A 15 kg box is sliding down an incline of 35 degrees. The incline has a coefficient of friction of 0.25. If the box starts at rest, how fast is it moving after it travels 3 meters?

Answers

Answer 1

The box has 3 forces acting on it:

• its own weight (magnitude w, pointing downward)

• the normal force of the incline on the box (mag. n, pointing upward perpendicular to the incline)

• friction (mag. f, opposing the box's slide down the incline and parallel to the incline)

Decompose each force into components acting parallel or perpendicular to the incline. (Consult the attached free body diagram.) The normal and friction forces are ready to be used, so that just leaves the weight. If we take the direction in which the box is sliding to be the positive parallel direction, then by Newton's second law, we have

• net parallel force:

F = -f + w sin(35°) = m a

• net perpendicular force:

F = n - w cos(35°) = 0

Solve the net perpendicular force equation for the normal force:

n = w cos(35°)

n = (15 kg) (9.8 m/s²) cos(35°)

n ≈ 120 N

Solve for the mag. of friction:

f = µ n

f = 0.25 (120 N)

f ≈ 30 N

Solve the net parallel force equation for the acceleration:

-30 N + (15 kg) (9.8 m/s²) sin(35°) = (15 kg) a

a ≈ (54.3157 N) / (15 kg)

a ≈ 3.6 m/s²

Now solve for the block's speed v given that it starts at rest, with v₀ = 0, and slides down the incline a distance of ∆x = 3 m:

v² - v₀² = 2 ax

v² = 2 (3.6 m/s²) (3 m)

v = √(21.7263 m²/s²)

v ≈ 4.7 m/s

A 15 Kg Box Is Sliding Down An Incline Of 35 Degrees. The Incline Has A Coefficient Of Friction Of 0.25.

Related Questions

A bus accelerates forward. If an apple were on the floor of the bus it would move forward.
A: True
B: False

Answers

Answer:

False

Explanation:

Since it is on the bus, it would not move forward because the outside acceleration cannot be considered.

What kind of waves are light waves and radio waves

Answers

Answer:

Electromagnetic waves

Explanation:

Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
covered by Asha.(a) (Numbering problem)_​

Answers

Distance walked to the west= 15m

" " " " north= 20m

" " " " east = 15m

Total Distance= (15+ 20+ 15) m

= 50m

Asha covered 50m distance in total.

Using the statistical definition of entropy, what is the entropy of a system where W = 4?

A. 1.87 × 10–23 joules/kelvin

B. 1.56 × 10–23 joules/kelvin

C. 1.91 × 10–23 joules/kelvin

D. 2.07 × 10–23 joules/kelvin

Answers

Answer: S = 1.91x10^(-23) J/K

Explanation:

The statistical definition of entropy says that:

S = k*Ln(W)

where:

W is the number of macrostates, in this case W = 4.

k is a constant:

k = 1.38x10^(-23) J/K

then the entropy of this system will be:

S = (1.38x10^(-23) J/K)*ln(4) = 1.91x10^(-23) J/K

Then the correct option is C.

Answer:

C. 1.91 × 10–23 joules/kelvin

can i be marked brainiest, please? Explanation:

A boy throws a stone vertically in the air with an initial speed of 40m/sec.At the instant the stone is thrown,a monkey at the top of a tree h m high falls freely.How long will it take for the stone to hit the monkey if they meet at a point mid way between the ground and the top of tree?

Answers

∞infinaty stones∞

because why not

Which of the following examples of energy transfer CANNOT happen?

A toy car rolling down a hill increases speed and then rolls to a stop.
A bunger jumper jumps from a bridge and goes up higher with each recoil.
A child playing on a swing moves fastest at the bottom of the swing's path.
A rock dropped from the top of a bridge increases in speed until it hits the water.

Answers

i think it’s the second one. sorry if im wrong :/

The energy transfer which cannot be happened is option c , at the bottom of the swing, the kinetic energy gets converted completely into its potential energy thus, it have no speed when it reached the bottom.

What is kinetic energy ?

Kinetic energy of a body is generated by virtue of its motion. Kinetic energy increases as its mass and velocity increases. Potential energy of a body is the energy stored on it when it comes to rest.

When an object is falling freely to the ground its kinetic energy is converting to the potential energy up to the point it reaches the ground. When it touches the ground, the kinetic energy converts back to potential energy.

Therefore, when the child in the swing comes down from a height its speed is increasing and have greater kinetic energy but this is converted to potential energy when it reach the bottom. Hence no speed it have at the bottom.

Find more on kinetic energy:

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A weightlifter takes 0.5s to raise a barbell with 2 free-weights from the ground to a height of 0.9m. If each free-weight has a mass of 30kg and the barbell has a mass of 20kg, calculate how much power the weightlifter produces when lifting the barbell?​

Answers

Answer:

P = 1412.82 [Watt]

Explanation:

First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.

[tex]m=30+30+20\\m= 80 [kg][/tex]

Weight is now defined as the product of mass by gravitational acceleration.

[tex]w=m*g[/tex]

where:

m = mass = 80 [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]w=80*9.81\\w=784.8[N][/tex]

Now using the product of the weight by the distance traveled we can calculate the work.

[tex]W=w*d[/tex]

where:

W = work [J]

w = weight = 784.8 [N]

d = distance = 0.9 [m]

[tex]W=784.8*0.9\\W=706.41[J][/tex]

And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.

[tex]P=W/t\\P=706.41/0.5\\P=1412.82[W][/tex]

In raising an object vertically at a constant speed of 2 m / s 10 watts of power is developed the weight of the object is

Answers

Answer:

5N

Explanation:

Power = Workdone/Time

Since workdone = Force * distance = mgh

Power = mgh/t

Given

Power = 10watts

speed = 2m/s

Power = Weight * velocity

Substitute

10 = Weight * 2

Weight = 10/2

Weight = 5N

Hence the weight of the object is 5N

Which is heavier: 30 kilogram or 300 milligrams?

Answers

Answer:

30 killograms is 85.9803

and 300 milligrams is 0.000661387 pounds

Explanation:

A washing machine is being dragged with a starting force of 380.8 N to the West, but this is reduced by friction. If the mass of the washing machine is 37 kg
and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?
A 10.27 m/s^2 South
B 5 m/s^2 South
C 19.01 m/s^2 South
D 7.6 m/s^2 South

Answers

Answer:

B. [tex]5\,\frac{m}{s^{2}}[/tex] South

Explanation:

The correct statement is:

A washing machine is being dragged with a starting force of 380.8 N to the South, but this is reduced by friction. If the mass of the washing machine is 37 kg  and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?

The net force of the washing machine moving on the horizontal ground is equal to the external force minus the friction force, where the normal force from the ground on the washing machine is equal to its weight. The free body diagram of the washing machine is presented below. The equation of equilibrium associated with the acceleration of the washing machine is:

[tex]\Sigma F = P -\mu_{k}\cdot m \cdot g = m\cdot a[/tex] (1)

Where:

[tex]P[/tex] - External force exerted on the washing machine, measured in newtons.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the washing machine.

If we know that [tex]P = 380.8\,N[/tex], [tex]m = 37\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\mu_{k} = 0.54[/tex], then the net acceleration experienced by the washing machine is:

[tex]a = \frac{P}{m}-\mu_{k}\cdot g[/tex]

[tex]a = \frac{380.8\,N}{37\,kg}-(0.54)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]a = 4.996\,\frac{m}{s^{2}}[/tex]

The correct answer is B.

The law of __________________________ says that people think of similar objects as belonging together.

Answers

Answer:

Explanation:is the law means that the police are the law

I think the answer would be the principle of similarity.. It states that when things appear to be similar to each other that people tend to group the objects together. Also they tend to think of them as the same function. Not totally sure, but I hope this helped.

how to create or build a homemade golf club. is this possible? If so, what suggestion did you find? Do you have an original idea on how to build a homemade golf club? what types of materials and tools would you need? what skills are necessary to construct the club?​

Answers

Answer:

All you need is golfing equipment make a small hole in the ground and have like something to cover the sun off of you and boom you got a golfing spot and a golf club no skills needed. Oh and you need a small flag for your gold hole but then your good and you can have fun

Explanation:

How high can a 40 N force move a load, when 395 J of work is done? (Show work)

Answers

Distance = Work / Force
Distance= 395J/ 40N
Distance= 9.875 meters

A 40 N force would move a load 9.875 m high when 395 J of work is done on the load.

What is work done?

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

The SI  unit of work done by an object is Joules.

IJ is the work done when a force of 1 N displaces an object by 1 m .

Work Done = Force * Displacement

For the given problem Force =40N and work done = 395 J

By using the above formula

Work Done = Force * Displacement

395 j = 40 N × height

height =9.875 m

Thus a 40 N force supported by a work done of 395 J moves the load up to 9.875 m height

Learn more about work done

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A train going 14m/s moves 250 m while accelerating to a stop. What is the train’s deceleration?

Answers

Answer:

-0.056 is the deceleration

As you enter the lab, you find two bottles labeled "concentrated ammonium phosphate." In one paragraph, using your own words, describe the steps you could take to change one of the bottles into a diluted solution, and one of the bottles into a saturated solution.

Answers

Answer:

Butane is a four member carbon chain.

The properties of butane are as follows.

Butane is less denser than water.

In the presence of air, it readily burns to form water vapour and carbon dioxide. The reaction is as follows.

           

It has a boiling point of .

Butane has faint petroleum like odor.

Butane does not react with water.

Butane has weak dispersion force and water has strong hydrogen bonding.  The weak dispersion force is unable to break the hydrogen bonding hence, butane does not dissolve in water.

Thus, we can conclude that the chemical properties butane burns readily in air and does not react with water are true out of the given list of options.

Explanation:

A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the
ground. How long will it take, in seconds, for the ball to hit the ground?

Answers

Answer:

0.73 s

Explanation:

The time taken can be found by using the formula

[tex] t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{3.5}{4.8} \\ = 0.72916...[/tex]

We have the final answer as

0.73 s

Hope this helps you

A machine that uses 200 w of power moves an object a distance of 15 m in 25 sec. Find
the force needed and the work done by this machine,

Answers

Answer:dummy

Explanation:

Dum dum

A hot air balloon holds 7.40 x 107 liters of gas. In order for the hot air balloon to rise into the sky, it must be heated to 120°C. Once the balloon is up in the air, the air needs to be cooled in order for the balloon to land. If the temperature of the balloon is decreased to 40.0°C, what will the new volume of the gas be?

Remember to pay close attention to the units of temperature before beginning your calculations.

Answers

Answer:

2.467×10^7 litres

Explanation:

Using the formula V1/T1 = V2/T2

V1 and V2 are the initial and final volume respectively

T1 and T2 are their respective temperatures

Given

V1 = 7.4×10^7litres

T1 = 120°C

T2 = 40°C

Required

V2

From the formula

V2 = V1T2/T1

V2 = 7.4×10^7(40)/120

V2 = (7.4×10^7)/3

V2 = 2.467×10^7 litres

Hence the new volume of the gas will be 2.467×10^7 litres

Incident ray X passes parallel to the principal axis of a concave lens. Incident ray Y passes parallel to the principal axis of a convex lens.

How do the rays behave differently after passing through each lens?

Ray X continues moving in the same direction, and ray Y refracts and passes through the focal point located behind the lens.
Both rays refract and move as though they passed through the focal point.
Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Both rays continue moving in the same direction.

Answers

Answer:

Explanation:

It would be option C. Ray x appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.

Answer:

c. Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.

Explanation:

pls help me with this

Answers

Answer:

A screw

Explanation:

Answer:
Screw
Explanation :
I hope it helps !

A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?

Answers

Answer:

3,544.375Joules

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;

Kinetic energy = 1/2mv²

m is the mass of the body

v is the velocity

For the ball carrier;

KE = 1/2(75)(6.5)²

KE = 3168.75/2

KE = 1584.375Joules

For the defender;

KE = 1/2(80)(7)²

KE = 3920/2

KE = 1960Joules

The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender

kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules

Cuatro niños jalan de manera separada un mismo carrito de baleros con un mismo desplazamiento, pero uno con un ángulo de 45°, otro con un ángulo de 35°, otro de 20° y el ultimo con un ángulo de 0°, medidos con respecto al eje horizontal. ¿Cuál de los cuatro realiza un mayor trabajo, si la fuerza que se aplica cada uno de ellos es la misma? Selecciona el ángulo:

Answers

Answer:

El niño que aplica una fuerza a un ángulo de 0º realiza el mayor trabajo.

Explanation:

Si consideramos que las fuerzas aplicadas en el carrito de baleros es constante tanto en magnitud como en dirección, el trabajo realizado por cada niño ([tex]W[/tex]), medido en joules, puede definirse mediante la siguiente expresión:

[tex]W =F\cdot x\cdot \cos \alpha[/tex] (1)

Donde:

[tex]F[/tex] - Magnitud de la fuerza aplicada por el niño, medida en newtons.

[tex]x[/tex] - Distancia desplazada por el carrito de baleros, medida en metros.

[tex]\alpha[/tex] - Dirección de la fuerza aplicada, medida en grados sexagesimales.

De (1) tenemos que la fuerza efectiva que empuja el carro es:

[tex]F_{e} = F\cdot \cos \alpha[/tex]

La fuerza aplicada por cada niño es despejada:

[tex]F = \frac{F_{e}}{\cos \alpha}[/tex]

A mayor ángulo, tenemos un menor valor del coseno y, por ende, mayor valor de la fuerza aplicada. Ahora, el mayor trabajo realizado se realiza con el menor ángulo posible y bajo esta consideración, el niño que aplica una fuerza a un ángulo de 0º realiza el mayor trabajo.

A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?


This needs to be done in 3 mins

Answers

Answer:

Okay I might be wrong and sorry if i am either its 12 or 0.402

Explanation:

* I recommend the second one cause its more logical

Be aware I might be wrong

Which of the following actions will induce an emf in a conductor?
a. Move a magnet near the conductor.
b. Move the conductor near a magnet.
c. Rotate the conductor in a magnetic field.
d. Change the magnetic field strength.
e. all of the above

Answers

Answer:

b . Move the conductor near a magnet

Answer:

(e) all the above....

Explanation:

That's all

Cause you know.......

A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the spring

Answers

The forces constant (spring constant) of the spring will be 41.09 N/m.

What is spring force?

The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;

F = kx

The given data in the problem is;

F is the spring force = 30 N

K is the spring constant= ?

x is the displacement of spring = 0.73 m

The spring constant is;

K =F/x

K=30/0.73

K=41.09 N/m

Hence the force constant (spring constant) of the spring will be 41.09 N/m.

To learn more about the spring force refer to the link;

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A man speeding at 40m/s decides to outrun the cops and starts to
accelerate at a rate of 2.5m/s2 for 12 seconds. What is the criminal's new
speed?

Answers

Answer:

70 m/s.

Explanation:

Given that,

Initial speed, u = 40 m/s

Acceleration = 2.5 m/s²

Time, t = 12 s

We need to find criminal's new  speed. Let it is v. Using equation of motion to find it as follows :

v = u +at

Substitute all the values

v = 40 + 2.5(12)

v = 70 m/s

So, the new speed is 70 m/s.

I dropped the ball from the roof of a building the speed when I hit the ground is 52 m/s how tall is the building

Answers

Answer:

Height of building = 135.2 m

URGENTE : Un cuerpo de 8m³ flota en el agua. Si el volumen sumergido es de 5m³. Determina el modulo de la fuerza de empuje (en kn) que presenta

Answers

Answer:

La magnitud del empuje hacia arriba o fuerza hacia arriba que actúa sobre el cuerpo es 48,853 kN

Explanation:

Los parámetros dados son;

El volumen del cuerpo = 8 m.³

El volumen del cuerpo sumergido = 5 m³

Por el principio de Arquímedes, que establece que el empuje hacia arriba, [tex]F_b[/tex], actuar sobre un cuerpo en un fluido es igual al peso del fluido desplazado por el cuerpo

Matemáticamente, tenemos;

[tex]F_b[/tex] = ρ × g × V

Dónde;

ρ = La densidad del fluido = La densidad del agua = 997 kg / m³

g = La aceleración debida a la gravedad = 9,8 m / s²

V = El volumen del fluido desplazado = El volumen del cuerpo sumergido = 5 m.³

∴ [tex]F_b[/tex] = 997 kg / m³ × 9,8 m / s² × 5 m³ = 48,853 N = 48,853 kN (hacia arriba)

La magnitud del empuje hacia arriba o la fuerza hacia arriba que actúa sobre el cuerpo = 48,853 kN.

Which of the following is an example of light energy being changed to chemical energy?

Group of answer choices
A flashlight with rechargeable batteries
A solar panel that charges a battery
Food that is eaten to provide mechanical energy

Answers

Answer:

A solar panel

Explanation:

I really dont know physics

Answers

Answer:

3

Explanation:

I had this question before

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