Answer:
8 x 8 =64 + 16 x 8 = 128 =$192
Step-by-step explanation:
Please solve with explanation (10 points)
Answer:
Question (a)
[tex]x^2-a^2-bx-ab=0[/tex]
Write in standard form [tex]ax^2+bx+c=0[/tex]:
[tex]\implies x^2-bx-(a^2+ab)=0[/tex]
Therefore,
[tex]a=1[/tex][tex]b=-b[/tex][tex]c=-(a^2+ab)[/tex]Using quadratic formula:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\implies x=\dfrac{b\pm\sqrt{(-b)^2+4(1)(a^2+ab)} }{2(1)}[/tex]
[tex]\implies x=\dfrac{b\pm\sqrt{b^2+4a^2+4ab} }{2}[/tex]
[tex]\implies x=\dfrac{b\pm\sqrt{(b+2a)^2} }{2}[/tex]
[tex]\implies x=\dfrac{b \pm (b+2a)} {2}[/tex]
[tex]\implies x=\dfrac{2b+2a} {2}=b+a[/tex]
[tex]\implies x=\dfrac{-2a} {2}=-a[/tex]
Question (b)
[tex]6x^2-15ax=2bx-5ab[/tex]
Write in standard form [tex]ax^2+bx+c=0[/tex]:
[tex]\implies 6x^2-15ax-2bx+5ab=0[/tex]
[tex]\implies 6x^2-(15a+2b)x+5ab=0[/tex]
Therefore,
[tex]a=6[/tex][tex]b=-(15a+2b)[/tex][tex]c=5ab[/tex]Using quadratic formula:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{(-15a-2b)^2-4(6)(5ab)} }{2(6)}[/tex]
[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{225a^2+60ab+4b^2-120ab} }{12}[/tex]
[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{225a^2-60ab+4b^2} }{12}[/tex]
[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{(15a-2b)^2} }{12}[/tex]
[tex]\implies x=\dfrac{(15a+2b) \pm (15a-2b) }{12}[/tex]
[tex]\implies x=\dfrac{30a }{12}=\dfrac52a[/tex]
[tex]\implies x=\dfrac{4b}{12}=\dfrac13b[/tex]
Question (c)
[tex]\dfrac{x^2}{x-1}=\dfrac{a^2}{2a-4}[/tex]
Cross multiply:
[tex]x^2(2a-4)=a^2(x-1)[/tex]
Write in standard form [tex]ax^2+bx+c=0[/tex]:
[tex](2a-4)x^2-a^2x+a^2=0[/tex]
Therefore,
[tex]a=(2a-4)[/tex][tex]b=-a^2[/tex][tex]c=a^2[/tex]Using quadratic formula:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\implies x=\dfrac{a^2\pm\sqrt{(-a^2)^2-4(2a-4)(a^2)} }{2(2a-4)}[/tex]
[tex]\implies x=\dfrac{a^2\pm\sqrt{a^4-8a^3+16a^2} }{4a-8}[/tex]
[tex]\implies x=\dfrac{a^2\pm\sqrt{a^2(a-4)^2} }{4a-8}[/tex]
[tex]\implies x=\dfrac{a^2\pm a(a-4)}{4a-8}[/tex]
[tex]\implies x=\dfrac{a^2\pm (a^2-4a)}{4a-8}[/tex]
[tex]\implies x=\dfrac{2a^2-4a}{4a-8}=\dfrac{2a(a-2)}{4(a-2)}=\dfrac12a \ \ \ (a\neq 2)[/tex]
[tex]\implies x=\dfrac{4a}{4a-8}=\dfrac{a}{a-2} \ \ \ \ (a\neq 2)[/tex]
The total yearly cost to rent a trumpet is $114. The monthly cost is constant with no initial fee.
A person rents a trumpet for 3 years and 5 months.
Show your work or explain how you would find the total cost, in dollars, for the person to rent the trumpet?
Write an equation that represents the relationship between m, the number of months a trumpet is rented, and t, the total cost to rent the trumpet.
Explain your equation.
Enter your answer and your work or explanation in the space provided.
Step-by-step explanation:
There are 12 months in a year so,
114/12= 9.5$/month
t=9.5m
Since T represents the total cost, we want to express it in terms of months by multiplying m which refers to the number of months by the monthly fee which i have already calculated.
Using this equation we can find out the answer to your previous question.
t=9.5m
but m=3×12+5=41 months (3 years 12 months each)
t=9.5(41)
t=389.5 $
Find the value of xx, yy, and zz in the parallelogram below.
Answer:
Step-by-step explanation:
Opposite sides of a parallelogram are congruent, so:
[tex]8x+3=19 \longrightarrow x=2[/tex]
[tex]27=-y-5 \longrightarrow y=-32[/tex]
What is the first step in solving In(x - 1) = In6 - Inx for x?
Answer:
x=3
Step-by-step explanation:
In(x-1) = In(6) - In(x)
In(x-1) + In(x) = In(6)
In((x-1)x) = In(6)
In(x^2-x) = In(6)
x^2-x=6
x^2-x-6=0
x^2+2x-3x-6=0
x(x+2)-3(x+2)=0
(x-3)(x+2)=0
x=3 because x=-2 need to be cancel out
Trevor folded a corner of a rectangular piece of paper to form a pentagon, as shown below. What is the area of the shaded pentagon? A. 84.5 square inches B. 75.5 square inches c. 39.5 square inches D. 35 square inches.
PLEASE HELP I WILL GIVE BRAINLIEST.
Answer:
B. 75.5 square inches
Step-by-step explanation:
Area (pentagon) = Area (rectangle) - Area (triangle)
= length x width - 1/2 x breadth x height
= 10 x 8 - 1/2 x 3 x 3
= 80 - 4.5
= 75.5 square inches
Solution :-
B. 75.5 square inches
Answer:
B) 75.5 in²
Step-by-step explanation:
Area of rectangle = width × length
⇒ area of rectangle = 8 × 10 = 80 in²
Area of triangle = 1/2 × base × height
⇒ area of triangle = 1/2 × 3 × 3 = 4.5 in²
Area of pentagon = area of rectangle - area of triangle
= 80 - 4.5
= 75.5 in²
What is the equation in slope intercept form of a line that is perpendicular to y = 1/4x - 1 and passing through the point (4, 1)?
1. y = 4x + 17
2. y = 4x - 1
3. y = 4x + 17
4. y = 1/4x + 17
HELP! Should be easy for people who have taken the class.
Answer:
See below
Step-by-step explanation:
Definitions are:
1. Straight line2. Transitive 3. Subtraction 4. ∠1 ≅ ∠3thanks again everyone
Answer:
4x^3
Step-by-step explanation:
GCF is the Greatest Common Factor
12x^6 + 4x^4 + 28x^3
= 4x^3(3x^3 + x + 7)
GCF is 4x^3
if m x and l m = 6 and l = 2 find the value of l when m = 15
Answer:
5
Step-by-step explanation:
6 / 2 = 15 / l
3 = 15 / l
l = 15 / 3
l = 5
50 POINTS PLUS BRANLEST ANSWER!!!!!!!!!!
Complete the table by writing the two missing forms of the number. Make sure your fractions are reduced to lowest terms.
Answer: Look at picture
Answer:
a.) 0,51
b.) 51%
c.) 1/100
d.) 1%
e.) 3/20
f.) 0,15
Step-by-step explanation:
[tex]a.) \: \frac{51}{100} = 51 \div 100 = 0.51[/tex]
[tex]b.) \: \frac{51}{100} = 51\%[/tex]
[tex]c.) \: 0.01 = \frac{1}{100} [/tex]
[tex]d. )\: 0.01 = \frac{1}{100} = 1\%[/tex]
[tex]e.) \: 15\% = \frac{15}{100} = \frac{3}{20} [/tex]
[tex]f.) \: 15\% = \frac{15}{100} = 0.15[/tex]
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Let f(x)=[tex]\footnotesize \rm \lim_{n \to \infty } \left \lgroup \frac{ {n}^n(x + n) \bigg( x + \dfrac{n}{ 2} \bigg) \dots \bigg(x + \dfrac{n}{n} \bigg)}{n!( {x}^{2} + {n}^{2}) \bigg( {x}^{2} + \dfrac{ {n}^2 }{4} \bigg) \dots \bigg( {x}^{2} + \dfrac{ {n}^{2} }{ {n}^{2} } \bigg) } \right \rgroup^{ \dfrac{x}{n} } \\ [/tex] , for all x > 0. Then
[tex]\rm(A) \: f \bigg( \dfrac{1}{2} \bigg ) \geq f(1)[/tex]
[tex]\rm(B) \: f \bigg ( \dfrac{1}{3} \bigg) \leq f \bigg ( \dfrac{2}{3} \bigg)[/tex]
[tex]\rm(C) \: f'(2) \leq0[/tex]
[tex] \rm(D) \: \frac{f'(3)}{f(3)} \geq \frac{f'(2)}{f(2)} \\ [/tex]
Use the old exp-log trick and properties of the logarithm to rewrite the limit as
[tex]\displaystyle \lim_{n\to\infty} \left(\frac{n^n \left(x+\frac n1\right) \left(x+\frac n2\right) \cdots \left(x+\frac nn\right)}{n! \left(x^2+\left(\frac n1\right)^2\right) \left(x^2+\left(\frac n2\right)^2\right) \cdots \left(x^2+\left(\frac nn\right)^2\right)}\right)^{\frac xn}[/tex]
[tex]\displaystyle = \exp\left[\lim_{n\to\infty} \frac xn \ln \left(\frac{n^n \left(x+\frac n1\right) \left(x+\frac n2\right) \cdots \left(x+\frac nn\right)}{n! \left(x^2+\left(\frac n1\right)^2\right) \left(x^2+\left(\frac n2\right)^2\right) \cdots \left(x^2+\left(\frac nn\right)^2\right)}\right)\right][/tex]
[tex]\displaystyle = \exp\left[x \lim_{n\to\infty}\frac1n\ln\left(\frac{n^n}{n!}\right) + \frac1n \sum_{k=1}^n \ln\left(x+\frac nk\right) - \frac1n \sum_{k=1}^n \ln\left(x^2+\left(\frac nk\right)^2\right)\right][/tex]
[tex]\displaystyle = \exp\left[x \lim_{n\to\infty}\frac1n\ln\left(\frac{n^n}{n!}\right) + \frac1n \sum_{k=1}^n \ln\left(x+\frac1{k/n}\right) - \frac1n \sum_{k=1}^n \ln\left(x^2+\frac1{\left(k/n\right)^2}\right)\right][/tex]
The first limit converges to 0, since n! asymptotically behaves like nⁿ, so ln(nⁿ/n!) → ln(1) = 0.
The two remaining sums converge to definite integrals:
[tex]\displaystyle \lim_{n\to\infty} \frac1n \sum_{k=1}^n \ln\left(x + \frac1{\frac kn}\right) = \int_0^1 \ln\left(x + \frac1y\right) \, dy = \frac{(x+1) \ln(x+1)}x[/tex]
[tex]\displaystyle \lim_{n\to\infty} \frac1n \sum_{k=1}^n \ln\left(x^2 + \left(\frac1{\frac kn}\right)^2\right) = \int_0^1 \ln\left(x^2 + \frac1{y^2}\right) \, dy = \frac{2\tan^{-1}(\sqrt x)}{\sqrt x} + \ln(1+x)[/tex]
It follows that
[tex]f(x) = \exp\left[x\left(0 + \dfrac{(x+1)\ln(x+1)}x - \dfrac{2\tan^{-1}(\sqrt x)}{\sqrt x} - \ln(x+1)\right)\right][/tex]
[tex]f(x) = \exp\left[\ln(x+1) - 2\sqrt x \tan^{-1}(\sqrt x)\right][/tex]
[tex]f(x) = (x+1) e^{-2\sqrt x \tan^{-1}(\sqrt x)}[/tex]
By computing f'(x) and f''(x), it's easy to show that f'(x) ≤ 0 and f''(x) ≥ 0 for all x > 0. So f(x) is decreasing and f'(x) is increasing, and
• (A) f(1/2) ≥ f(1) is true
• (B) f(1/3) ≤ f(2/3) is false
• (C) f'(2) ≤ 0 is true
• (D) f'(3)/f(3) ≥ f'(2)/f(2) ⟺ f'(3)/f'(2) ≥ f(3)/f(2) ⟺ (something larger than 1) ≥ (something smaller than 1) is true
This trapezoid represents the base of a right prism that has a surface area of 1280 square feet. The sum of the lengths of the legs of the trapezoid is 52 feet. What is the height of the prism? Enter your answer in the box.
PLEASE HELP I WILL GIV BRAINLY. 50 POINTS.
Answer:
6
Step-by-step explanation:
i took the test
The height of the prism is 49.2 feet
How to determine the height?The given parameters are:
Area = 1280 square feetThe sum of the length legs = 52 feetThe area of the trapezoid is:
Area = 0.5 * (Sum of opposite sides) * Height
So, we have:
1280 = 0.5 * 52 * Height
This gives
1280 = 26 * Height
Divide both sides by 26
Height = 49.2
Hence, the height of the prism is 49.2 feet
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Blue priced $25.00. How much would they cost if they were 60% off?
Answer:
10
Step-by-step explanation:
25 times .60 then take that answer and subtract it from 25 or half of 25 which it 12.5 then take off another 10%
Jennifer has a total of $50 to spend on a new outfit. She bought a sweater for $20. Which shows the part of her total Jennifer spent on the sweater?
A. 1/2
B. 0.4
C. 30%
D. 2/10
Answer: B 0.4
Step-by-step explanation:
50-20=30
0.4 is 40%
40% of 50 is 20
Help me pleasse i need help asap whoever answers it first get brainliest
What is the sum of all positive 1 digit integers that 4221462 is divisible by?
9514 1404 393
Answer:
19
Step-by-step explanation:
The prime factorization of 4221462 is ...
4221462 = 2·3·7·100511
so, the 1-digit divisors are ...
1, 2, 3, 6, 7
The total of these numbers is 19.
Write the ratio in the simplest form 25 to 45
Answer: 5/9 is the simplified fraction for 25/45 by using the GCD or HCF method. Thus, 5/9 is the simplified fraction for 25/45 by using the prime factorization method.
How far from the door must a ramp begin in order to rise 5 ft with an 11-degree angle of elevation? Round off your answer to the nearest hundredth.
PS. Please put a drawing/illustration. Thank you!
The door of the ramp must begin at a distance of 25.72ft in order to raise the ramp by 5ft.
Data;
height (opposite) = 5ftangle = 11°distance (adjacent) =xTrigonometric RatioTo solve this problem, this is a right angle triangle and we can use trigonometric ratio SOHCAHTOA here.
Since we have the value of angle and opposite and solving only for adjacent, we can use tangent of the angle.
[tex]tan \theta = \frac{opposite}{adjacent} \\[/tex]
Let's substitute the values into the formula above and solve
[tex]tan 11 = \frac{5}{x} \\x = \frac{5}{tan 11} \\x = 25.72ft[/tex]
The door of the ramp must begin at a distance of 25.72ft in order to raise the ramp by 5ft.
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PLEASE HELPPP!:( i’ll mark brainlest!
Which angles are adjacent to each other?
Answer:
Angles 7 and 8
Step-by-step explanation:
They are next to each other, and share a common side.
P = 0.5e - 5 to determine P
Answer:
Let's solve your equation step-by-step.
p=(0.5)(2.718282)−5
Step 1: Simplify both sides of the equation.
p=(0.5)(2.718282)−5
p=1.359141+−5
p=(1.359141+−5)(Combine Like Terms)
p=−3.640859
p=−3.640859
Answer:
p=−3.640859
Step-by-step explanation:
Please help! Will award BRAINLIEST if you complete it correctly!
Jen was making cake pops for the bake sale. After 3 hours, she had completed half of the work. She called Maryna for help and together they finished everything in half an hour. How long would it take Maryna to finish the job alone if she replaced Jen after Jen baked for 3 hours?
Answer:
3 hours
Step-by-step explanation:
as jen took 3 hours maryana will take equal amount of time as jen
Well, we already know that it took Jen, 3 hours, by herself to complete half the work. Then, together they both completed it in half an hour. Now, you must summarize your given data.
3 hours = Half of the work for Jen
30 Minutes = Jen and Maryna Together To Finish
If the two girls were working at the same pace, it would take them an hour and a half. However, it only took them 30 minutes to complete that. Now, we realize that Maryna works 3x faster than Jen does.
The question is asking, how long would it take her to FINISH the job.
So that means, we must divide 3 by Jen's time.
3 / 3 = 1
So, that means that it would only take Maryna 1 hour to complete the rest of the job.
given the function R(x)= x+5/x-5 find the value of x that make the function greater then or equal to zero. write the solution in interval notation
Answer:
Step-by-step explanation:
Hello,
First of all, let s take x real number different from 5, as we cannot divide by 0
[tex]\dfrac{x+5}{x-5}\geq 0 \\ \\<=> (x+5\geq 0 \ and \ x-5> 0) \ or \ (x+5\leq 0 \ and \ x-5< 0) \\ \\<=> (x\geq -5 \ and \ x> 5) \ or \ (x\leq -5 \ and \ x< 5)\\ \\<=> x> 5 \ or \ x\leq -5[/tex]
So the solution is
[tex]\Large \boxed{\sf \bf ]-\infty;-5]\cup]5;+\infty[}[/tex]
Thanks
Answer:
(−∞,−5]∪(5,∞)
if f(a)=b and g(b)=c are functions then domain and range of fog and gof equals to
Answer:
fog =gofthen it will be equal
Which scale of measurement most reasonably applies to Confidence in Education?
Answer:
I guess how many times out of x they will do something.
for example how many times out of 10 will bob ask out his crush vs Joe
Step-by-step explanation:
There isn't really an easy way to measure this.
The scale of measurement most reasonably applies to Confidence in Education would be the Ordinal scale.
What is the scale of measurement?The scale of measurement deals with how the variables are defined and categorized.
There are 4 types of scales of measurement;
1. Nominal scale
2. Ordinal scale
3. Interval scale
4. Ratio scale
We know that the Ordinale scale is used for variables in ranked order but the difference between them could not be determined.
Hence, The scale of measurement most reasonably applies to Confidence in Education would be the Ordinal scale.
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What is the gradient of the graph shown?
Gradient = Slope.
Use two points on the line to find the slope.
Slope = change in y over change in x
Points: (-4,0) and (0,-4)
Slope = (-4 - 0) / (0 - -4)
Slope = -4/4 = -1
Slope = -1
Slove for x
Show all work
Answer:
[tex]x=20[/tex]
Step-by-step explanation:
[tex]x^2=8(8+42)[/tex]
[tex]x^2=8*50[/tex]
[tex]x=20[/tex]
~
Ethan is packing bags with treats for a party. He wants every bag to have exactly the same treats in it. Ethan had 96 granola bars and 64 lollipops. If he wants to make the most number of bags possible, how many bags can he make?
Answer:
32 Bags.
Step-by-step explanation:
I took a picture bc I don’t feel like typing the question
A baker makes apple tarts and apple pies each day. Each tart, t, requires 1 apple, and each pie, p, requires 8 apples. The baker receives a shipment of 184 apples every day. If the baker makes no more than 40 tarts per day, which system of inequalities can be used to find the possible number of pies and tarts the baker can make?
Answer: t<40
8p+<184
Step-by-step explanation:
The inequalities representing the given condition will be [tex]t\leq40[/tex] and [tex]8p+t\leq184[/tex].
Given information:
A baker makes apple tarts and apple pies each day.
The baker receives a shipment of 184 apples every day.
A tart requires 1 apple and a pie requires 8 apples.
Let t be the number of tarts made each day and p be the number of pies made each day.
The baker makes no more than 40 tarts per day. So, the condition can be written as,
[tex]t\leq40[/tex]
And the condition for each day apple delivery can be written as,
[tex]8p+t\leq184[/tex]
Therefore, the inequalities representing the given condition will be [tex]t\leq40[/tex] and [tex]8p+t\leq184[/tex].
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