Rewrite 48 + 60 using the distributive property. but in the equation form​

Answer:(1,2)

Step-by-step explanation: The signs may not be right(positive, negative) Sorry it’s been a long time since I did this

= (7+20+9+35+12+15+7+10+20+25) : 10

with 10 = number of values

average distance = 160 : 10 = 16

Answer:

5, 30, and 70

Step-by-step explanation:

Multiply by  number of quarters by 5 to get the number of nickels.

Answer:

-2x^2 + 4x + 11

Step-by-step explanation:

whats 2x2 ? do you mean 2x^2 ? if so then...

8x + 4 - 2x^2 - 4x + 7

4x + 11 - 2x^2

-2x^2 + 4x + 11

Answer:

this is the answers 2x^2+4x+11

Step-by-step explanation:

The 53rd ball will be blue. I don't really know how to explain but I'll try.

So there are black, white and blue balls. If you look closer you'll see that the words 'black,white,blue,black, blue were repeated twice. So let's say that the first 5 letters are a set. To get the 50th color, all you have to do is 5 × 10 which is 50 and the 50th term is blue. Just add black(51st), white(52nd) and you'll get the 53rd color to be Blue.

I don't know how to do <2>.

Hope this helps!

Please mark me brainliest :)

Answer:

its true, depending on the times table.

Answer:

True

Step-by-step explanation:

This statement is always true.

[tex]ratio-of-red-blocks-to-yellow-blocks = \frac{number-of-red-blocks}{number-of-yellow-blocks} =\frac{12}{8} =\frac{3}{2}[/tex]

Answer: [tex]\frac{3}{2}[/tex] or   3 : 2

Hope it helps!

Answer:

3 : 2

Step-by-step explanation:

Answer:

31 degrees

Step-by-step explanation:

A line has angle of 180 degrees.

So

[tex](2z+17)+(4z-23)=180\\6z-6=180\\6z=186\\z=31[/tex]

Answer:

[tex]y=11x-3[/tex]

Step-by-step explanation:

Given ordered pairs:

(1, 8)  (2, 19)  (3, 30)  (4, 41)

As the y is directly proportional to x (y values increase +11 for every +1 increase for the x-values) then the equation will be linear.

Point-slope form of a linear equation:  [tex]y-y_1=m(x-x_1)[/tex]

(where [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is a point on the line)

[tex]\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

Let:

[tex]\implies \textsf{slope }m=\dfrac{19-8}{2-1}=11[/tex]

Using point-slope equation with m = 11 and point (1, 8):

      [tex]y-y_1=m(x-x_1)[/tex]

[tex]\implies y-8=11(x-1)[/tex]

[tex]\implies y=11x-3[/tex]

Using a t-distribution calculator, it is found that the critical value of t* for a 98% confidence interval with 25 observations is given by:

B. t* = 2.492

It is found using a calculator, with two inputs, which are given by:

In this problem, we have a confidence level of 98% and 25 - 1 = 24 df, hence the critical value is of t* = 2.492, which means that option B is correct.

More can be learned about the t-distribution at https://brainly.com/question/16162795

#SPJ2

Answer: 4.00, 9.00, 11.00, 4.00

Step-by-step explanation:

When we round, we round from the digit one smaller than the one we're rounding to. In this case, since we're rounding to the dollar, we round from the 10th place. To round, we need to know whether the number we're rounding from is smaller than, equal to, or larger than 5. If the number is smaller than 5, we round down. Larger, and we round up. If the number is equal to 5, we also round up.

[tex]\\ \rm\longmapsto 1/2(10x+20y+10z)[/tex]

[tex]\\ \rm\longmapsto 10x/2+20y/2+10z/2[/tex]

[tex]\\ \rm\longmapsto 5x+10y+5z[/tex]

Answer:

5x+10y+5z

Step-by-step explanation: it was on khan academy and it was right  

Answer:

The 12 portions weigh a total of 12*0.7 = 8.4 lbs

So, the almonds weigh 8.4 - 3.6 = 4.8 lbs

Answer:

Step-by-step explanation:

Let raisins weight be x

Then we get equation

Solving for x

Option B is correct one

Answer:

Value of x = 8

(3x - 7) = (5x - 23)

-2x = -16

x = 8

Value of m 8 = 17 degrees

5(8) - 23

40 - 23 = 17

Answer:

[tex]\boxed {x_{1} = 3}[/tex]

[tex]\boxed {x_{2} = -4}[/tex]

Step-by-step explanation:

Solve the following equation:

[tex]\left[\begin{array}{ccc}3&2\\5&5\\\end{array}\right] \left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right] + \left[\begin{array}{ccc}1\\2\\\end{array}\right] = \left[\begin{array}{ccc}2\\-3\\\end{array}\right][/tex]

-In order to solve a pair of equations by using substitution, you first need to solve one of the equations for one of variables and then you would substitute the result for that variable in the other equation:

-First equation:

[tex]3x_{1} + 2x_{2} + 1 = 2[/tex]

-Second equation:

[tex]5x_{1} + 5x_{2} + 2 = -3[/tex]

-Choose one of the two following equations, which I choose the first one, then you solve for [tex]x_{1}[/tex] by isolating

[tex]3x_{1} + 2x_{2} + 1 = 2[/tex]

-Subtract [tex]1[/tex] to both sides:

[tex]3x_{1} + 2x_{2} + 1 - 1 = 2 - 1[/tex]

[tex]3x_{1} + 2x_{2} = 1[/tex]

-Subtract [tex]2x_{2}[/tex] to both sides:

[tex]3x_{1} + 2x_{2} - 2x_{2} = -2x_{2} + 1[/tex]

[tex]3x_{1} = -2x_{2} + 1[/tex]

-Divide both sides by [tex]3[/tex]:

[tex]3x_{1} = -2x_{2} + 1[/tex]

[tex]x_{1} = \frac{1}{3} (-2x_{2} + 1)[/tex]

-Multiply [tex]-2x_{2} + 1[/tex] by [tex]\frac{1}{3}[/tex]:

[tex]x_{1} = \frac{1}{3} (-2x_{2} + 1)[/tex]

[tex]x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}[/tex]

-Substitute [tex]-\frac{2x_{2} + 1}{3}[/tex] for [tex]x_{1}[/tex] in the second equation, which is [tex]5x_{1} + 5x_{2} + 2 = -3[/tex]:

[tex]5x_{1} + 5x_{2} + 2 = -3[/tex]

[tex]5(-\frac{2}{3}x_{2} + \frac{1}{3}) + 5x_{2} + 2 = -3[/tex]

Multiply [tex]-\frac{2x_{2} + 1}{3}[/tex] by [tex]5[/tex]:

[tex]5(-\frac{2}{3}x_{2} + \frac{1}{3}) + 5x_{2} + 2 = -3[/tex]

[tex]-\frac{10}{3}x_{2} + \frac{5}{3} + 5x_{2} + 2 = -3[/tex]

-Combine like terms:

[tex]-\frac{10}{3}x_{2} + \frac{5}{3} + 5x_{2} + 2 = -3[/tex]

[tex]\frac{5}{3}x_{2} + \frac{11}{3} = -3[/tex]

-Subtract [tex]\frac{11}{3}[/tex] to both sides:

[tex]\frac{5}{3}x_{2} + \frac{11}{3} - \frac{11}{3} = -3 - \frac{11}{3}[/tex]

[tex]\frac{5}{3}x_{2} = -\frac{20}{3}[/tex]

-Multiply both sides by [tex]\frac{5}{3}[/tex]:

[tex]\frac{\frac{5}{3}x_{2}}{\frac{5}{3}} = \frac{-\frac{20}{3}}{\frac{5}{3}}[/tex]

[tex]\boxed {x_{2} = -4}[/tex]

-After you have the value of [tex]x_2[/tex], substitute for [tex]x_{2}[/tex] onto this equation, which is [tex]x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}[/tex]:

[tex]x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}[/tex]

[tex]x_{1} = -\frac{2}{3}(-4) + \frac{1}{3}[/tex]

-Multiply [tex]-\frac{2}{3}[/tex] and [tex]-4[/tex]:

[tex]x_{1} = -\frac{2}{3}(-4) + \frac{1}{3}[/tex]

[tex]x_{1} = \frac{8 + 1}{3}[/tex]

-Since both [tex]\frac{1}{3}[/tex] and [tex]\frac{8}{3}[/tex] have the same denominator, then add the numerators together. Also, after you have added both numerators together, reduce the fraction to the lowest term:

[tex]x_{1} = \frac{8 + 1}{3}[/tex]

[tex]x_{1} = \frac{9}{3}[/tex]

[tex]\boxed {x_{1} = 3}[/tex]

Answer:$51.5

Step-by-step explanation:

Answer:

here

Step-by-step explanation:

For the first one shade 38 squares

For the second one shade 65 of the squares

#1 is 38%

#2 is 65%

Answer:shade 19 out of 50 bloxks

Step-by-step explanation:

it shows on page

Answer:

His March Earnings is $20000

Step-by-step explanation:

Given

[tex]Salary = \$1500[/tex]

[tex]Commission = 5\%\ of\ sales[/tex]

[tex]March\ Earnings = \$2500[/tex]

Required

Determine the monthly sales

Represent the monthly sales with x

The march earnings can be determined using:

[tex]March\ Earnings = Salary + Commission[/tex]

[tex]March\ Earnings = Salary + 5\%\ of\ x[/tex]

Substitute values of March Earnings and Salary

[tex]2500 = 1500 + 5\% * x[/tex]

[tex]2500 = 1500 + 0.05 * x[/tex]

[tex]2500 = 1500 + 0.05x[/tex]

Solve for 0.05x

[tex]0.05x = 2500 - 1500[/tex]

[tex]0.05x = 1000[/tex]

Solve for x

[tex]x = 1000/0.05[/tex]

[tex]x = 20000[/tex]

Hence:

His March Earnings is $20000

Answer:

the complement of 37 degrees is 53 degrees.

Step-by-step explanation:

90-37=53

Check the picture below.

[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=26\\ \theta =\stackrel{180+34}{214} \end{cases}\implies \begin{array}{llll} A=\cfrac{\pi (214)(26)^2}{360}\implies A=\cfrac{18083\pi }{45} \\\\\\ A \approx 1262.43 \end{array}[/tex]

Hey there!

[tex]⇢ \: A = 2wl + 2lh + 2hw[/tex]

Substitute

[tex]⇢ \: = 2(8)(17) + 2(17)(12) + 2(12)(8)[/tex]

[tex]⇒872[/tex]

Surface area = 872 square inches

Answer:

x^2 + 8 = 64 is not a linear function

Step-by-step explanation:

using the process of elimination and a graphing calculator, you can see that the rest of the functions give you a linear function. therefore, the answer is x^2 + 8 = 64 is not a linear function!! i hope this helps you!! <3

The [tex]x^2 + 8 = 64[/tex] is not the liner function.

The following information regarding the linear function is:

Therefore we can conclude that the [tex]x^2 + 8 = 64[/tex] is not the liner function.

Learn more about the linear function here: brainly.com/question/20286983

Answer:

the answer is b b is the answer I did this before

Answer:

Colombian coffee bought = 0.5 lbs

French roast coffee beans bought = 0.5 lbs

Step-by-step explanation:

Let Colombian coffee bought = [tex]x[/tex] lbs

Total weight of mixture bought = 1 lbs

Therefore, French roast coffee beans bought = (1 - [tex]x[/tex]) lbs

Price of 1 lb Colombian coffee = $4.25

Price of [tex]x[/tex] lbs of Colombian coffee = $[tex]4.25x[/tex]

Price of 1 lb French roast coffee beans = $3.75

Price of (1 - [tex]x[/tex]) lbs French roast coffee beans = $3.75(1 - [tex]x[/tex])

It is given that total money spent is $4.

As per given statement:

[tex]4.25x+3.75(1-x)=4\\\Rightarrow 0.50x=0.25\\\Rightarrow x=\bold{0.5\ lbs}[/tex]

Colombian coffee bought = 0.5 lbs

French roast coffee beans bought = 0.5 lbs

Check the picture below.

[tex]~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&5\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&9\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-4.9t^2+5t+9\implies \stackrel{h(t)}{0}=-4.9t^2+5t+9 \implies 4.9t^2-5t-9=0[/tex]

since we don't get any neat integer values from it hmmm let's plug that in the quadratic formula to see what we get as h(t) = 0.

[tex]~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{4.9}t^2\stackrel{\stackrel{b}{\downarrow }}{-5}t\stackrel{\stackrel{c}{\downarrow }}{-9}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ t= \cfrac{ - (-5) \pm \sqrt { (-5)^2 -4(4.9)(-9)}}{2(4.9)}\implies t=\cfrac{5\pm\sqrt{25+176.4}}{9.8} \\\\\\ t=\cfrac{5\pm \sqrt{201.4}}{9.8}\implies t\approx \begin{cases} 1.96~~\checkmark\\ -0.94 \end{cases}[/tex]

notice, we do not use the negative value for "t", since the seconds cannot be less than 0.

Answer:

-2.2y-1.8

Step-byStep-byStep-byStep-byStep-byStep-byStep-byStep-byStep-by

1.2y-3.4y=-2.2y

4.5-6.3=-1.8

ssoso:-2.2y-1.8

2x - 5 + 3x = 35

simplify

5x - 5 = 35

add 5 to both sides

5x - 5 + 5 = 35 + 5

simplify

5x = 40

divide both sides by 5

5x/5 = 40/5

simplify

x = 8