Answers
Answer:
Step-by-step explanation:
Note : any number or variable with it's power 0 is considered as one.
Last one is the solution to find the two ration numbers between 2/5 and 3/4 (question which u asked just before this question).
Related Questions
I WILL MARK BRANLIEST IF YOU ANSWER CORRECTLY
Answers
Answer:
ok what is your question.
PLEASE HELPPPPpdododp
Answers
Answer:
f(x) - g(x) = x^3 - 3x^2 - 4x - 4
Step-by-step explanation:
f(x) - g(x)
x^3 - 2x^2 - 3x - 5 - ( x^2 + x - 1 )
x^3 - 2x^2 - 3x - 5 - x^2 - x + 1
x^3 - 3x^2 - 4x - 4
differentiate loge(x/x^2+7)
Answers
Answer:
1+1=11 2+2=22 ok na yan kuya or ate
Triangle A B C is cut by line segment D E. Line segment D E goes from side A C to line A B. The length of A E is 12, the length of E B is 4, and the length of A D is 9. What is the length of Line segment D C? 2 units 3 units 6 units
Answers
Answer:
3 units
Step-by-step explanation:
Write Ratio 2:12 in the form 1:n
Answers
1:6
Hope this helps! :)
______________
Answer:
n value is 6
2:12=1:6
n is 6
Help find instantaneous rate of change :)!
Answers
=========================================================
Explanation:
Let's say that point A is at (0,0) and B is somewhere else on the parabola.
I'll make point B go to the right of point A.
For now, let's say B is at (4,16).
If we compute the slope of line AB, then we find the average rate of change (AROC). The AROC in this case is (y2-y1)/(x2-x1) = (16-0)/(4-0) = 16/4 = 4. Because point A is at (0,0), we're really just computing y/x where the x,y values come directly from point B.
--------------
Now let's move B to (3,9). If we used the slope formula again, we would get the slope of 3. Note how y/x = 9/3 = 3.
Then let's move B to (2,4). The AROC is now y/x = 4/2 = 2
As B gets closer to A, the AROC is decreasing. The AROC is slowly approaching the IROC (instantaneous rate of change).
--------------
Point B is generally located at (x,x^2) for any real number x. Keeping A always fixed at the origin, the slope of line AB is y/x = (x^2)/x = x.
What does this all mean? It means that if x = 0, then the IROC is 0. You might be quick to notice that we cannot divide by zero. So instead of letting x be zero itself, we'll just get closer and closer to it. This is where the concept of limits come into use. This is what calculus is based on (both integral and differential calculus).
Anyway, when calculating the IROC, we're really calculating the slope of the tangent line to the f(x) curve. Refer to the diagram below.
----------------
In short, the slope of the tangent line at x = 0 is m = 0. We have a flat horizontal line that touches the parabola at (0,0).
112x/5= 43.60 solve for x
Answers
Answer:
x=109/56
dn did djs. hd hd hd hd hd hd
Find the slope of the line that passes through the following points. Simplify answer (-6,8)and(-1,8)
Answers
Answer:
m = 0
General Formulas and Concepts
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]Step-by-step explanation:
Step 1: Define
Identify points
Point (-6, 8)
Point (-1, 8)
Step 2: Find slope m
Simply plug in the 2 coordinates into the slope formula to find slope m
Substitute in points [Slope Formula]: [tex]\displaystyle m = \frac{8 - 8}{-1 - -6}[/tex][Fraction] Subtract: [tex]\displaystyle m = \frac{0}{5}[/tex]Divide: [tex]\displaystyle m = 0[/tex]Can someone help me please
Answers
Answer:0.02
Step-by-step explanation:
You are working as an office apprentice for the bksb Newcastle Arena. You are helping collect a customer satisfaction survey for the arena. Enter the following replies into the table below.
Answers
Answer:
Step-by-step explanation:
Enlarge the triangle by scale factor -1/3 with centre (-1,2)
PLEASE CAN SOMEONE HELP?????????????/
Answers
The coordinates of the image after a dilation by scale factor -1/3 with center (-1, 2) are (0, 2), (0, 4), and (-1, 4).
What is dilation?In Geometry, dilation can be defined as a type of transformation which typically changes the size of a geometric object, but not its shape.
Next, we would have to dilate the coordinates of the pre-image by using a scale factor of -1/3 centered at the point (-1, 2) by using this mathematical expression:
(x, y) → (k(x - a) + a, k(y - b) + b)
For coordinate A, we have;
Coordinate A = (-4, 2) → (-1/3(-4 - (-1)) + (-1), -1/3(2 - 2) + 2)
Coordinate A = (-4, 2) → (-1/3(-4 + 1) - 1, -1/3(2 - 2) + 2)
Coordinate A' = (1, 1) → (0, 2)
For coordinate B, we have;
Coordinate B = (-4, -4) → (-1/3(-4 - (-1)) + (-1), -1/3(-4 - 2) + 2)
Coordinate B = (-4, -4) → (-1/3(-4 + 1) - 1, -1/3(-4 - 2) + 2)
Coordinate B' = (1, 1) → (0, 4)
For coordinate C, we have;
Coordinate C = (-1, -4) → (-1/3(-1 - (-1)) + (-1), -1/3(-4 - 2) + 2)
Coordinate C = (-1, -4) → (-1/3(-1 + 1) - 1, -1/3(-4 - 2) + 2)
Coordinate C' = (1, 1) → (-1, 4).
Read more on dilation here: brainly.com/question/20482938
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Multiply 2x(5x+8y+3)
Answers
Answer:
10x² + 16xy + 6x
Step-by-step explanation:
2x(5x+8y+3)
10x² + 16xy + 6x
Answer:
[tex]10x^{2} + 16xy + 6x[/tex]
Hope this helped!
A road has a scale of 1:50 000 The length of a road on the map is 8.5cm.Work out the length of the real road in kilometres
Answers
The answer is 2.1 Km. Hope this helps!
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and width.4x+y^2=12, x=yThen find the area S of the region.
Answers
Answer:
The Area of the Enclosed Region Is 64/3.
Step-by-step explanation:
As Given in Question
We have, Curve 4x+[tex]Y^{2}[/tex]=12
& X=Y
Solution.
4Y+[tex]Y^{2}[/tex]=12 (X=Y)
[tex]Y^{2}[/tex]+4Y-12=0
[tex]Y^{2}[/tex]+6Y-2Y-12=0
Y(Y+6)-2(Y+6)=0
(Y-2)*(Y+6)=0
Y=2 & -6 (X=Y)
Now at (2,2) & (-6,-6) both curves intersect each other.
The Area Of Enclosed Region is [tex]\int\limits^2_{-6} [(3-Y^{2}/4 )-Y] \, dy[/tex]
by Solving This Equation we get Area of Region = 64/3 .
this equation Solution & Curve Diagram please see In Attachment .
factor the polynomial by grouping
[tex]5 {x}^{2} - 11x + 6[/tex]
Answers
Factor
−
11
-
11
out of
−
11
x
-
11
x
.
5
x
2
−
11
(
x
)
+
6
5
x
2
-
11
(
x
)
+
6
Rewrite
−
11
-
11
as
−
5
-
5
plus
−
6
-
6
5
x
2
+
(
−
5
−
6
)
x
+
6
5
x
2
+
(
-
5
-
6
)
x
+
6
Apply the distributive property.
5
x
2
−
5
x
−
6
x
+
6
What are the solutions to this equation?
-7 + (x2 – 19) = 20
-10
5.6
There are no solutions.
10
-5.6
Answers
[tex]\sqrt{160000}[/tex]
what is the value of this
Answers
Answer:
400
Step-by-step explanation:
sqrt(160000)=sqrt(16)*sqrt(10000)=4*100
What is the value of x in this number sentence
[tex]\frac{x}{7} - 4 = 6[/tex]
Answers
x=10(7)
x=70
Hope this helps!
Answer:
[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]
[tex] \frac{x}{7} - 4 = 6 \\ \frac{x}{7} = 6 + 4 \\ \frac{x}{7} = 10 \\ x = 10 \times 7 \\ x = 70[/tex]
____________________
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
➳ RainbowSalt2²2² ❦
PLEASE HELP URGENT Give evidence and proof no links
1/What is the correct written expression for the variable expression: (3 - x)/7 *
the difference of 3 and x divided by 7
3 divided by the difference of 7 and x
the sum of 3 and x divided by 7
the difference of 3 divided by 7 and x
2.Johnny is 5 less than 3 times the age of Elizabeth. If Elizabeth is e years old, which expression shows Johnny's age? *
3e - 5
3e + 5
5 - 3e
5 + 3e
3.What is the value of 4a - 7b - 8, when a = 7 and b = 3? *
1
15
-1
-45
4.Jose has g video games. Tony has 8 fewer games than Jose. What variable expressions represents the total number of video games Jose and Tony have? *
g + 8
2g + 8
g - 8
g + (g - 8)
5. Which written expression represents the variable expression 1/2 (8 - y) *
One half of eight less than a number y
A number y less than half of eight
One half the difference between eight and a number y
the difference of one half of eight and a number y
Answers
A1/ the difference of 3 and x divided by 7
A2/ 3e - 5
A3/ -1
A4/ g + (g - 8)
A5/ One half the difference between eight and a number y
I'm not sure, but I hope it helps :)
Pluto is 3,647,720,000 miles from the sun. what is that distance in AU?
1. 3.4
2. 39.2
3. 0.25
4. 26.3
Answers
Answer:
39.2 AU.
Step-by-step explanation:
If my memory serves me right an astronomical unit is 93,000,000 miles.
So the answer is 3647720000/93000000
= 39.2 AU.
Which statement is true about the end behavior of the
graphed function?
• As the x-values go to positive infinity, the function's
values go to negative infinity.
O As the x-values go to zero, the function's values go to
positive infinity.
• As the x-values go to negative infinity, the function's
values are equal to zero
As the x-values go to positive infinity, the function's
values go to positive infinity.
Answers
Answer:
I believe it is the first choice
Step-by-step explanation:
As the x-values go to positive infinity, the function's
values go to negative infinity is the answer because the x-valures are in the first coordinate which is positive but the functions is going negative because of the line in the 3rd coordinate.
I tried my best, i hope you get it correct.
Please let me know if this is correct or not, if not i will edit my answer.
Please mark brainliest :)
Make a substitution to express the integrand as a rational function and then evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) x 49 x dx
Answers
Answer:
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2\sqrt{x + 49} +49\ln|\frac{\sqrt{x + 49}-7}{\sqrt{x + 49}+7}|+c[/tex]
Step-by-step explanation:
Given
[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx[/tex]
Required
Solve by substitution
Let:
[tex]u = \sqrt{x + 49}[/tex]
Square both sides
[tex]u^2 = x + 49[/tex]
Differentiate
[tex]2udu = dx[/tex]
Also notice that:
[tex]x = u^2 - 49[/tex]
So, we have:
[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{u}{u^2 - 49}} \, 2udu[/tex]
[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{2u^2}{u^2 - 49}} \, du[/tex]
Add 0 to the numerator
[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{2u^2+0}{u^2 - 49}} \, du[/tex]
Express 0 as 98 -98
[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{2u^2-98+98}{u^2 - 49}} \, du[/tex]
Split the fraction
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( \frac{2u^2-98}{u^2 - 49}+\frac{98}{u^2 - 49} )\, du[/tex]
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( \frac{2(u^2-49)}{u^2 - 49}+\frac{98}{u^2 - 49} )\, du[/tex]
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( 2+\frac{98}{u^2 - 49} )\, du[/tex]
Rewrite as:
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( 2+\frac{98}{u^2 - 7^2} )\, du[/tex]
Integrate
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +\int\frac{98}{u^2 - 7^2} \, du[/tex]
Remove constant (98)
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +98\int\frac{1}{u^2 - 7^2} \, du[/tex]
As a general rule,
[tex]\int \frac{1}{x^2 - a^2} \, dx = \frac{1}{2}\ln|\frac{x-a}{x+a}|[/tex]
So, we have:
[tex]\int \frac{1}{u^2 - 7^2} \, du = \frac{1}{2}\ln|\frac{u-7}{u+7}|[/tex]
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +98\frac{1}{u^2 - 7^2} \, du[/tex] becomes
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +98*\frac{1}{2}\ln|\frac{u-7}{u+7}|+c[/tex]
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +49\ln|\frac{u-7}{u+7}|+c[/tex]
Substitute values for u
[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2\sqrt{x + 49} +49\ln|\frac{\sqrt{x + 49}-7}{\sqrt{x + 49}+7}|+c[/tex]
A swimming pool is circular with a 40-ft diameter. The depth is constant along east-west lines and increases linearly from 3 ft at the south end to 8 ft at the north end. Find the volume of water in the pool. (Round your answer to the nearest whole number.)
Answers
Answer:
[tex]V=6912ft^3[/tex]
Step-by-step explanation:
From the question we are told that:
Diameter [tex]D=40ft[/tex]
Radius [tex]r=d/2=>20ft[/tex]
Depth at south [tex]d_s=3ft[/tex]
Depth at north [tex]d_n=8ft[/tex]
Average depth of the pool
[tex]d_a=\frac{3+8}{2}[/tex]
[tex]d_a=5.5ft[/tex]
Generally the equation for Volume is mathematically given by
[tex]V=\pi r^2h[/tex]
[tex]V=3.142*(20)^25.5[/tex]
[tex]V=6912ft^3[/tex]
A right rectangular container is 10 cm wide and 24 cm long and contains water to a depth of 7cm. A stone is placed in the water and the water rises 2.7 cm. Find the volume of the stone.
Answers
Answer:
The volume of the rock is 648 cm^3
Step-by-step explanation:
Likely the only dimension that is free to move is the depth of 7 cm.
Volume of the Rock = L * W * h1
L = 24
W = 10
h1 = 2.7
V = 24 * 10 * 2.7
V = 648 cm^3
The product of ______________ and (-1) is -35.
Answers
Answer:
35Step-by-step explanation:
The product of 35 and (-1) is -35.
As,
35 × (-1) = -35
5 is subtracted from the sum of 8 and 7.
Answers
Answer:
10
Step-by-step explanation:
Sum of 8 and 7 = 8 + 7 = 15
5 subtracted from sum of 8 and 7 = 15 - 5 = 10
The answer to this question = 10
What do you mean by a sum?The sum is the result of the addition of two or more numbers.
What do you mean by subtraction?The difference between the two numbers is called subtraction.
How do we evaluate the given question?First, we find the sum of 8 and 7
8 + 7 = 15
Now, we subtract 5 from 15
15 - 5 = 10
∴ The result to the given question = 10
Learn more about the Addition/Subtraction at
https://brainly.com/question/25421984
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What is the volume of a cone that has a radius of 11.2 cm and a height of 25.3 cm?
Your Answer:
Sim
Answers
Step-by-step explanation:
V≈3323.42cm³
r Radius
11.2
cm
h Height
25.3
cm
Solution
V=πr2h
3=π·11.22·25.3
3≈3323.41966cm³
hope it is helpful
Joe drives for 3 hours and covers 201 miles. In miles per hour, how fast was he driving?
Answers
Answer:
67 mph
Step-by-step explanation:
201/3 = 67
Prove the following statement by contradiction.
If a and b are rational numbers, b ≠ 0, and r is an irrational number, then a + br is irrational.
Proof by contradiction: Select an appropriate statement to start the proof.
A. Suppose not. That is, suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational.
B. Suppose not. That is, suppose there exist rational numbers a and b such that b ≠ 0, r is an irrational number, and a + br is irrational.
C. Suppose not. That is, suppose there exist rational numbers a and b such that b ≠ 0, r is an irrational number, and a + br is rational.
D. Suppose not. That is, suppose there exist irrational numbers a and b such that b ≠ 0, r is an irrational number, and a + br is rational.
E. Suppose not. That is, suppose there exist rational numbers a and b such that b ≠ 0, r is a rational number, and a + br is irrational.
Then by definition of rational,
a = c/d, b = i/j , and a + br = m/n
where c, d, i, j, m, and n are___and____. Since b ≠ 0, we also have that i ≠ 0. By substitution,
c/d + i/j r = m/n
Solving this equation for r and representing the result as a single quotient in terms of c, d, i, j, m, and n gives that
r = c - a/b
Answers
Answer:
spongebob at the bottom of the sea
Step-by-step explanation:
In a plain, robust, conversational style, the author known as “Elena Ferrante” has captivated readers worldwide with her chronicle of a complicated friendship between two women.
The step would be, "Suppose not. That is, suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational." Option A is correct.
Given that,
a and b are rational numbers, b ≠ 0, and r is an irrational number, then a + br is irrational. the first step of the proof with contradiction is to be determined.
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
here,
For the statement,
a and b are rational numbers, b ≠ 0, and r is an irrational number, then a + br is irrational.
Contradiction will be "suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational."
Thus, the step would suppose not. That is, suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational.
Learn more about simplification here:
https://brainly.com/question/12501526
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If ABC~DEF what is the length of BC?
If ABC~DEF what is the length of EF?
Answers
BC would equal the same as EF, they are similar. All you would have to do is figure out the pre image (BC) of EF.
Answer: 8
Step-by-step explanation: