Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm. (Plus could you tell me which sides i can use for starting the diagram) please help me before tmrw

Answer:

A= 3x B= 6/8

Step-by-step explanation:

The value of a is 7, and the value of b is 2√(2) for the given quadratic function f(x) = x² - 14x + 53.

The quadratic function is defined as a function containing the highest power of a variable is two.

The quadratic function f(x) = x² - 14x + 53 is equal to zero when x = a + bi or x = a - bi. This means that the roots of the quadratic equation are a + bi and a - bi.

The roots of a quadratic equation can be found using the quadratic formula:

x = (-b +/- √(b² - 4ac)) / (2a)

In this case, a = 1, b = -14, and c = 53. Substituting these values into the quadratic formula, we get:

x = (-(-14) +/- √((-14)² - 4153)) / (2*1)

x = (14 +/- √(196 - 212)) / 2

x = (14 +/- √(-16)) / 2

Since the square root of a negative number is an imaginary number, the roots of the quadratic equation are a + bi and a - bi, where a = 14/2 = 7 and b = √(-16)/2 = 2√(2).

Therefore, the value of a is 7, and the value of b is 2√(2).

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The sequence of transformation is a reflection across the x-axis, followed by horizontal shift to the right by 2 units, and vertical shift up by 6 units

The vertices of triangle ABC are given as:

[tex]A = (1,9)[/tex]

[tex]B = (3,12)[/tex]

[tex]C =(4,4)[/tex]

The vertices of triangle A"B"C" are given as:

[tex]A" = (3,-3)[/tex]

[tex]B" = (5,-6)[/tex]

[tex]C" =(6,2)[/tex]

Start by reflecting the coordinates of triangle ABC across the x-axis.

The rule of this transformation is:

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex]A' =(1,-9)[/tex]

[tex]B' =(3,-12)[/tex]

[tex]C' =(4,-4)[/tex]

Next, shift triangle A'B'C' 2 units right and 6 units up

The rule of this transformation is:

[tex](x,y) \to (x+2,y+6)[/tex]

So, we have:

[tex]A" = (3,-3)[/tex]

[tex]B" = (5,-6)[/tex]

[tex]C" =(6,2)[/tex]

Hence, the sequence of transformation is a reflection across the x-axis, followed by horizontal shift to the right by 2 units, and vertical shift up by 6 units

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Answer:

hypotenuse Pythagoras property

Answer:

60

Step-by-step explanation:

10 ×6

that is the simple answer to your question

Answer:

53

Step-by-step explanation:

248-195 is 53

you should take his weight and then subtract the amount he wants to weigh

Answer:

53 pounds

Step-by-step explanation:

248 minus 195 which gives you 53

He needs to lose 53 pounds.

Hope that helped!

Answer:

In both the cases, the given total amount is given as:

T  = 10 + 0.05 m     (when minutes talked m   < 600)

T   =  40   +   0.15 k           (when minutes talked  k   > 600)

Step-by-step explanation:

Answer:

Step-by-step explanation:

The coordinates of the graph representing the given situation are listed below

A (0 ,400)

B ( 1 ,350 )

C (2,300)

D(3,250)

 E(4, 200)

 F(5, 150)

 G(6, 100)

  H(7, 50)

  I (8, 0)

The graph attached shows the nature of the graph.

Answer:

42

Step-by-step explanation:

the half of 42 is 21 so if she mailed the half of it then she just have 21 cards

Answer:

x = - 9/10

workings

2/3 x = - 3/5

multiply by 3/2 on both sides

x = - 9/10

Answer:

2/3x=-3/5

x=-3/5*3/2

x=-8/10

Answer:  Attached.

Step-by-step explanation:

Either solve the equations directly, or graph them and look for the point of intersection.  

Answer:

$79

Step-by-step explanation:

Answer:

There is no difference

Step-by-step explanation:

The difference between the polynomials is 7y² + 8xy - 3

Polynomials are functions that have a degree of power greater than two.

According to the question we are to find the difference between the polynomials (7y2 + 6xy) - (-2xy + 3)

f(x, y) = (7y^2 + 6xy) - (-2xy + 3)

f(x, y) = 7y² + 6xy + 2xy - 3

f(x, y) = 7y² + 8xy - 3

Hence the difference between the polynomials is 7y² + 8xy - 3

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Answer: No, this relation is not a function.

Step-by-step explanation:

Two of the points with the same Y axis have different X values (as stated in answer A)

Answer:

32

...when you subtract five from 37

It is a pattern that goes:

-13

-11

-9

-7

and now -5 = 32

Answer: #2 CD=CA

Step-by-step explanation:

So sorry if wrong but i think it may be right.

GOOD LUCK!!

the average weight of 4boys 39.6 is Wight

Answer:

57kg

Step-by-step explanation:

The maximum weight of a shipping container would be 57 kilograms.

The units of measurement are a collection of units used to quantify various physical quantities. Since ancient times, humans have measured these things using a variety of units, including length, mass, volume, current, and temperature.

The maximum weight of a shipping container is 125 pounds which are given in the question.

We have to determine the maximum weight in kilograms

We know that the unit conversion of pounds to kilograms as

1 pound ≈ 0.45359237 kilogram

Multiply by 125 to get

125 pounds = 0.45359237 × 125 kilograms

125 pounds = 56.69904625 kilograms

Round to the nearest kilogram,

125 pounds = 57 kilograms

Therefore, the maximum weight of a shipping container would be 57 kilograms.

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Step-by-step explanation:

hope it will help you....

Answer:it is possible to have a triangle with the given side lengths. 7,9,13. Add any two sides and see if it is greater than the other side.

Step-by-step explanation:

Answer:

297 J

Step-by-step explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

Answer:

54 minutes

Step-by-step explanation:

1) There are 60 minutes in an hour. So, you can do 60-36 to find the first value. (24)

2) Add 24 minutes to 30 and get 54 minutes.

Step by step explanation:

4100625+373248

so the answer is;

4473873

answer in Alternative Form

4.473873x10⁶

trust my answer and liked and make it brainliest please

Based on the boxplots, it can be stated that the interquartile ranges for the two websites are the same.

This is so for the following reasons:

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We know

[tex]\\ \sf\Rrightarrow Speed=Distance/Time[/tex]

[tex]\\ \sf\Rrightarrow Distance=Time\times {Speed}[/tex]

Let hours be x

[tex]\\ \sf\Rrightarrow 12x+10x=34[/tex]

[tex]\\ \sf\Rrightarrow 22x=34[/tex]

[tex]\\ \sf\Rrightarrow x=34/22[/tex]

[tex]\\ \sf\Rrightarrow x=17/11[/tex]

[tex]\\ \sf\Rrightarrow x=1.5h[/tex]

Answer:

its C

Step-by-step explanation:

im smart

Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.

There are a few options we can take. One way is to use the tangent ratio to tie together the opposite and adjacent sides, and then apply the inverse tangent (aka arctangent) to get the angle itself.

Let x be the upper left acute angle, and y be the lower right acute angle.

We can say

tan(angle) = opposite/adjacent

tan(x) = 16/5

x = arctan(16/5)

x = 72.645975 approximately

x = 72.6

and also

tan(angle) = opposite/adjacent

tan(y) = 5/16

y = arctan(5/16)

y = 17.3540246

y = 17.4

Note how x+y = 72.6+17.4 = 90. The two acute angles of any right triangle are complementary, meaning they always add to 90. So if you found x, then you can compute y = 90-x without needing the tangent ratio.

Your calculator needs to be in degree mode when using the arctangent function, which is denoted as [tex]\tan^{-1}[/tex] on many graphing calculators.

Answer:

57 cookies

Step-by-step explanation:

32/0.56= 57.14

Answer:

Step-by-step explanation:

The numbers in the fraction cannot be reduced to create a simplified fraction. Therefore there are 3 ways to write this answer ...

1) [tex]\frac{534}{43}[/tex]

2) 12[tex]\frac{18}{43}[/tex]

3) 12.41861