then get another paper that's transparent enough, and place a dot roughly where R would be. Rotate it 270* clockwise (3 times around 90 degrees), and R would be in the bottom right area. That means the figure would be around that area and you can base the coordinates from that.
order the numbers from least to greatest -20 3/4 -14 3/4 -1/4 and -15 1/2
Answer:
-20 3/4, -15 1/2, -14 3/4,
Step-by-step explanation:
Which situation represents a non-proportional relationship?
The cost of purchasing p pounds of salmon for $7.99 per pound.
The amount a student makes mowing m number of lawns charging $35 per lawn.
The amount of water draining at a rate of 2.5 gallons per minute.
The total cost of renting a jet ski for $25 per hour plus a fee of $50.
Answer:
Correct option:
"The total cost of renting a jet ski for $25 per hour plus a fee of $50."
Step-by-step explanation:
Proportional relationships are associations between two variables where the ratio of these two variables are correspondent. Or, in a proportional relationship, one variable is a constant value times the other variable. This constant is known as the "constant of proportionality".
The first three options represents a proportional relationship.
But the last option does not.
"The total cost of renting a jet ski for $25 per hour plus a fee of $50."
That is,
TC = 25·h + 50
The relationship is linear not proportional.
Help please! This has to do with the Pythagorean theorem.
Alec types
3
5
of a paragraph in
2
3
minute. If he continues at the same rate, what fraction of a paragraph can Alec complete in 1 minute?
Answer:
9/10 of a paragraph in a minute
Step-by-step explanation:
find out how much he can type in 1/3 of a minute
(3/5)/2 3/5=6/10 (6/10)/2 3/10
(3/10)*3=9/10
Answer:
9/10
Step-by-step explanation:
hope it worked
Find the are of the semi circle.Either enter an exact answer in terms of pie or use 3.14 and enter your answer as a decimal.The raduis is 4
TRUE OR FALSE
The unit rate is when the ratio has a denominator 1
True
False
Answer:
that would be true
Step-by-step explanation:
Answer:FALSE
Step-by-step explanation:
Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the population proportion p at the given level of significance alpha using the given sample statistics. Claim: p is not equal to 0.22; Alpha = 0.01; Sample statistics: p = 0.15, n = 180Can the normal sampling distribution be used? A. No, because np is less than 5. B. No, because nq is less than 5. C. Yes, because both np and nq are greater than or equal to 5. D. Yes, because pq is greater than alpha = 0.01. State the null and alternative hypotheses. Determine the critical value(s).Find the z-test statistic.
Answer:
A
The correct option is C
B
The value of z-test is [tex]z = -2.267[/tex]
Step-by-step explanation:
From the question we are told that
The null hypothesis [tex]H_o : p = 0.22[/tex]
The alternative hypothesis [tex]H_a : p \ne 0.22[/tex]
The level of significance is [tex]\alpha = 0.01[/tex]
The sample proportion is [tex]\^ p = 0.15[/tex]
The sample size is n = 180
Generally from central limit theorem
if np and nq are > 5 then normal sampling distribution can be used
So
np = 180 * 0.22 = 39.6 > 5
and
nq = 180 * (1 -0.22) = 140.4 > 5
So normal sampling distribution can be used
Generally the z-test is mathematically represented as
[tex]z = \frac{\^ p - p }{ \sqrt{\frac{ p(1- p ) }{n } } }[/tex]
=> [tex]z = \frac{ 0.15 - 0.22 }{ \sqrt{\frac{ 0.2(1- 0.22 ) }{ 180 } } }[/tex]
=> [tex]z = -2.267[/tex]
HELP PLS ASAP!! ILL GIVE 10 BRAINLEST THINGYS !!!
Explain how to find the slope of the function without using technology.
2x + 3y = 12
Answer: The slope is −2/3
Step-by-step explanation:
2 x + 3 y = 12 is the standard form for a linear equation. To determine the slope, solve the equation for y in order to convert to the slope-intercept form y = m x + b , where m is the slope and b is the y-intercept.
2 x + 3 y = 12
Subtract 2 x from both sides.
3 y = − 2 x + 12
Divide both sides by
3 . y = − 2 /3 x + 12 /3 =
y = − 2 /3 x + 4
The slope is
− 2 /3
Please help me fast!!!. Joe and his family are touring Chicago. They want to visit the Willis Tower, hang out at Navy Pier, and shop on Michigan Avenue before their dinner reservations at 5:10 P.M. They plan to spend 1 hour and 10 minutes at the Willis Tower, 3 hours and 10 minutes at Navy Pier, and 1 hour and 15 minutes shopping. What is the latest time Joe's family can start their tour of Chicago and still make it to dinner on time?
Include A.M. or P.M. in your answer.
Answer:
11:10 am.
Step-by-step explanation:
The first thing I'm going to do is to add all the given time together
Total time = time spent at Willis tower + time spent at Navy Pier + time spent shopping
Total time = 1 HR and 10 minutes + 3 HR and 10 minutes + 1 hour and 15 minutes
Total time = (1 + 3 + 1) hr + (10 + 10 + 15) minutes
Total time = 5 hours + 35 minutes
The question doesn't make mention of how long they spent making the journey so, I'm assuming they spent 35 minutes driving around from Willis to the Pier and finally while shopping
Time = total time + time spent driving
Time = 5 hours 35 minutes + 35 minutes
Time = 6 hours and 10 minutes
Now, this time we've calculated, is what we're going to subtract from the dinner time to get our final answer
Needed time = dinner time - time
Needed time = 5:10 pm - 6:10
Needed time = 17:10 - 6:10
Needed time = 11:10
This means that they ought to start their tour by 11:10 am, so that they can meet their dinner
which of the following represents the equation with a slope of 3 and a y-intercept of 2?
Answer:
c is the correct answer
Step-by-step explanation:
Question 2 (5 points)
(01.01 LC)
Which rational number equals 0 point 1 with bar over 1? (5 points)
Question 2 options:
1)
1 over 11
2)
1 over 10
3)
1 over 9
4)
1 over 8
Answer:
3. 1 over 9 is the correct answer
Answer:
option 3 is correct.
hope it helps
Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknight evening, customers arrive at Movies Tonight with an arrival rate of 1.25 customers per minute. The checkout clerk has a service rate of 2 customers per minute/ Assume Poisson arrivals and exponential service times.a. What is the probability that no customers are in the system?b. What is the average number of customers waiting for service?c. What is the average time a customer waits for service to begin?d. What is the probability that an arriving customer will have to wait for service to begin?e. Do the operating charachteristics indicate that the one-clerk checkout system provides and acceptable level of service?
Answer:
Probability [No customers in system] = 0.375Customers waiting for service = 25/24Average time customer wait = 1.25/1.5May be waitPer customer average time = 1.33 (Approx)Step-by-step explanation:
Given:
Arrival rate λ = 1.25 min
Mean μ = 2
Computation:
(a) Probability [No customers in system]
Probability [No customers in system] = 1-[λ/μ]
Probability [No customers in system] = 1-[1.25/2]
Probability [No customers in system] = 0.375
(b) Customers waiting for service
Customers waiting for service = λ²/ [μ(μ-λ)]
Customers waiting for service = 1.25²/ [2(2-1.25)]
Customers waiting for service = 25/24
(c) Average time customer wait
Average time customer wait = λ / [μ(μ-λ)]
Average time customer wait = 1.25/ [2(2-1.25)]
Average time customer wait = 1.25/1.5
(d) May be wait because Customers waiting for service = 25/24
(e) Per customer average time
Per customer average time = 1/(μ-λ)
Per customer average time = 1/(2-1.25)
Per customer average time = 1.33 (Approx)
[tex] \frac{18}{100} [/tex]
is what percent
A. 36%
B. 8%
C. 9:
D. 18%