Answer:
1-state what the lab is about, that is, what scientific concept (theory, principle, procedure, etc.) you are supposed to be learning about by doing the lab. You should do this briefly, in a sentence or two. If you are having trouble writing the opening sentence of the report, you can try something like: "This laboratory experiment focuses on X…"; "This lab is designed to help students learn about, observe, or investigate, X…." Or begin with a definition of the scientific concept: "X is a theory that…."
2-give the necessary background for the scientific concept by telling what you know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab). In relatively simple labs you can do this in a paragraph following the initial statement of the learning context. But in more complex labs, the background may require more paragraphs.
Explanation:
Calculate the aceleration of a vehicle of 100 kg when applicates 400 N
Answer:
For this we applicate 2nd law of Newton:
F = ma
Replacing:
400 N = 100 kg * a
a = 400 N / 100 kg
a = 4 m/s²
The aceleration is 4 meters per second squared.
Answer:
....................
Explanation:
---------------------
A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface
Answer:
[tex]x =\frac{-R}{2}[/tex]
Explanation:
From the question we are told that mass
Thin layer radius [tex]= 2R[/tex]
Generally the expression for ths solution is given as
Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2
the center of mass will not move at initial state
Considering the center of mass of both bodies
[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]
[tex]x =\frac{-R}{2}[/tex]
Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]
The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
Given-
Radius of the ball is [tex]R[/tex].
the mass of the ball is [tex]m[/tex].
The mass of the thin shell is [tex]m[/tex].
The radius of the thin shell is [tex]2 R[/tex].
For the two bodies with mass [tex]m[/tex], the center of mass can be given as,
[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]
In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,
[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]
[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]
[tex]x_{cm} =x[/tex]
Distance for center of mass can also be given as,
[tex]x_{cm} =m\times o[/tex]
[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]
[tex]x_{cm} =\dfrac{-R}{2}[/tex]
Comparing both the values of the distance of center of mass we get,
[tex]x =\dfrac{-R}{2}[/tex]
Hence, The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
For more about the center of mass follow the link below,
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in a hydraulic press,a force of 200N is applied to a master piston of area 25cm² if the press is designed to produce a force of 5000N,determine the radius of the slave piston
Answer:
The radius of the slave piston = 14.10 cm
Explanation:
The formula to apply here is that for pressure where ;
Pressure = Force / Area
F₁ /A₁ =F₂/A₂ where ; F₁=200 N , A₁= 25 cm² , F₂ =5000 N ,A₂ =?
Apply values in the equation as ;
200/ 25 = 5000/ A₂
A₂ = 625 cm²
Formula for area is ;
A = πr²
625 = π * r²
625/π = r²
√625/π =r
14.10 cm = r
What is 2 + 2 i have been stuff on this for weeks
Answer:
4..... the answer is 4
Explanation:
the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equator option d increase from pole to equator which is the answer
Answer:
D. Increases from pole to equator
Explanation:
I majored in Science
An object with a mass of 10 kg is rolled down a frictionless ramp from a height of 3 meters. If a factory worker at the bottom of the ramp slows the object until it comes to a stop, how much work must the factory worker have done
Answer:
The amount of work the factory worker must to stop the rolling ramp is 294 joules
Explanation:
The object rolling down the frictionless ramp has the following parameters;
The mass of the object = 10 kg
The height from which the object is rolled = 3 meters
The work done by the factory worker to stop the rolling ramp = The initial potential energy, P.E., of the ramp
Where;
The potential energy P.E. = m × g × h
m = The mass of the ramp = 10 kg
g = The acceleration due to gravity = 9.8 m/s²
h = The height from which the object rolls down = 3 m
Therefore, we have;
P.E. = 10 kg × 9.8 m/s² × 3 m = 294 Joules
The work done by the factory worker to stop the rolling ramp = P.E. = 294 joules
How much energy is released by the conversion of 4.2 x 10 kg of mass to energy? How much mass must be converted to energy to produce 1.00 J of energy?
Explanation:
4.2×+10=42kg
energy/work =
mxacceleration
420joulse
not sure
=42 mass I guess
Which of the following best describes the difference between type a and type b
What is the distance moved by a horse galloping at 75 km/h in 10.0 s?
750 m
208 m
125 m
7.5 m
125Answer:
Explanation:uruhavdfh
If you have 100 kg of each of these substances, which would require the most energy to increase its temperature by 25 Kelvin?
A. Iron
B. Carbon
C. Rubber
D. Air
Answer:
iron
Explanation:
An electrically charged atom is called an
Answer:
It's called an ion. Excuse me if I'm wrong.
Explanation:
help me please I will thank you
Answer:
DNA= 2 strands, sugar is deoxyribose, and the Nitrogen Bases are adenine, uracil, cytosine, and thymine.
RNA= 1 strands, sugar is ribose, and the Nitrogen Nases are adenine, uracil, cytosine, and guanine.
Hope this helps :)
Explanation:
What is the height of a shelf that has 15 kg objects with 450 J of gravitational potential energy
A ball is thrown up into the air. Ignore air resistance. When it is rising and reaches half of its maximum height,the net force acting on it is
Answer:
The net and only force acting on the ball thrown up into the air at half of its maximum height is the weight of the ball
Explanation:
When the ball is rising in the air, the force, F, acting on it is given by the product of the mass, m × acceleration, a
The acceleration of a body thrown in the air = Gravitational acceleration = g = Constant
Therefore;
The force acting on the body thrown in the air F = Constant = m × g (downwards)
The force acting on the ball thrown up into the air at half of its maximum height = The mass of the ball × The acceleration due to gravity = The weight of the ball.
similarities between the flow of water and an electric circuit.
They both flow in currents. Water has a pump that works like a battery and pipes that work like a circuit.
Relative density of mercury is 13600 what does it mean
Answer:
relative density is the density divided by some reference density.
for liquids like mercury the reference density is most likely water, so
relative density = density mercury / density of water = 13600
What is a force that opposes motion between two surfaces that are in contact?
Answer:
Friction is a force that opposes motion.
A spiral spring of natural length 20.00cm has a scale
pan hanging on its lower end while the other end is
fixed firmly to a support.When an object of mass 50g
is placed in the pan, the length of the spring becomes
22.00 cm.When another object of mass 70g is placed in
The pan, the length becomes 22.25cm Calculate the
mass of the scale pan. (g = 10m/s]
The mass of the scale pan : 0.11 kg
Further explanationGiven
A spiral spring's length = 20 cm
mass 50 g ⇒ the length = 22 cm
mass 70 g ⇒ the length = 22.25 cm
Required
the mass of the scale pan
Solution
Hooke's Law :
[tex]\tt F=k.\Delta x[/tex]
The spring constant (k) :
[tex]\tt k=\dfrac{\Delta F}{\Delta x}=\dfrac{g.(70-50)}{22.25-22}=\dfrac{g.20}{0.25}=g.80~g/cm=10~m/s^2\times 8~kg/m=80~N/m[/tex]
mass of the scale pan=m(for 50 g mass) :
[tex]\tt (m+0.05).g=80\times (0.22-0.20)\\\\m=0.11~kg[/tex]
True or false: " The rotation of the earth and revolution of the earth mean essentially the same thing."
Answer:
FALSE
Explanation:
Rotation is spinning on its axis
Revolution is spinning around the sun
If you launch an object in space, it
will continue to move forward
until an external force stops it.
This is a characteristic of which
law?
Answer:
I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.
newtons _ law of motion states that every action has an equal and opposite reaction
Answer:
3rd
Explanation:
3rd
Heat _________________ throughout our environment ________________ of the ________________.
is spread
....!
!
please complete the question
Which of the following does not illustrate a complete circuit?
Answer:
I think A
Explanation:
because it dosn't have enough tools
Which statement best explains why Earth’s outer core is in liquid form? The iron-nickel alloy melts due to hot temperatures. The outer core has a tarry consistency. This region is less dense when compared to the mantle. This region is under extreme pressure from the weight of other layers.
Answer:
I took the science quiz and Its A
Explanation:
HOPE THIS HELPS!
The iron-nickel alloy melts due to hot temperatures. This statement best explains why Earth’s outer core is in liquid form
Where is the outer core?The Earth's outer core is the second innermost layer, located between the inner core and the mantle. It contains mostly iron and nickel, which- due to lower pressure than existing at the inner core- are in the liquid form. The outer core, about 2,200 kilometers (1,367 miles) thick, is mostly composed of liquid iron and nickel because of the high temperature. However, the intense pressure, which increases towards the inner core, dramatically changes the melting point of the nickel–iron, making it solid. The iron and nickel alloy of the outer core is very hot, between 4,500° and 5,500° Celsius (8,132° and 9,932° Fahrenheit).
The outer core is a liquid alloy of mainly iron and nickel. The reason why the core is metal is that the heavy metals sank to the center while the Earth was cooling. The mantle which lies above the core is made of molten rock
correct option is a) The iron-nickel alloy melts due to hot temperatures.
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A golf ball is sitting on a tee. The ball is struck with a golf club and flies
through the air. How does the force on the club compare with the force on the
ball when momentum is transferred between the club and ball?
Answer:
c i kn now it is
Explanation:
Lina holownicza wytrzymuje działanie siły o wartości co najwyżej 1400 N (większa siła powoduje rozerwanie liny). Oblicz maksymalne przyspieszenie, jakie może osiągnąć samochód o masie 2000 kg holowany na takiej linie po poziomej jezdni, jeżeli wiadomo, że łączna wartość sił oporu ruchu tego samochodu w czasie holowania wynosi 400 N.
Odpowiedź:
0,5 m / s²
Wyjaśnienie:
Jeśli się uwzględni:
Masa samochodu (m) = 2000 kg
Wartość siły oporu podczas holowania = 400N
Lina o maksymalnej sile może wytrzymać = 1400N
Maksymalne przyspieszenie = siła / masa samochodu
Siła = maksymalna siła - siła oporu
Siła = 1400 N - 400 N = 1000 N.
Stąd maksymalne przyspieszenie;
1000 N / 2000 kg
= 0,5 m / s²
What is the average depth of the oceanic crust? What percentage of our planet does it cover?
Answer: Oceanic crust, the outermost layer of Earth's lithosphere that is found under ... Sort out the facts and see how deep your knowledge goes in this quiz of the world's oceans. ... They commonly are thin (only about 10 cm [4 inches] thick) and cover a ... km (85 square miles) of seafloor to an average depth of 70 metres (230 feet).
Explanation:
Which of the following best describes why understanding a watershed and its boundaries is important in designing housing developments along a river?
A
The water contained in a watershed is more likely to become polluted if the soil has high permeability, so it is important to locate all point sources to reduce contamination
B
Watersheds provide habitats for hundreds of marine species, so it is important to protect their feeding and nesting sites when designing housing for humans.
c
Watersheds provide space for cultivating land to produce food and other products, so it is important to avoid locating a housing development on the most fertile land.
D
Surface water and stormwater runoff will drain downstream within the watershed boundaries, so it is important to understand the flow of water through the watershed
Answer:
d
Explanation:
The watersheds are the major hydrological structures that supports the downstream of surface water and storm water. Hence, option (D) is correct.
The given problem is based on the concept and fundamentals of watershed boundary. The watershed boundary is defined as the topmost elevations surrounding the lake or river segment, such that the drop of water falling outside the boundary will drain to another watershed.
Watersheds are the naturally occurring boundaries that determine into which streams, rivers, and oceans water naturally flows.It is necessary to plot out the concept of watershed because the surface water and storm water runoff will drain downstream within the watershed boundaries.Thus, we can conclude that the watersheds are the major hydrological structures that supports the downstream of surface water and storm water. Hence, option (D) is correct.
Learn more about the watershed boundary here:
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Jack travelled 360 km at an average speed of 80 km/h. Elaine took 1.5 hours more to complete the same amount of distance. What was Elaine’s average speed for the whole journey? _____km/h and m/s
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
Velocity is defined as rate of change of displacement wit respect to time.
tangential velocity is (11/10)πr , where r is radius of circular track.
Since, tangential velocity is, [tex]=\frac{distance}{time}[/tex]
In one revolution, distance travelled is circumference of circular track.
If radius of circular track is r , then distance travelled in one revolution is, = 2πr
So, 11 revolutions = 11(2πr) = 22πr
Time taken = 20 second
So, tangential velocity = 22πr/20 = (11/10)πr meter per second.
Learn more:
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